Write a program in Java that reads a set of doubles from a file, sto.pdf

•

0 likes•2 views

will you give your wife your money Solution Yes, after marriage the couple is a family, and every individual in the family has basic needs which can be fulfilled only by money. Even when only the husband earns, the income is meant for the family, as he is equally responsible for each and every member of the family. However it is better, if every individual in the family earns independently..

Education

Write a program in Java that reads a set of doubles from a file, stores them in an array or
ArrayList, and then prints them back out to the console (using System.out.println statements) in
REVERSE order.
For example, if the input file input.txt file contains
27.3
45.6
98.3
10.1
The console output will display
10.1
98.3
45.6
27.3
Solution
ReadAndDisplayReverse.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class ReadAndDisplayReverse {
public static void main(String[] args) throws FileNotFoundException {
File inputFile = new File("D:input.txt");
if(inputFile.exists()){
Scanner scan = new Scanner(inputFile);
ArrayList list = new ArrayList();
while(scan.hasNextDouble()){
list.add(scan.nextDouble());
}
System.out.println("The numbers in reverse order: ");
for(int i=list.size()-1; i>=0; i--){
System.out.println(list.get(i));

}
}
else{
System.out.println("Input file does not exist");
}
}
}
Output:
The numbers in reverse order:
10.1
98.3
45.6
27.3

Similar to Write a program in Java that reads a set of doubles from a file, sto.pdf

import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; import java.util.List; import java.util.Scanner; public class FileEdit { public static List lines = new ArrayList(); public static void main(String[] args) throws IOException { Scanner s = new Scanner(System.in); System.out.print("EDIT: "); String fileName = s.nextLine(); BufferedReader br = new BufferedReader(new FileReader(new File(fileName))); String str=""; int count=0; while((str=br.readLine())!=null) { lines.add(count, str); System.out.println((++count) + "> "+ str); } String text=""; String command = ""; System.out.print((++count)+"> "); command=s.nextLine(); String commandArr[]; int flag; while(!command.equals("E")) { flag=0; commandArr = command.split("\\s"); if(commandArr[0].equals("I")) //Insertion { while(true) { if(commandArr.length==1&&flag!=2) { System.out.print((count)+"> "); text = s.nextLine(); insertLine(text,count-1); } else if(commandArr.length==2&&flag!=2) { System.out.print((commandArr[1])+"> "); count=Integer.parseInt(commandArr[1]); text = s.nextLine(); insertLine(text,Integer.parseInt(commandArr[1])-1); } else insertLine(text,count-1); System.out.print((++count)+"> "); command=s.nextLine(); commandArr = command.split("\\s"); if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm andArr[0].equals("E")) { flag=1; break; } else { flag=2; text=command; } } } else if(commandArr[0].equals("L")) //Listing { printList(); } else if(commandArr[0].equals("D")) //Deletion { if(commandArr.length==1) { deleteLine(count-1,count-1); } else if(commandArr.length==2) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1); } else if(commandArr.length==3) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1); } count=lines.size(); } if(flag!=1) { System.out.print((count++)+"> "); command = s.nextLine(); } } } public static void insertLine(String text,int count) { if (count >= lines.size()) { for(int i = lines.size(); i <= count; i++) { lines.add(null); } } lines.set(count,text); } public static void deleteLine(int start,int end) { for(int i=start;i<=end;i++) lines.remove(i); } public static void printList() { for(int i=0;i "+lines.get(i)); } } Here is my output: EDIT: textin.txt 1> The First Line 1> 2> And another line 3> I 3 3> The second line 4> One more line 5> L 1> null 2> null 3> The second line 4> One more line 5> D 2 3> L 1> null 2> The second line 3> One more line 4> E How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like this: 1> The first line 2> 3> And another line 4> I 3 3> The second line 4> One more line 5> L 1> The first line 2> 3> The second line 4> One more line 5> And another line 5> D 2 4> L 1> The first line 2> The second line 3> One more line 4> And another line 5> E.

import java.io.BufferedReader;import java.io.File;import java.io.pdf

manojmozy

Write a program that will count the number of characters, words, and lines in a file. Words are separated by whitespace characters. The file name should be passed as a command-line argument, as shown; c:\\exercise>java Exercise12_13 Loan.java File Loan.java has 1919 characters 210 words 71 lines c:\\exercise> Solution import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; import java.util.StringTokenizer; public class ass1 { public static void main(String[] args) throws FileNotFoundException { //Â Â Scanner console = new Scanner(System.in); System.out.println(args[0]); //System.out.println(args[1]); //System.out.println(args[2]); String inputFile=args[0]; File file = new File(inputFile); Scanner in = new Scanner(file); int words = 0; int lines = 0; int chars = 0; while(in.hasNextLine()) { lines++; String line = in.nextLine(); chars += line.length(); words += new StringTokenizer(line, \" \").countTokens(); } System.out.println(\"characters are \"+chars); System.out.println(\"words are \"+words); System.out.println(\"lines are \"+lines); } } .

