Here I have a function in my code that checks the separation of airc.pdf

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Here I have a function in my code that checks the separation of aircraft when called and returns either no separation issues if the predicted paths of all other aircraft (stored in an expandable array) does not intersect with the minimum distance circle around the current one when comparing their relative position and velocity. it doesn't work though and I'm really confused as to what is wrong. I can send the rest of the code through if required void check_separation(ADSBPacket *plane, int planes_info) { int num = -1; for(int i = 0; i < planes_info; i++) { if(plane[planes_info].id == plane[i].id) { num = i; break; } } int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[num].speed * time_change / 1000; double angle = plane[num].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[num].north + north_change; plane[planes_info].east = plane[num].east + east_change; plane[planes_info].heading = plane[num].heading; for(int i = 0; i < planes_info; i++) { int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[i].speed * time_change / 1000; double angle = plane[i].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[i].north + north_change; plane[planes_info].east = plane[i].east + east_change; plane[planes_info].heading = plane[num].heading; double delta_p_north = plane[planes_info].north - plane[num].north; double delta_p_east = plane[planes_info].east - plane[num].east; double delta_v_north = (plane[planes_info].speed * sin(plane[i].heading)) - (plane[num].speed * sin(plane[i].heading)); double delta_v_east = (plane[planes_info].speed * cos(plane[i].heading)) - (plane[num].speed * cos(plane[i].heading)); double a = (delta_v_east * delta_v_east) + (delta_v_north * delta_v_north); double b = 2 * ((delta_v_north * delta_p_north) + (delta_v_east * delta_p_east)); double separation = 100; double c = (delta_p_north * delta_p_north) + (delta_p_east + delta_p_east) - (separation * separation); if((b * b)- (4 * a * c) >= 0) { printf("Separation issue\n"); break; } } printf("No separation issues\n"); }.

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$Here I have a function in my code that checks the separation of aircraft when called and returns either no separation issues if the predicted paths of all other aircraft (stored in an expandable array) does not intersect with the minimum distance circle around the current one when comparing their relative position and velocity. it doesn't work though and I'm really confused as to what is wrong. I can send the rest of the code through if required void check_separation(ADSBPacket *plane, int planes_info) { int num = -1; for(int i = 0; i < planes_info; i++) { if(plane[planes_info].id == plane[i].id) { num = i; break; } } int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[num].speed * time_change / 1000; double angle = plane[num].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[num].north + north_change; plane[planes_info].east = plane[num].east + east_change; plane[planes_info].heading = plane[num].heading; for(int i = 0; i < planes_info; i++) { int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[i].speed * time_change / 1000; double angle = plane[i].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[i].north + north_change; plane[planes_info].east = plane[i].east + east_change;$

$plane[planes_info].heading = plane[num].heading; double delta_p_north = plane[planes_info].north - plane[num].north; double delta_p_east = plane[planes_info].east - plane[num].east; double delta_v_north = (plane[planes_info].speed * sin(plane[i].heading)) - (plane[num].speed * sin(plane[i].heading)); double delta_v_east = (plane[planes_info].speed * cos(plane[i].heading)) - (plane[num].speed * cos(plane[i].heading)); double a = (delta_v_east * delta_v_east) + (delta_v_north * delta_v_north); double b = 2 * ((delta_v_north * delta_p_north) + (delta_v_east * delta_p_east)); double separation = 100; double c = (delta_p_north * delta_p_north) + (delta_p_east + delta_p_east) - (separation * separation); if((b * b)- (4 * a * c) >= 0) { printf("Separation issuen"); break; } } printf("No separation issuesn"); }$

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Exchange Rate Determination Theory: Overshooting Exchange rate overshooting refers to the process in which the movement of the exchange rate reacts more than the long-term equilibrium state in the short run when a currency volume shock occurs. Answer the following questions. (1) Illustrate and explain the short-term and long-term effects of the increase in the home country's money supply on the local currency volume, the local interest rate, and the exchange rate (the Korean won's exchange rate against the dollar) in a two-country model in which both countries (Korea) and foreign (US) exist. (2) In the problem above (1), picture the movement of nominal currency volume, price level, interest rate, exchange rate, and real currency volume over time (i.e., time path) after the domestic currency volume was moderate..

