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© UCLES 2016 [Turn over
Cambridge International Examinations
Cambridge International Advanced Subsidiary and Advanced Level
CHEMISTRY 9701/42
Paper 4 A Level Structured Questions October/November 2016
MARK SCHEME
Maximum Mark: 100
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the
examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the
details of the discussions that took place at an Examiners’ meeting before marking began, which would have
considered the acceptability of alternative answers.
Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for
Teachers.
Cambridge will not enter into discussions about these mark schemes.
Cambridge is publishing the mark schemes for the October/November 2016 series for most
Cambridge IGCSE®
, Cambridge International A and AS Level components and some Cambridge O Level
components.
Page 2 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
1(a) (an element) forming (one or more stable) ions with incomplete d subshell [1] 1
1
1(b)(i)
co-ordination number oxidation number
[Ni(CN)2(NH3)2] 4 +2
[CrCl2(H2O)4]+
6 +3
2
1(b)(ii) dative (covalent)/co-ordinate 1
1
1(b)(iii) correct diagram of [Ni(CN)2(NH3)2]
or
square planar or tetrahedral
1
1
2
1(c)(i) (concentrated) hydrochloric acid / soluble chloride ion 1
1
1(c)(ii) ligand exchange/substitution 1
1
1(d)(i) cis-trans (isomerism) / geometric(al) 1
1
Page 3 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
1(d)(ii) one 3D isomer
one correct isomer
other isomer correct in 3D
1
1
1
3
Total: 12
Page 4 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
2(a) NaN3 →Na+1.5N2 1
1
2(b)
all atoms must have 8 outer electrons
coding for electrons correct = 16 (10× 5• 1 □)
central N must have 8 bonding electrons (inc. 5 • and no non-bonded electrons)
allow
1
1
1
3
2(c)(i) (energy change) when 1 mole of an (ionic) compound is formed
or (energy change) when 1 mole of an ionic solid/lattice/crystal is formed (from)
gas (phase) ions/gaseous ions (under standard conditions)
1
1
2
2(c)(ii) forming an (ionic) bond 1
1
Page 5 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
2(c)(iii) use of ∆Hi1 494 (kJ mol-1
)
∆Ho
f = +107+494+142–732
∆Ho
f = +11 (kJ mol-1
)
1
1
1
3
2(c)(iv) (ionic) radius/size of Na+
is smaller (so stronger attraction to azide ion)
OR ionic radius increases down the group 1
1
Total: 11
Question Answer Mark
3(a) Fe [Ar] 3d6
4s2
Fe3+
[Ar] 3d5
1
1
2
3(b)(i) (catalyst is in) the same phase/state as the reactants 1
1
3(b)(ii) S2O8
2–
+2I–
→2SO4
2–
+I2 1
1
3(b)(iii) (two) negatively-charged species repel each other 1
1
3(b)(iv) Equation 1: 2Fe3+
+2I–
→2Fe2+
+I2
Equation 2: S2O8
2–
+2Fe2+
→2SO4
2–
+2Fe3+
1
1
2
Page 6 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
3(c)(i) (entropy is a measure/degree of the) disorder of a system/substance 1
1
3(c)(ii) ∆So
=(2×27)+(3×214)–(90)–(3×198) OR 696 – 684
∆So
=(+)12 (J K–1
mol–1
)
1
1
2
3(c)(iii) ∆Go
=–43.6–(298×12/1000)
∆Go
=–47.2 (kJ mol–1
)
1
1
2
3(c)(iv) high Ea and to speed up the rate 1
1
Total: 13
Page 7 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
4(a) d orbitals split into lower and upper orbitals
light/photon absorbed
electron(s) promoted/excited/jumps up to (higher) (d–) orbital or
electron(s) moves/jumps (from lower (d–)) to higher (d–) orbital
1
1
1
3
4(b)(i) Cu+4HNO3 →Cu(NO3)2 +2NO2 +2H2O
or ionic Cu+4H+
+2NO3
–
→Cu2+
+2NO2 +2H2O
correct species
correct balancing
1
1
2
4(b)(ii) moles S2O3
2–-
=0.1×22.4/1000=2.24×10–3
moles of Cu2+
in 25cm3
=2.24×10–3
moles of Cu2+
in 250cm3
==2.24×10–2
mass of Cu=2.24×10-
2×63.5=1.4224g
% Cu=1.42/1.75×100=81.1 or 81.3%
1
1
1
1
4
Total: 9
Page 8 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
5(a)
Ka =
2- +
4 3
2 4
[HPO ][H O ]
