six lone pairs (each F has three lone pairs) nit.pdf

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six lone pairs (each F has three lone pairs) nitrate has three resonance structures. Solution six lone pairs (each F has three lone pairs) nitrate has three resonance structures..

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Water molecules do not participate in acid base neutralization react.pdf

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The Mouse and the track ball uses pointing and dragging tasks.The actions of pointing and dragging are fundamental, low-level operations in direct manipulation interfaces.pointing and dragging both are diffrent to each other. pointing by fitt\'s law: Pointing tasks have been studied extensively. Much of this work is based on a robust model of human movement known as Fitts\' law. The law predicts that the time to acquire a target is logarithmically related to the distance over the target size. More formally, the time (MT) to move to a target of width W which lies at distance (or amplitude) A is where a and b are empirical constants determined through linear regression. The log term is called the index of difficulty (ID) and carries the units \"bits\" (because the base is \"2\"). The reciprocal of b is the index of performance (IP) in bits/s. This is purportedly the human rate of information processing for the movement task under investigation. Card, English, and Burr (1978) found IP = 10.4 bits/s for the mouse in a text selection task. MT = a + b log2(A / W + 1). dragging by using fitt\'s law: Using Fitts\' law to model dragging is best explained using an example. Consider the case of deleting a file on the Apple Macintosh. First, the user acquires the icon for the file in question. This point/select operation is a classic two-dimensional target acquisition task. Then, while holding the mouse button down, the icon is dragged to the trashcan. This also is a target acquisition task. One is really just acquiring the trashcan icon. In this case, however, the task is performed with the mouse button depressed. Pressing and releasing the mouse button over an icon selects the icon and leaves the user in State 1. Depressing the mouse button over an icon and moving the mouse drags the icon. This is a State 2 action. Releasing the mouse button returns to the tracking state, State 1. State 2 motion on most input devices requires active maintenance of the state (e.g., by holding down a button), generally restricting the freedom of movement. Given the frequency of State 2 actions in direct manipulation systems, we feel the following are important:MT = a + b log2(2A / W)(1) Solution The Mouse and the track ball uses pointing and dragging tasks.The actions of pointing and dragging are fundamental, low-level operations in direct manipulation interfaces.pointing and dragging both are diffrent to each other. pointing by fitt\'s law: Pointing tasks have been studied extensively. Much of this work is based on a robust model of human movement known as Fitts\' law. The law predicts that the time to acquire a target is logarithmically related to the distance over the target size. More formally, the time (MT) to move to a target of width W which lies at distance (or amplitude) A is where a and b are empirical constants determined through linear regression. The log term is called the index of difficulty (ID) and carries the units \"bits\" (because the base is \"2\"). T.

The Mouse and the track ball uses pointing and dragging tasks.The ac.pdf

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The employer must estimate the total cost of the benefits promised and then allocate these costs to the periods in which the employees provide service. Most Defined Benifit pension plans are funded through a separate legal entity, typically a pension trust, and the assets of the trust are used to make the payments to retirees. The Pension Trust make investment of the contribution to meet the pension obligation in the stock,Bond market,real estate and commodity market knows as Plan Asset. The sponsoring company is responsible for making contributions to the plan. The company also must ensure that there are sufficient assets in the plan to pay the ultimate benefits promised to plan participants. Regulatory requirements usually specify minimum funding levels for Defined Benifit pension plans, but those requirements vary by country.Because the company has promised a defined amount of benefit to the employees, it is obligated to make those pension payments when they are due regardless of whether the pension plan assets generate sufficient returns to provide the benefits. In other words, the company bears the investment risk. Solution The employer must estimate the total cost of the benefits promised and then allocate these costs to the periods in which the employees provide service. Most Defined Benifit pension plans are funded through a separate legal entity, typically a pension trust, and the assets of the trust are used to make the payments to retirees. The Pension Trust make investment of the contribution to meet the pension obligation in the stock,Bond market,real estate and commodity market knows as Plan Asset. The sponsoring company is responsible for making contributions to the plan. The company also must ensure that there are sufficient assets in the plan to pay the ultimate benefits promised to plan participants. Regulatory requirements usually specify minimum funding levels for Defined Benifit pension plans, but those requirements vary by country.Because the company has promised a defined amount of benefit to the employees, it is obligated to make those pension payments when they are due regardless of whether the pension plan assets generate sufficient returns to provide the benefits. In other words, the company bears the investment risk..

