Find a basis for the column, row, and null space of Solution det(A) = 3*[17*(-11) - 8*(-24)] = 3*[-187+192] = 15!=0 => rank(A) = 3 => basis for column space = {[17 8 16]^T, [-24 -11 -28]^T, [0 0 3]^T} basis for row space = {[17 -24 0], [8 -11, 0], [16 -28 3]}.