Write a program that will count the number of characters- words- and l.docx

lez31palka

Here is my code for a line/file editor: import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; import java.util.List; import java.util.Scanner; public class FileEdit { public static List lines = new ArrayList(); public static void main(String[] args) throws IOException { Scanner s = new Scanner(System.in); System.out.print("EDIT: "); String fileName = s.nextLine(); BufferedReader br = new BufferedReader(new FileReader(new File(fileName))); String str=""; int count=0; while((str=br.readLine())!=null) { lines.add(count, str); System.out.println((++count) + "> "+ str); } String text=""; String command = ""; System.out.print((++count)+"> "); command=s.nextLine(); String commandArr[]; int flag; while(!command.equals("E")) { flag=0; commandArr = command.split("\\s"); if(commandArr[0].equals("I")) //Insertion { while(true) { if(commandArr.length==1&&flag!=2) { System.out.print((count)+"> "); text = s.nextLine(); insertLine(text,count-1); } else if(commandArr.length==2&&flag!=2) { System.out.print((commandArr[1])+"> "); count=Integer.parseInt(commandArr[1]); text = s.nextLine(); insertLine(text,Integer.parseInt(commandArr[1])-1); } else insertLine(text,count-1); System.out.print((++count)+"> "); command=s.nextLine(); commandArr = command.split("\\s"); if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm andArr[0].equals("E")) { flag=1; break; } else { flag=2; text=command; } } } else if(commandArr[0].equals("L")) //Listing { printList(); } else if(commandArr[0].equals("D")) //Deletion { if(commandArr.length==1) { deleteLine(count-1,count-1); } else if(commandArr.length==2) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1); } else if(commandArr.length==3) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1); } count=lines.size(); } if(flag!=1) { System.out.print((count++)+"> "); command = s.nextLine(); } } } public static void insertLine(String text,int count) { if (count >= lines.size()) { for(int i = lines.size(); i <= count; i++) { lines.add(null); } } lines.set(count,text); } public static void deleteLine(int start,int end) { for(int i=start;i<=end;i++) lines.remove(i); } public static void printList() { for(int i=0;i "+lines.get(i)); } } Here is my output: EDIT: textin.txt 1> The First Line 1> 2> And another line 3> I 3 3> The second line 4> One more line 5> L 1> null 2> null 3> The second line 4> One more line 5> D 2 3> L 1> null 2> The second line 3> One more line 4> E How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like this: 1> The first line 2> 3> And another line 4> I 3 3> The second line 4> One more line 5> L 1> The first line 2> 3> The second line 4> One more line 5> And another line 5> D 2 4> L 1> The first line 2> The second line 3> One more line 4> And another line 5> E.

Here is my code for a linefile editor import java.io.BufferedRea.pdf

pratyushraj61

Create a text file named lnfo.txt. Enter the following informatio.pdf

shahidqamar17

Write a java program that allows the user to input the name of a fil.docx

ajoy21

Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\" Solution package expertques; import java.io.File; import java.io.PrintWriter; import java.util.Scanner; public class evenoddwithfile { public static void main(String[] args) throws Exception { File in;//file input File even = new File(\"f://even.txt\");//creates file even File odd = new File(\"f://odd.txt\");//creates file odd Scanner s = new Scanner(System.in);//reads input from console or user System.out.println(\"Enter the file name with path: \"); in = new File(s.nextLine()); System.out.println(\"Enter the number of integers n the file: \"); int n = s.nextInt(); if (in.exists()) {//checks if input file exist or not Scanner ins = new Scanner(in);//reads input file PrintWriter pe = new PrintWriter(even);//write to even file PrintWriter po = new PrintWriter(odd);//writes to odd file for (int i = 0; i < n; i++) {//loop till the numbers exists int x = ins.nextInt();//reads from input file if (x % 2 == 0) {//checks for even or odd pe.println(x);//if even writes in even file } else { po.println(x);//if odd writes in odd file } } pe.close();//closes even file very important else nothing will be written in the file po.close();//closes odd file very important else nothing will be written in the file System.out.println(\"File successfully written with odds and evens\"); } else { System.out.println(\"Error file not found at specified path\");//if file not exist } } } output run: Enter the file name with path: f://integers.txt Enter the number of integers n the file: 8 File successfully written with odds and evens BUILD SUCCESSFUL (total time: 6 seconds) .

Write a java program that allows the user to input the name of a file.docx

noreendchesterton753

Lab4

siragezeynu

Write a Java program that opens the file, reads all the Grade from the file, and using a method calculates and displays the following A) Displays the grades with their letter values (80 - B) B) the sum of the Grades in the file C) the average of the Grades in the file Solution GradeRead.java import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class GradeRead { public static void main(String[] args) throws FileNotFoundException { Scanner scan1 = new Scanner(System.in); System.out.print(\"Enter the file name: \"); String fileName = scan1.next(); File file = new File(fileName); if(file.exists()){ Scanner scan = new Scanner(file); calculateGradeDetail(scan); } else{ System.out.println(\"Input does not exist\"); } } public static void calculateGradeDetail(Scanner scan){ int sum = 0; int count = 0; char gradeLetter = \'\\0\'; while(scan.hasNextInt()){ count++; int n = scan.nextInt(); sum = sum + n; if(n >=90 && n<=100){ gradeLetter = \'A\'; } else if(n >=80 && n<90){ gradeLetter = \'B\'; } else if(n >=70 && n<80){ gradeLetter = \'C\'; } else if(n >=60 && n<=70){ gradeLetter = \'D\'; } else { gradeLetter = \'E\'; } System.out.println(\"Grade: \"+gradeLetter+\" - \"+n); } System.out.println(\"The sum of the Grades in the file: \"+sum); double average = sum/(double)count; System.out.println(\"the average of the Grades in the file: \"+average); System.out.println(); } } Output: Enter the file name: D:\\\\grade.txt Grade: D - 60 Grade: C - 70 Grade: B - 80 Grade: A - 90 Grade: A - 100 Grade: E - 40 Grade: E - 50 Grade: D - 60 The sum of the Grades in the file: 550 the average of the Grades in the file: 68.75 Grade.txt 60 70 80 90 100 40 50 60.

Write a Java program that opens the file, reads all the Grade from t.pdf

fashiionbeutycare

Inheritance

آصف الصيفي

Please help me with a UML class diagram for the following code: import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; import java.util.List; import java.util.Scanner; public class FileEdit { public static List lines = new ArrayList(); public static void main(String[] args) throws IOException { Scanner s = new Scanner(System.in); System.out.print("EDIT: "); String fileName = s.nextLine(); BufferedReader br = new BufferedReader(new FileReader(new File(fileName))); String str=""; int count=0; while((str=br.readLine())!=null) { lines.add(count, str); System.out.println((++count) + "> "+ str); } String text=""; String command = ""; System.out.print((++count)+"> "); command=s.nextLine(); String commandArr[]; int flag; while(!command.equals("E")) { flag=0; commandArr = command.split("\\s"); if(commandArr[0].equals("I")) //Insertion { while(true) { if(commandArr.length==1&&flag!=2) { System.out.print((count)+"> "); text = s.nextLine(); insertLine(text,count-1); } else if(commandArr.length==2&&flag!=2) { System.out.print((commandArr[1])+"> "); count=Integer.parseInt(commandArr[1]); text = s.nextLine(); insertLine(text,Integer.parseInt(commandArr[1])-1); } else insertLine(text,count-1); System.out.print((++count)+"> "); command=s.nextLine(); commandArr = command.split("\\s"); if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm andArr[0].equals("E")) { flag=1; break; } else { flag=2; text=command; } } } else if(commandArr[0].equals("L")) //Listing { printList(); } else if(commandArr[0].equals("D")) //Deletion { if(commandArr.length==1) { deleteLine(count-1,count-1); } else if(commandArr.length==2) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1); } else if(commandArr.length==3) { deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1); } count=lines.size(); } if(flag!=1) { System.out.print((count++)+"> "); command = s.nextLine(); } } } public static void insertLine(String text,int count) { if (count >= lines.size()) { for(int i = lines.size(); i <= count; i++) { lines.add(null); } } lines.set(count,text); } public static void deleteLine(int start,int end) { for(int i=start;i<=end;i++) lines.remove(i); } public static void printList() { for(int i=0;i "+lines.get(i)); } }.