[ ]H PO −
1
1
5(b)(i) a solution that resists changes in pH
when small amounts of acid and base/alkali are added
1
1
2
5(b)(ii) addition of acid: H+
+HPO4
2–
H2PO4
–
OR H+
+H2PO4
–
H3PO4
addition of base: HO–
+H2PO4
–
HPO4
2–
+H2O
OR OH–
+HPO4
2–
H2O+PO4
3–
1
1
2
5(c) [H+
] = 10–7.4
=3.98×10–8
[HPO4
2–
]/[H2PO4
–
]=Ka /[H+
]
([HPO4
2–
]/[H2PO4
–
])=6.31×10–8
/3.98×10–8
=1.58-1.6
1
1
1
3
5(d)(i) HCl+H2PO4
–
→H3PO4 +Cl–
OR H+
+H2PO4
–
→H3PO4
OR H2O+H2PO4
–
→H3PO4 +OH–
1
1
Page 9 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
5(d)(ii) NaOH+HPO4
2–
→PO4
3–
+H2O+Na+
OR OH–
+HPO4
2–
→PO4
3–
+H2O
OR H2O+HPO4
2–
→PO4
3–
+H3O+
1
1
Total: 10
Question Answer Marks
6(a)
HO
O
O
O
O
Q
*
1
6(b)(i) ratio of the concentration of a solute in the (two immiscible) solvents/liquids
at equilibrium
1
1
2
6(b)(ii) Kpartition =(0.06/40)/(0.25–0.06/10) or reversed ratio: Kpartition = (0.25–0.06/10) / (0.06/40)
Kpartition =0.079 (0.0789) Kpartition = 12.7/13.0
1
1
2
Page 10 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
6(c)
reagent structure of product(s)
type of
reaction
excess
Br2(aq)
addition of bromine to alkene
2×Br substituted in phenol at positions 2 and 6
(electrophilic)
substitution
or
(electrophilic)
addition
NaBH4
reduction
(allow
nucleophilic
addition)
1
1
1
Page 11 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
excess hot
NaOH(aq)
hydrolysis
all three reaction types
1+1
1
6
6(d) mixture of (two) optical/stereo isomers formed 1
1
Total: 12
Page 12 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
7(a)(i) electrophilic substitution 1
1
7(a)(ii) (Br2 +AlBr3)→Br+
+AlBr4
–
curly arrow from ring system to Br+
correct intermediate
curly arrow from C–H bond into ring and loss of H+
1
1
1
1
4
7(b) both amide 1
1
7(c)(i) step 1, AlBr3 and CH3Br OR other suitable halogen instead of Br
step 2, KMnO4 or potassium manganate(VII)
step 3, conc. H2SO4 and conc. HNO3
step 4. Sn and (conc.) HCl (heat)
1
1
1
1
4
Page 13 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
7(c)(ii)
1 mark for each correct structure
3
7(d)(i)
1 mark for each correct structure
2
7(d)(ii) reduction 1
1
Page 14 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
7(e)(i)
1 mark for each correct structure 2
7(e)(ii) 1
1
7(e)(iii) (precipitate) compound is less polar /more non-polar/non-ionic resulting in less hydrogen bonding to water 1
1
Total: 20
Page 15 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
8(a) 102×0.314=32(32.028)(102–32=70)
and (12×5)+(1×10)=70
OR F contains CO2H=45 so 102–45=57 so C4H9
1
1
8(b)(i)
2 correct = 1 mark
3 correct = 2 marks
2
8(b)(ii) 2-methyl butanoic acid 1
1
8(c)(i)
OH
O
1
1
8(c)(ii)
δ/ppm
environment of
the carbon atom
hybridisation of
the carbon atom
27 alkyl/CH3 sp3
41 next to carboxyl/(CH3)3C sp3
179 carboxyl/CO2H sp2
2
Page 16 Mark Scheme Syllabus Paper
Cambridge International AS/A Level – October/November 2016 9701 42
© UCLES 2016
Question Answer Marks
8(d)(i)
δ/ppm type of proton
number of
protons
splitting
0.9 alkane/CH/CH3 6 doublet
1.6 alkane/CH 1 [multiplet]
2.4 alkyl next to C=O/CH(2)CO/CH 2 doublet
11.5 OH/CO2H/carboxylic acid 1 singlet
4
8(d)(ii)
1
1
8(e) CDCl3 OR D2O, DMSO, CD2Cl2, CCl4 1
1
Total 13

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9701 w16 ms_42

  • 1. ® IGCSE is the registered trademark of Cambridge International Examinations. This document consists of 16 printed pages. © UCLES 2016 [Turn over Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level CHEMISTRY 9701/42 Paper 4 A Level Structured Questions October/November 2016 MARK SCHEME Maximum Mark: 100 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2016 series for most Cambridge IGCSE® , Cambridge International A and AS Level components and some Cambridge O Level components.
