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designideas
                                                                                                    Edited By Martin Rowe
                                                                                                     and Fran Granville




                                                           readerS SOLVE DESIGN PROBLEMS



Read multiple switches and
                                                                                           D Is Inside
a potentiometer setting                                                                    72 Three-transistor modulator-
with one microcontroller input pin                                                         amplifier circuit works with swept-
                                                                                           control frequencies
Kevin Fodor, Palatine, IL
                                                                                               76 Tables ease microcontroller


        The circuit in this Design Idea    multistep process, and a spreadsheet,               programming
        provides a way to convey mixed     which you can download at www.edn.                  76 Monitor alarm and indicator
analog and digital inputs into a micro-­   com/100422dia, aids in performing the               display multiple deviation
controller using one input pin. The out-­  calculations. Say, for example, that you            boundaries
put of the circuit connects to a micro-­   want 5-kV potentiometer RADJ to pro-­
controller’s ADC-input pin. The circuit    duce a 0 to 100% value into the micro-­             ETo see all of EDN’s Design
comprises a single variable resistor and   controller. Typically, you would map                Ideas, visit www.edn.com/
a number of SPST (single-pole/single-      the sampled value of 0 to 255 into a                designideas.
throw) switches (Figure 1). The push-­     0 to 100 value to represent a percent-­
buttons allow the user to select modes,    age. However, by selecting the values
states, or options, and the analog input   of bias resistor RBIAS, you arrive at a di-­       The computed value of RBIAS is
provides a method of conveying an ad-­     rect analog input centered on the 0 to 3875V. Using a standard value of 3.3
justable parameter. The implementa-­       255 range of the ADC—for example, kV, the potentiometer’sdi 4591 rang-­
                                                                                            Equations for edn100401 input
                                            Equations for edn100401di 4591
tion requires you to analyze a parallel    78 to 178.                                      es from 73 to 182. This range yields a
resistor circuit and a voltage divider.       To compute the appropriate high- larger dynamic range than you need but
If you carefully select the resistor val-­              Equations for edn100401di allows for 1 guard range between the
                                           and low-side bias-resistor values, the4591       Equation a
ues, the circuit for edn100401di 4591
      Equations provides a discernible     following 1
                                            Equation equations solve this circuit potentiometer’s values and the push-­
analog input as well as a number of dis-­  as a simple voltage divider:                    buttons’ values. Because the position
crete pushbutton-input states.                          Equation 1                         of RADJ affects R overall resistance
                                                                                                             the                             R BIA
                                                                                                               BIAS
                                                                           di 4591 V the = = BIAS ++ 2 × Ryou V × VMAX; VHIGH = R
   Selecting the resistor values is a                        R edn                          VLOW R sees when
                                                                                                circuit       R ADJ       press either
      Equation 1                               Equations for BIAS100401× V
                                            VLOW =                                                    R ADJ            ×
                                                      R ADJ + 2 × R BIAS
                                                                               MAX; HIGH   switch, the microcontroller must .inter-­
                                                                                                  R ADJ + 2 × R BIAS
                                                                                                                     BIAS MAX                ADJ