Please help me with a UML class diagram for the following code im.pdf

aioils

import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; import java.util.StringTokenizer; /** * Read a .dat file and reverse it. * CPS 350 */ public class Reverse { public static void main(String[]args) { if (args.length != 3) { System.err.println(" Incorrect number of arguments"); System.err.println(" Usage: "); System.err. println("\tjava Reverse <stack type> <input file> <output file>"); System.exit(1); } boolean useList = true; if (args[0].compareTo("list")==0) useList = true; else if (args[0].compareTo("array")==0) useList = false; else { System.err.println("\tSaw "+args[0]+" instead of list or array as first argument"); System.exit(1); } try { // // Set up the input file to read, and the output file to write to // BufferedReader fileIn = new BufferedReader(new FileReader(args[1])); PrintWriter fileOut = new PrintWriter(new BufferedWriter(new FileWriter(args[2]))); // // Read the first line of the .dat file to get sample rate. // We want to store the sample rate value in a variable, // but we can ignore the "; Sample Rate" part of the line. // Step through the first line one token (word) at a time // using the StringTokenizer. The fourth token is the one // we want (the sample rate). // StringTokenizer str; String oneLine; int sampleRate; String strJunk; oneLine = fileIn.readLine(); str = new StringTokenizer(oneLine); strJunk = str.nextToken(); // Read in semicolon strJunk = str.nextToken(); // Read in "Sample" strJunk = str.nextToken(); // Read in "Rate" // Read in sample rate sampleRate = Integer.parseInt(str.nextToken()); // // Read in the remainder of the file on line at a time. // The values in the first column are thrown away. // Place values from the second column on the stack. // Stop reading if we reach the end of the file. // DStack s; if (useList) s = new ListStack(); else s = new ArrayStack(); String timestep; double data; int count = 0; while ((oneLine = fileIn.readLine()) != null) { if (oneLine.charAt(0) == ';') { continue; } str = new StringTokenizer(oneLine); // Read in time step value from first col.

import java.io.BufferedReader;import java.io.BufferedWriter;.docx

wilcockiris

Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments. // complete import statement(s) here public class FileRead { public static void main(String[] args) { // complete the code here } } Solution import java.io.File; import java.util.Scanner; /** * @author * */ public class FileRead { /** * @param args */ public static void main(String[] args) { // complete the code here Scanner scanner = null; try { File file = new File(\"FruitList.txt\"); scanner = new Scanner(file); // checks the file contains data if (scanner.hasNext()) { // prints first line System.out.println(scanner.nextLine()); } } catch (Exception e) { // TODO: handle exception } } } FruitList.txt Apple Orange Papaya Banana Jack Fruit Watermelon KIWI Grapes Mango Pineapple OUTPUT: Apple .

Complete the following Java code such that it opens a file named Fruit.docx

ljohn878

Packages and interfaces

bhuvaneshwariA5

In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a “fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is often used to implement various wait lists in computer systems. For example, jobs waiting to use the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short, whenever we want a fair strategy for waiting we use queues. A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it differs in that it allows for insertions AND deletions from either end of the list (both the front and the rear). Your implementation MUST use a doubly-linked-list implementation. You may not use a static array implementation. Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for any insertion or deletion. The 6 operations supported are : public void insertFront( int item ) - insert the given item (as a node) into the first position of the Deque. public void insertRear( int item ) - insert the given item (as a node) into the last position of the Deque. public int deleteFront( ) - delete and return the element stored in the first node of the Deque. public int deletRear( ) – delete and return the element stored in the last node of the Deque. public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not. public void printDeque( ) - print the integers from the list, one per line, from the first element through to the last in order. Classes Your program must implement the following 3 classes. public class dequeDriver This class will contain your program’s main method. It will need to declare a deque object and process input as indicated below. Your program should prompt the user for the path of an input file. It should open the file for input and process it line by line. Each line of the input file will have one of the following forms. PR IF IR DF DR The meanings of each input is as follows: PR - print the current contents of the deque from front to rear using the printDeque( ) method of the deque object. IF - insert the given int value into the front of the deque. IR - insert the given int value into the rear of the deque. DF - delete the front value from the deque. DR – delete the rear element of the deque. Below is an example input file that your program should be able to process. PR IF 4 IF 5 IF 6 IR 7 PR DR PR DF PR The output for the input file shown above is : EMPTY DEQUE ----- Front ----- 6 5 4 7 ----- Rear ----- ----- Front ----- 6 5 4 ----- Rear ----- ----- Front ----- 5 4 ----- Rear ----- public class dequeNode This class will implement the linked nodes that will be used to implement the deque itself. It should have the following protected data members. protected dequeNode next; // next pointer to next node protected dequeNode prev; // previous pointer to previous node protected int val; // the integer value stored within the dequeNod.

