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Algebra 2 Day 4 Notes

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Algebra 2 Day 4 Notes

  1. 1. Day 3 ­ Absolute Value Inequalities We know that the absolute value of a number is the distance that number is  from 0 on a number line. Keeping that in mind, how would we find the solution and graph... |x| ≥ 2 |x| < 2 ­3 ­2 ­1 0 1 2 3 ­3 ­2 ­1 0 1 2 3 1
  2. 2. Solving an absolute value inequality is JUST like solving an absolute value  equation, but with one extra step! Ex 1: 2 | x ­ 3 | ≤ 4 1st ­ Solve as if it were an equation and get two answers. These two solutions are called critical points. 2nd ­ Plot the critical points on a number  line and pick test points (tp) from  each of the three intervals that  have been created. ­10 ­9 ­8 ­7 ­6 ­5 ­4 ­3 ­2 ­1 0 1 2 3 4 5 6 7 8 9 10 **Always plug t.p. into ORIGINAL 2
  3. 3. Ex 2: | 2x + 3 | >  7 1st ­ Solve as if it were an equation and get two answers. These two solutions are called critical points. 2nd ­ Plot the critical points on a number  line and pick test points (tp) from  each of the three intervals that  have been created. ­10 ­9 ­8 ­7 ­6 ­5 ­4 ­3 ­2 ­1 0 1 2 3 4 5 6 7 8 9 10 **Always plug t.p. into ORIGINAL 3

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