Integrative Problems equire the integration of multiple concepts to find the solutions. 187. A 2.14-g sample of sodium hypoiodite is dissolved in water make 1.25 L of solution. The solution pH is 11.32. What is Kp for the hypoiodite ion? Solution molarity    = W/G.M.Wt * volume of solution in L = 2.14/165.893*1.25    = 0.0103M NaIO(aq) ---------> Na^+ (aq) + IO^- (aq) 0.0103M                                 0.0103M PH = 11.32 POH = 14-PH = 14-11.32 =2.68 POH = 2.68 -log[OH^-] = 2.68 [OH^-]   = 10^-2.68   = 0.00209M IO^- (aq) + H2O ----------> HIO(aq) + OH^- I                  0.0103    0    0 C               -0.00209                         0.00209        0.00209 E                0.00821                          0.00209        0.00209 Kb   = [HIO][OH^-]/[IO^-] = 0.00209*0.00209/0.00821   = 0.00053 Kb of hypoiodite ion = 5.3*10^-4 >>>>answer .

1. Integrative Problems equire the integration of multiple concepts to find the solutions. 187. A
2.14-g sample of sodium hypoiodite is dissolved in water make 1.25 L of solution. The solution
pH is 11.32. What is Kp for the hypoiodite ion?
Solution
molarity = W/G.M.Wt * volume of solution in L
= 2.14/165.893*1.25 = 0.0103M
NaIO(aq) ---------> Na^+ (aq) + IO^- (aq)
0.0103M 0.0103M
PH = 11.32
POH = 14-PH
= 14-11.32
=2.68
POH = 2.68
-log[OH^-] = 2.68
[OH^-] = 10^-2.68 = 0.00209M
IO^- (aq) + H2O ----------> HIO(aq) + OH^-
I 0.0103 0 0
C -0.00209 0.00209 0.00209
E 0.00821 0.00209 0.00209

2. Kb = [HIO][OH^-]/[IO^-]
= 0.00209*0.00209/0.00821 = 0.00053
Kb of hypoiodite ion = 5.3*10^-4 >>>>answer