In java , I want you to implement a Data Structure known as a Doubly.pdf

aromalcom

I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work package projectOne; import java.io.File; import java.io.FileNotFoundException; import java.util.ArrayList; import java.util.Scanner; import java.util.*; import java.io.*; public class Main { public static void main(String[] pArgs){ Main mainObject = new Main(); mainObject.run(); } private void run() { public FileReader readFile() throws FileNotFoundException { FileReader file = new FileReader(\"p01-in.txt\"); return file; } public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException { Scanner data_read = new Scanner(new BufferedReader(file)); ArrayList<Integer> data = new ArrayList<Integer>(); while (data_read.hasNext()) { int item = data_read.nextInt(); data.add(item); } return data; } public ArrayList<Integer> calcRuns(ArrayList<Integer> data) { ArrayList<Integer> runs = new ArrayList<Integer>(); Iterator<Integer> i_data = data.iterator(); int run = 0; int temp = i_data.next(); while (i_data.hasNext()) { int t1 = i_data.next(); if (temp < t1) run++; else { runs.add(run); run = 0; } temp = t1; } i_data = data.iterator(); temp = i_data.next(); run = 0; while (i_data.hasNext()) { int t1 = i_data.next(); if (temp > t1) run++; else { runs.add(run); run = 0; } temp = t1; } return runs; } public void writeOutput(ArrayList<Integer> runs) throws IOException { PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\")); ArrayList<Integer> run_count = new ArrayList<Integer>(); int i = 0; int r_count = Collections.frequency(run_count, i); while (i < 100) { run_count.add(r_count); i++; r_count = Collections.frequency(runs, i); } Iterator<Integer> i_runs = run_count.iterator(); i = 0; while (i_runs.hasNext()) { int run = i_runs.next(); String line = \"run_\" + i + \" ,\" + run; i++; out.println(line); } } public void run() throws Exception { FileReader fin = this.readFile(); ArrayList<Integer> data = this.getData(fin); ArrayList<Integer> runs = this.calcRuns(data); this.writeOutput(runs); } } Solution In your program you have to change the syntax errors at method declaration.so your not getting output. .

I can not get my code to comply it gets mad that I have run declare mo.docx

hamblymarta

Java ppt

Rohan Gajre

Write a java program that compute the frequency of each word in the file Task: Implementing Word Counter Problem description: Given a text file, you need to compute the frequency of each word in the file. WordFrequency word: String count: int +WordFrequency(String) +getWord): String +getCount): int +incCount): void TestClass +static main(String[): void / /implements ArrayList of // WordFrequency The WordFrequency class stores the frequency (count) of each word. Solution import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.util.LinkedHashMap; import java.util.List; import java.util.Map; import java.util.Map.Entry; class FileIO { public static void main (String[] args) throws IOException { readTextFileInBinaryMode (\"T.txt\"); } public static void readTextFileInBinaryMode (String fileName) { FileReader fileReader = null; LinkedHashMap <String, Integer> wordcount = new LinkedHashMap <String, Integer> (); try { File file = new File (fileName); fileReader = new FileReader (file); int ch = -1; boolean prevCharIsNotSpace = true; StringBuilder strBuild = new StringBuilder (); while ((ch = fileReader.read ()) != -1) { if (ch == 32) { if (prevCharIsNotSpace) { Integer freq = wordcount.get (strBuild.toString ()); wordcount.put (strBuild.toString (), (freq == null ? : freq + 1)); } prevCharIsNotSpace = false; continue; } if (prevCharIsNotSpace == false) strBuild = new StringBuilder (); strBuild.append ((char) ch); prevCharIsNotSpace = true; } } catch (Exception e) { System.out.println(\"Exception occurs\"+e.getException()); } //sorting List <Map.Entry <String, Integer>> list = new ArrayList <Map.Entry <String, Integer>> (); for (Map.Entry <String, Integer> entry : wordcount.entrySet ()) { System.out.println (entry.getKey () + \" \" + entry.getValue ()); list.add (entry); } Collections.sort (list, new MapComprator ()); for (Map.Entry <String, Integer> entry : list) { System.out.println (entry.getKey () + \" \" + entry.getValue ()); } } } class MapComprator implements Comparator <Map.Entry <String, Integer>> { public int compare (Entry <String, Integer> o1, Entry <String, Integer> o2) { return (o2.getValue ().compareTo (o1.getValue ())); } } .

Write a java program that compute the frequency of each word in the fi.docx

noreendchesterton753

JAVA Write a program that takes a command-line argument representing a text file name. The program should read the given text file and print two lists, each in ascending order. One list should be the words that exist only once in the text file. The other list should be the words that appear more than once. Ignore the case of the words when determining whether a word has appeared more than once. Your program may ignore punctuation. Solution //CountOccurrenceOfWords.java import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.Map; import java.util.Set; import java.util.TreeMap; import java.util.ArrayList; import java.util.*; public class CountOccurrenceOfWords { public static void main(String[] file) throws FileNotFoundException, IOException { if (file.length == 0) { System.out.println(\"Usage: java CountOccurrenceOfWords targetfile\"); System.exit(0); } BufferedReader br = null; br = new BufferedReader(new FileReader(file[0])); String text = null; TreeMap treemap = new TreeMap(); try { while ((text = br.readLine()) != null) { String[] line = text.split(\"[ \ \\t\ .,;:!?(){}]\"); for (int count = 0; count < line.length; count++) { String key = line[count].toLowerCase(); if (key.length() > 0) { if (treemap.get(key) == null) { treemap.put(key, 1); } else { int value = treemap.get(key).intValue(); value++; treemap.put(key, value); } } } } Set> entrySet = treemap.entrySet(); // create an empty array list with an initial capacity ArrayList list1 = new ArrayList(100); ArrayList list2 = new ArrayList(100); for (Map.Entry entry : entrySet) { if(entry.getValue() == 1 ) list1.add(entry.getKey()); else list2.add(entry.getKey()); } System.out.print(\"Words that appear \" + \"one \"+ \"time are: \"); for (String word : list1) { System.out.print(word + \", \"); } System.out.println(\"\ \"); System.out.print(\"Words that appear more than one time are: \"); for (String word : list2) { System.out.print(word + \", \"); } System.out.println(\"\ \"); } catch (IOException error) { System.out.println(\"Invalid File\"); } finally { br.close(); } } } /* words.txt Sophie Sally and Jack were dachshunds Dachshunds are the best dogs and all dogs are better than cats output: Words that appear one time are: all, best, better, cats, jack, sally, sophie, than, the, were, Words that appear more than one time are: and, are, dachshunds, dogs, */.

