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Kenny’s POTW Solution

       3/29/10
• When dividing x101 + x+ 1 by x2 + 1, look for a
  pattern.

      X99 -x97 + x95-x93…
x2+ 1 x101+ 0x100+0x99 … + x+1
      -x101 –x100
             -x99 + 0x99
              +x99 + x97
                    +x97 +0x98
                    -x97 - x95
                         -x95…
• The exponents of the answer are decreasing
  by two and switching signs every term.
• If you bring the pattern all the way down to
  terms that can work with the x + 1 in the
  dividend, you end up with… x3 –x.
• Taking this end of the answer, you can apply it
  to the end of the dividend. By using the
  opposite of x3 –x, you work backwards in the
  division like so…
… x3 –x +1       •Since the patter was
x2+ 1 …x5 –x3 +x +1    also followed under
       -x5 – x3        the dividend, it can be
                       concluded that –x3 +x
          -x3 +x       +1 will follow. When
           +x3 +x      the division is
               2x +1   completed, the
                       remainder becomes
                       2x+1/ x2+ 1

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Kenny Mc Pherson P O T W

  • 2. • When dividing x101 + x+ 1 by x2 + 1, look for a pattern. X99 -x97 + x95-x93… x2+ 1 x101+ 0x100+0x99 … + x+1 -x101 –x100 -x99 + 0x99 +x99 + x97 +x97 +0x98 -x97 - x95 -x95…
  • 3. • The exponents of the answer are decreasing by two and switching signs every term. • If you bring the pattern all the way down to terms that can work with the x + 1 in the dividend, you end up with… x3 –x. • Taking this end of the answer, you can apply it to the end of the dividend. By using the opposite of x3 –x, you work backwards in the division like so…
  • 4. … x3 –x +1 •Since the patter was x2+ 1 …x5 –x3 +x +1 also followed under -x5 – x3 the dividend, it can be concluded that –x3 +x -x3 +x +1 will follow. When +x3 +x the division is 2x +1 completed, the remainder becomes 2x+1/ x2+ 1