1. Dr Patrick Geoghegan
Book: H. Versteeg and W. Malalasekera An Introduction to
Computational Fluid Dynamics: The Finite Volume Method
FEA/CFD for
Biomedical
Engineering
Week 11: CFD
3. • Reynolds-averaged Navier-Stokes Equations (RANS)
– Mean flow is resolved, the effect of turbulence on the mean flow
incorporated without resolving the turbulence
Alternatives for modelling turbulence? RANS!
u′
u
time, t
velocity,
u
Velocity fluctuation
Mean Velocity
• Solve for mean flow
• Effect of turbulence on
mean flow taken into
account
4. • Derivation of Reynolds-averaged Navier-Stokes Equations (RANS)
– Split the velocity into mean and fluctuating components, plug into Navier-
Stokes Equations and then apply time averaging to the resultant
equations
Alternatives for modelling turbulence? RANS!
u
u
t
u ′
+
=
)
(
u′
u
time, t
velocity,
u
𝑢𝑢𝑢 2 =
1
∆𝑡𝑡
�
0
∆𝑡𝑡
𝑢𝑢𝑢 2
𝑑𝑑𝑑𝑑
5. • Conservation of Mass (Continuity Equation)
• Conservation of Momentum
• Conservation of internal energy
• State Equations
Original Navier – Stokes equations
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝛻𝛻 � 𝜌𝜌𝐮𝐮 = 0
𝜕𝜕 𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔 + 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔 + 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔 + 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = −𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝐮𝐮 + 𝑑𝑑𝑑𝑑𝑑𝑑 𝑘𝑘𝑘𝑘𝑘𝑘𝑘𝑘𝑘𝑘𝑘𝑘 + 𝑆𝑆𝐸𝐸
𝑝𝑝 = 𝑝𝑝 𝜌𝜌, 𝑇𝑇 𝑖𝑖 = 𝑖𝑖 𝜌𝜌, 𝑇𝑇
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝐮𝐮 = 0
or
We won derive this here
6. • Conservation of Mass
• Reynolds Equations
Reynolds-averaged Navier-Stokes Equations (RANS)
𝜕𝜕 𝜌𝜌�
𝑢𝑢
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌�
𝑢𝑢𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔�
𝑢𝑢 + −
𝜕𝜕𝜌𝜌𝑢𝑢′𝑢𝑢𝑢
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑢𝑢′𝑣𝑣𝑣
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑢𝑢′𝑤𝑤𝑤
𝜕𝜕𝜕𝜕
+ 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕 𝜌𝜌 ̅
𝑣𝑣
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌 ̅
𝑣𝑣𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔 ̅
𝑣𝑣 + −
𝜕𝜕𝜌𝜌𝑢𝑢′𝑣𝑣𝑣
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑣𝑣′𝑣𝑣𝑣
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝜌𝜌𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕 𝜌𝜌�
𝑤𝑤
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌�
𝑤𝑤𝐮𝐮 = −
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔 + −
𝜕𝜕𝜌𝜌𝑢𝑢′𝑤𝑤𝑤
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑣𝑣′𝑤𝑤𝑤
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑤𝑤′𝑤𝑤𝑤
𝜕𝜕𝜕𝜕
+ 𝑆𝑆𝑀𝑀𝑀𝑀
𝜕𝜕𝜕𝜕
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝐮𝐮 = 0
Viscous Stresses Convective transfer of momentum due
to turbulence
Reynolds Stresses = Normal Stresses + Shear Stresses
In turbulent flow, Reynolds stresses dominate viscous stresses except very close to walls where turbulent
fluctuations go to zero
7. • Original Scalar Transport Equation for an arbitrary scalar Φ (energy,
mass fraction, etc)
• RANS Scalar Transport Equation for an arbitrary scalar Φ (energy,
mass fraction, etc)
Reynolds-averaged Navier-Stokes Equations (RANS)
𝜕𝜕 𝜌𝜌𝛷𝛷
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = 𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤
𝛷𝛷𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔Φ + −
𝜕𝜕𝜌𝜌𝑢𝑢′Φ
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑣𝑣′Φ
𝜕𝜕𝜕𝜕
−
𝜕𝜕𝜌𝜌𝑤𝑤′Φ
𝜕𝜕𝜕𝜕
+ 𝑆𝑆Φ
Convective transfer of Φ due to
turbulent eddies
𝜕𝜕 𝜌𝜌𝛷𝛷
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = 𝑑𝑑𝑑𝑑𝑑𝑑 𝛤𝛤