JAVAWrite a program that takes a command-line argument representin.pdf

jibinsh

Lec2

Nikhil Chilwant

srgoc

Gaurav Singh

Similar to Write a program in Java that reads a set of doubles from a file, sto.pdf (20)

import java.io.BufferedReader;import java.io.File;import java.io.pdf

Write a program that will count the number of characters- words- and l.docx

Here is my code for a linefile editor import java.io.BufferedRea.pdf

Create a text file named lnfo.txt. Enter the following informatio.pdf

Write a java program that allows the user to input the name of a fil.docx

Write a java program that allows the user to input the name of a file.docx

Lab4

Write a Java program that opens the file, reads all the Grade from t.pdf

Inheritance

Please help me with a UML class diagram for the following code im.pdf

import java.io.BufferedReader;import java.io.BufferedWriter;.docx

Complete the following Java code such that it opens a file named Fruit.docx

Packages and interfaces

In java , I want you to implement a Data Structure known as a Doubly.pdf

I can not get my code to comply it gets mad that I have run declare mo.docx

Java ppt

Write a java program that compute the frequency of each word in the fi.docx

JAVAWrite a program that takes a command-line argument representin.pdf

Lec2

srgoc

More from arihantpatna

Compare and contrast the advantages and disadvantages of arrays and linked lists. Give an example problem that is best accomplished by an array. Give an example problem that is best accomplished with an array. access directly with array while linked list take some time to access data. However, list can insert easily the value into middle of list while array needs to increase the capacity and copy behind part and fore part and input. Array\'s size is fixed while linked list has flexible size. Stack or queue is well match with linked list because if push and pop from the end point of data structure. array is good with when program needs random access. Solution Ex: 1,2,3,4,5 to be stored in array a[0]=1, a[1]=2 etc.. in LL we have to create space for 1 and store the address next to it as null. next when we want to insert 2 we have to create address for 2 and store that address in pointer of 1. and so on==> 1->2- >3->4->5. Initiallly array size is to be definrd, but ll size can grown dynamicallyArrayLinked ListCollections of elements with same data typeOrdered collection of data conecting by linksArray elements are stored continuosly in memorystored in the space available and are linkedcan have random acessbut here it will be sequential accesstakes more time for insertion and deletion because we are storing continuosly in the memoryit takes more time here as the value of the link needs to changed onlyIt is static memory allocation as we have to decide beforeDynamic we have to create space for each value storedCan be 1D 2D and 3DSingular, Doubly, circularelement is independent because we do not have connection with previous memory locationaddress of the element is stored in the link partneed extra space for pointerneed extra space for pointer.

Compare and contrast the advantages and disadvantages of arrays and .pdf

arihantpatna

Answer and describe the following five plants: habit, habitat, life span, throns, spines or prickles, infloresences, leaves (complexity, attachment to stem, arrangement, blade shape, margin, apex, base, venation and trichomes). Other interesting facts. 1. Isomeris arboea (Bladderpod) - Drought tolerant plant 2. Sinningia macrostachya 3. Ceropegia dichotoma 4. Lilium longiflorum 5. Peperomia verticiliata Solution I. Isomeris arboea Also known as Bladderpod, Burrofat and California cleome.This plant is a fast-growing evergreen dicot shrub from the family Capparaceae. It is a dense shrub with profuse branching and small hairs/trichomes. It normally grows in well-draining rocky areas with good exposure to sunlight. It is found in Southern Sierra Nevada Foothills, Tehachapi Mountain area, San Joaquin Valley,Central Coast, South Coast, Channel Islands, Deserts, and Baja,CA Habitat - Coastal bluffs, hills, desert washes, flats below 3,900\' Height by Width: 3-4\' H x 4\' W Stems - profusely branched; glabrate or puberulent (bark corky, twigs smooth) inflorescence: The plant produces abundant inflorescences at the ends of the stem branches, each a cluster of bright yellow flowers. Each flower has usually four petals and six whiskery protruding stamens with curling tips holding the anthers. The fruit is an inflated capsule about 4 centimeters long and usually oval in shape. It is smooth and green when new, aging to light brown. Fruits when dry, resemble a paper lantern that rattles (the seeds inside the dried fruit rattle around). The flowers are dense terminal racemes. The calyx is four-cleft and the sepals are fused in the basal half. It has four petals ½” long, 6 yellow stamens that are long and a pistil with a short style. Sepals persistent, connate ca. 1/2 of length, green, lanceolate, 4–7 × 2.2–4 mm, margins entire, glabrous; petals yellow, ovate-elliptic, 8–14 × 4.2–5 mm, (apex acute); stamens yellow, 15–25 mm; anthers 2–2.5 mm; gynophore (reflexed), 10–20 mm in fruit; ovary 3–6 mm (often aborting in bud); style 0.9–1.2 mm. Capsules (tardily dehiscent), usually inflated ,(valves sometimes 3), 20–30 × 6–12 mm, smooth. Seeds 5–25, dark brown, obovoid, 6–7 × 5–6 mm, smooth. Leaves: Its leaves are made up of three equal leaflike leaflets, each a long, pointed oval 1-4 cm long. The leaves are alternate, entire, petiolate and trifoliate with leaflets that are oblong-elliptic with small pointed tips. petiole 1–3 cm; leaflets 3, blade oblong-elliptic, 1.5–4.5 × 0.4–1.3 cm, margins serrate, apex acuminate to obtuse, surfaces glaucous. Racemes 1–3 cm (6–40 cm in fruit); bracts unifoliate, obovate to spatulate, 2–15 mm. Pedicels 7–15 mm (thickened in fruit). extra information: II. Sinningia macrostachya Family: Gesneriaceae Popular names – leather leaf, Gloxinia Sinningia macrostachya has a perennial stem base, very stiff leaves, and numerous small orange flowers. Its fleshy stems are joined to the woody trunk. Each year, the woody part of the stems exten.

Answer and describe the following five plants habit, habitat, life .pdf

arihantpatna

A plant has the genotype (Aa; Bb; Cc). How many different genotype.pdf

arihantpatna

A) Explain how bilateral symmetry contributed to motion and cephalization (the evolution of a head and brain)? B) Explain the common adaptations for reproduction seen in both: organisms with a parasitic life-style and sessile organisms (those that do not move). C) Explain why those adaptations are beneficial for each life-style. Solution When the animal has right and left sides morror images of each other such a symettry is called bilateral symmetry. Bilateral symmetry has contributed to both cephalization and locomotion in animals possessing them. Animals wuth bilateral symmetry has locomotive organs legs on opposite sides of the body in symmetrical position. This symmetrical arrangement of locomotive organs enables these animalsto move thotougjly in steady direction. Bilateral symmetry resulted in the concentration of brain ,nerves, sense organs ,eyes to the anterior side of the body forming head..

