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MATHEMATICS ENHANCEMENT
in NUMERACY THROUGH
ACTIVE LEARNING (MENTAL)
MATH
Dr. Feliculo U. Japona, Jr.,PhD
Binuangan National High School
Multiplication of numbers
Case 1 : Multiplication 2 digit by 2 digit
Example 1. Find the product of 24 and 46.
2
24
x 26
144 partial product
48
624 product
Shortcut method (Pattern 1)
Case 1 : Multiplication 2 digit by 2 digit
Example 1. Find the product of 24 and 46.
2 o o
24 o o 4 X 6 = 24 carry over
x 2 26 o o
624 o o 2x6 = 12 , 2x 4 = 8 => 12 + 8 = 20 + 2 = 22
o o carry over
o o 2x 2 = 4 + 2 = 6
Example 2. Find the product of 57 and 86.
4 o o
57 o o 7 X 6 = 42 carry over
x 9 86 o o
4902 o o 5x6 = 30 , 7x 8 = 56 => 30 +56 = 86 + 4 = 90
o o carry over
o o 5x 8 = 40 + 9 = 49
Example 3. Find the product of 34 and 98.
3 o o
34 o o 4 X 8 = 32 carry over
x 6 98 o o
3332 o o 3x8 = 24 , 4x 9 = 36 => 24 +36 = 60 + 3 = 63
o o carry over
o o 3x 9 = 27 + 6 = 33
Multiplying 3 digit by 3 digit
Example 1. Multiply 234 by 476
Solution : 2 2
2 2 234
1 1 x 476
1404
1638 partial product
936
111384 final product
Shortcut method (Pattern 2)
Case 2 : Multiplication 3 digit by 3 digit
Example 1. Find the product of 234 and 476.
5 4 2 o o o o o o 3 x 6 = 18 carry over
234 o o o 4 X 6 = 24 o o o 4 x 7 = 28 =>18+28=46 +2 = 48
x 3 476 o o o 2 x 6 =12 , 4 x 4 =16 , 3 x 7 = 21 carry over
111384 o o o 12 + 16 +21 = 49 + 4 = 53
o o o 2 x 7 = 14 carry over o o o carry over
o o o 3x 4 = 12=> 14+12= 26 +5 = 31 o o o 2 x 4 = 8 + 3 =11
Example 2. Find the product of 945 and 578.
13 7 4 o o o o o o 4 x 8 = 32 carry over
945 o o o 5 X 8 = 40 o o o 5 x 7 = 35 =>32+35=67 +4 = 71
x 9 578 o o o 9 x 8 =72 , 5 x 5 =25 , 4 x 7 = 28 carry over
546210 o o o 72 + 25 +28 = 125 + 7 = 132
o o o 9 x 7 = 63 carry over o o o carry over
o o o 4 x 5 = 20=> 63+20= 83 +13 = 96 o o o 9 x 5 = 45 + 9 =54
Example 3. Find the product of 632 and 97.
7 4 1 o o o o o o 2 x 9 = 18 carry over
632 o o o 2 X 7 = 14 o o o 3 x 7 = 21 =>18+21=39 +1 = 40
x 6 097 o o o 6 x 7 =42 , 0 x 2 =0 , 3 x 9 = 27 carry over
61304 o o o 42 + 0 + 27 = 69 + 4 = 73
o o o 6 x 9 = 54 carry over o o o carry over
o o o 0 x 3 = 0=> 54+0= 54 +7 = 61 o o o 0 x 6 = 0 + 6 =6
PATTERN
Case 1: 2 digits by 2 digits
o o o o o o
o o o o o o
1 2 1
Case 2: 3 digits by 3 digits
o o o o o o o o o o o o o o o
o o o o o o o o o o o o o o o
1 2 3 2 1
Case 3: 4 digits by 4 digits
o o o o o o o o o o o o o o o o
o o o o o o o o o o o o o o o o
1 2 3 4
o o o o o o o o o o o o
o o o o o o o o o o o o
3 2 1
Squaring 2 digit number
Example 1: What is 26 2
?
Step 1. Square the ten digit number : 2 x 2 = 04
Step 2. Square the one digit number: 6 x 6 = 36
26 2
0436
24
676
Step 3: Multiply tens digits by one digits then double it. 2x6=12 x2 =24
Place under 43 then add. Final answer comes in.