                            V                                                              pret a range of values for + R switch.
                                                                                                                R BIAS
                                                                                                                         each
                                                                        R BIAS                                              ADJ
             Equations for edn100401di 4591             VLOW =+ R
                                               Equation R BIAS R ADJ+ 2 × R
                                                          1                             × VMAX; VHIGH =the switch resistance, MAX .
                                                                                           To determine                            ×V
                   R BIAS                                                                   Equation 2 S R ADJ,+ 2 ×use a paral-­
                                                                                                                           R BIAS
    VLOW =                       × VMAX; VHIGH =                    ADJ     × VMAX . RSW, for either 1 or S2 you
                                                                                 BIAS
              R ADJ + 2 ×RR BIAS R          Equation 2 ADJ + 2 × R BIAS
                                                       R
                          SW        BIAS                                                   lel-resistor network at both extremes of
                                                                                           the potentiometer’s position.
             Equation 1                                         R solving for R
                                              Substituting andBIAS                                     R BIAS +S R
                                                                                                         V press R ADJ ADJ R at the
                   S2                          VLOW =   Equation 2             × VMAX VR When you LOW × 1 and R×= is ADJ × (VHIGHVMAX
                                                                                   BIAS
                                                                                            HIGH =                  ADJ     VMAX .
                                                        VLOW × maximum R ADJ × (;VHIGHVMAX ) + 2 × the effective resis-­
                                                          R ADJ + R × R BIAS voltage maximumV
                                                                  2 ADJ                       BIAS =R ADJ
    Equation 2
MICROCONTROLLER                   RADJ
                                           and given that the
                                            R BIAS =                       =                                =2 R BIAS
                                                                                                        position,× V
                                                                                                        MAX 3875V.   LOW         VMAX2 × VHIGH
      ADC                                  reports a value 2255,LOW maximum 2 × VHIGH bottom leg of the divider
                                                      VMAXof × V the              VMAX tance of the
                    S1       R BIAS        low voltage reports aRvalue +× R the R RSW× (V
                                                                     BIAS R ADJ
                                                                    VLOWof 78, × V isADJ in parallel with the series combi-­
             VLOW =                        × VMAX; VHIGH =                       ADJ      MAX .        HIGHVMAX )
                VLOW R ADJ + 2 ×RBIASADJ maximum high voltage value reported = nation of2 × V RBIAS. = 3875V.
                       × RSW
                         R ADJ     RR          Equation MAX = V
                                                        R2
                                      BIAS × (VHIGHVBIAS ) R ADJ +×× V 2 R BIAS
                                                                           2                  VMAX
                                                                                                      R and             At the mini-­
                                                                                            Equation 3ADJ the effective resistance
                                                                                               u position, HIGH
    R BIAS =                      =                                 MAX
                                                                 = a value       LOW
                                           is 178, and RADJ has 3875V. of 5 kV mum
              VMAX2 × VLOW                 Equation 3
                                               u 2× V
                                         VMAXthe following equation:
                                           yield       HIGH                                is RSW in parallel with RBIAS:
               Equation 2                              EquVLOW × R ADJ = R ADJ × (VHIGHVMAX ) =×3875V. + R BIAS )
                                                R BIAS = R ation (3
                                                          u                                         R SW (R ADJ                        R
                                                                                VMAX2 ×= R = R
                                                         VMAX× 2 × VLOW BIAS ) ; R R EFFMAXSW × R BIAS .
                                                           SW R ADJ + R                      VHIGH                        ; R EFFMIN = SW
     Equation 3
        u
  Figure 1 This circuit allows one          R EFFMAX =                             EFFMIN              SW + R ADJ + R BIAS             R SW
                                                          R SW + R ADJ + R BIAS                R SW + R BIAS
  microcontroller pin to read multiple
                            VLOW × R ADJ      R ADJ × (VHIGHVMAX ) × (R
              R BIAS =
  switches and edn100401di45911 DIANE
                a potentiometer             =                        R SW 3875V. + R BIAS )
                                                                          =   ADJ                        R     × R BIAS
                         ×THE ADJ × VLOW
                   R SW VMAX2+ R BIAS )
                            (R 4-8 FOLDER)     EquMAX2SW × R= R
                                                        R3×V
                                                  Vation EFFMAX
                                                   u                                        ; R EFFMIN = SW             .
  value.                                                 R     HIGH SW + R ADJ + R BIAS
                                                                   BIAS .            Equation 4          R SW + R BIAS
                =
     R EFFMAX(PLACED IN                    ; R EFFMIN =
                   R SW + R ADJ + R BIAS Equation 4 R SW + R BIAS

               Equation 3
                 u                                          R SW × (R ADJ + R BIAS )                  ×
                                                                                                 R SW R R BIAS
                                                       Equation 4
                                               R EFFMAX =                               EFFMIN =
                                                                                     ; RV
                                                                                         S1MAX = R
                                                                                                       EFFMAX.
     Equation 4                            VS1MAX =
                                                             R EFFMAX ADJ + R BIAS
                                                             R SW + R      × VMAX .                   + R BIAS2010 × VMAX .71
                                                                                                    April +
                                                                                                 R EFFMAX22,R BIAS | EDN
                                                                                                   SW
                                                        R EFFMAX + R BIAS
                            R SW × (R ADJ + R BIAS )              R    × R BIAS
               R          =                          ;R         = SW R EFFMAX   .
R BIAS =                      =                            = 3875V.
                   VMAX2 × VLOW            VMAX2 × VHIGH
designideas
      Equation 3 SW × (R ADJ + R BIAS )
        u
   R EFFMAX =
               R                                    R
                                        ; R EFFMIN = SW
                                                         × R BIAS
                                                                  .
        Equation SW + R ADJ + R BIAS
           u    R3                                  R SW + R BIAS

