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WOLLEGA UNIVERSITY
SCHOOL OF GRADUATE STUDIES
COLLEGE OF ENGINEERING AND TECHNOLOGY
DEPARTMENT OF MECHANICAL ENGINEERING, MSC. IN
MANUFACTURING ENGINEERING
ADVANCED MANUFACTURING AND METROLOGY
ASSIGNMENT 04
TO: NEGASHALEMU (Professor)
BY: ALEMU MERGA (1400082)
JUNE, 2022
Nekemte, Oromia, Ethiopia
1. The chordal thickness of an involute gear is being measured using a gear calliper.
Determine the chordal height to which the gear tooth calliper should be set during
measurement, if the number of teeth = 28, addendum circle diameter = 120 mm, pressure
angle = 20°, and least count of the calliper is 0.02 mm.
Solution
Given;
z=28, number of teeth
Pressure angle= 200
Addendum circle diameter=120mm,
To find the hc = Chordal height,
hc = m + gc2/4d ,
Where,
d = Pitch circle diameter
gc = Chordal thickness of gear tooth along the pitch circle
z = Number of teeth on the gear
And to find gc = Chordal thickness of gear tooth along the pitch circle,
gc = d sin (90°/z)
m = (addendum circle diameter)/ (z + 2)
m=120mm/ (28+2)
m=4
To find d = Pitch circle diameter,
d= mz
d=4(28) =112mm
Then, gc = d sin (90°/z)
gc = 112 sin (900/32)
gc =5.4956mm ,
So Theoretical value of chordal thickness is 5.4956mm
Now easily we find the chordal height of the gear as;
hc = m + gc2/4d ,
hc= 4+5.49562 /4(112)
hc= 4.0674mm
Thus, the gear tooth calliper should be set to a chordal height of 4.0674mm
2. Determine the effective diameter of a metric screw using the three-wire method. The following
data is available: diameter of the best size wire = 0.740 mm, distance over the wires =
25.58 mm, and pitch = 1.25 mm.
Solution
Given values;
x = 60° for metric threads.
p=1.25 mm.
d= 0.740 mm,
M=25.58 mm,
Where; M= the distance over the wires,
E= the effective diameter of the screw,
d= the diameter of best-size wires,
p= pitch
Figure principle of three wire method
Now, OC = OA cosec (x/2) =
𝑑
2
cosec(x/2)
If h is the height of the Centre of wire from the pitch line, then h = OC − BC.
h =
𝑑
2
cosec(x/2) −
𝑝
2
cot (x/2)
Distance over wires, M = E + 2h + 2r, where r is the radius of the wires.
Therefore, effective diameter.
E = M − d cosec (x/2) +
𝑝
2
cosec(x/2)-d
E = M − d [1 + cosec (x/2)] +
𝑝
2
cot(x/2)……………………….equation.
Now substituting given values in the formula,
E=25.58- 0.740[1+ cosec (60/2)] +
1.25
2
cot (60/2)
E=24.4425mm is effective diameter of metric screw.
3.A metric screw thread is being inspected using the two-wire method in order to measure its
effective diameter and the following data is generated: pitch = 1.5 mm, diameter of the best size
wire = 0.866 mm, distance over the wires = 26.58 mm, and thread angle = 60°. Determine the
effective diameter of the screw thread.
Solution:
Given;
p= 1.5 mm,
d=0.866 mm
M=26.58 mm,
x=60°.
Where,
p= pitch
M= distance over the wires
d= diameter of the best size wire
x= thread angle
The effective diameter,
De = T + P ………………………………………1
Where T is the dimension under the wires and P is the correction factor.
And,
T = M − 2d ………………………………………………….2
These relationships can be easily derived by referring the below figure.
Measurement in two wire method
Accordingly, from triangle OFD, OF =
𝑑
2
cosec (x/2)
FA=
𝑑
2
cosec (x/2) -
𝑑
2
=
𝑑[cosec(𝑥/2) − 1]
2
FG = GC cot (x/2) =
𝑝
4
cot (x/2) (because BC = pitch/2 and GC = pitch/4)
Therefore, AG = FG − FA =
𝑝
4
cot (x/2)-
𝑑[cosec(𝑥/2) − 1]
2
Since AG accounts for the correction factor only on one side of the screw, we have to multiply this
value by 2 in order to account for that on the opposite flank.
Therefore, total correction factor is as follows:
P = 2 AG=
𝑝
2
cot (x/2) − d [cosec(x/2) – 1]………………………3
So now before going to calculate for effective diameter we need to compute correction factor P,
From equation 3 above,
P =
𝑝
2
cot (x/2) − d [cosec(x/2) – 1]
P=
1.25
2
cot (60/2) −0.866 [cosec (60/2) – 1]
P= 0.2165mm
Similarly to find dimension under the wires T,
T= M − 2d
T=26.58-2(0.866)
T=24.848mm
Now we can compute effective diameter screw thread as,
De = T + P
De =24.848mm+0.2165mm
De= 25.064mm is effective diameter of given screw thread using two wire method.

