Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). ***The answer is NOT .1799 as previously provided by rapunzal so I need correct answer please. Thanks. Solution z1 = lower z score = 0.52 z2 = upper z score = 1.22 Using table/technology, the left tailed areas between these z scores is P(z < z1) = 0.698468212 P(z < z2) = 0.888767563 Thus, the area between them, by subtracting these areas, is P(z1 < z < z2) = 0.1903 [ANSWER] ***********************.