For air at atmospheric pressure Solubility of N2 in water/blood = 0.015 g/L => 1 L of blood contains 0.015 g of N2 Molar mass of N2 = 28.01 g/mol Moles of N2 per liter of blood = mass/molar mass = 0.015/28.01 = 5.36 x 10-4 mol ˜ 5.4 x 10-4 mol Solution For air at atmospheric pressure Solubility of N2 in water/blood = 0.015 g/L => 1 L of blood contains 0.015 g of N2 Molar mass of N2 = 28.01 g/mol Moles of N2 per liter of blood = mass/molar mass = 0.015/28.01 = 5.36 x 10-4 mol ˜ 5.4 x 10-4 mol.