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Addition and
Subtraction of
Dissimilar
Fractions
MATHEMATICS 6 – Q1 Week 1 (Lesson 2)
WHAT’S IN
A. Give the LCD of the
following pairs of
dissimilar fractions.
πŸ‘
πŸ’
𝒂𝒏𝒅
πŸ“
πŸ•
πŸ•
πŸ—
𝒂𝒏𝒅
πŸ•
𝟏𝟐
𝟏
πŸπŸ“
𝒂𝒏𝒅
πŸ–
𝟏𝟎
πŸ•
πŸ–
𝒂𝒏𝒅
πŸ“
πŸπŸ’
𝟏𝟐
πŸπŸ“
𝒂𝒏𝒅
πŸ‘
𝟐𝟎
28 36 30
24 100
WHAT’S IN
B. Change the following
dissimilar fractions to
similar fractions. Write the
answer on your paper.
πŸ’
πŸ“
,
𝟐
πŸ’
πŸ‘
πŸ–
,
𝟏𝟏
πŸπŸ’
πŸ•
πŸ•πŸ
,
𝟏𝟏
πŸπŸ–
𝟐
πŸ“
,
πŸ“
πŸ–
,
πŸ—
𝟏𝟎
πŸ“
πŸ”
,
πŸπŸ‘
𝟐𝟎
,
πŸ‘
πŸ’
πŸπŸ”
𝟐𝟎
,
𝟏𝟎
𝟐𝟎
πŸ—
πŸπŸ’
,
𝟏𝟏
πŸπŸ’
πŸ•
πŸ•πŸ
,
πŸ’πŸ’
πŸ•πŸ
πŸπŸ”
πŸ’πŸŽ
,
πŸπŸ“
πŸ’πŸŽ
,
πŸ‘πŸ”
πŸ’πŸŽ
πŸ“πŸŽ
πŸ”πŸŽ
,
πŸ‘πŸ—
πŸ”πŸŽ
,
πŸ’πŸ“
πŸ”πŸŽ
WHAT’S NEW Aling Celo, a
dressmaker, is sewing
facemasks which she
will donate for the
frontliners. She has 3
pieces of cloth which
measure as follows:
𝟏
𝟐
π’Ž,
𝟐
πŸ‘
π’Ž, and
πŸ’
πŸ”
π’Ž. How many
meters of cloth does
she have in all?
Answer the following
questions:
1.) What is the work of Aling Celo?
2.) What does she sew?
3.) To whom would she donate the
facemasks?
4.) What is asked in the problem?
Let’s add
𝟏
𝟐
,
𝟐
πŸ‘
, 𝒂𝒏𝒅
πŸ’
πŸ”
step by
step.
𝟏
𝟐
+
𝟐
πŸ‘
+
πŸ’
πŸ”
= 𝑡
The fractions are dissimilar
(different denominators).
𝟏
𝟐
=
πŸ”
𝟐
πŸ‘
=
πŸ”
+
πŸ’
πŸ”
=
πŸ”
Change the
fractions to similar
by using the least
common
denominator (LCD)
which is 6.
𝟏
𝟐
=
πŸ”
𝟐
πŸ‘
=
πŸ”
+
πŸ’
πŸ”
=
πŸ”
Divide the LCD by the denominator then
multiply the quotient by the numerator.
πŸ” Γ· 𝟐 π’™πŸ = πŸ‘
3
(πŸ” Γ· πŸ‘) 𝒙 𝟐 = πŸ’
4
(πŸ” Γ· πŸ”) 𝒙 πŸ’ = πŸ’
4
πŸ‘
πŸ”
+
πŸ’
πŸ”
+
πŸ’
πŸ”
=
𝟏𝟏
πŸ”
Add the numerators over the
common denominators.
𝟏𝟏
πŸ”
= 𝟏
πŸ“
πŸ”
Simplify your answer or
reduce to lowest term.
Therefore,
Aling Celo
has 𝟏
πŸ“
πŸ”
π’Ž of
cloth.