Example 2: What is 94 2 ?
Step 1. Square the ten digit number : 9 x 9 = 81
Step 2. Square the one digit number: 4 x 4 = 16
94 2
8116
72
8836
Step 3: Multiply tens digits by one digits then double it. 9x4=36 x2 =72
Place under 11 then add. Final answer comes in.
Squaring 3 digit number
Example 1: What is 2672 ?
Step 1 : Square the hundred digits: 2 x 2 = 04
Step 2 : Square the ten digits : 6 x 6 = 36
Step 3 : Square the one digits : 7 x 7 = 49
Step 4 : Multiply the one digits by tens digit then double:
6 x7 = 42 x 2 = 84
Step 5:Multiply the ten digits by hundred digits then double:
2 x 6 = 12 x 2 = 24
Arrange them together as shown below:
2672
043649
2484
28
71289
Step 6: Multiply the hundred digits and one digits then double:
2 x 7 = 14 x 2 = 28 place under hundred digits then add.
Example 2: What is 9372 ?
Step 1 : Square the hundred digits: 9 x 9 = 81
Step 2 : Square the ten digits : 3 x 3 = 09
Step 3 : Square the one digits : 7 x 7 = 49
Step 4 : Multiply the one digits by tens digit then double:
7 x3 = 21 x 2 = 42
Step 5:Multiply the ten digits by hundred digits then double:
3 x 9 = 27 x 2 = 54
Arrange them together as shown below:
9372
810949
5442
126
877969
Step 6: Multiply the hundred digits and one digits then double:
9 x 7 = 63 x 2 = 126 place under hundred digits then add.
Multiplying Polynomials
Example 1: Multiply 3x + 2 by 4x-9
Use 1 2 1 pattern:
3x + 2 o o o o o o
4x - 9 o o o o o o
12π‘₯2
-19x -18 2(-9) 3x(-9)+4x(2) 3x(4x)
-27x+8x 12π‘₯2
-19x
Example 2: Multiply 8x - 3 by 5x +10
Use 1 2 1 pattern:
8x - 3 o o o o o o
5x +10 o o o o o o
40π‘₯2 +25x -30 -3(10) 8x(10)+5x(-3) 8x(5x)
40x-15x 40π‘₯2
25x
Example 3: Multiply 4π‘₯2
-5x -2 by 3π‘₯2
+6x + 1
Use 1 2 3 2 1 pattern:
4π‘₯2
-5x - 2 o o o o o o o o o
3π‘₯2
+6x + 1 o o o o o o o o o
12π‘₯4
+9π‘₯3
-32π‘₯2
-17x -2 -2(1) (-5x)(1)+6x(-2) 4π‘₯2
(1)+ 3π‘₯2
(-2) +(-5x)(6x)
-5x-12x 4π‘₯2
βˆ’6π‘₯2
- 30π‘₯2
-17x - 32π‘₯2
o o o o o o
o o o o o o
4π‘₯2
(6x)+ 3π‘₯2
(-5x) 4π‘₯2
( 3π‘₯2
)
24π‘₯3
βˆ’ 15 π‘₯3
12π‘₯4
9π‘₯3
Example 4: Multiply 2π‘₯2
+3x +5 by π‘₯2
-x + 1
Use 1 2 3 2 1 pattern:
2π‘₯2
+3x + 5 o o o o o o o o o
π‘₯2
- x + 1 o o o o o o o o o
12π‘₯4
+9π‘₯3
-32π‘₯2
-17x -2 -2(1) (-5x)(1)+6x(-2) 4π‘₯2
(1)+ 3π‘₯2
(-2) +(-5x)(6x)
-5x-12x 4π‘₯2
βˆ’6π‘₯2
- 30π‘₯2
-17x - 32π‘₯2
o o o o o o
o o o o o o
4π‘₯2
(6x)+ 3π‘₯2
(-5x) 4π‘₯2
( 3π‘₯2
)
24π‘₯3
βˆ’ 15 π‘₯3
12π‘₯4
9π‘₯3

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MATHEMATICS ENHANCEMENT in NUMERACY THROUGH ACTIVE LEARNING ( - Copy.pptx

  • 1. MATHEMATICS ENHANCEMENT in NUMERACY THROUGH ACTIVE LEARNING (MENTAL) MATH Dr. Feliculo U. Japona, Jr.,PhD Binuangan National High School
