Imagine the next few innovation in network technology, what would it.pdf

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Imagine the next few innovation in network technology, what would it look like and what could it do? Solution In last 10 years there is a huge devolepment in networking technology by using in many ways like optical fibres, internet, next generation networks etc are become more efficient in communicating and transferring data with high quality thus it enhances very largely and showing its market in social activities. There are many changes that are occuring time to time like there are variety of sensors and appliance comes in to existence to make the work free, there are many solutions for unexpected mistakes and errors that are posssibily occuring. moreover the main problem is usage of power is decreased by devoleping a special type of technology which incorporated with this. There are huge amount of increasing smart phones in every hand so there must be a encryption is needed in every hand that it is possible to generate good network topologies so that the energy is needed. Networking will work abnormally when architecture works well when all layers collaborate to combine the various resources available..

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Firefly luciferase is a commonly used reporter gene. The gene originates from fireflies (a type of beetle) and when it combines with its substrate, luciferin, light is produced. Luciferin is very expensive to purchase. You would therefore like to figure out the biosynthetic pathway for making luciferin so that you can get bacteria to make luciferin. This will enable you pay off all your college loans! You have obtained 5 mutant firefly stocks that each fail to glow at night. The flies in each stock have the wild type luciferase gene but ultimately fail to make the luciferin substrate. Each stock has a unique mutation in one of the genes required to make luciferin. You know that the biosynthesis of luciferin involves 5 intermediate compounds: A, B, C, D, and E. However, you do not know the order that these compounds appear in the pathway. When you feed these intermediate compounds to the mutant fireflies, they sometimes are able glow (+) and sometimes still cannot glow (-). However, when you feed the mutant fireflies luciferin, they always glow. Based on the results in the table above, write the biosynthetic pathway for luciferin, showing the order of the intermediates (A-E) and the genes (M1-M5) required to convert each intermediate to the next in the pathway. Solution This is a probem, where in you can get the answer by the means of trial and error. Now that we have all pieces to this puzzle, lets join them. E>B>D>C>A this is the pathway in the production of Luciferase..

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Arrowdeepak

Find all hazards in this circuit. Redesign the circuit as a three-level NOR circuit that is free of all hazards Show how four 2-to-1 and one 4-to-1 multiplexers could be connected to form an 8- to-1 MUX with three control inputs Solution 1 University of Wisconsin - Madison ECE/Comp Sci 352 Digital Systems Fundamentals Charles R. Kime Section 2 – Fall 2001 Chapter 2 – Combinational Logic Circuits – Part 7 Charles Kime & Thomas Kaminski © 2001 Prentice Hall, Inc Logic and Computer Design Fundamentals Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 2 NAND and NOR Implementation We found that we could implement general Boolean equations with these three primitives: • AND • OR • NOT In this section we will find that either of two gates, the NAND gate or the NOR gate can be used to implement arbitrary logic functions. We use the Positive Logic Convention (where all signals are active high) and a small circle to on a symbol to represent NOT or invert. 2 Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 3 NAND Gates The basic positive logic NAND gate is denoted by the following symbol: • AND-Invert (NAND) NAND comes from NOT AND, I. e., the AND function with a NOT applied. We call this symbol for a NAND gate an AND-Invert. The small circle represents the invert function. If we apply DeMorgan\'s Law we get: X Y Z X YZ = X + Y + Z F(X, Y,Z) = X Y Z Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 4 NAND Gates (Cont.) Applying DeMorgan\'s Law gives: • Invert-OR (NAND) We call this symbol for a NAND gate the Invert - OR since all inputs are inverted, followed by the OR function. Both symbols represent the NAND gate - it is sometimes more logically descriptive to use one form over the other. A NAND gate with one input degenerates to an inverter. X Y Z F(X, Y,Z) = X + Y + Z 3 Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 5 NAND Function Implementation NAND gates can implement a simplified Sum-ofProducts form. Constructing two level NAND-NAND gate circuit: The first level is two 2-input NAND gates using ANDInvert. The second level is one 2- input NAND gate using Invert-OR. Using the NAND relationship, we have: G(A,B,C,D) = AB CD = AB + CD = A B + CD A B C D G(A,B,C,D) = AB + CD Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 6 NAND Implementation (Cont.) In the implementation, note that the bubbles are on opposite ends of the same line. Thus, they can be combined and deleted: A B C D G(A,B,C,D) This form of the implementation is the Sum-of- Products form. 4 Logic and Computer Design Fundamentals © 2001 Prentice Hall, Inc Chapter 2-Part 7 7 NAND Implementation (Cont.) In the implementation, the bubbles are on opposite ends of the same line. By , they can be combined and deleted: A sum-of-products (SOP) form results To implement an equation like: F(A,B,C) = A + BC, the NAND for A degenerates t.