A) Explain how bilateral symmetry contributed to motion and cephaliz.pdf

arihantpatna

You have been asked to examine a database to evaluate referential integrity. Which of the following should you review? A. Field B. Aggregation C. Composite key D. Foreign key Solution D. The foreign key because it refers to an attribute in one table whose value matches the primary key in another table. Answer A is incorrect because the field refers to the smallest unit of data within a database. Answer B is incorrect because aggregation refers to the process of combining several low-sensitivity items, with the result that these items produce a higher-sensitivity data item. Answer C is incorrect because a composite key is two or more columns that are together designated as the computer’s primary key..

_______ are any substances that when introduced into the body, stimul.pdf

arihantpatna

X=[0:10(a) Create a matrix called test of size 2x2 such that the elements of the matrix test are test(i, j) = (i^2 - j). Use the command window statements to create this matrix. Use the keyboard to alter the value of test(1, 2) to -5 and test(2, 2) to 20 What is the value of test(3)? What does this represent? What is the value of test(5)? Why does this give an error message? Why do test (2, 2) and test (4) yield the same value? Add a row to test so that the last row of test contains the entries 2, 9 Create a 1x2 matrix called test 1 whose elements are 12 and 14. Concatenate test 1 with test. Use the cat function to add another column to test. The elements of this new column are 4, 3, and 7 Solution (a) %(a) creating 2 by 2 test matrix for i=1:2 for j=1:2 test(i,j)=i^2-j; end end test test(1,2)=-5; test(2,2)=20; test (b) test(3)=-5 (Since third element matrix is -5 or actual index test(2,1) so 2+1=3, test(3)=-5). test(5) displays error message because it contains only 4 elements. test(2,2) and test(4) both are same because index (2,2) means (2+2)=4. so test(2,2)=test(4) (c) test(3,1)=2; test(3,2)=9; (d) test1=[12 14]; test=[test; test1].

You decide to spend Break hiking through the Rockies upon arrival, yo.pdf

arihantpatna

Which is the appropriate test (Z test, single sample, independent samples t or related samples t) for the following: A researcher is interested in determining whether a new med for appetite suppression is effective by giving the med to one group that has been matched on weight with another group that reveives a placebo. Solution As the medicine is given to two groups and we want to test whether a new med for appetite suppression is effective or not. This can be tested only by considering the data of the two samples and taking their difference. So, the test has to be a two sample test. So, the possibility of a Z test or a single sample t-test is nullified. Next, as the two sample data are matched by weight, so the data of the two samples are no more independent. Hence, the option of independent t-test is also nullified. So, we are only left with the related sample t-test. And this is also supported by the data. As they are matched by weight, so they are related to each other. Hence we would go for aa \'related sample t-test\'..

Which of the following statements is true about cultureA. Culture.pdf

arihantpatna

What specific mutation is in each of the following proto-oncogenes: A)EGF receptor, B) Ras, C) Src kinase, would cause them to become oncogenes? Explain. Solution A) The most common EGFR mutations are deletion of exon 19 which converts the EGFR proto oncogene to oncogene that leads to lung cancer. B) Ras proto-oncogene encodes a protein that receives and transfers signals required for cell division. Mutation at amino acid position 12 or 61 causes formation of oncoprotein that leads to uncontrolled cell division. Thus mutation of amino acid 12 or 61 converts Ras proto-oncogene to oncogene. C) A truncating mutation of codon 531 of SRC proto-oncogene converts it into oncogene that leads to colorectal cancer.

Which data set has the least sample standard deviation Data set (ii.pdf

arihantpatna

What is the price earnings Ratio for Lowe\'s and Home Depot? HOME DEPOT Balance Sheet Consolidated Balance Sheets - USD ($) $ in Millions LOWES Balance Sheet Consolidated Balance Sheets - USD ($) $ in Millions Consolidated Balance Sheets - USD ($) $ in Millions Jan. 29, 2017 Jan. 31, 2016Current Assets:Cash and Cash Equivalents$ 2,538$ 2,216Receivables, net2,0291,890Merchandise Inventories12,54911,809Other Current Assets608569Total Current Assets17,72416,484Property and Equipment, at cost40,42639,266Less Accumulated Depreciation and Amortization18,51217,075Net Property and Equipment21,91422,191Goodwill2,0932,102Other Assets1,2351,196Total Assets42,96641,973Current Liabilities:Short-Term Debt710350Accounts Payable7,0006,565Accrued Salaries and Related Expenses1,4841,515Sales Taxes Payable508476Deferred Revenue1,6691,566Income Taxes Payable2534Current Installments of Long-Term Debt54277Other Accrued Expenses2,1951,941Total Current Liabilities14,13312,524Long-Term Debt, excluding current installments22,34920,789Other Long-Term Liabilities1,8551,965Deferred Income Taxes296379Total Liabilities38,63335,657STOCKHOLDERS\' EQUITYCommon Stock, par value $0.05; authorized: 10 billion shares; issued: 1.776 billion shares at January 29, 2017 and 1.772 billion shares at January 31, 2016; outstanding: 1.203 billion shares at January 29, 2017 and 1.252 billion shares at January 31, 20168888Paid-In Capital9,7879,347Retained Earnings35,51930,973Accumulated Other Comprehensive Loss(867)(898)Treasury Stock, at cost, 573 million shares at January 29, 2017 and 520 million shares at January 31, 2016(40,194)(33,194)Total Stockholders’ Equity4,3336,316Total Liabilities and Stockholders\' Equity$ 42,966$ 41,973 Solution Price at 29 Jan 2017 = 40194 / 573 = $70.15 per share (from Treasury stock data) Price at 31 Jan 2016 = 33194 / 520 = $63.83 per share EPS for 2017 = (RE $35519 - RE $30973)m = 4546m / outstanding shares 1776m = $2.56 pershare Price Earnings ratio for 2017 = Price on 29 Jan 17 / EPS for 2017 = $70.15 / $2.56 = 27.40 times.

