1. Speed of Light c _ Fibonacci Decimals
Chirp Mass
V 02/22/16
Fibonacci says c = 3E+08 (MKS) e.g. M = (m1m2)3/5/(m1+m2)1/5 = c3G-1(Δλ x rH)
for large Δλ where Δλ = nb 1≤n≤(1/b3) and b3(meter) = B-1 = c-2 (meter1 event-1).
I get decimals c = 2.997189 instead of 2.997925 (the later is correct.)
Fibonacci infinite sequence dictates:
The number 1 (one) as perceived in D=3 or three spatial dimensions:
--- this next part is incorrect --- see below ---
1 = 0.9982933 = [1 + (5/13)^(5/2)^(8/3)]^-1 (a change from D=8 aka chirp mass)
3 = {[1+(1/12.42)^13/5]^-1 x [1 + (5/13)^(3/1)^(5/2)]^+1} x 3 = 2.997189
instead of 2.997925 (the correct measured 3-D value.)
--- this part is still correct ---
But if:
Let 1 = [1 + (5/13)^(13/5)^(21/8)^(34/13)^(55/21)]^-1
Then: 1 = 1 and 3 = 3
---
What am I doing wrong? 2/15/16
Getting there… 2/16/16
3 = {…} x (3*1)
where 1 = 0.99923 …(only contains the powers 3/1 and 5/2.)
Except: Now we only get c = 2.997689E+08 (better) instead of 2.997189E+08.
2. Must need to change another “dimensional 1” somewhere…
And now maybe D=5 instead of D=8 for chirp mass, and maybe not. Hole should obey math for
D=8 and light should obey D=5.
02/18/16
--------
D = 8
Most likely: 3/1, 5/2, etc. are OK because they are fractions (divide out.)
Probably, I was wrong to distrust the power 3 = 3/1 a fraction.
To me, now the single “1’s” in the equation are suspect (subject to our misperception.)
<Work-in-progress>
---Excel_Fib_c3---
02/20/16
c = 2.99792371E+08 MKS (still do not get 2.99792458)
I used 13 = 0.99926844
33 = 2.99792371
Used 𝛾 infinity = 1 – ϕ instead of one of the 5/13 values.
02/21/16
The most likely source of error in the last 3 digits is the use of the number 13 yesterday.
13 is more likely derived by changing from 1infinity to at least (one) local value in:
1infinity + [(1infinity - ϕ)^(3/1)^(5/2)] x (1infinity + RE
13/5)-1. RE = 1/RLOG = 1/12.42 = (𝛾-1^𝛾-1)-1.
3. 02/22/16
OR the empirical value (also depends on h = h x 1) has a greater uncertainty from the various
methods of measurement than the theoretical prediction?
![Speed of Light c _ Fibonacci Decimals
Chirp Mass
V 02/22/16
Fibonacci says c = 3E+08 (MKS) e.g. M = (m1m2)3/5/(m1+m2)1/5 = c3G-1(Δλ x rH)
for large Δλ where Δλ = nb 1≤n≤(1/b3) and b3(meter) = B-1 = c-2 (meter1 event-1).
I get decimals c = 2.997189 instead of 2.997925 (the later is correct.)
Fibonacci infinite sequence dictates:
The number 1 (one) as perceived in D=3 or three spatial dimensions:
--- this next part is incorrect --- see below ---
1 = 0.9982933 = [1 + (5/13)^(5/2)^(8/3)]^-1 (a change from D=8 aka chirp mass)
3 = {[1+(1/12.42)^13/5]^-1 x [1 + (5/13)^(3/1)^(5/2)]^+1} x 3 = 2.997189
instead of 2.997925 (the correct measured 3-D value.)
--- this part is still correct ---
But if:
Let 1 = [1 + (5/13)^(13/5)^(21/8)^(34/13)^(55/21)]^-1
Then: 1 = 1 and 3 = 3
---
What am I doing wrong? 2/15/16
Getting there… 2/16/16
3 = {…} x (3*1)
where 1 = 0.99923 …(only contains the powers 3/1 and 5/2.)
Except: Now we only get c = 2.997689E+08 (better) instead of 2.997189E+08.](https://image.slidesharecdn.com/b944dfbb-7278-4f89-ba4c-fa52be588903-160222061810/85/chirpmass-1-320.jpg)
![Must need to change another “dimensional 1” somewhere…
And now maybe D=5 instead of D=8 for chirp mass, and maybe not. Hole should obey math for
D=8 and light should obey D=5.
02/18/16
--------
D = 8
Most likely: 3/1, 5/2, etc. are OK because they are fractions (divide out.)
Probably, I was wrong to distrust the power 3 = 3/1 a fraction.
To me, now the single “1’s” in the equation are suspect (subject to our misperception.)
<Work-in-progress>
---Excel_Fib_c3---
02/20/16
c = 2.99792371E+08 MKS (still do not get 2.99792458)
I used 13 = 0.99926844
33 = 2.99792371
Used 𝛾 infinity = 1 – ϕ instead of one of the 5/13 values.
02/21/16
The most likely source of error in the last 3 digits is the use of the number 13 yesterday.
13 is more likely derived by changing from 1infinity to at least (one) local value in:
1infinity + [(1infinity - ϕ)^(3/1)^(5/2)] x (1infinity + RE
13/5)-1. RE = 1/RLOG = 1/12.42 = (𝛾-1^𝛾-1)-1.](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)