Assume f has period 2pi. Sketch the graph of f in the interval [-4pi.pdf

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Assume f has period 2pi. Sketch the graph of f in the interval [-4pi,4pi]. Is this function an even function? Explain. Is this function an odd function? Explain 3 3 Solution let theta theta = t from the graph y = f(t) = 3 + 2sin(t) f(-t) = 3 + 2sin(-t) = 3 - 2sint therefore f(t) not equal to f(-t) then f(t) is odd function.

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