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[10] degrees of freedom assignment
- 1. 1.
N = 7
J = 8
DOF = 3(N – 1) – 2J = 3(6) – 2(8)
DOF = 2
2.
N = 4
J = 3
H = 1
DOF = 3(N – 1) – 2J - H = 3(3) – 2(3) – 1
DOF = 2
3.
N = 8
J =
DOF = 3(N – 1) – 2J = 3(7) – 2(10)
DOF = 1
- 2. 4.
N = 5
J =
DOF = 3(N – 1) – 2J = 3(4) – 2(6)
DOF = 0
5.
N = 8
J =
DOF = 3(N – 1) – 2J = 3(7) – 2(9)
DOF = 3