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REVIEW IN MATH
Prepared By:
Teacher MELCHOR
Get ready!
START
ROUND 1:
(1 Point)
Get the nth term of the
following numbers
ANSWER: 125
πŸ‘
Question 1:
ANSWER: 225
𝟐
Question 2:
ANSWER: 1, 331
πŸ‘
Question 3:
ANSWER: 1, 728
πŸ‘
Question 4:
ANSWER: 196
𝟐
Question 5:
Get the nth root of the
following numbers
ANSWER: 13
πŸ‘
πŸπŸ”πŸ—
Question 6:
ANSWER: 11
πŸ‘
πŸπŸ‘πŸ‘πŸ
Question 7:
ANSWER: 12
πŸπŸ’πŸ’
Question 8:
ANSWER: 25
πŸ”πŸπŸ“
Question 9:
ANSWER: 55
πŸ‘πŸŽπŸπŸ“
Question 10:
Answer the following
questions.
ANSWER:
NUMERICAL COEFFICIENT
In the radical expression
πŸ•πš πŸ‘π’™π’š, what do you call
7a?
Question 1:
ANSWER: πŸ•πŸπ’™π’š 𝟐
In the radical expression
βˆ’ πŸ‘π’‚ 𝟐 πŸ‘
πŸ•πŸπ’™π’š 𝟐, what is the
radicand?
Question 2:
ANSWER: 3 π’š
What is the simplified
form of
πŸ‘
πŸπŸ•π’š πŸ‘?
Question 3:
ANSWER: 𝒙 πŸ‘
π’šπ’› πŸ’
What is the simplified
form of
πŸ‘
𝒙 πŸ— π’š πŸ‘ 𝒛 𝟏𝟐?
Question 4:
ANSWER: π’Žπ’š 𝟐
𝒛 πŸ• πŸ‘
π’Ž 𝟐 π’šπ’›
What is the simplified
form of
πŸ‘
π’Ž πŸ“ π’š πŸ• 𝒛 𝟐𝟐?
Question 5:
ROUND 2:
(2 Points)
SIMPLIFY
the following radical
expressions
ANSWER: πŸ—π’™
πŸ–πŸπ’™ 𝟐
Question 1:
ANSWER: πŸπŸ‘π’Ž
πŸπŸ”πŸ—π’Ž 𝟐
Question 2:
ANSWER: πŸπŸπ’Ž 𝟐 𝒏 𝟐 𝒏
πŸπŸπŸπ’Ž πŸ’ 𝒏 πŸ“
Question 3:
ANSWER: 3𝒂𝒄 πŸ‘
𝒄
πŸ‘
πŸπŸ•π’‚ πŸ‘ 𝒄 πŸ’
Question 4:
ANSWER: πŸ—π’‚π’„ 𝟐 πŸ‘
𝒃𝒄
πŸ‘
πŸ•πŸπŸ—π’‚ πŸ‘ 𝒃𝒄 πŸ•
Question 5:
ROUND 3:
(3 Points)
Multiply
the following radical
expressions
ANSWER: 14 πŸ‘
πŸπŸ– βˆ™ 𝟐𝟏
Question 1:
ANSWER: πŸπ’™ πŸ“ π’š πŸ“ πŸ‘π’™π’š
πŸ‘π’™ πŸ’ π’š πŸ• βˆ™ πŸ’π’™ πŸ• π’š πŸ’
Question 2:
ANSWER: πŸ”π’™ 𝟐 π’š πŸ’ πŸ•
πŸ‘
πŸ”πŸ‘π’™π’š πŸ’ βˆ™
πŸ‘
πŸπŸ’π’™ πŸ“ π’š πŸ–
Question 3:
ANSWER: πŸ’
πŸ’πŸ— + πŸ’πŸ“ πŸ’πŸ— βˆ’ πŸ’πŸ“
Question 4:
ANSWER: πŸπŸ“πšπ›
πŸ‘ πŸ•π’‚π’ƒ + πŸ”π’‚π’ƒ πŸ‘ πŸ•π’‚π’ƒ βˆ’ πŸ”π’‚π’ƒ
Question 5:
GOD BLESS
I wish everyone to
Pass your Exams

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