                  R SW ×
     R EFFMAX =           value + R BIAS )
     You determine the (R ADJ when you; R             R SW × R BIAS
                                            EFFMIN =                .
   Equation by evaluating R ADJ + R BIAS )
   press S1 4      R SW + × (R ADJ + R BIAS
                     R SW the voltage di-­            R SW + R BIAS
                                                         R SW × R BIAS
   viderR EFFMAX =and RRFFMAX form:R
         that RBIAS R                       ; R EFFMIN =               .
                        SW + R ADJ + BIAS                R SW + R BIAS

     Equation 4 R EFFMAX
   VS1MAX =                    × VMAX .
             R EFFMAX + R BIAS
       Equation 4
       Observe that when RADJ is at its max-­
                      R EFFMAX
   imum value and you press S1, it×must .
      VS1MAX =                          VMAX
   produce    5 R EFFMAX + R BIAS
   Equation a value less R EFFMAX smallest
                          than the
         VS        =                     ×V       .
   value R1MAX R EFFMAX + toBIAS
            ADJ
                produces by itself R unique-­ MAX
   ly determine that you have pressed the
      Equation 5 R         2
   switch. So the maximum effective re-­
                      BIAS
   sistance, <EFFMAX, must produce a value
   R EFFMAXR
         Equation BIAS + R ADJ
                 R 5
                                 .
   less than the maximum low voltage, as
   the following equation shows:
                       R      2
     R EFFMAX <      BIAS      .
   Equation 6          +     2
                R BIAS R R ADJ
        R EFFMAX <      BIAS      .
                   R BIAS + R ADJ                 Figure 2 The circuit can have 10 pushbuttons and one potentiometer.

      Equation 6 3 + R
   Substituting and solving2this ADJ
            R BIAS     BIAS × R equation       values is not necessary, it minimizes        two pushbuttons, but the number of
   R SW < switch resistance yields: .
   for the                                     the number of calculations you need          pushbuttons can vary. Input ranges
        Equation + 2 × R
                 2 6
           R ADJ         ADJ × R BIAS          to perform and simplifies the design.        are available for as many as 10 push-­
                       3        2
                R BIAS + R BIAS × R ADJ        Furthermore, selecting smaller series        buttons and one potentiometer, all of
      R SW <              3        2
                                           .   switch resistors opens the guard range       which share the same input pin (Fig-
                     2
               R R BIAS ×+ R BIAS R× R ADJ between them and the potentiometer,
                       + 2 R ADJ × BIAS                                                     ure 2). Although the computed rang-­
         R SW <ADJ                           .
                  R ADJ2 + 2 × R ADJ × R BIAS which may be desirable if the result-­        es do not overlap and are unique, it
       Using the spreadsheet to compute ing values are too close together. The              is doubtful that your ADC hardware
    the switch resistance yields 1558V, microcontroller uses a small subrou-­               can reliably distinguish these bands
    and you can choose a nominal 1.5- tine, Listing 1, which you can down-­                 under all circumstances. Choosing
    kV resistor. This selection causes S1 to load at www.edn.com/100422dia, to              smaller resistor values keeps these
    produce a range of 28 to 71 when you determine both switch positions and                bands farther apart, creating a larger
    press it, depending on the potentiom-­ the potentiometer’s setting.                     guard range.
    eter’s position. Likewise, choosing the      The limitation of this technique is           Using this technique with four
    same value for S2 produces a range of that you cannot press more than one               pushbuttons and one potentiometer
    184 to 227. These ranges are bands of pushbutton at any time. In addition,              is well within reason. Experimenting
    values that you can use to determine the microcontroller can read the po-­              with the spreadsheet helps make quick
    which switch you pressed regardless tentiometer’s position only when you                work of determining just the right se-­
    of the potentiometer’s position. Al-­ are not pressing any other pushbut-­              ries-resistor values for each switch and
    though selecting symmetrical resistor tons. This example shows how to use               its output range.EDN