The employer must estimate the total cost of the benefits promised a.pdf

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slopeSolutionslope.pdf

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Plz send the clear image to me...so that i can solve it..Solutio.pdf

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public class Passenger { public static enum Section { First, Economy } private String name; private Section section; private String confirmationCode; /** * Constructor * * @param name * @param section * @param confirmationCode */ public Passenger(String name, Section section, String confirmationCode) { this.name = name; this.section = section; this.confirmationCode = confirmationCode; } /** * Copy Constructor that produces a deep copy of the argument * * @param */ public Passenger(Passenger p) { this.name = p.name; this.section = p.section; this.confirmationCode = p.confirmationCode; } /** * Returns a string with confirmation code */ public static String generateCode() { String alphabet = \"abcdefghijklmnopqrstuvwxyz\"; String[] letters = new String[6]; String code = \"\"; for (int i = 0; i < 6; i++) { letters[i] = \"\" + alphabet.charAt((int) Math.floor(Math.random() * 26)); code += letters[i]; } return code.toUpperCase(); } /** * @return the name */ public String getName() { return name; } /** * @param name the name to set */ public void setName(String name) { this.name = name; } /** * @return the section */ public Section getSection() { return section; } /** * @param section the section to set */ public void setSection(Section section) { this.section = section; } /** * @return the confirmationCode */ public String getConfirmationCode() { return confirmationCode; } /** * @param confirmationCode the confirmationCode to set */ public void setConfirmationCode(String confirmationCode) { this.confirmationCode = confirmationCode; } @Override public String toString() { return \"\ Passenger name: \" + getName() + \"\ Class: \" + getSection() + \"\ Confirmation Code: \" + getConfirmationCode(); } } import java.util.Scanner; public class Manifest { public static void printBP(Passenger p) { System.out.print(String.format(\"\ %30s\", \" \").replaceAll(\" \", \"-\")); System.out.print(p); System.out.print(String.format(\"\ %30s\", \" \").replaceAll(\" \", \"-\")); } public static void main(String[] args) { final int FIRST_CAPACITY = 2; final int ECO_CAPACITY = 4; // Scanner to get user input Scanner in = new Scanner(System.in); // Create passenger array Passenger[] pList = new Passenger[6]; int reservationCount = 0; // Variables to track whether a section is full int firstSeats = 0; int ecoSeats = 0; char ch = \' \'; do { // Get pax name System.out.print(\"Enter the passenger\'s full name: \"); String name = in.nextLine(); // Get section int section = -1; while (true) { System.out.println(\"Select a section 0-First, 1-Economy: \"); section = in.nextInt(); // Check if selected section is full if (section == 0) { if (firstSeats == FIRST_CAPACITY) { System.out.println(\"First class seats are full. Do you wan to reserve a seat in the economy section[Y/N]: \"); char reserve = in.next().charAt(0); //If user does not want to make the reservation //finish booking without a reservation if(Character.toUpperCase(reserve) == \'N\') break; section = 1; //Change sect.

public class Passenger { public static enum Section { .pdf

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Prior to 2010, the United States banned HIV-positive individuals from entering the United states, even the foreigners who were found HIV positive forced to leave US as undisirables. HIV is deadily and transmissible, it spreads uncontrollably, millions will be infected and eventually will die but these are fear rather than facts. HIV positive individuals are already living in shadows, discriminating them is more like running away from the problem instead fighting and defeating the problem. Banning entry of HIV positive individuals into United states spreads a worldwide message which is more fearful and vanquished. But message to the world from US should be more positive and strong. The message to the world from US should be the fight against HIV is still on and we will win. Foreigners avoid the testing to enter US which worsen the situation. Individuals deny to be HIV positive and takes extreme steps instead fighting with the disease. Now when the Ban is lifted individuals are more truthful to the fact and mentally stronger to fight with the disease, decrease in xenophobia and increase in responsibility and a positive message gone to the world. Solution Prior to 2010, the United States banned HIV-positive individuals from entering the United states, even the foreigners who were found HIV positive forced to leave US as undisirables. HIV is deadily and transmissible, it spreads uncontrollably, millions will be infected and eventually will die but these are fear rather than facts. HIV positive individuals are already living in shadows, discriminating them is more like running away from the problem instead fighting and defeating the problem. Banning entry of HIV positive individuals into United states spreads a worldwide message which is more fearful and vanquished. But message to the world from US should be more positive and strong. The message to the world from US should be the fight against HIV is still on and we will win. Foreigners avoid the testing to enter US which worsen the situation. Individuals deny to be HIV positive and takes extreme steps instead fighting with the disease. Now when the Ban is lifted individuals are more truthful to the fact and mentally stronger to fight with the disease, decrease in xenophobia and increase in responsibility and a positive message gone to the world..