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Fergie has the choice between investing in State of New York bond at 10.2 percent and a Surething bond at 11.5 percent. Assuming that both bonds have the same nontax characteristics and that Fergie has a 30 percent marginal tax rate, in which bond should she invest? Solution After tax rate of return for Surething bond =11.5(1-0.3)=8.05% Hence since State of New York bond has a higher rate of return;State of New York bond bond must be invested upon..

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Arrowdeepak

Explain the “life” of a secreted protein molecule - trace the pathway in a cell by which a secreted protein, such as an antibody, would be produced in an animal cell, starting in the nucleus. Solution Cells secrete proteins for their own cytosol or for release into surrounding extracellular fluid. These secretions may include various hormones, digestive enzymes, antibodies, mucus etc. The transcription process (conversion of DNA to mRNA) occurs inside the nucleus. This newly formed mRNA is translated into proteins in the cytosol at cellular structures called ribosomes.the ribosome remains in the cytosol if the protein has to be used within the cell, whereas if it is destined for secretion outside the cell, the signal sequence (first few amino acids) is synthesized on the ribosome and then the ribosome docks at the rough endoplasmic reticulum (RER) for completion of protein synthesis. Proteins enter and cross endoplasmic recticulum (ER) membrane co-translationally (i.e., they cross ER during synthesis of polypeptide). In the lumen of ER, proteins undergo glycosylation and molecular chaperones aid in the process of protein folding. Misfolded proteins are retrotranslocated to the cytosol, where they are degraded by a proteasome action. The vesicles with correctly folded proteins then enter the golgi appratus where further posttranslational modifications occur including cleavage and functionalization. When the protein moves through the entire Golgi apparatus, it buds off as secretion vesicles. Now, with the help of cell\'s cytoskeleton, it moves towards the edge of the cell and attaches itself to the membrane. Eventually, vesicle fuses with the cell membrane releasing its contents out of the cell through the process of exocytosis. This secretion pathway is followed for all protein molecules including antibodies..

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Arrowdeepak

7. Using to Table 1 to assist you, explain the rational for the diversity of the mycobiome, as compared to the number of bacterial species identified in the lungs of CF patients. This should be a full paragraph, not one or two sentences. Solution From the tabulated data given, it can be clearly noticed that majority of the population suffers from ascomycete infections. Particularly, the most infectious species can be identified as Candida albicans followed by C. dubliniensis. Saccharomyces cerevisiae infections are also very high followed by C. parapsilosis and C. glabrata. Other types of infections are also evident in patients but these organisms remain the most frequent infective agents for patients with cystic fibrosis. Since all of these microbes spread the disease from one organism to another, they are highly communicable in nature. Also, since very high frequency of some of the species can be noticed from the data, it is also suggested that the infections are opportunistic in nature i.e. they will infect the individual as soon as his immunity against these microbes is minimized. Importantly, since a huge population is suffering form nearly similar kind of infections, it can be suggested that fixation of these microbial infections is possible in this population which can be clinically deleterious in advanced stages because eradication of these microbes using multiple antibiotic treatment would be difficult. Hence, it can be evaluated from the data that the statisitical figures are clinically alarming and demand immediate attention..

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Arrowdeepak

A. list two vertebrae that spinal nerve t12 travels between B. Define the function of ground substance in connective tissue proper. A. list two vertebrae that spinal nerve t12 travels between B. Define the function of ground substance in connective tissue proper. B. Define the function of ground substance in connective tissue proper. Solution A. Two vertebrae that spinal nerve t12 travels between are-cervical spine vertebrae and lumbar spine vertebrae B. Groud substance is an amorphous gel-like substance present in the connective tissue proper, which surrounds the cells. Glycoproteins and Hydrophilic muco-polysacharides present in the ground substance attract water to induce variation in viscosity. Groud substance of all connective tissue proper make intimate contact with the cells. Hence, these cells doesnot occupy distinct space within the matrix..