Let’s have another
example:
πŸ‘
πŸ“
+
𝟏
πŸ”
= 𝑡
The fractions are dissimilar
(different denominators).
πŸ‘
πŸ“
=
πŸ‘πŸŽ
+
𝟏
πŸ”
=
πŸ‘πŸŽ
Change the fractions
to similar by using the
least
common denominator
(LCD) which is 30.
πŸ‘
πŸ“
=
πŸ‘πŸŽ
+
𝟏
πŸ”
=
πŸ‘πŸŽ
Divide the LCD by the denominator then
multiply the quotient by the numerator.
(πŸ‘πŸŽ Γ· πŸ“) 𝒙 πŸ‘ = πŸπŸ–
18
(πŸ‘πŸŽ Γ· πŸ”) 𝒙 𝟏 = πŸ“
5
πŸ‘
πŸ“
=
πŸπŸ–
πŸ‘πŸŽ
+
𝟏
πŸ”
=
πŸ“
πŸ‘πŸŽ
πŸπŸ‘
πŸ‘πŸŽ
Add the numerators
over the common
denominators.
You could also find the difference of two dissimilar
fraction following the same steps.
πŸ•
πŸ—
βˆ’
𝟐
πŸ‘
= 𝑡
The fractions are dissimilar
(different denominators).
πŸ•
πŸ—
=
πŸ—
βˆ’
𝟐
πŸ‘
=
πŸ—
Change the fractions
to similar by using the
least
common denominator
(LCD) which is 9.
πŸ•
πŸ—
=
πŸ—
βˆ’
𝟐
πŸ‘
=
πŸ—
Divide the LCD by the denominator then
multiply the quotient by the numerator.
(πŸ— Γ· πŸ—) 𝒙 πŸ• = πŸ•
7
(πŸ— Γ· πŸ‘) 𝒙 𝟐 = πŸ”
6
πŸ•
πŸ—
=
πŸ•
πŸ—
βˆ’
𝟐
πŸ‘
=
πŸ”
πŸ—
𝟏
πŸ—
You could subtract mixed fractions with unlike
denominators following the same steps.
𝟏𝟐
𝟐
πŸ‘
βˆ’ πŸ“
𝟐
πŸ“
= 𝑡
The fractions are dissimilar
(different denominators).
𝟏𝟐
𝟐
πŸ‘
= 𝟏𝟐
πŸπŸ“
βˆ’ πŸ“
𝟐
πŸ“
= πŸ“
πŸπŸ“
The LCD of 3
and 5 is 15.
𝟏𝟐
𝟐
πŸ‘
= 𝟏𝟐
πŸπŸ“
βˆ’ πŸ“
𝟐
πŸ“
= πŸ“
πŸπŸ“
Divide the LCD by the denominator then
multiply the quotient by the numerator.
(πŸπŸ“ Γ· πŸ‘) 𝒙 𝟐 = 𝟏𝟎
(πŸπŸ“ Γ· πŸ“) 𝒙 𝟐 = πŸ”
10
6
𝟏𝟐
𝟐
πŸ‘
= 𝟏𝟐
𝟏𝟎
πŸπŸ“
βˆ’ πŸ“
𝟐
πŸ“
= πŸ“
πŸ”
πŸπŸ“
πŸ•
πŸ’
πŸπŸ“
Subtract the
fractional part
then, the
whole
number.
More Examples
𝟐
𝟏
𝟐
βˆ’
πŸ‘
πŸ’
= 𝑡
The fractions are dissimilar
(different denominators).
𝟐
𝟏
𝟐
= 𝟐
πŸ’
βˆ’
πŸ‘
πŸ’
=
πŸ’
The LCD of 2
and 4 is 4.
𝟐
𝟏
𝟐
= 𝟐
πŸ’
βˆ’
πŸ‘
πŸ’
=
πŸ’
Divide the LCD by the denominator then
multiply the quotient by the numerator.