Prior to 2010, the United States banned HIV-positive individuals fro.pdf

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option (e) is correct.the feature that distinguishes fluorescence .pdf

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NADP is the source of electrons for the light reactions The electron acceptor of the light reactions, NADP+, which functions as an electron carrier in cellular respiration. The light reactions use solar power to reduce NADP+ to NADPH by adding a pair of electrons along with a hydrogen nucleus, or H The light reactions also generate ATP by powering the addition of a phosphate group to ADP, a process called photophosphorylation. Solution NADP is the source of electrons for the light reactions The electron acceptor of the light reactions, NADP+, which functions as an electron carrier in cellular respiration. The light reactions use solar power to reduce NADP+ to NADPH by adding a pair of electrons along with a hydrogen nucleus, or H The light reactions also generate ATP by powering the addition of a phosphate group to ADP, a process called photophosphorylation..

NADP is the source of electrons for the light reactionsThe electro.pdf

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import java.util.Scanner; public class Bottle { private static final int MAX=100; //max constant private static final int MIN=0; // min constant static Scanner scan = new Scanner(System.in); private int noOfBottle=0; //method 1 to read the value form console public void read() { int x = scan.nextInt(); noOfBottle=x; } //method 2 to set the no of bottle property of bottle class public void set(int a) { if(a<=MAX) { noOfBottle=a; }else { System.out.println(\"number is greater than max value\"); } } //method 3 to set the noOfBottle property from bottle object public void setBottle(Bottle a) { if(a.noOfBottle<=MAX) { noOfBottle=a.noOfBottle; }else { System.out.println(\"number is greater than max value\"); } } //method 4 to get he noOfBottle value public int get() { return this.noOfBottle; } //method 5 addition of bottle objects public Bottle add(Bottle bottle) { if(this.noOfBottle+bottle.noOfBottle<=MAX) { this.noOfBottle=this.noOfBottle+bottle.noOfBottle; } else { System.out.println(\"Alert : addition excedding the maximum number \"); } return this; } //method 6 subtraction of bottle objects public Bottle subtract(Bottle bottle) { if(this.noOfBottle-bottle.noOfBottle>=MIN) { this.noOfBottle=this.noOfBottle-bottle.noOfBottle; } else { System.out.println(\"Alert : Subtraction reducing the bottle to below min range possible \"); } return this; } //method 7 multiplication of bottle objects public Bottle multiply(Bottle bottle) { if(this.noOfBottle*bottle.noOfBottle<=MAX) { this.noOfBottle=this.noOfBottle*bottle.noOfBottle; } else { System.out.println(\"Alert : Multiplication exceeding MAX value \"); } return this; } //method 8 division of bopttle objects public Bottle divide(Bottle bottle) { try{ if(this.noOfBottle/bottle.noOfBottle>=MIN) { this.noOfBottle=this.noOfBottle/bottle.noOfBottle; } else { System.out.println(\"Alert : Division reducing to possible MIN value \"); } }catch(Exception e) { System.out.println(\"/ By zero error\"); e.printStackTrace(); } return this; } //method 9 addition of int value to bottle noOfObject property public Bottle add(int a) { if(this.noOfBottle+a<=MAX) { this.noOfBottle=this.noOfBottle+a; } else { System.out.println(\"Alert : addition excedding the maximum number \"); } return this; } //method 10 subtraction of bottle noOfObject property public Bottle subtract(int a) { if(this.noOfBottle-a>=MIN) { this.noOfBottle=this.noOfBottle-a; } else { System.out.println(\"Alert : Subtraction reducing the bottle to below min range possible \"); } return this; } //method 11 multiplication of bottle noOfObject property public Bottle multiply(int a) { if(this.noOfBottle*a<=MAX) { this.noOfBottle=this.noOfBottle*a; } else { System.out.println(\"Alert : Multiplication exceeding MAX value \"); } return this; } //method 12 d of bottle noOfObject property public Bottle divide(int a) { try{ if(this.noOfBottle/a>=MIN) { this.noOfBottle=this.noOfBottle/a; } else { System.out.println(\"Alert : Division reducing below to possible MIN val.

