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A girl has re-created Young’s double slit experiment. At a certain slit spacing and deflection
angle, she observes 7 fringes on her screen.
For questions 1 and 2, always refer back to the original conditions (especially spectral
order) that produces 7 fringes.
1) If she wanted to see 11 fringes, by what factor could she change the original slit
spacing, d? Assume she keeps all other factors constant.
2) If she wanted to see 5 fringes, by what factor should she change the original light
wavelength? Assume she keeps all other factors constant.
3) If L and y are equal in length, and the slit spacing, d, is 5 m, how much longer is D1
than D2 ?
4) Instead of light waves, can a beam of small particles be used in Young’s double slit
experiment?
Answers:
1) The original value for the spectral order is 3, since the number of fringes is 7. In
other words, the 7 fringes can be labelled m= -3, -2, -1, 0, 1, 2, and 3.
To see 11 fringes, the value of m must be 5. This is achieved by multiplying our
original m by a factor of 5/3. Use the following equation:
dsinθ = mλ
Since we are told we can only manipulate d in this question, multiply the slit spacing
also by 5/3 (since the m value is directly proportional to d).
2) The original value for the spectral order is 3. To see 5 fringes, we obtain an m value
of 2 by multiplying m by 2/3. Since we are told we can only manipulate the light
wavelength, we multiply the wavelength by 3/2 (since the m value is inversely
proportional to the wavelength).
3) Since L and y are equal, then tanθ = y/L = 1. By taking the inverse tangent, θ = 45°.
The difference between D1 and D2 is equal to dsinθ. Since sinθ = sin45° ≃ 0.707 and
d is equal to 5 m, the difference between D1 and D2 ≃ 3.54 m.
4) Light can be used in this model since it has wave properties. Discovering this fact
was the purpose of Young’s experiment! A beam of particles would not create
fringes on the screen. Only particles that moved directly through the slits would be
able to pass through and hit the screen. The other particles would rebound off of the
slit plate. No wave fringe patterns would be observed.
Photo credit to: http://astro.physics.sc.edu/~rjones/phys153/lec06.html

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Double Slit Experiment

  • 1. A girl has re-created Young’s double slit experiment. At a certain slit spacing and deflection angle, she observes 7 fringes on her screen. For questions 1 and 2, always refer back to the original conditions (especially spectral order) that produces 7 fringes. 1) If she wanted to see 11 fringes, by what factor could she change the original slit spacing, d? Assume she keeps all other factors constant. 2) If she wanted to see 5 fringes, by what factor should she change the original light wavelength? Assume she keeps all other factors constant. 3) If L and y are equal in length, and the slit spacing, d, is 5 m, how much longer is D1 than D2 ? 4) Instead of light waves, can a beam of small particles be used in Young’s double slit experiment?
  • 2. Answers: 1) The original value for the spectral order is 3, since the number of fringes is 7. In other words, the 7 fringes can be labelled m= -3, -2, -1, 0, 1, 2, and 3. To see 11 fringes, the value of m must be 5. This is achieved by multiplying our original m by a factor of 5/3. Use the following equation: dsinθ = mλ Since we are told we can only manipulate d in this question, multiply the slit spacing also by 5/3 (since the m value is directly proportional to d). 2) The original value for the spectral order is 3. To see 5 fringes, we obtain an m value of 2 by multiplying m by 2/3. Since we are told we can only manipulate the light wavelength, we multiply the wavelength by 3/2 (since the m value is inversely proportional to the wavelength). 3) Since L and y are equal, then tanθ = y/L = 1. By taking the inverse tangent, θ = 45°. The difference between D1 and D2 is equal to dsinθ. Since sinθ = sin45° ≃ 0.707 and d is equal to 5 m, the difference between D1 and D2 ≃ 3.54 m. 4) Light can be used in this model since it has wave properties. Discovering this fact was the purpose of Young’s experiment! A beam of particles would not create fringes on the screen. Only particles that moved directly through the slits would be able to pass through and hit the screen. The other particles would rebound off of the slit plate. No wave fringe patterns would be observed. Photo credit to: http://astro.physics.sc.edu/~rjones/phys153/lec06.html