    Three-transistor modulator-                                                             tion is not important in these applica-­
                                                                                            tions. When you drive a piezoelectric
    amplifier circuit works                                                                 load, its natural resonance removes any
                                                                                            frequency components other than the
    with swept-control frequencies                                                          fundamental. This circuit combines a
                                                                                            modulator and an amplifier into a sin-­
    Horia-Nicolai L Teodorescu and Victor Cojocaru,
                                                                                            gle stage. The compactness of the cir-­
    Gheorghe Asachi Technical University, Iasi, Romania
                                                                                            cuit makes it appropriate for portable-

    
           Many applications require a          electric generator in a robot. Other ap-­   system applications.
           circuit to perform pulse mod-­       plications include driving small motors        The load is in series with two switch-­
    ulation and voltage amplification to        or LEDs. Echolocation and ultrasound        es (Figure 1). The input signal controls
    drive a load with a train of impulses. A    visualization use a sweeping-frequen-­      S2, S3 controls S1, and the modulating
    typical application is driving a piezo-­    cy, or chirp, signal. Nonlinear distor-­    signal controls S3. This circuit’s mod-­



 72 EDN | April 22, 2010
designideas

                                                       ulation operation is similar to that of
                                                       an AND gate. The switches must have          If the load imped-
       RLOAD                                           internal resistance to dissipate the har-­
                                                       monics that the resonant load reflects.
                                                                                                    ance varies, the
                         S3
                                                       This circuit uses transistors Q1 and Q2      circuit does
               S1                                      as switches, although they operate in        not degrade the
                                                       the active region (Figure 2). Their op-­
                                                       eration resembles that of controlled re-­    impulse shape.
                    S2
                                                       sistors, and they perform voltage and
                                                       current amplification. You drive Q2
                                                       with a 42-kHz signal that matches the        the state of Q2. Q1 and Q2 operate con-­
                                                       load’s resonance. You modulate the Q3        jointly; Q1 conducts only when Q2 is
                                                       transistor with a periodic low-frequen-­     conducting. You can view this scheme
                                                       cy impulse signal. These impulses open       as a differential amplifier in which the
     Figure 1 This simple modulator                    Q3, which drives Q1 and Q2 toward sat-­      signal in one branch controls the load
     uses three switches.                              uration. When Q3 opens, it drops the         of another branch.
                                                       voltage across the base of Q1, blocking         Q2 and Q3 operate over large signals
                                                                                                    yet remain in the active region most of
                                                                                                    the time. The resistor values in the base
       MURATA
       MA40B8R                                                                                      and collector of Q1 are critical. When
        edn100401di46181 DIANE
                                                                                                    the frequency of the signal is higher
                  THE 4-8L1
       (PLACED IN 1       FOLDER)
                               2
                                                                                                    than the load’s resonant frequency, D1
                                                                                                    protects Q1 from the effects of L1 and
                                                                                +
                                                R1                                     25V dc       of harmonics on the LC circuit. The
                                               100                              –
                                                                                         V1         collector voltage has a spectrum rich in
        C1                     R5
        62F
                                                                     R2                             harmonics due to the nonlinear behav-­
                              100                                    5k
                                                                                                    ior of transistors. This characteristic is
                                                             R4
                                                             90k
                                                                                                    not a serious disadvantage because the
                                    2
                                                                                                    resonant load removes the harmonics.
                                        D1                                                             The value of R1 is critical to the cur-­
                                    1 1N6392          Q1                                            rent and voltage amplification of the
                                                     BC516
                                                                                                    Q1/Q2 stage. The swing of voltage in
                                     Q2
                                                                                                    the collector of Q1 is sensitive to the
                                    BC517                                        R5
                           R5                                                                       value of R1 (Figure 3). Q1 operates in
                          100k                                                  100k
                                                                                                    the active mode because its collector
                                                                                                    voltage increases slowly toward the
                                                                                                    maximal value. The significant glitch
                                                                       Q3
                                                                      BC517                         at small collector voltages shows that
                                                                                                    the blocking process partly occurs in
                                                                                                    the active regions of Q2 and Q3. If the
     Figure 2 A three-transistor modulator with a resonant load works over a large                  load impedance varies, the circuit does
     input range.                                                                                   not degrade the impulse shape. This
                                                                                                    situation is true even at twice the load’s
                                                                                                    resonant frequency. The circuit func-­
                                                                                                    tions with input voltages of 4.5 and
                                                                                                    11V. This voltage range allows you to
                                                                                                    drive the circuit with a 5V microcon-­
                                                                                                    troller (Reference 1).EDN