import java.util.Scanner;public class Bottle { private stat.pdf

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In previous year, 2 birthdays were on tuesday but this year there\'s only 1 birthday on wednesday. It means 1 birthday was is month of feb or jan (which was on tuesday prev year) and now it is on thursday. And the other 1 has wednesday birthday and falls after february. So the days of birthday are wednesday, thursday, monday and saturday. The months of birthday are jan/feb, nov, july, august. 1 birthday on jan which means jan thursday was a birthday. Novemeber b\'day could be mon/wed. the 2 person with 14 n 15 age must ve same age 4 2 months in a year. only august n nov have 2 months difference. The person wid thursday b\'day was 4 years older dan paul. So paul\'s age is 7 and the person with Jan Thusrday b\'day is 11. Either Don is 14 or 15 n born in aug. The person with monday b\'day has month either nov or august. The july birthday can\'t be a thursday or a monday. If it\'s a wednesday, Lucky has monday b\'day n is 15 years old. Else if it\'s a sat, lucky cud be 15 n nov monday b\'day or wed b\'day in august n is 14. The 2nd option is cancelled as Don is born in august. It imply that Lawrence is 11 and born in jan thursday. and Paul is born on July wednesday. Hence don is born in august saturday. Lawrence: Jan thursday 11 Paul: July Wednesday 7 Don: august saturday 14 Lucky: November monday 15 Solution In previous year, 2 birthdays were on tuesday but this year there\'s only 1 birthday on wednesday. It means 1 birthday was is month of feb or jan (which was on tuesday prev year) and now it is on thursday. And the other 1 has wednesday birthday and falls after february. So the days of birthday are wednesday, thursday, monday and saturday. The months of birthday are jan/feb, nov, july, august. 1 birthday on jan which means jan thursday was a birthday. Novemeber b\'day could be mon/wed. the 2 person with 14 n 15 age must ve same age 4 2 months in a year. only august n nov have 2 months difference. The person wid thursday b\'day was 4 years older dan paul. So paul\'s age is 7 and the person with Jan Thusrday b\'day is 11. Either Don is 14 or 15 n born in aug. The person with monday b\'day has month either nov or august. The july birthday can\'t be a thursday or a monday. If it\'s a wednesday, Lucky has monday b\'day n is 15 years old. Else if it\'s a sat, lucky cud be 15 n nov monday b\'day or wed b\'day in august n is 14. The 2nd option is cancelled as Don is born in august. It imply that Lawrence is 11 and born in jan thursday. and Paul is born on July wednesday. Hence don is born in august saturday. Lawrence: Jan thursday 11 Paul: July Wednesday 7 Don: august saturday 14 Lucky: November monday 15.

In previous year, 2 birthdays were on tuesday but this year theres.pdf

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Homology is defined as structures which are derived from a common ancestor like wings of bird and forelimbs of bat. Divergent evolution: It is the process where two or more related species become more and more dissimilar. Divergent evolution produces homologous structures e.g.same bones can be used in many ways leading to divergent evolutionary paths like frogs, bats, birds so on. So the correct option is (c):Divergent evolution. Solution Homology is defined as structures which are derived from a common ancestor like wings of bird and forelimbs of bat. Divergent evolution: It is the process where two or more related species become more and more dissimilar. Divergent evolution produces homologous structures e.g.same bones can be used in many ways leading to divergent evolutionary paths like frogs, bats, birds so on. So the correct option is (c):Divergent evolution..