  • 2. Multiplication of numbers Case 1 : Multiplication 2 digit by 2 digit Example 1. Find the product of 24 and 46. 2 24 x 26 144 partial product 48 624 product
  • 3. Shortcut method (Pattern 1) Case 1 : Multiplication 2 digit by 2 digit Example 1. Find the product of 24 and 46. 2 o o 24 o o 4 X 6 = 24 carry over x 2 26 o o 624 o o 2x6 = 12 , 2x 4 = 8 => 12 + 8 = 20 + 2 = 22 o o carry over o o 2x 2 = 4 + 2 = 6
  • 4. Example 2. Find the product of 57 and 86. 4 o o 57 o o 7 X 6 = 42 carry over x 9 86 o o 4902 o o 5x6 = 30 , 7x 8 = 56 => 30 +56 = 86 + 4 = 90 o o carry over o o 5x 8 = 40 + 9 = 49
  • 5. Example 3. Find the product of 34 and 98. 3 o o 34 o o 4 X 8 = 32 carry over x 6 98 o o 3332 o o 3x8 = 24 , 4x 9 = 36 => 24 +36 = 60 + 3 = 63 o o carry over o o 3x 9 = 27 + 6 = 33
  • 6. Multiplying 3 digit by 3 digit Example 1. Multiply 234 by 476 Solution : 2 2 2 2 234 1 1 x 476 1404 1638 partial product 936 111384 final product
  • 7. Shortcut method (Pattern 2) Case 2 : Multiplication 3 digit by 3 digit Example 1. Find the product of 234 and 476. 5 4 2 o o o o o o 3 x 6 = 18 carry over 234 o o o 4 X 6 = 24 o o o 4 x 7 = 28 =>18+28=46 +2 = 48 x 3 476 o o o 2 x 6 =12 , 4 x 4 =16 , 3 x 7 = 21 carry over 111384 o o o 12 + 16 +21 = 49 + 4 = 53 o o o 2 x 7 = 14 carry over o o o carry over o o o 3x 4 = 12=> 14+12= 26 +5 = 31 o o o 2 x 4 = 8 + 3 =11
  • 8. Example 2. Find the product of 945 and 578. 13 7 4 o o o o o o 4 x 8 = 32 carry over 945 o o o 5 X 8 = 40 o o o 5 x 7 = 35 =>32+35=67 +4 = 71 x 9 578 o o o 9 x 8 =72 , 5 x 5 =25 , 4 x 7 = 28 carry over 546210 o o o 72 + 25 +28 = 125 + 7 = 132 o o o 9 x 7 = 63 carry over o o o carry over o o o 4 x 5 = 20=> 63+20= 83 +13 = 96 o o o 9 x 5 = 45 + 9 =54
  • 9. Example 3. Find the product of 632 and 97. 7 4 1 o o o o o o 2 x 9 = 18 carry over 632 o o o 2 X 7 = 14 o o o 3 x 7 = 21 =>18+21=39 +1 = 40 x 6 097 o o o 6 x 7 =42 , 0 x 2 =0 , 3 x 9 = 27 carry over 61304 o o o 42 + 0 + 27 = 69 + 4 = 73 o o o 6 x 9 = 54 carry over o o o carry over o o o 0 x 3 = 0=> 54+0= 54 +7 = 61 o o o 0 x 6 = 0 + 6 =6
  • 10. PATTERN Case 1: 2 digits by 2 digits o o o o o o o o o o o o 1 2 1 Case 2: 3 digits by 3 digits o o o o o o o o o o o o o o o o o o o o o o o o o o o o o o 1 2 3 2 1
  • 11. Case 3: 4 digits by 4 digits o o o o o o o o o o o o o o o o o o o o o o o o o o o o o o o o 1 2 3 4 o o o o o o o o o o o o o o o o o o o o o o o o 3 2 1
  • 12. Squaring 2 digit number Example 1: What is 26 2 ? Step 1. Square the ten digit number : 2 x 2 = 04 Step 2. Square the one digit number: 6 x 6 = 36 26 2 0436 24 676 Step 3: Multiply tens digits by one digits then double it. 2x6=12 x2 =24 Place under 43 then add. Final answer comes in.