Whats wrong with this Hardy Weinberg question I thought it was a.pdf

arihantpatna

6. List and define the underlying conditions, or assumptions, which have had an impact on the development of GAAP. Solution ANSWER: The underlying conditions/ assumptions, which have had an impact on the development of GAAP are as follows: --Business entity: The company for which the financial statements are prepared is distinct and separate from the owners. --Going concern or continuity : The assumption is made that the organisation will remain in business for an indefinite time frame. --Monetary unit : Accountants requires certain standard of measure to bring financial transactions together in an appropriate way. --Realization: Revenue must be recognized when the earning process is virtually complete and the exchange value need to be objectively determined --Matching: This concept states to recognize the costs that are related with the recognized revenue --Full disclosure: Accounting reports must disclose all facts that may influence the judgment of an informed reader --Materiality: The approach involves the relative size and importance of an item to a business. --Verifiability: The accountant need to adhere as closely as possible to verifiable data. --Industry practices: Few business use accounting reports that do not conform to the general theory that underlies accounting --Transaction approach : The accountant records only events that affect the business financial position and also can be reasonably determined in monetary terms. --Accrual basis: Expenses need to recognized when incurred (matching concept), and revenue are to be recognized when it is realized (realization concept), and --Consistency: The business must give the similar treatment to comparable transactions from period to period --Conservatism : The measurement with the least favorable effect on financial position and net income in the current period need to be selected. --Historical cost : Of the numerous values that could be used, the objective and determinable value should be selected -- Time period With this assumption, inaccuracies of accounting for entity short of its complete life span are accepted..

6. List and define the underlying conditions, or assumptions, which .pdf

arihantpatna

Wha is the difference between the large intestine and colon? Wha is the difference between the large intestine and colon? Solution Answer: The large intestine starts in the pelvis at the right iliac region located immediately under the waist on the right-hand side. It has 5 parts that are -cecum, appendix, colon, rectum and anus. Overall function of large intestine is to form feces. Colon makes up most part of large intestine. It helps in water and salt absorption..

What does the LP tableau below indicate (The xs are decision varia.pdf

arihantpatna

Using the six general trends of the general environment, give a hypothetical example of how each trend could affect a restaurant business. Solution There are six general trends of the general environment-- 1) Demographic Segment--It consists of people from different ethnic groups like Indians, Europeans, Asians etc and its affect on a business. In case of a restaurant business opening of a Indian restaurant in China will attract lower customers 2)Socio Cultural Segment--It consists of diverse set of people in the workplace who helps in the company\'s success in the Global Market. E.g. a business employing women, not engaging into racial discrimination etc. will attract more employees 3)Economic Segment--It depends on the nation\'s economic condition in the World Market. In case of a restaurant business, an economic slowdown or recession will have a negative impact on the business. 4)Legal Segment--This segment is dependent on an economy\'s governance laws, policies, taxation laws and regulations for its employees. In case of restaurant business, a restaurant set up in a country with heavy taxes and strict regulation, operations can be difficult and prove to be of losses. 5)Technological Segment--It relates to technological advancements and updation of newer technology at pace with the competitors. In case of restaurant business, restaurants adopting newer technologies will be able to produce more and earn more 6)Global Segment--This segment expands the organisation globally so that it can gain a competitive advantage over its competitors when they have a global presence in the industry. In case of a restaurant business, going global can prove to be profitable if given chances..

Wha is the difference between the large intestine and colon .pdf

arihantpatna

Using \" for \" loop to calculate compound interest for 20 years. The starting principal is 5000 and the rate is 0.04. Show amount on deposit for each year. Solution #include #include #include int main() { double principal=5000.0; double rate=0.04; int time=20; double amt=principal; for(int i=1;i<=20;i++) { printf(\"\ Deposit for year %d : %lf\",i,amt); amt=amt+((amt*rate*1.0)/100); } printf(\"compound interest for 20 yrs : %lf\",(amt*pow(1.0+(rate/100),20))); return 0; }.

Was airpower decisive in winning World War II Defend your answer..pdf

arihantpatna

Solve the following: a. How many permutations of all 26 letters of the alphabet are there that contain at least one of the words: CAR, CART, SCARF, SCARE, SCAR? b. How many permutations of all 26 letters of the alphabet are there that contain at least one of the words: MAZE, SWORD, PLANT, CARTS? Solution This computer science but: a) The answer should be Factorial(24) i.e . factorial of 24. It can be solved by formulating a simple recurrence relation. b)(26C4+26C5+26C5+26C5)/26!. It can also be seen as a recurrence relation and solved..

Summarize the workflow of the study of microbial diversity. Draw a d.pdf

arihantpatna

Salaries of 40 college graduates who took a statistics course in college have a mean, x , of $ 68,200. Assuming a standard deviation, , of $18,561, construct a 95% confidence interval for estimating the population mean . $___ < < $___ Round to the nearest integer as needed. Solution Confidence Interval CI = x ± Z a/2 * (sd/ Sqrt(n)) Where, x = Mean sd = Standard Deviation a = 1 - (Confidence Level/100) Za/2 = Z-table value CI = Confidence Interval Mean(x)=68200 Standard deviation( sd )=18561 Sample Size(n)=40 Confidence Interval = [ 68200 ± Z a/2 ( 18561/ Sqrt ( 40) ) ] = [ 68200 - 1.96 * (2934.752) , 68200 + 1.96 * (2934.752) ] = [ 62447.887,73952.113 ] = [ 62448 ,73953 ].

Shifting allocations most often arise as a result of which of the fo.pdf

arihantpatna

16.) How would you determine if Cellulous is hydrophobic or hydrophilic? Solution Hydrophilic substance interact with water and willabsorb it easly . Hydrophobicmeans it seperate the water . Cellulise is a plymer chain of monosachhride . It is hydrophilic and atrract water molecules due to its functional group . But it is aplymer chai water does not have ability to surround compltely each monomerof cellulose fiber .Polymer is less soluble than monomwes because of entropy . cellulose have hydrogen bond but not as well as water and plymer have low entropy due to their confuguration and constrained. the attract water on the surface if the molecules are smaller then water . cellulose is a big polymer so the particals are to large too dissolved..

