A solar pond based electricity generation plant has an efficiency of 5% and power output of 500 MW. If the solar insolation is 1000 W/m², what is the area of solar pond? [UGC NET- July’2016]

1. Environmental Science
Numerical on Solar Energy
PART-1
NTA/UGC/NET/CSIR/ICAR/DU/BHU/JNU

2. Question: A solar pond based electricity generation plant has an
efficiency of 5% and power output of 500 MW. If the solar insolation is
1000 W/m², what is the area of solar pond? [UGC NET- July’2016]
Solution:
Given: a) Efficiency, η= 5%
b) Power Output, Po= 500 MW
c) Solar Insolation, SI= 1000 W/m²
Find out: Area, A = ?? m² or km²

3. Solution:
Given: a) Efficiency, η= 5%
b) Power Output, Po= 500 MW = 500 × 106 W
c) Solar Insolation, SI= 1000 W/m²
Find: Area, A = ?? m² or km²
Formulae to be used:
Efficiency, η =
Po
P𝑖
× 100
SI =
P𝑖
Area
Using above two formulae,
Efficiency, η =
Po
SI×Area
× 100
Area, A =
Po
SI×η
× 100 =
500 × 106 W
1000 W/m²×5
× 100 = 107 m² or 10 km²
cont. …