  • 13. Example 2: What is 94 2 ? Step 1. Square the ten digit number : 9 x 9 = 81 Step 2. Square the one digit number: 4 x 4 = 16 94 2 8116 72 8836 Step 3: Multiply tens digits by one digits then double it. 9x4=36 x2 =72 Place under 11 then add. Final answer comes in.
  • 14. Squaring 3 digit number Example 1: What is 2672 ? Step 1 : Square the hundred digits: 2 x 2 = 04 Step 2 : Square the ten digits : 6 x 6 = 36 Step 3 : Square the one digits : 7 x 7 = 49 Step 4 : Multiply the one digits by tens digit then double: 6 x7 = 42 x 2 = 84 Step 5:Multiply the ten digits by hundred digits then double: 2 x 6 = 12 x 2 = 24
  • 15. Arrange them together as shown below: 2672 043649 2484 28 71289 Step 6: Multiply the hundred digits and one digits then double: 2 x 7 = 14 x 2 = 28 place under hundred digits then add.
  • 16. Example 2: What is 9372 ? Step 1 : Square the hundred digits: 9 x 9 = 81 Step 2 : Square the ten digits : 3 x 3 = 09 Step 3 : Square the one digits : 7 x 7 = 49 Step 4 : Multiply the one digits by tens digit then double: 7 x3 = 21 x 2 = 42 Step 5:Multiply the ten digits by hundred digits then double: 3 x 9 = 27 x 2 = 54
  • 17. Arrange them together as shown below: 9372 810949 5442 126 877969 Step 6: Multiply the hundred digits and one digits then double: 9 x 7 = 63 x 2 = 126 place under hundred digits then add.
  • 18. Multiplying Polynomials Example 1: Multiply 3x + 2 by 4x-9 Use 1 2 1 pattern: 3x + 2 o o o o o o 4x - 9 o o o o o o 12π‘₯2 -19x -18 2(-9) 3x(-9)+4x(2) 3x(4x) -27x+8x 12π‘₯2 -19x
  • 19. Example 2: Multiply 8x - 3 by 5x +10 Use 1 2 1 pattern: 8x - 3 o o o o o o 5x +10 o o o o o o 40π‘₯2 +25x -30 -3(10) 8x(10)+5x(-3) 8x(5x) 40x-15x 40π‘₯2 25x
  • 20. Example 3: Multiply 4π‘₯2 -5x -2 by 3π‘₯2 +6x + 1 Use 1 2 3 2 1 pattern: 4π‘₯2 -5x - 2 o o o o o o o o o 3π‘₯2 +6x + 1 o o o o o o o o o 12π‘₯4 +9π‘₯3 -32π‘₯2 -17x -2 -2(1) (-5x)(1)+6x(-2) 4π‘₯2 (1)+ 3π‘₯2 (-2) +(-5x)(6x) -5x-12x 4π‘₯2 βˆ’6π‘₯2 - 30π‘₯2 -17x - 32π‘₯2 o o o o o o o o o o o o 4π‘₯2 (6x)+ 3π‘₯2 (-5x) 4π‘₯2 ( 3π‘₯2 ) 24π‘₯3 βˆ’ 15 π‘₯3 12π‘₯4 9π‘₯3
  • 21. Example 4: Multiply 2π‘₯2 +3x +5 by π‘₯2 -x + 1 Use 1 2 3 2 1 pattern: 2π‘₯2 +3x + 5 o o o o o o o o o π‘₯2 - x + 1 o o o o o o o o o 12π‘₯4 +9π‘₯3 -32π‘₯2 -17x -2 -2(1) (-5x)(1)+6x(-2) 4π‘₯2 (1)+ 3π‘₯2 (-2) +(-5x)(6x) -5x-12x 4π‘₯2 βˆ’6π‘₯2 - 30π‘₯2 -17x - 32π‘₯2 o o o o o o o o o o o o 4π‘₯2 (6x)+ 3π‘₯2 (-5x) 4π‘₯2 ( 3π‘₯2 ) 24π‘₯3 βˆ’ 15 π‘₯3 12π‘₯4 9π‘₯3