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FORCES AND MOTION
1
2
 Apply Newton's Laws as basic principles for dynamics of
particle in linear motion and vertical motion.
 State each of Newton's laws of motion
 Describe the definitions and types of forces acting on a body in
different situation (pulley, inclined surface, tension of string)
 Apply F = m.a in solving problems related to linear motion of a
body
 Apply F = m.a in solving problems related to vertical motion of
a body
 Analyze relation between force and its frictional force
 Analyze the coefficient of frictional force (static and kinetic
friction) through inclined plane
After studying this topic, you are expected to be able
to:
3
What is Force?
Force  PUSH/ PULL
 unit: newton
(kg.m/s2
)
It is a VECTOR
QUANTITY
4
Types of Force:
5
6
7
8
How to deal with forces?
Free Body Diagram
To keep things simple  only draw forces that
acting on the object
Example:
N
Frictional force (f)
W
9
Exercise:
10
A body is pulled in two opposing
directions by two ropes as shown in
Figure beside. The resultant force acting
is the vector sum of the forces.
How to calculate forces?
Force is Vector, so….
 Calculate forces : calculate vectors!
Example:
If a body is pulled by two perpendicular
ropes as in Figure 2.33, then the vector
addition is solved using vectors addition.
11
Exercise:
12
Forces Balanced  Equilibrium
13
Forces Balanced  Equilibrium
14
Forces Balanced  Equilibrium
Another example:
Separate the vectors into 2 components:
x & y
If the box is in equilibrium, then:
Total component in x = 0  forces left = forces right
Total component in y = 0  forces up = forces down
15
Example:
Consider the situation below. If the forces on this box are
balanced:
a) write an equation for the components of the forces
parallel to the ramp
b) write equation for the forces perpendicular to the ramp
c) find the friction (F) & normal force (N)
16
Example:
A ball of weight 10 N is suspended on a
string and pulled to one side by another
horizontal string as shown beside.
If the forces are balanced:
(a) write an equation for the horizontal
components of the forces acting on the
ball
(b) write an equation for the vertical
components of the forces acting on the
ball
(c) use the second equation to calculate
the tension in the upper string, T
(d) use your answer to (c) plus the first
equation to find the horizontal force F.
17
Example:
A rock climber is hanging from a rope
attached to the cliff by two bolts as
shown in Figure beside. If the forces are
balanced
a) write an equation for the vertical
component of the forces on the knot
b) write an equation for the horizontal
forces exerted on the knot
c) calculate the tension T in the ropes
joined to the bolts. The result of this
calculation shows why ropes should
not be connected in this way.
18
Newton’s Laws of Motion
Forces balanced  object is at rest (?)
Forces not balanced  object moves (?)
How do we explain that with strong
argument?
Newton’s Laws of Motion
1st
Law:
A body will remain at rest or moving with constant
velocity unless acted upon by an unbalanced force.
Net force = 0  no acceleration
19
Example:
20
Example:
21
22
23
24
Constant velocity  Net force = 0
25
Example:
26
Example:
27
Application of
1st Law:
Seat Belts
mechanism
28
29
Note:
If the forces are
balanced, will the
object always be at rest
or moving with
constant velocity?
30
2nd Law:
The acceleration of an object is
directly proportional to the net force acting on it and
inversely proportional to its mass.
Σ 𝐹 = 𝑚. 𝑎
31
Example:
32
33
Example:
34
Example:
35
• Simple Pulley system
Example:
36
37
Single isolated force
can’t exist

Pair of forces on
two different objects
3rd Law:
If body A exerts a force on body B then body B will
exert an equal and opposite force on body A.
38
39
CONCEPTUAL EXAMPLE 4-5 I Third Isw clsrfiic@ion. klichclnngzlo's
‹a«sisl‹ant hnr hccn avxigncd thE I:1fik nf mn‹’ing a hI‹›ck ‹›f marhtc using a »Icd
(Ftg, 4—I2).He say» to hi6 hu«s,”When T exert n fnr«'.ard f‹›rcc on the rlcd, the
xIcd exert» iin cgu:II :ind uppclitc force h:›«kvxtrd. Su huw can I c'cr 1ti!rl it mnving/
Nn m:itt«r hen' hard T gull, thu hackn'ard rc‹actiun fore» always cyuat.r my ft›rv.
rd f‹.›r«c, »‹› the net f‹›rce n1uxt he ’/crn. f’Il nc‹'cr hu ithlc tu mnvc thi,s lnad,” I»
thi» a ca»e cl a little knnu'Icdge hcing dungereu»"/ Exgl:›in,
exerted
by assistant
a»i»a”nt
exerted
Example:
A car of mass m is on an icy driveway inclined at an
angle 30.0o
, as in Figure 4.16a. Determine (a) the
acceleration of the car, assuming that the incline is
frictionless. (b) If the length of the driveway is 20.0 m
and the car starts from rest at the top, how long does it
take to travel to the bottom? (c) What is the car’s speed
at the bottom?
