Heart Disease Prediction using machine learning.pptx
Fundamentals of power system
1. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Chapter-1
Fundamentals of Power System
Introduction:
The waveform of voltage at the buses of a power system can be assumed to be
purely sinusoidal and of constant frequency. In developing most of the theory in this
subject we will concerned with the phasor representations of sinusoidal voltages and
currents and use the capital letters V and I to indicate these phasor (with appropriate
subscripts where required). Vertical bars enclosing V & I designated the magnitudes of
the phasor. Lowercase letters are usually indicates instantaneous values.
Single-Subscript Notation:
The single-subscript notation Va specifies the voltage at point a with respect to ground
(zero volts). If the voltage is less than zero volts, a negative sign must be associated
with the magnitude of Va.
In Fig.1, Va is the voltage from point a to ground. Va = 10 V since it is right across the
source voltage E. The voltage Vb is the voltage from point b to ground. Vb = 4 V.
Fig.1: Defining the use of single subscript notation for voltage levels.
Double subscript Notation:
The double subscript notation Vab specifies point a as the higher potential. If this is
not the case, a negative sign must be associated with the magnitude of Vab.
In Fig. the two points that define the voltage across the resistor R are denoted by Vab.
Since a is the first subscript for Vab, point a must have a higher potential than point b
if Vab is to have a positive value. If in fact point b Is at a higher potential than point a,
Vab will have a negative value.
Power in 1-phase AC Circuits:
Electrical power is the “rate” at which energy is being consumed in a circuit. Electrical
power can be time-varying either as a DC quantity or as an AC quantity. The amount
of power in a circuit at any instant of time is called the instantaneous power.
2. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
For DC circuit,
Where: V is the dc voltage, I is the dc current and R is the value of the resistance.
For AC circuit,
Complex Power:
Complex power is “the complex sum of real and reactive powers”. It is also termed as
apparent power, measured in terms of Volt Amps (or) in Kilo Volt Amps (kVA). The
rectangular power of complex power is given below:
Where, S is complex or apparent power, P is real power measured in terms of Watts
and Q is reactive power measured in terms of Volt Amps Reactive (generally in kVAR).
The polar form of complex power is given below:
In addition, the complex power for transformer can be written as, S=VI. The complex
power for transmission lines is, S=VI*, where I* is complex conjugate of current. The
magnitude of the complex power is the apparent power.
The Power Triangle:
Power Triangle is the representation of a right angle triangle showing the relation
between active power, reactive power and apparent power.
3. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
The power which is actually consumed or utilized in an AC Circuit is called True
power or Active Power or real power. It is measured in kilowatt (kW) or MW. The
power which flows back and forth that means it moves in both the direction in the
circuit or reacts upon it, is called Reactive Power. The reactive power is measured in
kVAR or MVAR. The product of RMS value of voltage and current is known as
Apparent Power. This power is measured in KVA or MVA.
Direction of Power Flow:
Example 1.1. Two ideal voltage sources designated as machines 1 and 2 are
connected, as shown in Fig. If E1 = 100 V, E2 = 100∟30° V, and Z = 0 + j5 Ω,
determine (a) whether each machine is generating or consuming real power and
the amount, (b) whether each machine is receiving or supplying reactive power
and the amount, and (c) the P and Q absorbed by the impedance.
4. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Solution:
Current entering box-1 = -I
Current entering box-2 = I
Reactive power absorbed in the series impedance is
NOTE: Machine-1 may be expected to be a generator because of the current direction
and polarity markings. However, since P1 is positive and Q1 is negative, the machine
consumes energy at the rate of 1000W and supplies reactive power of 268 VAR. The
machine is actually a motor.
Machine-2, expected to be a motor, has negative P2 and negative Q2. Therefore, this
machine generates energy at the rate of 1000W and supplies reactive power of 268
VAR. The machine is actually a generator.
Note that the supplied reactive power of 268 + 268 =536 VAR, which is required by the
inductive reactance of j5Ω. Since the impedance is purely reactive, no P is consumed
by the impedance, and all the watts generated by machine 2 are transferred to
machine 1.
Voltage and Current in Balanced Three Phase Circuits
Star Connection (Y)
5. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Star Connection is obtained by connecting together similar ends of the three coils. The
other ends are joined to the line wires. The common point is called the neutral. Star
Connection, is also called Three Phase 4 wires system. The Voltage between Line and
Neutral is called Phase voltage and the voltage between two Lines is called Line
Voltage.