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Do people from different cultures experience emotions differently? One study designed to examine this question collected data from 411 college students from five different cultures. The participants were asked to record, on a 1 (never) to 7 (always) scale, how much of the time they typically felt eight specific emotions. These were averaged to produce the global emotion score for each participant. Here is a summary of this measure: Note that the convention of giving the standard deviations in parentheses after the means saves a great deal of space in a table such as this. (a) The ANOVA F statistic was reported as 5.57. Give the degrees of freedom and either an approximate (from Table E) or an exact (from software) P- value. Sketch a picture of the F distribution that illustrates the P-value. (Round your P-value to four decimal places.) What do you conclude? We have strong evidence at the 5% level that the means are not all the same. We have no evidence at the 5% level that the means are different. (b) Without doing any additional formal analysis, describe the pattern in the means that appears to be responsible for your conclusion in part (a). Are there pairs of means that are quite similar? European Americans have the highest emotion scores, Indians are in the middle, and the other three cultures are lowest. Hispanic Americans have the highest emotion scores, Japanese are in the middle, and the other three cultures are lowest. Japanese have the highest emotion scores, Hispanic Americans are in the middle, and the other three cultures are lowest. Asian Americans have the highest emotion scores, Japanese are in the middle, and the other three cultures are lowest. European Americans have the highest emotion scores, Hispanic Americans are in the middle, and the other three cultures are lowest. Culture n Mean (s)European American Asian American Japanese Indian Hispanic American48 32 91 160 804.39 (1.01) 4.35 (1.18) 4.71 (1.13) 4.34 (1.26) 5.04 (1.16) Solution (a) numerator df= 5-1=4 denominator df = 48+32+91+160+80-5 =406 P-value = P(F with df=4 and df=406 >5.57 ) =0.0002 (from F table) We have strong evidence at the 5% level that the means are not all the same. --------------------------------------------------------------------------------------------------------- (b)Hispanic Americans have the highest emotion scores, Japanese are in the middle, and the other three cultures are lowest..

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1. Please explain: 1. What is cosolidation of a soi? 2. What are the assumptions for 1-D consoildation theory proposed by Kar Terzaghi? 3. Compared to compaction, what are the difference? 4. How do you define the process of a soil consolidation? 2. For settlements, what are the major components of a soil settlment? What is the difference between between settlment in sands and clays, please describe the details. Solution 1) Consolidation is the reduciton of soil volume by expulsion of pore water. 2) assumptions: 3) Compaction is expulsion of air and consolidation is expulsion of water. 4) Process of soil consolidation is not instataneous. It ia time taking process..

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Arrowdeepak

What type of gametes did Sutton predict? Mendel? (parental, recombinant, both) Solution 1. According to Mendel’s law of segregation : 2 . The Chromosomal Theory of Inheritance (Theodor Boveri and Walter Sutton --1903) was consistent with Mendel\'s laws and the basic postulates were: -----------------------These lead to the conclusion that both Sutton and Mendel predicted parental types of gametes because in case of parental type , gametes are produced in equal proportion but recombinant type produces gametes in unequal proportions. Besides this , In 1911, after observing that linked traits could on occasion be inherited separately, Thomas Hunt Morgan suggested that \"crossovers\" can occur between linked genes and crossover is the prime reason for recombination.

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Arrowdeepak

With reference to Barth (2014), discuss how the author assessed the extent to which unmodified historical cost, modified historical cost, and fair value measurement possess the qualitative characteristics specified in the IFRS Conceptual Framework. Solution The conceptual framework in IFRS states the qualitative characteristics of the financial statements to be useful which are as follows: 1. Fundamental : Fundamental qualitative characteristics are relevance and faithful representation. 2. Enhancing: Enhancing qualitative characteristics are comparability, completeness, verifiablity and understandability. According to Barth(2014), Historical cost does not possess the qualitative characteristics of the IFRS conceptual framework as it does not facilitates comparability and relevance but yes it is sometimes relevant. The historical cost should be modified to use in financial statements, it should be indexed for Inflation. Modified historical cost possess the qualitative characteristics of the IFRS. It is understandable, complete, accurate, but not considered as faithful representation. This is widely used but both modified historical cost and unmodified historical cost lack meaning. Whereas the Fair value presentation is more consistent with the new framework and hence it should be widely used. This paper concludes that assets and liabilities at large should be measured at fair value to provide the financial statements with the qualitative characteristics..

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1. Peter Grant - the evolutionary biologist who has studied finches on Daphne Major (an island in the Galapagos) for several decades - collected data on birds\' beak sizes, weight, diet and mating behavior to test his hypotheses. This kind of data is an example of: 2. In the video \"How Does Evolution Really Work?\", biologists described an example where the length of individual hummingbird beaks grew longer in response to changes in their food source (flowers). True False 3 The observation that the individuals possessing favorable traits are more likely to survive and reproduce than those possessing less favorable traits is the basis for: 4. Which one of the following descriptions, pertaining to a scientific hypothesis or theory, is NOT true? 5. Which of the following is involved in the scientific method (MARK ALL THAT APPLY)? making observations 6. Due to ___________________, \"bad science” (e.g. fake data or fake results) is eventually discovered and revealed. powerful police forces 7. Darwin\'s Hypothesis of Evolution by Natural Selection included the observation that populations often grow faster than the food supply and therefore individuals need to compete for resources. Darwin borrowed this idea from the work of: 8. Lamarck\'s \"Inheritance of Acquired Characteristics\" can best be described as: disease and starvation are required to keep population size in check 9. Aristotle and other early philosophers believed that species were \"immutable\" or \"fixed\", which means: species are always changing species don\'t change over timeA.taxonomy B.artificial selectionC.empirical evidenceD.non-factual informationE.a belief Solution 1)B)Artificial Selection as it tells about the way birds survive and their mating. 2)True yes it is rightly stated. 3)D)Natural selection which says traits move from one generation to other. and the ones with more traits survive more than other here. 4)E)it must deal with evidence that is empirical (i.e. the kind that can be observed).