(πŸ’ Γ· 𝟐) 𝒙 𝟏 = 𝟐
(πŸ’ Γ· πŸ’) 𝒙 πŸ‘ = πŸ‘
2
3
Since
𝟐
πŸ’
<
πŸ‘
πŸ’
, we cannot subtract
𝟐
𝟐
πŸ’
= 𝟏 +
πŸ’
πŸ’
+
𝟐
πŸ’
= 𝟏
πŸ”
πŸ’
Therefore, you have to
regroup 1 or
πŸ’
πŸ’
from 2.
βˆ’
πŸ‘
πŸ’ You can now subtract the
fractional part, then whole
number.
1
πŸ‘
πŸ’
WHAT’S MORE
Direction
Add or subtract. Choose the letter
of the correct answer inside the
box to discover the word formed.
1
𝟏
𝟐
+ 𝟐
πŸ‘
πŸ”
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
2
𝟐
πŸ‘
πŸ•
+ 𝟏𝟎
πŸ’
πŸ”
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
3
πŸ‘
πŸ•
πŸ–
βˆ’
𝟏
𝟐
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
4
πŸ—
πŸ‘
πŸ“
βˆ’ πŸ“
𝟐
πŸ‘
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
5
𝟐𝟏
πŸ•
𝟏𝟐
βˆ’ πŸ”
πŸ“
πŸ–
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
ANSWERS
1
𝟏
𝟐
+ 𝟐
πŸ‘
πŸ”
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
2
𝟐
πŸ‘
πŸ•
+ 𝟏𝟎
πŸ’
πŸ”
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
3
πŸ‘
πŸ•
πŸ–
βˆ’
𝟏
𝟐
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
4
πŸ—
πŸ‘
πŸ“
βˆ’ πŸ“
𝟐
πŸ‘
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
5
𝟐𝟏
πŸ•
𝟏𝟐
βˆ’ πŸ”
πŸ“
πŸ–
=
A. πŸ’
πŸ‘
πŸ–
O. πŸπŸ‘
𝟐
𝟐𝟏
C. 𝟏
T. πŸπŸ’
πŸπŸ‘
πŸπŸ’
N. πŸ‘
πŸπŸ’
πŸπŸ“
U. πŸ‘
πŸ‘
πŸ–
WHAT’S MORE
Direction
Perform the indicated operation.
Reduce your answer to lowest
term.
𝟏. ) πŸ’
πŸ’
πŸ“
+
πŸ”
𝟏𝟎
=
𝟐. ) πŸ—
πŸ‘
πŸ’
+
πŸ‘
𝟏𝟐
+ 𝟐
𝟐
πŸ‘
=
πŸ‘. )
πŸ‘
πŸ’
βˆ’
𝟏
𝟏𝟐
=
πŸ’. ) πŸπŸ•
𝟏
πŸ’
βˆ’ 𝟏𝟐
πŸ’
πŸ“
=
πŸ“. ) πŸ‘πŸ”
πŸ”
πŸ–
βˆ’ πŸπŸ‘
πŸ•
πŸ—
=
ANSWERS
𝟏. ) πŸ’
πŸ’
πŸ“
+
πŸ”
𝟏𝟎
=
𝟐. ) πŸ—
πŸ‘
πŸ’
+
πŸ‘
𝟏𝟐
+ 𝟐
𝟐
πŸ‘
=
πŸ“
𝟐
πŸ“
𝟏𝟐
𝟐
πŸ‘
πŸ‘. )
πŸ‘
πŸ’
βˆ’
𝟏
𝟏𝟐
=
πŸ’. ) πŸπŸ•
𝟏
πŸ’
βˆ’ 𝟏𝟐
πŸ’
πŸ“
=
𝟐
πŸ‘
πŸπŸ’
πŸ—
𝟐𝟎
πŸ“. ) πŸ‘πŸ”
πŸ”
πŸ–
βˆ’ πŸπŸ‘
πŸ•
πŸ—
=
𝟐𝟐
πŸ‘πŸ“
πŸ‘πŸ”
WHAT I CAN DO
Direction
Find the total.