Homology is defined as structures which are derived from a common an.pdf

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HI is a strong acid, so its [H+] = 4.5 10-2 molesL = 0.045pH is.pdf

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For first figure Member BEFor second figure Members BH , DFF.pdf

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constructor to initialize the tree object Function to insert the nodes into the tree function to create a node function to get maximum in a tree function to get minimum function to check whether the element is present in the tree function to remove an element from a tree function to check the tree is empty function isEmpty(node){ if(node==NULL) return true; else return false; } function to find leaf node are present to the given node functiom isLeaf(node){ if(node doesnot contain children) return true; else return false; funtion to copy into string and display Solution constructor to initialize the tree object Function to insert the nodes into the tree function to create a node function to get maximum in a tree function to get minimum function to check whether the element is present in the tree function to remove an element from a tree function to check the tree is empty function isEmpty(node){ if(node==NULL) return true; else return false; } function to find leaf node are present to the given node functiom isLeaf(node){ if(node doesnot contain children) return true; else return false; funtion to copy into string and display.

constructor to initialize the tree objectFunction to insert the no.pdf

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a lysine lysine is basic amino acid with extra NH.pdf

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ans.)Solutionans.).pdf

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A)Provide three examples that demonstrate how security can be instilled within the Systems Development Life Cycle (SDLC) Context Description Example Confidentiality This is that there should be very less accessing right only to the authorize user. Identify users of project and give them rights. E.g. The student in a university database. It can view only its result or anything which is related to it, not other information of university database. Integrity Trusted source of information Monitoring of data from source to destination. E.g.Like in android mobiles, there is an option Don’t allow installation from unknown sources (other than googleplay) which is set to be off for security reason Ownership Possession for control of information Give the role and responsibility in analysis phase of SDLC for different modules. E.g. Role for the particular activity in a school play. Q. Provide two examples on what users may experience with software products if they are released with minimal security planning. If there is minimal security, then the security breach can effect on product in following terms No Utility: No perfection for the product. No Proper Authenticity. Unsurprisingly availability of information Also the confidentiality and integrity will be effected (b) Suggest three ways that application security can be monitored and evaluated for effectiveness. Choose what you believe to be the most effective way and discuss why. System development life cycle 1.Planning 2.Feasibility Study 3.Analysis 4.Design 5.Testing 6.Implementation 7.Maintenance These are the phases of SDLC. In first phase and second there is no need of security, because the main part of SDLC begins from 3 phase i.e. analysis and continues till the last. Analysis phase: 1.Risk analysis in the functional requirement specification and software requirement specification 2.Identify security realm 3.Security functional requirement Design Phase: 1. Develop some security controls 2.Develop security mechanism and security action plan 3.Develop security coding guidelines. Testing phase: 1. Regression testing. 2. Independent functionality testing. 3. Threat analysis testing The most effective way is Independent functionality testing. Because in this, each phase is tested by outsiders, no person concerned in designing of project is included in testing. This is like Beta testing in which a project is sent to company\'s friend company. Beceause it is difficult to find own mistake. Context Description Example Confidentiality This is that there should be very less accessing right only to the authorize user. Identify users of project and give them rights. E.g. The student in a university database. It can view only its result or anything which is related to it, not other information of university database. Integrity Trusted source of information Monitoring of data from source to destination. E.g.Like in android mobiles, there is an option Don’t allow installation from unknown sources (other than goo.