41
42
43
Frictional Force
A frictional force  vector
sum of many forces acting
between the surface atoms of
one body and those of
another body
44
Types of Frictional Force:
Static Friction (fs)
45
Kinetic Friction (fk)
46
Note:
fs max > fk
47
Static Frictional Force:
fs ≤ s.N
Maximum static frictional force:  in verge of
slipping
fs max = s.N
s= coefficient of static friction  depend on the
nature of surfaces
N = Normal force
Kinetic Frictional Force:
fk = k.N
k= coefficient of kinetic friction
48
49
50
51
Example:
1. The hockey puck in Figure 4.22, struck by a
hockey stick, is given an initial speed of 20.0 m/s on
a frozen pond. The puck remains on the ice and
slides 120 m, slowing down steadily until it comes
to rest. Determine the coefficient of kinetic friction
between the puck and the ice.
52
Suppose a block with a mass of
2.00 kg is resting on a ramp. If
the coefficient of static friction
between the block and ramp is
0.30, what maximum angle can
the ramp make with the
horizontal before the block starts
to slip down?
53
A loaded penguin sled weighing 40√2 N
rests on a plane inclined at angle  = 45° to
the horizontal (Figure beside). Between the
sled and the plane, the coefficient of static
friction is 0.25, and the coefficient of
kinetic friction is 0.15. Determine:
a. Maximum static friction between sled and plane.
b. Magnitude of the force required in order to make the sled stay at
rest, not sliding down the plane. (remember, there are frictional
force and weight of object)
c. What is the minimum magnitude F that will start the sled moving
up the plane? (Hint: draw the force first)
d. What value of F is required to move the sled up the plane at
constant velocity?
54
A block with mass m1 = 4.00 kg and
a ball with mass m2 = 7.00 kg are
connected by a light string that
passes over a frictionless pulley, as
shown in Figure 4.23a. The
coefficient of kinetic friction between
the block and the surface is 0.300.
Find the acceleration of the two
objects and the tension in the string.
55

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forces-and-motion-ppt.docx lecture in Physical Science

  • 2. 2  Apply Newton's Laws as basic principles for dynamics of particle in linear motion and vertical motion.  State each of Newton's laws of motion  Describe the definitions and types of forces acting on a body in different situation (pulley, inclined surface, tension of string)  Apply F = m.a in solving problems related to linear motion of a body  Apply F = m.a in solving problems related to vertical motion of a body  Analyze relation between force and its frictional force  Analyze the coefficient of frictional force (static and kinetic friction) through inclined plane After studying this topic, you are expected to be able to:
  • 3. 3 What is Force? Force  PUSH/ PULL  unit: newton (kg.m/s2 ) It is a VECTOR QUANTITY
  • 5. 5
  • 6. 6
  • 7. 7
  • 8. 8 How to deal with forces? Free Body Diagram To keep things simple  only draw forces that acting on the object Example: N Frictional force (f) W
  • 10. 10 A body is pulled in two opposing directions by two ropes as shown in Figure beside. The resultant force acting is the vector sum of the forces. How to calculate forces? Force is Vector, so….  Calculate forces : calculate vectors! Example: If a body is pulled by two perpendicular ropes as in Figure 2.33, then the vector addition is solved using vectors addition.
  • 12. 12 Forces Balanced  Equilibrium
  • 13. 13 Forces Balanced  Equilibrium
  • 14. 14 Forces Balanced  Equilibrium Another example: Separate the vectors into 2 components: x & y If the box is in equilibrium, then: Total component in x = 0  forces left = forces right Total component in y = 0  forces up = forces down
  • 15. 15 Example: Consider the situation below. If the forces on this box are balanced: a) write an equation for the components of the forces parallel to the ramp b) write equation for the forces perpendicular to the ramp c) find the friction (F) & normal force (N)
  • 16. 16 Example: A ball of weight 10 N is suspended on a string and pulled to one side by another horizontal string as shown beside. If the forces are balanced: (a) write an equation for the horizontal components of the forces acting on the ball (b) write an equation for the vertical components of the forces acting on the ball (c) use the second equation to calculate the tension in the upper string, T (d) use your answer to (c) plus the first equation to find the horizontal force F.