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Hello. I need help with my assignment. Translate the ER Diagram for the Animal Pet Rescue Database Entities: Donator DonatorID (Primary Key) Name Address Phone Number Email 2. Pet PetID (Primary Key) Name Type Age DonatorID (Foreign Key) 3. Staff StaffID (Primary Key) Name Email Phone Number Employee Number CenterID (Foreign Key) 4. Center CenterID (Primary Key) Name Location Phone Contact Person Email 5. Rescuer RescuerID Primary Key) Name Email Phone Number Home Address Internal ID 6. Transportation TransportationID (Primary Key) Vehicle Type Pickup Point Delivery Point 7. Pickup Schedule PickupID (Primary Key) DonatorID (Foreign Key) StaffID (Foreign Key) TransportationId (Foreign Key) Pickup Date Time 8. Delivery Schedule DeliveryID (Primary Key) RescuerID (Foreign Key) StaffID ( Foreign Key) TransportID (Foreign Key) Delivery Date Time Relationships: Donator to pet (One-to-many): One donor can donate multiple Pets. Pet has a foreign Key (DonatorID) to link to the Donator. Center to Staff (One-to -Many): One Center can have multiple staff members. Staff has a foreign key (CenterID) to link to the center. Rescuer to pickup Schedule(One-to-Many): One rescuer can be scheduled for multiple pickups. Pickup Schedule has a foreign key (RescuerID) to link to the Rescuer. Staff to pickup Schedule One-to-Many): One Staff member can schedule multiple pickups. Pickup Schedule has a Foreign Key (StaffID) to link to the staff. Transport to Pickup Schedule(One-to-many): One Transportation can be associated with multiple pickups. Pickup Schedule has a foreign key (TransportID) to link to the Transportation. Rescuer to Delivery Schedule (One-to-Many): One rescuer can be scheduled for multiple deliveries. Delivery schedule has a foreign key (RescuerID) to link to the rescuer. Staff to Delivery Schedule(One-to-Many): One Staff member can schedule multiple deliveries. Delivery schedule has a foreign key (StaffID) to link to the staff. Transport to Delivery Schedule (One-to-Many): One Transportation can be associated with multiple deliveries. Delivery Schedule has a Foreign Key (TransportID)to link to the Transportation..

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1. Here I have a function in my code that checks the separation of aircraft when called and returns either no separation issues if the predicted paths of all other aircraft (stored in an expandable array) does not intersect with the minimum distance circle around the current one when comparing their relative position and velocity. it doesn't work though and I'm really confused as to what is wrong. I can send the rest of the code through if required void check_separation(ADSBPacket *plane, int planes_info) { int num = -1; for(int i = 0; i < planes_info; i++) { if(plane[planes_info].id == plane[i].id) { num = i; break; } } int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[num].speed * time_change / 1000; double angle = plane[num].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[num].north + north_change; plane[planes_info].east = plane[num].east + east_change; plane[planes_info].heading = plane[num].heading; for(int i = 0; i < planes_info; i++) { int original_time = (plane[num].hours * 3600) + (plane[num].minutes * 60); int new_time = (plane[planes_info].hours * 3600) + (plane[planes_info].minutes * 60); int time_change = new_time - original_time; double distance = plane[i].speed * time_change / 1000; double angle = plane[i].heading * M_PI / 180; double east_change = distance * cos(angle); double north_change = distance * sin(angle); plane[planes_info].north = plane[i].north + north_change; plane[planes_info].east = plane[i].east + east_change;

2. plane[planes_info].heading = plane[num].heading; double delta_p_north = plane[planes_info].north - plane[num].north; double delta_p_east = plane[planes_info].east - plane[num].east; double delta_v_north = (plane[planes_info].speed * sin(plane[i].heading)) - (plane[num].speed * sin(plane[i].heading)); double delta_v_east = (plane[planes_info].speed * cos(plane[i].heading)) - (plane[num].speed * cos(plane[i].heading)); double a = (delta_v_east * delta_v_east) + (delta_v_north * delta_v_north); double b = 2 * ((delta_v_north * delta_p_north) + (delta_v_east * delta_p_east)); double separation = 100; double c = (delta_p_north * delta_p_north) + (delta_p_east + delta_p_east) - (separation * separation); if((b * b)- (4 * a * c) >= 0) { printf("Separation issuen"); break; } } printf("No separation issuesn"); }

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