Please Provide details and I will raterigh.
Solution
Let |S| = m , an integer, and let |T| = n . We aregiven that m > n.
Now function f can map to one or more elements of T. Thebest case for the most number of
distinct mappings is when f coversor reaches all elements of T. In this situation, thereare m-n
overflow elements in S that map to a previouslymapped element in T (pigeon hole principle). Or
restated,there are elements s1 ands2 in S such thatf(s1) = f(s2).
If f does not cover T, then there exists some element t1 in Tthat is not reached. So, some other
element of T is reachedby one or more elements in S by f. Or, as before, thereexist one or more
elements s1, s2 of S where f(s1)=f(s2).
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
Please Provide details and I will raterigh.SolutionLet S = m.pdf
1. Please Provide details and I will raterigh.
Solution
Let |S| = m , an integer, and let |T| = n . We aregiven that m > n.
Now function f can map to one or more elements of T. Thebest case for the most number of
distinct mappings is when f coversor reaches all elements of T. In this situation, thereare m-n
overflow elements in S that map to a previouslymapped element in T (pigeon hole principle). Or
restated,there are elements s1 ands2 in S such thatf(s1) = f(s2).
If f does not cover T, then there exists some element t1 in Tthat is not reached. So, some other
element of T is reachedby one or more elements in S by f. Or, as before, thereexist one or more
elements s1, s2 of S where f(s1)=f(s2)
