integration of dx/ square root of x^2 +16 Solution To solve this irrational integral, we can use the following formula: [int] dx/sqrt(x^2 + a^2) = ln [(x + sqrt(x^2 + a^2))/a] Comparing, we\'ll get a^2 = 16 => a = sqrt 16 => a = [+-] 4 The requested integral is: [int] dx/sqrt(x^2 + 16) = ln [(x + sqrt(x^2 + 16))/4] + C.

1. integration of dx/ square root of x^2 +16
Solution
To solve this irrational integral, we can use the following formula:
[int] dx/sqrt(x^2 + a^2) = ln [(x + sqrt(x^2 + a^2))/a]
Comparing, we'll get a^2 = 16 => a = sqrt 16 => a = [+-] 4
The requested integral is:
[int] dx/sqrt(x^2 + 16) = ln [(x + sqrt(x^2 + 16))/4] + C