  • 2. Page 2 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 1(a) (an element) forming (one or more stable) ions with incomplete d subshell [1] 1 1 1(b)(i) co-ordination number oxidation number [Ni(CN)2(NH3)2] 4 +2 [CrCl2(H2O)4]+ 6 +3 2 1(b)(ii) dative (covalent)/co-ordinate 1 1 1(b)(iii) correct diagram of [Ni(CN)2(NH3)2] or square planar or tetrahedral 1 1 2 1(c)(i) (concentrated) hydrochloric acid / soluble chloride ion 1 1 1(c)(ii) ligand exchange/substitution 1 1 1(d)(i) cis-trans (isomerism) / geometric(al) 1 1
  • 3. Page 3 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 1(d)(ii) one 3D isomer one correct isomer other isomer correct in 3D 1 1 1 3 Total: 12
  • 4. Page 4 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 2(a) NaN3 →Na+1.5N2 1 1 2(b) all atoms must have 8 outer electrons coding for electrons correct = 16 (10× 5• 1 □) central N must have 8 bonding electrons (inc. 5 • and no non-bonded electrons) allow 1 1 1 3 2(c)(i) (energy change) when 1 mole of an (ionic) compound is formed or (energy change) when 1 mole of an ionic solid/lattice/crystal is formed (from) gas (phase) ions/gaseous ions (under standard conditions) 1 1 2 2(c)(ii) forming an (ionic) bond 1 1
  • 5. Page 5 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 2(c)(iii) use of ∆Hi1 494 (kJ mol-1 ) ∆Ho f = +107+494+142–732 ∆Ho f = +11 (kJ mol-1 ) 1 1 1 3 2(c)(iv) (ionic) radius/size of Na+ is smaller (so stronger attraction to azide ion) OR ionic radius increases down the group 1 1 Total: 11 Question Answer Mark 3(a) Fe [Ar] 3d6 4s2 Fe3+ [Ar] 3d5 1 1 2 3(b)(i) (catalyst is in) the same phase/state as the reactants 1 1 3(b)(ii) S2O8 2– +2I– →2SO4 2– +I2 1 1 3(b)(iii) (two) negatively-charged species repel each other 1 1 3(b)(iv) Equation 1: 2Fe3+ +2I– →2Fe2+ +I2 Equation 2: S2O8 2– +2Fe2+ →2SO4 2– +2Fe3+ 1 1 2
  • 6. Page 6 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 3(c)(i) (entropy is a measure/degree of the) disorder of a system/substance 1 1 3(c)(ii) ∆So =(2×27)+(3×214)–(90)–(3×198) OR 696 – 684 ∆So =(+)12 (J K–1 mol–1 ) 1 1 2 3(c)(iii) ∆Go =–43.6–(298×12/1000) ∆Go =–47.2 (kJ mol–1 ) 1 1 2 3(c)(iv) high Ea and to speed up the rate 1 1 Total: 13
  • 7. Page 7 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 4(a) d orbitals split into lower and upper orbitals light/photon absorbed electron(s) promoted/excited/jumps up to (higher) (d–) orbital or electron(s) moves/jumps (from lower (d–)) to higher (d–) orbital 1 1 1 3 4(b)(i) Cu+4HNO3 →Cu(NO3)2 +2NO2 +2H2O or ionic Cu+4H+ +2NO3 – →Cu2+ +2NO2 +2H2O correct species correct balancing 1 1 2 4(b)(ii) moles S2O3 2–- =0.1×22.4/1000=2.24×10–3 moles of Cu2+ in 25cm3 =2.24×10–3 moles of Cu2+ in 250cm3 ==2.24×10–2 mass of Cu=2.24×10- 2×63.5=1.4224g % Cu=1.42/1.75×100=81.1 or 81.3% 1 1 1 1 4 Total: 9