𝟏. ) πŸ”
𝟏
𝟐
+ 𝟐
𝟏
πŸ‘
=
𝟐. )
𝟏
πŸ”
+
𝟏
𝟐
=
πŸ‘. )
𝟏
𝟐
+
𝟏
πŸ“
+
𝟏
𝟏𝟎
=
πŸ’. ) πŸπŸ–
𝟏
𝟐
βˆ’ πŸ•
πŸ‘
πŸ’
=
πŸ“. )
πŸ“
𝟐𝟎
+ πŸ•
πŸ—
𝟏𝟎
+ 𝟏
𝟏
𝟐
=
ANSWERS
𝟏. ) πŸ”
𝟏
𝟐
+ 𝟐
𝟏
πŸ‘
=
𝟐. )
𝟏
πŸ”
+
𝟏
𝟐
=
𝟏
𝟏𝟏
πŸ’
πŸ•
πŸ‘. )
𝟏
𝟐
+
𝟏
πŸ“
+
𝟏
𝟏𝟎
=
πŸ’. ) πŸπŸ–
𝟏
𝟐
βˆ’ πŸ•
πŸ‘
πŸ’
=
πŸπŸ“
𝟏
πŸ“
πŸπŸ•
𝟏
πŸ‘
πŸ“. )
πŸ“
𝟐𝟎
+ πŸ•
πŸ—
𝟏𝟎
+ 𝟏
𝟏
𝟐
=
πŸπŸ‘
𝟐
πŸ‘
ASSESSMENT
Direction
Perform the indicated operation.
𝟏. )
πŸπŸ“
𝟏𝟎
βˆ’
𝟏𝟎
πŸπŸ“
=
𝟐. )
πŸ—
πŸπŸ“
βˆ’
πŸ‘
𝟏𝟎
=
πŸ‘. )
𝟏
𝟐
+
𝟏
πŸ“
+
𝟏
𝟏𝟎
=
πŸ’. ) πŸ—
πŸ“
πŸ—
βˆ’ πŸ”
πŸ”
πŸ•
=
πŸ“. ) πŸπŸ”
πŸ•
𝟏𝟐
βˆ’ πŸ’
πŸ’
πŸ–
=
ANSWERS
𝟏. )
πŸπŸ“
𝟏𝟎
βˆ’
𝟏𝟎
πŸπŸ“
=
𝟐. )
πŸ—
πŸπŸ“
βˆ’
πŸ‘
𝟏𝟎
=
πŸ“
πŸ”
πŸ‘
𝟏𝟎
πŸ‘. )
𝟏
𝟐
+
𝟏
πŸ“
+
𝟏
𝟏𝟎
=
πŸ’. ) πŸ—
πŸ“
πŸ—
βˆ’ πŸ”
πŸ”
πŸ•
=
πŸ‘
πŸπŸ”
πŸ’πŸ“
𝟐
πŸ’πŸ’
πŸ”πŸ‘
πŸ“. ) πŸπŸ”
πŸ•
𝟏𝟐
βˆ’ πŸ’
πŸ’
πŸ–
=
𝟏𝟐
𝟏
𝟏𝟐
ADDITIONAL
ACTIVITY
Direction
Fill-in the blanks to complete the
steps on How to Add and Subtract
Dissimilar Fractions and Mixed
Fractions.
1
To add and subtract dissimilar fractions, find
the ____________________ to make them similar.
Divide LCD by the ____________________ then
multiply the quotient by the ____________________.
Continue the process using the steps in adding
and subtracting similar fractions.
2
To add and subtract mixed fractions with
dissimilar fractions, rewrite the ____________________
parts to similar fractions using the
____________________. Regroup the similar fractions if
necessary, then perform the indicated operation.
Write the answer in ____________________ terms, if
possible.

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