For coherently demodulated BPSK, what should Eb/N0 be in dB so as to give a bit error probability of 0.0015? Choose the closest answer. A: 3.5 dB. B: 7.5 dB. C: 6.5 dB. D: 4.5 dB. E: 5.5 dB Solution Pe= probability of error= 0.5*erfc(E/no) Given Pe= 0.0015 Hence. erfc(E/no)= 0.003 Using table: E/no= 2.09 E/no=6.4 db (C) 6.5 db is correct.