𝛷𝛷𝜇𝜇𝑔𝑔𝑔𝑔𝑔𝑔𝑔𝑔Φ + 𝑆𝑆Φ
Rate of
accum. of
Φ in fluid
element
Net rate of
flow of Φ
into fluid
element
(Convection)
Rate of change
of Φ due to
diffusion
Rate of change
of Φ due to
sources
+ +
=
9. • Solve equations for mean properties of flow (u, v, w, F)
• By applying time averaging, we lose details of the turbulent fluctuations
• But for engineering purposes, we usually only interested in mean
properties of the flow anyway
• With the Navier-Stokes Equations, we had 5 equations (4 transport
equations and one state-equation) and 5 unknowns (u, v, w, ρ, p)
• With the Reynolds-averaged Navier-Stokes Equations are now 6 extra
unknowns (the Reynolds stresses)
• Turbulence modelling is about developing equations to model the
Reynolds stresses
Reynolds-averaged Navier-Stokes Equations (RANS)
10. • Turbulent kinetic energy is a measure of the energy in the fluctuations
of the flow, not the mean flow
• Procedure for deriving the transport equation for turbulent kinetic
energy
1) Multiply the momentum equations of the Navier-Stokes equations by the
appropriate fluctuating velocity component (x-component momentum
equation multiplied by u’ etc)
2) Add the three resultant equations to form one equation
3) Repeat 1) and 2) for the Reynolds-averaged Navier-Stokes equations
4) Subtract the two resultant equations
Turbulent Kinetic Energy Equation, k
𝑘𝑘 =
1
2
𝑢𝑢𝑢 2 + 𝑣𝑣𝑣 2 + 𝑤𝑤𝑤 2
11. Turbulent Kinetic Energy Equation, k
𝑘𝑘 =
3
2
𝑢𝑢𝑢𝑟𝑟𝑟𝑟𝑟𝑟
2
Units =
𝑚𝑚2
𝑠𝑠2
𝑘𝑘 =
1
2
𝑢𝑢𝑢 2 + 𝑣𝑣𝑣 2 + 𝑤𝑤𝑤 2 Or
𝐼𝐼 =
𝑢𝑢𝑢𝑟𝑟𝑟𝑟𝑟𝑟
𝑢𝑢
× 100%
Remember
It is often assumed the fluctuations are the same in all directions so often
𝑘𝑘 =
1
2
𝑢𝑢𝑢𝑟𝑟𝑟𝑟𝑟𝑟
2
+ 𝑣𝑣𝑣𝑟𝑟𝑟𝑟𝑟𝑟
2
+ 𝑤𝑤𝑤𝑟𝑟𝑟𝑟𝑟𝑟
2
This can all be used to calculate the turbulence kinetic energy
12. Turbulent Kinetic Energy Equation, k
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = 𝑑𝑑𝑑𝑑𝑑𝑑 −𝑝𝑝′𝒖𝒖′ + 2𝜇𝜇𝒖𝒖′𝑠𝑠𝑖𝑖𝑖𝑖′ − 𝜌𝜌
1
2
𝑢𝑢𝑖𝑖
′
. 𝑢𝑢𝑖𝑖 ′𝑢𝑢𝑗𝑗′ − 2𝜇𝜇𝑠𝑠𝑖𝑖𝑖𝑖
′𝑠𝑠𝑖𝑖𝑖𝑖′ + 𝜌𝜌𝑢𝑢𝑖𝑖′𝑢𝑢𝑖𝑖′. 𝑆𝑆𝑖𝑖𝑖𝑖
Rate of
Change of
turbulent
kinetic
energy (k)
Rate of
Change of k
by
convection
Transport
of k by
pressure
Transport
of k by
viscous
stresses
Transport
of k by
Reynolds
Stresses
Rate of
dissipation
of k
Rate of
production
of k
13. • Rate of dissipation of k or viscous dissipation
• Work done by smallest eddies against viscous
stresses
• Always negative, destroys turbulent kinetic energy
• Divide by density to get dissipation rate (ε) (m2/s3)
Turbulent Kinetic Energy Equation, k
Rate of
dissipation
of k
𝜀𝜀 = 2𝜈𝜈𝑠𝑠𝑖𝑖𝑖𝑖
′𝑠𝑠𝑖𝑖𝑖𝑖′
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = 𝑑𝑑𝑑𝑑𝑑𝑑 −𝑝𝑝′𝒖𝒖′ + 2𝜇𝜇𝒖𝒖′𝑠𝑠𝑖𝑖𝑖𝑖′ − 𝜌𝜌
1
2
𝑢𝑢𝑖𝑖
′
. 𝑢𝑢𝑖𝑖 ′𝑢𝑢𝑗𝑗′ − 2𝜇𝜇𝑠𝑠𝑖𝑖𝑖𝑖
′𝑠𝑠𝑖𝑖𝑖𝑖′ + 𝜌𝜌𝑢𝑢𝑖𝑖′𝑢𝑢𝑖𝑖′. 𝑆𝑆𝑖𝑖𝑖𝑖
14. • Rate of production of k
• Represents conversion of kinetic energy from the
mean flow into turbulent kinetic energy (that is
production of turbulent kinetic energy)
• Always positive
Turbulent Kinetic Energy Equation, k
Rate of
production
of k
𝜕𝜕 𝜌𝜌𝜌𝜌
𝜕𝜕𝜕𝜕
+ 𝑑𝑑𝑑𝑑𝑑𝑑 𝜌𝜌𝜌𝜌𝐮𝐮 = 𝑑𝑑𝑑𝑑𝑑𝑑 −𝑝𝑝′𝒖𝒖′ + 2𝜇𝜇𝒖𝒖′𝑠𝑠𝑖𝑖𝑖𝑖′ − 𝜌𝜌
1
2
𝑢𝑢𝑖𝑖
′
. 𝑢𝑢𝑖𝑖 ′𝑢𝑢𝑗𝑗′ − 2𝜇𝜇𝑠𝑠𝑖𝑖𝑖𝑖
′𝑠𝑠𝑖𝑖𝑖𝑖′ + 𝜌𝜌𝑢𝑢𝑖𝑖′𝑢𝑢𝑖𝑖′. 𝑆𝑆𝑖𝑖𝑖𝑖
15. • Terms in the equation mathematically
represent phenomena observed to occur
in nature energy cascade
(1)Largest eddies extract energy from the
mean flow by a mechanism of vortex
stretching
(2)This energy is passed down to smaller
eddies existing within the larger eddies,
also by a mechanism of vortex
stretching, and so onwards to smaller
and smaller eddies
(3)At the smallest eddy-scales, energy is
finally dissipated as heat by friction
Turbulent Kinetic Energy Equation, k