  • 8. Page 8 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 5(a) Ka = 2- + 4 3 2 4 [HPO ][H O ] [ ]H PO − 1 1 5(b)(i) a solution that resists changes in pH when small amounts of acid and base/alkali are added 1 1 2 5(b)(ii) addition of acid: H+ +HPO4 2– H2PO4 – OR H+ +H2PO4 – H3PO4 addition of base: HO– +H2PO4 – HPO4 2– +H2O OR OH– +HPO4 2– H2O+PO4 3– 1 1 2 5(c) [H+ ] = 10–7.4 =3.98×10–8 [HPO4 2– ]/[H2PO4 – ]=Ka /[H+ ] ([HPO4 2– ]/[H2PO4 – ])=6.31×10–8 /3.98×10–8 =1.58-1.6 1 1 1 3 5(d)(i) HCl+H2PO4 – →H3PO4 +Cl– OR H+ +H2PO4 – →H3PO4 OR H2O+H2PO4 – →H3PO4 +OH– 1 1
  • 9. Page 9 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 5(d)(ii) NaOH+HPO4 2– →PO4 3– +H2O+Na+ OR OH– +HPO4 2– →PO4 3– +H2O OR H2O+HPO4 2– →PO4 3– +H3O+ 1 1 Total: 10 Question Answer Marks 6(a) HO O O O O Q * 1 6(b)(i) ratio of the concentration of a solute in the (two immiscible) solvents/liquids at equilibrium 1 1 2 6(b)(ii) Kpartition =(0.06/40)/(0.25–0.06/10) or reversed ratio: Kpartition = (0.25–0.06/10) / (0.06/40) Kpartition =0.079 (0.0789) Kpartition = 12.7/13.0 1 1 2
  • 10. Page 10 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 6(c) reagent structure of product(s) type of reaction excess Br2(aq) addition of bromine to alkene 2×Br substituted in phenol at positions 2 and 6 (electrophilic) substitution or (electrophilic) addition NaBH4 reduction (allow nucleophilic addition) 1 1 1
  • 11. Page 11 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks excess hot NaOH(aq) hydrolysis all three reaction types 1+1 1 6 6(d) mixture of (two) optical/stereo isomers formed 1 1 Total: 12
  • 12. Page 12 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 7(a)(i) electrophilic substitution 1 1 7(a)(ii) (Br2 +AlBr3)→Br+ +AlBr4 – curly arrow from ring system to Br+ correct intermediate curly arrow from C–H bond into ring and loss of H+ 1 1 1 1 4 7(b) both amide 1 1 7(c)(i) step 1, AlBr3 and CH3Br OR other suitable halogen instead of Br step 2, KMnO4 or potassium manganate(VII) step 3, conc. H2SO4 and conc. HNO3 step 4. Sn and (conc.) HCl (heat) 1 1 1 1 4
  • 13. Page 13 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 7(c)(ii) 1 mark for each correct structure 3 7(d)(i) 1 mark for each correct structure 2 7(d)(ii) reduction 1 1
  • 14. Page 14 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 7(e)(i) 1 mark for each correct structure 2 7(e)(ii) 1 1 7(e)(iii) (precipitate) compound is less polar /more non-polar/non-ionic resulting in less hydrogen bonding to water 1 1 Total: 20
  • 15. Page 15 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 8(a) 102×0.314=32(32.028)(102–32=70) and (12×5)+(1×10)=70 OR F contains CO2H=45 so 102–45=57 so C4H9 1 1 8(b)(i) 2 correct = 1 mark 3 correct = 2 marks 2 8(b)(ii) 2-methyl butanoic acid 1 1 8(c)(i) OH O 1 1 8(c)(ii) δ/ppm environment of the carbon atom hybridisation of the carbon atom 27 alkyl/CH3 sp3 41 next to carboxyl/(CH3)3C sp3 179 carboxyl/CO2H sp2 2
  • 16. Page 16 Mark Scheme Syllabus Paper Cambridge International AS/A Level – October/November 2016 9701 42 © UCLES 2016 Question Answer Marks 8(d)(i) δ/ppm type of proton number of protons splitting 0.9 alkane/CH/CH3 6 doublet 1.6 alkane/CH 1 [multiplet] 2.4 alkyl next to C=O/CH(2)CO/CH 2 doublet 11.5 OH/CO2H/carboxylic acid 1 singlet 4 8(d)(ii) 1 1 8(e) CDCl3 OR D2O, DMSO, CD2Cl2, CCl4 1 1 Total 13