Star Connection Delta Connection
It is seen from the fig 2 that;
Line voltages are 120° apart from each other
6. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Line voltages are 30° leading from the corresponding phase voltages
The angle Ф between line currents and respective line voltages are (30°+Ф), i.e.
each line current is lagging (30°+Ф) from the corresponding line voltage.
Example 1.2:
A balanced Y-connected load of 8+j6 Ω per phase connected to a balanced 3-
phase 400V supply. Find the line current, power factor, power and total volt
amp.
Solution:
Example 1.3
A balanced three-phase load connected in star consists of (6+8) Ω impedance
in each phase. It is connected to a three phase supply of 400 V, 50 Hz. Find
(i) Phase current (ii) Line current (iii) Per phase power and (iv) Total power.
7. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Per-unit quantities:
The per unit value of any quantity is defined as the ratio of actual value in any unit
and the base or reference value in the same unit.
The per unit value are dimensionless.
Actual Quantity Base Quantity
Voltage, V1
Current, I1
Base Voltage, VB
Base Current, IB
8. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Resistance, R1
Reactance, X1
Active power, P1
Reactive power, Q1
Impedance, Z1
Base Power, SB
Base Impedance, ZB
Out of four base quantity,
SB and VB …….selected base quantity
ZB and IB ………derived base quantity from selected base
For a single-phase system, the following formulas relate the various quantities.
Per unit values
Voltage in pu
Current in pu
Resistance in pu
Reactance in pu
Active power in pu
Reactive power in pu
Impedance in pu
Advantages of per-unit calculation
1. Manufacturers usually specify the impedance of a piece of apparatus in
percent or per-unit on the base of the name plate rating.
2. The per-unit impedances of machines of same type and widely different
rating usually lie within narrow range.
3. For a transformer, when impedance in ohm is specified, it must be clearly
mentioned whether it is with respect to primary or secondary. The per-unit
9. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
impedance of the transformer, once expressed on proper base, is the same
referred to either side.
4. The way in which the three-phase transformers are connected does not
affect the per-unit impedances although the transformer connection does
determine the relation between the voltage bases on the two sides of the
transformer.
5. Calculation using pu system is easier.
Changing the Base in Per- Unit Quantities: (or, Per-unit quantities on a different
base:
From eq.() It is to be noted that the per-unit impedance is directly proportional to base
MVA and inversely proportional to (base kV)2. Therefore, to change from per-unit
impedance on a given base to per-unit impedance on a new base, the following
equation applies:
System-01 System-02
From equation(21) and (22)
Example: 1.4
A three phase 500 MVA, 22 kV generator has winding reactance of 1.065 Ω. Find
its per unit reactance.
Solution:
10. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Example: 1.5
The reactance of a generator is given as 0.25 per-unit based on the generator’s of
18 kV, 500 MVA. Find its per-unit reactance on a base of 20 kV, 100 MVA.
Solution:
Node Equations:
Once the per-unit equivalent circuit is created, it can be used to determine the
voltages, currents, and powers at various points. The most common technique used to
solve such circuits is nodal analysis. To simplify the equations,
Replace the generators by their Norton equivalent circuits
Replace the impedances by their equivalent admittances
Represent the loads by the current they draw (for now)
Kirchhoff’s current flow law (KCL) can be used to establish and solve a system of
simultaneous equations with the unknown node voltages. Assuming that the current
from the current sources are entering each node, and that all other currents are
leaving the node, applying the KCL to the 3 nodes yields
11. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
In matrix from,
………..(25)
Which is an equation of the form:
Where Ybus is the bus admittance matrix of the system. Ybus has a regular form that is
easy to calculate:
The diagonal elements Yii equal the sum of all admittances connected to node i.
Other elements Yij equal to the negative admittances connected to nodes I and j.
The diagonal elements of Ybus are called the self admittance or driving point
admittances of the nodes; the off diagonal elements are called the mutual admittances
or transfer admittances of the nodes.
The Single Line or One Line Diagram:
The single-line diagram is the blueprint for electrical system analysis. It is the first
step in preparing a critical response plan, allowing you to become thoroughly familiar
with the electrical distribution system layout and design in your facility.
Whether you have a new or existing facility, the single-line diagram is the vital
roadmap for all future testing, service and maintenance activities.
