1. *Corresponding Author: Rao Li, Email: raol@usca.edu
REVIEW ARTICLE
Available Online at www.ajms.in
Asian Journal of Mathematical Sciences 2017; 1(2):65-66
Signless Laplacian Spread and Hamiltonicity of Graphs
1
Rao Li*
1
*Dept. of mathematical sciences University of South Carolina Aiken, Aiken, SC 29801
Received on: 18/02/2017, Revised on: 06/03/2017, Accepted on: 14/03/2017
ABSTRACT
The signless Laplacian spread of a graph G is the difference between the largest and smallest signless
Lapacian eigenvalues of G. Using a result on the signless Laplacian spread obtained by Liu and Liu in
[3], we in this note present a sufficient condition based on the signless Laplacian spread for the
Hamiltonicity of graphs. 2010 Mathematics Subject Classification: 05C50, 05C45.
Keywords : signless Laplacian spread, Hamiltonian properties
INTRODUCTION
We consider only finite undirected graphs without loops or multiple edges. Notation and terminology not
defined here follow those in [1]. For a graph G = (V (G), E(G)), we use n and e to denote its order |V (G)|
and size |E(G)|, respectively. For a subset V1 of V , its average degree is defined as P
v∈V1 d(v)/|V1|. Let
D(G) be a diagonal matrix such that its diagonal entries are the degrees of vertices in a graph G. The
signless Laplacian matrix of a graph G, denoted Q(G), is defined as D(G)+A(G), where A(G) is the
adjacency matrix of G. The eigenvalues of Q(G) are called the signless Laplacian eigenvalues of G. The
signless Laplacian spread of a graph G, denoted by SQ(G), was introduced by Liu and Liu in [3]. It is
defined as the difference between the largest and smallest signless Laplacian eigenvalues of G. A cycle C
in a graph G is called a Hamiltonian cycle of G if C contains all the vertices of G. A graph G is called
Hamiltonian if G has a Hamiltonian cycle. The purpose of this note is to present a sufficient condition
based on the signless Laplacian spread for the Hamiltonicity of graphs. The main result is as follows.
Theorem 1. Let G be a graph of order n, size e, and connectivity κ(κ ≥ 2).
If
,
then G is Hamiltonian.
In order to prove Theorems 1, we need the following result as our lemma. Lemma 1 below is Theorem
2.3 on Page 509 in [3].
Lemma 1. Let G be a connected graph on n ≥ 2 vertices with e edges. Suppose G contains a nonempty
set of t independent vertices, the average degree of which is d0. Then
.
Proof of Theorem 1.
Let G be a graph satisfying the conditions in Theorem 1. Suppose that G is not Hamiltonian. Since κ ≥ 2,
G contains a cycle. Choose a longest cycle C in G and give an orientation on C. Since G is not
Hamiltonian, there exists a vertex x0 ∈ V (G)V (C). By Menger’s theorem, we can find s (s ≥ κ) pairwise