16.) How would you determine if Cellulous is hydrophobic or hydrophi.pdf

arihantpatna

Pattern of Stars Listing 6.4 in the text book demonstrates the use of a nested for loop by printing a pattern of asterisks (stars), starting from the least number of stars per row (1) to the most number of stars per row (10). You will modify this program so that it does the following: Asks the user how many rows of stars they want. Prints the stars starting with the least stars per row and ending with the most stars per row, but the stars must be lined up along the right margin instead of the left. (In other words, print a version of the pattern that has been flipped horizontally i.e. along a vertical axis). You will need: An input statement to prompt the user for the number of rows. An assignment statement to store the number of rows. A nested for loop as shown in Listing 6.4 (pg 263). You will need to modify the conditions in some of your for loops to accomplish this task. This time, you will need two for loops nested within the outermost loop. The outer loop will control the number of rows, as in the example. One of the inner loops will control the number of stars per row, again as in the example. You will need to create another for loop that controls the number of spaces per row, to achieve the intended pattern. The spaces need to be printed before each row of stars is printed. Note: The two inner loops do not have to be nested. See the code shell for the intended design. Sample output: Enter the number of rows: 8 * ** *** **** ***** ****** ******* ******** Code Shell //********************************************************* // StarPattern.java // // This is a modified version of the Stars.java program // from Listing 6.4 in the text. //********************************************************* //import Scanner class here public class StarPattern1 { //------------------------------------------------------ // Prints a triangle shape using asterisk (star) // characters. //------------------------------------------------------ public static void main(String[] args) { //Create Scanner variable final int MAX_ROWS = 10; // Replace this constant // with a variable to store // the number of rows //Ask for number of rows //Store in variable for (int row = 1; /*adjust condition*/; row++) { /*insert a for loop here. This one should control the number of spaces before each star*/ for (int star = 1; star <= row; star++) System.out.print(\"*\"); System.out.println(); } } } Solution //import Scanner class here import java.util.Scanner; public class StarPattern1{ public static void main(String[] args) { Scanner input = new Scanner( System.in ); //Create Scanner variable final int MAX_ROWS; System.out.println(\"Enter the number of rows: \"); MAX_ROWS = input.nextInt(); for (int row = 1; row=row;j--){ System.out.print(\" \"); /*insert a for loop here. This one should control the number of spaces before each star*/ } for (int star = 1; star <= row; star++){ System.out.print(\"*\"); } System.out.println(); } } }.

Please Explain CompletelyWhat defines the beginning of the hepatic.pdf

arihantpatna

ooo T-Mobile LTE 5:40 PM courses.apexlearning.com s of Polynomial Functions Which point is the best approximation of the relative maximum of the polynomial function graphed below? 30 20 2 10 O A (-2.3, 17.9) O B. (-1.4, 16.9) O c. (-1.1, 14.8) D. (-2.1, 17.2) IL Solution in the x axis the value is between -1 and -2 , and the y-axis value is closer to 20 then the answer is the letter B = (-1.4, 16.9).

Plant Diversity II – Seed Plants1. Explain how the rise in pro.pdf

arihantpatna

17) Fill out the following table: Structure Pili or Fimbriae Flagella Capsule PHB inclusion Sulfur granules Magnetosomes Endo LPS layer Cell wall Function Location Solution structure Function Location Pili or fimbrae Required for bacterial conjugation On the surface, embedded in cell membrane Flagella Bacterial cell motility On the surface, embedded in cell membrane; numbers vary from 1 to multiple Capsule Outside the cell envelope Protection from antibiotics, mechanical stress and desiccation PHB inclusion Present in the bacterial cytoplasm Acts as storage granules in bacteria Sulfur granules Inclusion bodies in cytoplasm May aid in metabolism- bacteria that use Hydrogen sulfide as electron source for respiration Magnetosomes Membranous organelles that are present in magnetotactic bacteria; containing magnetic crystals Help the bacteria orient in geomagnetic field to search proper environment Endospores Generally present in the cytoplasm Helps the bacterial cells propagate asexually in extreme conditions LPS layer Part of cell wall in Gram negative bacterial cells Protection of the cells, transport of materials and also imparts pathogenicity to the bacterial cells Cell wall A part of the cell envelope, surrounding cell membrane Protection of the cells, transport of materials and maintenance of osmotic pressure. structure Function Location Pili or fimbrae Required for bacterial conjugation On the surface, embedded in cell membrane Flagella Bacterial cell motility On the surface, embedded in cell membrane; numbers vary from 1 to multiple Capsule Outside the cell envelope Protection from antibiotics, mechanical stress and desiccation PHB inclusion Present in the bacterial cytoplasm Acts as storage granules in bacteria Sulfur granules Inclusion bodies in cytoplasm May aid in metabolism- bacteria that use Hydrogen sulfide as electron source for respiration Magnetosomes Membranous organelles that are present in magnetotactic bacteria; containing magnetic crystals Help the bacteria orient in geomagnetic field to search proper environment Endospores Generally present in the cytoplasm Helps the bacterial cells propagate asexually in extreme conditions LPS layer Part of cell wall in Gram negative bacterial cells Protection of the cells, transport of materials and also imparts pathogenicity to the bacterial cells Cell wall A part of the cell envelope, surrounding cell membrane Protection of the cells, transport of materials and maintenance of osmotic pressure..

17) Fill out the following table Structure Pili or Fimbriae Flagella.pdf

arihantpatna

Let’s assume 3M produces “Command Hooks” at a rate of 10,000 units per day. Before reconfiguring their production process, their flowtime through the process was 100 days. After reconfiguring, the new flowtime is 35 days. After reconfiguring, how many units of work in progress inventory are in the process? < 100,000 Between 100,000 and 300,000 Between 300,000 and 600,000 Between 600,000 and 900,000 >900,000 < 100,000 Between 100,000 and 300,000 Between 300,000 and 600,000 Between 600,000 and 900,000 >900,000 Solution The number of units in the work in progress inventory would be in the range of 600,000 and 900,000. As the flowtime has decreased from 100 days to 35 days, thus there would be inventory of 65 days remaining in the process or in other words there would be wor in process remaining for 65 days. Earlier, when the flowtime was 100 days, then each day production was 10,000, hence inventory in the system would be for 65 days and related with producing 10,000 units per day, which would come in the range of 600,000-900,000..

Mark and I.isa registered for Physics 101 class. Mark attends class 6.pdf

arihantpatna

More from arihantpatna (20)