Application:
Short circuit calculations
Coordination studies
Load flow studies
Safety evaluation studies
All other engineering studies
Electrical safety procedures
Efficient maintenance
The single line diagram uses single line and symbols to represent the path and the
components of an electrical circuit. These diagrams are specifically use when the
information about the circuit is required but the details of the actual wire connection
and the operation of the circuit are not needed. The single diagram provides an easy
and understanding of the connection and the component.
12. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
Importance of single line diagram
1. Identification of the problem location, in safety conformity and the staff safety can
be benefited by the use of single line diagram.
2. If in any case the inaccuracy in the connection and the failure arises the updation
of the single diagram becomes easy even on the regular basis.
3. The information from one line diagram can be widely used to enhance the
performance of service activities.
4. The single line diagram can be termed as building an electrical system.
Construction of single line diagram
1. As we know that the single line diagram is a simplified way for representing a 3
phase power system, so in case of representing each of the 3 phases with a separate
terminal only one conductor is used to represent it.
2. The electrical elements like transformer, capacitor, circuit breaker, bus bars are
represented by the standard schematic symbols.
3. It is to be noted that the elements portrait on the diagram doesnot represent actual
physical size of the electrical component.
4. The component of the diagram are arranged in the order of the decreasing voltage
level i.e the component with the highest voltage is present at the top right of the
diagram and hence forth.
Impedance and reactance diagram
13. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
In order to calculate the performance of a power system under load condition or upon
the occurrence of a fault, the one line diagram is used to draw the single-phase or per
phase equivalent circuit of the system.
Refer the one-line diagram of a sample power system shown in Fig. 1.4.
Fig.1.9 combines the equivalent circuits for the various components shown in Fig. 1.4
to form the per-phase impedance diagram of the system.
The impedance diagram does not include the current limiting impedances shown in
the one-line diagram because no current flows in the ground under balanced
condition.
Short Questions with answers
14. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
1. What is per unit system? Why it is used for the studies of power system?
Ans: The per unit value of any electrical quantity is defined as the ratio of the actual
value of the quantity to its base value expressed as a decimal.
It is used for the studies of power system due because PU system makes the
calculation refereed to power system simple.
2. List the advantages of per unit computations.
a. The per unit impedance referred to either side of a single phase
transformer is the same.
b. The per unit impedance referred to either side of a three phase
transformer is the same regardless of the three phase connections
whether they are Y-Y, Δ-Δ or Δ-Y
c. The chance of confusion between the line and phase quantities in a three
phase balanced system is greatly reduced.
d. The manufacturers usually provide the impedance values in per unit.
e. The computational effort in power system is very much reduced with the
use of per unit quantities.
3. What is single line diagram in power system and explain its importance?
The single line diagram of a power system is the network which shows the main
connections and arrangement of the system components along with their data (such
as output rating, voltage, resistance and reactance, etc.).
4. Write the equation for converting the per unit impedance expressed in one
base to another.
5. What are various sources of reactive power? Explain its significance.
The sources of reactive power are generators, capacitors, and reactors.
6. A single phase AC voltage of 250 is supplied to a series circuit whose
impedance is 5+j8. Find R,X,P and Q and the power factor of the circuit.
15. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur
7. What is complex power?
Complex power is “the complex sum of real and reactive powers”. It is also termed as
apparent power, measured in terms of Volt Amps (or) in Kilo Volt Amps (kVA). The
rectangular power of complex power is given below:
The polar form of complex power is given below:
In addition, the complex power for transformer can be written as, S=VI. The complex
power for transmission lines is, S=VI*, where I* is complex conjugate of current. The
magnitude of the complex power is the apparent power.
8. What do you mean by reactance diagram of the power system and explain
its importance.
The reactance diagram is the simplified equivalent circuit of power system in which
the various components of power system are represented by their reactances. The
reactance diagram can be obtained from impedance diagram if all the resistive
components are neglected. The reactance diagram is used for fault calculations.
9. What is the need for selecting a base value for pu representation?
The components or various sections of power system may operate at different voltage
and power levels. It will be convenient for analysis of power system if the voltage,
power, current and impedance rating of components of power system are expressed
with reference to a common value called base value.
10. The reactance of a generator is given as 0.25 per-unit based on the
generator’s of 18 kV, 500 MVA. Find its per-unit reactance on a base of 20
kV, 100 MVA.
Solution:
16. Power System Operation & Control, 6th Semester
Prepared by Balaram Das, EE Department, GIET, Gunupur