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Assignment #4.docx

  • 1. WOLLEGA UNIVERSITY SCHOOL OF GRADUATE STUDIES COLLEGE OF ENGINEERING AND TECHNOLOGY DEPARTMENT OF MECHANICAL ENGINEERING, MSC. IN MANUFACTURING ENGINEERING ADVANCED MANUFACTURING AND METROLOGY ASSIGNMENT 04 TO: NEGASHALEMU (Professor) BY: ALEMU MERGA (1400082) JUNE, 2022 Nekemte, Oromia, Ethiopia
  • 2. 1. The chordal thickness of an involute gear is being measured using a gear calliper. Determine the chordal height to which the gear tooth calliper should be set during measurement, if the number of teeth = 28, addendum circle diameter = 120 mm, pressure angle = 20°, and least count of the calliper is 0.02 mm. Solution Given; z=28, number of teeth Pressure angle= 200 Addendum circle diameter=120mm, To find the hc = Chordal height, hc = m + gc2/4d , Where, d = Pitch circle diameter gc = Chordal thickness of gear tooth along the pitch circle z = Number of teeth on the gear And to find gc = Chordal thickness of gear tooth along the pitch circle, gc = d sin (90°/z) m = (addendum circle diameter)/ (z + 2) m=120mm/ (28+2) m=4 To find d = Pitch circle diameter, d= mz d=4(28) =112mm Then, gc = d sin (90°/z) gc = 112 sin (900/32) gc =5.4956mm , So Theoretical value of chordal thickness is 5.4956mm Now easily we find the chordal height of the gear as;
  • 3. hc = m + gc2/4d , hc= 4+5.49562 /4(112) hc= 4.0674mm Thus, the gear tooth calliper should be set to a chordal height of 4.0674mm 2. Determine the effective diameter of a metric screw using the three-wire method. The following data is available: diameter of the best size wire = 0.740 mm, distance over the wires = 25.58 mm, and pitch = 1.25 mm. Solution Given values; x = 60° for metric threads. p=1.25 mm. d= 0.740 mm, M=25.58 mm, Where; M= the distance over the wires, E= the effective diameter of the screw, d= the diameter of best-size wires, p= pitch Figure principle of three wire method Now, OC = OA cosec (x/2) = 𝑑 2 cosec(x/2) If h is the height of the Centre of wire from the pitch line, then h = OC − BC. h = 𝑑 2 cosec(x/2) − 𝑝 2 cot (x/2) Distance over wires, M = E + 2h + 2r, where r is the radius of the wires.
  • 4. Therefore, effective diameter. E = M − d cosec (x/2) + 𝑝 2 cosec(x/2)-d E = M − d [1 + cosec (x/2)] + 𝑝 2 cot(x/2)……………………….equation. Now substituting given values in the formula, E=25.58- 0.740[1+ cosec (60/2)] + 1.25 2 cot (60/2) E=24.4425mm is effective diameter of metric screw. 3.A metric screw thread is being inspected using the two-wire method in order to measure its effective diameter and the following data is generated: pitch = 1.5 mm, diameter of the best size wire = 0.866 mm, distance over the wires = 26.58 mm, and thread angle = 60°. Determine the effective diameter of the screw thread. Solution: Given; p= 1.5 mm, d=0.866 mm M=26.58 mm, x=60°. Where, p= pitch M= distance over the wires d= diameter of the best size wire x= thread angle The effective diameter, De = T + P ………………………………………1 Where T is the dimension under the wires and P is the correction factor. And, T = M − 2d ………………………………………………….2 These relationships can be easily derived by referring the below figure.
  • 5. Measurement in two wire method Accordingly, from triangle OFD, OF = 𝑑 2 cosec (x/2) FA= 𝑑 2 cosec (x/2) - 𝑑 2 = 𝑑[cosec(𝑥/2) − 1] 2 FG = GC cot (x/2) = 𝑝 4 cot (x/2) (because BC = pitch/2 and GC = pitch/4) Therefore, AG = FG − FA = 𝑝 4 cot (x/2)- 𝑑[cosec(𝑥/2) − 1] 2 Since AG accounts for the correction factor only on one side of the screw, we have to multiply this value by 2 in order to account for that on the opposite flank. Therefore, total correction factor is as follows: P = 2 AG= 𝑝 2 cot (x/2) − d [cosec(x/2) – 1]………………………3 So now before going to calculate for effective diameter we need to compute correction factor P, From equation 3 above, P = 𝑝 2 cot (x/2) − d [cosec(x/2) – 1] P= 1.25 2 cot (60/2) −0.866 [cosec (60/2) – 1] P= 0.2165mm Similarly to find dimension under the wires T,
  • 6. T= M − 2d T=26.58-2(0.866) T=24.848mm Now we can compute effective diameter screw thread as, De = T + P De =24.848mm+0.2165mm De= 25.064mm is effective diameter of given screw thread using two wire method.