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If a researcher rejects a null hypothesis when that hypothesis is actually true, he has committed: a type I error a type II error a type III error no error a type I error a type II error a type III error no error Solution If a researcher rejects a null hypothesis when that hypothesis is actually true, he has committed: a type I error a type II error a type III error no error A type I error is the incorrectly rejecting a true null hypothesis. a type I error a type II error a type III error no error.

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Arrowdeepak

Write an algorithm that reads a list of integers from the keyboard, creates a list of them using linked list implementation, and prints the result Solution /* Algorithm: Implementation of linked list. Create a node type class which will hold an integer and next pointer to point to another node. Create a constructor which will construct an object of type node with the integer type data as the only parameter and initializing next pointer to NULL. Create LinkedList class which will only have head pointer. Create a constructor which will initialize this head pointer to NULL. Create a append method which will recieve an input of type integer from the user and append it to LinkedList using below steps: 1.Create a Node type object. 1.IF head is NULL assign a Node type object created in 1st step. 2.IF head is not NULL then traverse to the end of the linked list till you found a Node which has next pointer set to NULL. 3.Add Node type object created in first step to the next pointer of last node. Create a print method which will traverse the list from the head of the linked list to the last node(Node with next pointer NULL) and while traversing it will keep printing the node data. Get the userinput: Ask user for integer continously till user input -1 and append all the integers to the linked list. */ PROGRAM: #include using namespace std; class Node { public: int data; Node *next; Node(int data) { this->data = data; this->next = NULL; } }; class LinkedList { private: Node *head; public: LinkedList() { head = NULL; } void addToFront(int data) { Node *temp = new Node(data); if(head == NULL) head = temp; else { temp->next = head; head = temp; } } void append(int data) { Node *temp = new Node(data); Node *current = head; if(current == NULL) { head = temp; return; } while(current->next != NULL) { current = current->next; } current->next = temp; } void print() { Node *current = head; if(current == NULL) cout << \"No element in list. \ \"; while(current != NULL) { cout << current->data << \" \"; current = current->next; } cout << endl; } void deleteLinkedList() { Node *prev; Node *current = head; while(current!=NULL) { prev = current; current = current->next; delete prev; } } void deleteLastNode() { Node *current = head; Node *prev = NULL; if(current == NULL) return; while(current->next != NULL) { prev = current; current = current->next; } if(prev == NULL) { delete current; head = NULL; } else { prev->next = NULL; delete current; } } ~LinkedList() { deleteLinkedList(); } }; int main() { LinkedList list; int data; while(1) { cout << \"Enter the integer(-1 to Quit) : \"; cin >> data; if(data==-1) break; list.append(data); } cout << \"Content of LinkedList is : \"; list.print(); return 0; } OUTPUT: Enter the integer(-1 to Quit) : 1 Enter the integer(-1 to Quit) : 2 Enter the integer(-1 to Quit) : 3 Enter the integer(-1 to Quit) : 4 Enter the integer(-1 to Quit) : -1 Content of LinkedList is : 1 2 3 4.

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Arrowdeepak

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Which of the following is a way in which meiosis differs from mitosis? In meiosis, a spindle of microtubules does not form. Meiosis produces only diploid daughter cells. Meiosis is found in asexual reproduction. In meiosis, the parent cell divides twice. Meiosis never produces gametes (sex cells). Question Part Solution Answer is 4 In meiosis parent cell divides twice whereas in mitosis parent cell divides only once. Meiosis is a reductional division which occurs in diploid cell to produce four tabloid cells whereas mitosis is a educational division which either occur in haploid or diploid cell to produce haploid or diploid daughter cells. Meiosis produces balloon gametes. Also, meiosis is not found in asexual reproduction. Meiosis and mitosis both involves formation of spindle of microtubules..

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Arrowdeepak

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Arrowdeepak

What is the profitability index for an investment with the following cash flows given a 6 percent required return? 1.38 0.72 1.06 0.81 1.23 What is the profitability index for an investment with the following cash flows given a 6 percent required return? Solution Present value of inflows=cash inflow*Present value of discounting factor(rate%,time period) 15700/1.06+18000/1.06^2+17400/1.06^3 =$45440.6322 PI=Present value of inflows/Present value of outflows =$45440.6322/$37000 which is equal to =1.23(Approx)..

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