                                                                                                    R e fe r e nce
                                                                                                    1   Teodorescu, Horia-Nicolai L, “Algo-
                                                                                                    rithm for Adaptive Distance Estima-
                                                                                                    tors for Echolocation in Air,” Interna-
                                                                                                    tional Solid-State Circuits Confer-
     Figure 3 Changing the value of R1 yields different response waveforms.                         ence, 2009, www.adbiosonar.ugal.ro/
                                                                                                    ad/content/funding.



 74 EDN | April 22, 2010
designideas
                                                                                                        When working with tables, you
    Tables ease                                                                                      should always use indexed addressing

    microcontroller programming                                                                      mode. It provides access to data using
                                                                                                     variable addresses. Most microcon-­
                                                                                                     trollers have two index registers, X and
    Abel Raynus, Armatron International, Malden, MA
                                                                                                     H. Register X contains the low byte of

    
            When creating microcontroller                                                            the conditional address of the operand;
                                                             START
            firmware, you often need to                                                              H contains the high byte. The algo-­
    work with data arrays. Tables make                                                               rithm of working with tables is straight-­
                                                       CLEAR REGISTER X
    easy work of data arrays, such as those            CLEAR REGISTER H                              forward. After you detect the input
    for digital-code transformation, correc-­                                                        value, you should then compare it with
    tion for sensor linearity, sophisticated         GET THE INPUT VALUE, V                          the table’s input data. The X index de-­
    calculations, and multiple output orga-­                                                         termines this value, starting with X50
    nization. Table 1 shows how you can                                                              and ending with X5N. In this exam-­
    organize data in a table. Outputs A, B,                  V=VX?
                                                                              YES
                                                                                                     ple, N54. When you find table data
    and C have values based on the input                                                             equal to the input value, you use the
                                                                    NO
    value, V.                                                                       AX�REGISTER A    corresponding X as an index to load the
      When using a lookup table, choose                      X>N?
                                                                              YES   BX�REGISTER B    output registers with their values. In the
                                                                                    CX�REGISTER C
    the proper microcontroller input and                                                             case of 2-byte numbers, you should load
    outputs. Assign values for input and                            NO
                                                                                                     the output registers separately, first with
    outputs data in Table 2. These data can              INCREMENT X                                 a high byte and then with a low one.
    consist of constants in binary, hexadec-­                                                        Figure 1 illustrates this process.
    imal, or decimal format or names. For                            END                                The listing of assembler code is
    names, you should assign a constant                                                              available from the online version of
    value to each one. For example:                                                                  this Design Idea at www.edn.com/
    data1 equ $0a                                    Figure 1 You can use a look-up table            article/100422dib. In the listing, you
    data2 equ $0b                                    in microcontroller code.                        can double-check the table content
    data3 equ $0c                                                                                    in memory at addresses $F800 through
    data3 equ $0d                                 ORG ROM                                            $F813. The listing uses Freescale (www.
      Next, put the data from Table 2 in ei-­     Vx FCB 0T,2T,4T,6T                                 freescale.com) assembler because most
    ther the beginning or the end of ROM,         Ax FCB data1,data2,data3,data4                     of the appropriate applications employ
    which makes the data easy to find. For        Bx FCB $aa,$bb,$cc,$dd                             inexpensive, 8-bit microcontrollers
                                                   edn100401di46341 DIANE
    definition of 1-byte data storage, use        Cx FDBTHE 4-8 FOLDER)
                                                  (PLACED IN $1122,$3344,$5566,$7788                 from Freescale’s HC08 Nitron family.
    pseudo operators FCB or DB. For stor-­           Note that commas separate the data.             You can, however, use this approach
    age of data comprising 2 bytes, use FDB       Don’t place a comma after the last                 with any type of microcontroller and
    or DW, as in the following example:           data, or it will be considered as $00.             assembly language.EDN