A)Provide three examples that demonstrate how security can be instil.pdf

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1) x : x-1 add: x+x-1 = 2x-1 answer:2x-1 subtract: x - (x-1) = 1 answer: 1 multiply: x(x-1) = x^2 - 1 answer:x^2 - 1 2) x : y - 1 add: x + y - 1 answer: x + y - 1 subtract: x - (y-1) = x - y + 1 answer:x - y + 1 multiply: x(y-1) = xy -x answer:xy - x 3) x - 1 : x - 2 add: x - 1 + x - 2 = 2x - 3 answer:2x - 3 subtract: x - 1 - x + 2 = 1 answer:1 multiply: (x-1)(x-2) = x^2 - 3x + 2 answer:x^2 - 3x + 2 4) x^2 : x add: x^2 + x answer: x^2 + x subtract: x^2 - x answer: x^2 - x multiply: x^2 * x = x^3 answer: x^3 5) x^2 - 1 : x - 2 add: x^2 - 1 + x - 2 = x^2 + x - 3 answer:x^2 + x - 3 subtract: x^2 - 1 - x + 2 = x^2 - x + 1 answer:x^2 - x + 1 multiply: (x^2 - 1)(x - 2) = x^3 - 2x^2 - x + 2 answer: x^3 - 2x^2 - x + 2 Solution 1) x : x-1 add: x+x-1 = 2x-1 answer:2x-1 subtract: x - (x-1) = 1 answer: 1 multiply: x(x-1) = x^2 - 1 answer:x^2 - 1 2) x : y - 1 add: x + y - 1 answer: x + y - 1 subtract: x - (y-1) = x - y + 1 answer:x - y + 1 multiply: x(y-1) = xy -x answer:xy - x 3) x - 1 : x - 2 add: x - 1 + x - 2 = 2x - 3 answer:2x - 3 subtract: x - 1 - x + 2 = 1 answer:1 multiply: (x-1)(x-2) = x^2 - 3x + 2 answer:x^2 - 3x + 2 4) x^2 : x add: x^2 + x answer: x^2 + x subtract: x^2 - x answer: x^2 - x multiply: x^2 * x = x^3 answer: x^3 5) x^2 - 1 : x - 2 add: x^2 - 1 + x - 2 = x^2 + x - 3 answer:x^2 + x - 3 subtract: x^2 - 1 - x + 2 = x^2 - x + 1 answer:x^2 - x + 1 multiply: (x^2 - 1)(x - 2) = x^3 - 2x^2 - x + 2 answer: x^3 - 2x^2 - x + 2.

1) x x-1addx+x-1 = 2x-1answer2x-1subtract.pdf

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16). Active transport of molecules require energy. Active transport needs energy, and it help to move ions against their concentration gradients. The two types active transport mechanisms are, (i). Primary active transport (ii). Secondary active transport For example, the concentration of sodium ions is more outside the cell. Still, the sodium ions move from the inside of cell to outside through ion channels, by means of active transport. Active transport needs energy, and it help to move ions against their concentration gradients. Eg: Na+-K+ ATPase is an ATP (adenosine triphosphate) driven pump, which establishes the sodium gradient (it pump sodium ions out of the cell against its concentration gradient and allows the influx of potassium ions). The theory of secondary active transport: The secondary active transport is an active transport in which the downhill movement of an ion (either sodium or hydrogen) is coupled with the uphill movement of another molecule (against its concentration) by the transporter protein. Thus, the electrochemical gradient of an ion drives uphill transport of another molecule. Eg: Glucose absorption by cell is an example of secondary active transport. The sodium-glucose linked transporter (SGLTs, a co-transporter) uses the energy generated by the ATPase pump through the downhill sodium ion gradient for the glucose transportation across the apical membrane (against the glucose gradient). SGLTs are an example of secondary active transport. The glucose transporters (GLUT) present in the basolateral membrane now allow the glucose transport into the peritubular capillaries. Inhibition of the Na+/K+/ATPase fails to generate energy required for the SGLT secondary transporters, which inhibits glucose uptake. Other examples include Na+/phosphate coransporter, Na+/Iodide symporter, Na+/Cl- cotransporter, etc. Solution 16). Active transport of molecules require energy. Active transport needs energy, and it help to move ions against their concentration gradients. The two types active transport mechanisms are, (i). Primary active transport (ii). Secondary active transport For example, the concentration of sodium ions is more outside the cell. Still, the sodium ions move from the inside of cell to outside through ion channels, by means of active transport. Active transport needs energy, and it help to move ions against their concentration gradients. Eg: Na+-K+ ATPase is an ATP (adenosine triphosphate) driven pump, which establishes the sodium gradient (it pump sodium ions out of the cell against its concentration gradient and allows the influx of potassium ions). The theory of secondary active transport: The secondary active transport is an active transport in which the downhill movement of an ion (either sodium or hydrogen) is coupled with the uphill movement of another molecule (against its concentration) by the transporter protein. Thus, the electrochemical gradient of an ion drives uphill transport of another molecule. Eg: .

16).Active transport of molecules require energy. Active transport.pdf

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