Part I: Write a program that uses a function that takes in two integers as inputand returns a minimum value (using pass-by-value). (HINT: the prototype lookslike: int minimum(int num1, int num2); Part II: Modify your original program to include a function that take in fourintegers; two of which are passed-by-value, and the other two are passed-by-reference. The pass-by-reference integers are the min and max of the two pass-by-value integers. Find the min and max and \"return\" the values back to main.The prototype here is: void minmax(int &min, int &max, int num1, int num2); Solution Question1: #include using namespace std; int minimum(int num1, int num2); int main() { int num1, num2, min; cout<<\"Enter first number: \"; cin >> num1; cout<<\"Enter second number: \"; cin >> num2; min = minimum(num1, num2); cout<<\"The minimum number is \"<< min< using namespace std; void minmax(int &min, int &max, int num1, int num2); int main() { int num1, num2, min, max; cout<<\"Enter first number: \"; cin >> num1; cout<<\"Enter second number: \"; cin >> num2; minmax(min, max, num1, num2); cout<<\"The minimum number is \"<< min< num2){ min = num2; max = num1; } else{ min = num1; max = num1; } } Output: Enter first number: 6 Enter second number: 5 The minimum number is 5 The maximum number is 6 sh-4.3$ g++ -std=c++11 -o main *.cpp sh-4.3$ main Enter first number: 4 Enter second number: 5 The minimum number is 4.

1. Part I: Write a program that uses a function that takes in two integers as inputand returns a
minimum value (using pass-by-value). (HINT: the prototype lookslike: int minimum(int num1,
int num2);
Part II: Modify your original program to include a function that take in fourintegers; two of
which are passed-by-value, and the other two are passed-by-reference. The pass-by-reference
integers are the min and max of the two pass-by-value integers. Find the min and max and
"return" the values back to main.The prototype here is: void minmax(int &min, int &max, int
num1, int num2);
Solution
Question1:
#include
using namespace std;
int minimum(int num1, int num2);
int main()
{
int num1, num2, min;
cout<<"Enter first number: ";
cin >> num1;
cout<<"Enter second number: ";
cin >> num2;
min = minimum(num1, num2);
cout<<"The minimum number is "<< min<
using namespace std;
void minmax(int &min, int &max, int num1, int num2);
int main()
{
int num1, num2, min, max;
cout<<"Enter first number: ";
cin >> num1;
cout<<"Enter second number: ";
cin >> num2;
minmax(min, max, num1, num2);
cout<<"The minimum number is "<< min< num2){

2. min = num2;
max = num1;
}
else{
min = num1;
max = num1;
}
}
Output:
Enter first number:
6
Enter second number:
5
The minimum number is
5
The maximum number is
6
sh-4.3$ g++ -std=c++11 -o main
*.cpp
sh-4.3$
main
Enter first number:
4
Enter second number:
5
The minimum number is 4