  • 17. 17 Example: A rock climber is hanging from a rope attached to the cliff by two bolts as shown in Figure beside. If the forces are balanced a) write an equation for the vertical component of the forces on the knot b) write an equation for the horizontal forces exerted on the knot c) calculate the tension T in the ropes joined to the bolts. The result of this calculation shows why ropes should not be connected in this way.
  • 18. 18 Newton’s Laws of Motion Forces balanced  object is at rest (?) Forces not balanced  object moves (?) How do we explain that with strong argument? Newton’s Laws of Motion 1st Law: A body will remain at rest or moving with constant velocity unless acted upon by an unbalanced force. Net force = 0  no acceleration
  • 21. 21
  • 22. 22
  • 23. 23
  • 24. 24 Constant velocity  Net force = 0
  • 27. 27
  • 28. Application of 1st Law: Seat Belts mechanism 28
  • 29. 29 Note: If the forces are balanced, will the object always be at rest or moving with constant velocity?
  • 30. 30 2nd Law: The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Σ 𝐹 = 𝑚. 𝑎
  • 31. 31
  • 37. 37 Single isolated force can’t exist  Pair of forces on two different objects 3rd Law: If body A exerts a force on body B then body B will exert an equal and opposite force on body A.
  • 38. 38
  • 39. 39
  • 40. CONCEPTUAL EXAMPLE 4-5 I Third Isw clsrfiic@ion. klichclnngzlo's ‹a«sisl‹ant hnr hccn avxigncd thE I:1fik nf mn‹’ing a hI‹›ck ‹›f marhtc using a »Icd (Ftg, 4—I2).He say» to hi6 hu«s,”When T exert n fnr«'.ard f‹›rcc on the rlcd, the xIcd exert» iin cgu:II :ind uppclitc force h:›«kvxtrd. Su huw can I c'cr 1ti!rl it mnving/ Nn m:itt«r hen' hard T gull, thu hackn'ard rc‹actiun fore» always cyuat.r my ft›rv. rd f‹.›r«c, »‹› the net f‹›rce n1uxt he ’/crn. f’Il nc‹'cr hu ithlc tu mnvc thi,s lnad,” I» thi» a ca»e cl a little knnu'Icdge hcing dungereu»"/ Exgl:›in, exerted by assistant a»i»a”nt exerted
  • 41. Example: A car of mass m is on an icy driveway inclined at an angle 30.0o , as in Figure 4.16a. Determine (a) the acceleration of the car, assuming that the incline is frictionless. (b) If the length of the driveway is 20.0 m and the car starts from rest at the top, how long does it take to travel to the bottom? (c) What is the car’s speed at the bottom? 41
  • 42. 42
  • 43. 43 Frictional Force A frictional force  vector sum of many forces acting between the surface atoms of one body and those of another body
  • 44. 44 Types of Frictional Force: Static Friction (fs)
  • 47. 47 Static Frictional Force: fs ≤ s.N Maximum static frictional force:  in verge of slipping fs max = s.N s= coefficient of static friction  depend on the nature of surfaces N = Normal force Kinetic Frictional Force: fk = k.N k= coefficient of kinetic friction
  • 48. 48
  • 49. 49
  • 50. 50
  • 51. 51 Example: 1. The hockey puck in Figure 4.22, struck by a hockey stick, is given an initial speed of 20.0 m/s on a frozen pond. The puck remains on the ice and slides 120 m, slowing down steadily until it comes to rest. Determine the coefficient of kinetic friction between the puck and the ice.
  • 52. 52 Suppose a block with a mass of 2.00 kg is resting on a ramp. If the coefficient of static friction between the block and ramp is 0.30, what maximum angle can the ramp make with the horizontal before the block starts to slip down?
  • 53. 53 A loaded penguin sled weighing 40√2 N rests on a plane inclined at angle  = 45° to the horizontal (Figure beside). Between the sled and the plane, the coefficient of static friction is 0.25, and the coefficient of kinetic friction is 0.15. Determine: a. Maximum static friction between sled and plane. b. Magnitude of the force required in order to make the sled stay at rest, not sliding down the plane. (remember, there are frictional force and weight of object) c. What is the minimum magnitude F that will start the sled moving up the plane? (Hint: draw the force first) d. What value of F is required to move the sled up the plane at constant velocity?
  • 54. 54 A block with mass m1 = 4.00 kg and a ball with mass m2 = 7.00 kg are connected by a light string that passes over a frictionless pulley, as shown in Figure 4.23a. The coefficient of kinetic friction between the block and the surface is 0.300. Find the acceleration of the two objects and the tension in the string.
  • 55. 55