     Table 1 Output values versus input values                                          Table 2 Input and output values
         Input V         Output A          Output B              Output C                  Input V    Output A       Output B      Output C
           V1               A1                  B1                   C1                    V1=0T        data1           $aa          $1122
           V2               A2                  B2                   C2                    V2=2T        data2           $bb          $3344
          ....              ....                ....                 ....                  V3=4T        data3           $cc          $5566
           VN               AN                  BN                   CN                    V4=6T        data4           $dd          $7788




                                                                                                     indication of both the direction and
    Monitor alarm and indicator display                                                              the magnitude of the temperature’s de-­

    multiple deviation boundaries                                                                    viation from a user-set mean in a sol-­
                                                                                                     der pot. Using a Microchip (www.mi-­
                                                                                                     crochip.com) 12F675 controller, the
    William Grill, Riverhead Systems, Lenexa, KS
                                                                                                     coded sequences allow the user to both

    
          A low-cost monitor can visu-­           high- or low-temperature characteris-­             set the mean and scale the range of the
          ally indicate a process problem,        tic. The microcontroller-based circuit             monitored variation. The application
    such as a failed cabinet fan or other         in Figure 1 provided a simple visual               uses the controller’s internal clock and



 76 EDN | April 22, 2010
designideas

    two of the controller’s four ADCs.               scaled boundaries to a corresponding      quences of one or both LEDs. The
       Asserting switch S1 on Pin 4 copies           display format. The processor moni-­      monitor also asserts an output on Pin 5
    the input voltage under test from Pin            tors both the input under test and a      when the measured variation exceeds
    7, which becomes the mean value. The             second analog level, on Pin 6, to scale   the third tabled boundary.
    code then evaluates the input-voltage            the internal deviation/boundary tables.     The circuit provides independent
    deviation from the mean and applies              It then schedules as many as four se-­    positive- and negative-deviation ta-­
                                                                                               bles and multiplies the ranges by inter-­
                                                                                               preting the voltage on Pin 6, resulting
                                                    10 �F
                                                                                               in the application of a multiple from
                  1N4148
       7 TO 12V
                                                                                               one to eight on the boundary limits.
                                78L05
                                                                                               You configure the converter reference
                      4.7 �F            4.7k
                                                    1            8
                                                                                               to use the controller’s VDD voltage.
                                                                       RED LED       470       Using only 8 bits of the controller’s
                                                    7            2
      PARAMETER/VOLTAGE UNDER TEST
                                                        12F675
                                                                                               10-bit ADC, the deviation can be as
                                                    6            3                   470
          SCALER-SET VOLTAGE                                                                   small as one step or 1/2563VDD, the
                                                                     GREEN LED       470
                               4.7k                 4            5                             drain-to-drain voltage. For a 5V ref-­
                                                                       ALARM/ERROR             erence, this voltage is approximately
                                               S1
                               SET MEAN
                                                                          RED LED              9 mV.
                                                                                                 Figure 2 shows the boundaries and
                                                                                               their possible spans, which Pin 6 and
                                                                                               corresponding display-format num-­
                                                                                               bers set (Table 1). Using the provid-­
     Figure 1 This microcontroller-based circuit provides a simple visual indication of        ed minimum value of the deviation/
     both the direction and the magnitude of the temperature’s deviation from a user-          boundary table, neglecting the error
     set mean in a solder pot.                                                                 that results from the use of the 78L05
                                                                                               as a reference, and assuming the scal-­




                                         edn100401di46321 DIANE
                                        (PLACED IN THE 4-8 FOLDER)




 78 EDN | April 22, 2010
MEAN SETPOINT
                                                                                           Table 1 Display-format
                                          �1 (DERIVED FROM PIN 6)                          numbers and table-based
                                                                                           sequence
                                                                 DISPLAY-FORMAT
        �5        �4     �3 �2 �1 1 2  3       4        5        NUMBER                    Display-format
   20        14        9   5 2     2 5   9         14       20   DEVIATION/                   number           Sequence
                                                                 BOUNDARY COUNT �1
        ADC-BIT DEVIATION FROM MEASURED VALUE TO MEAN                                             >5           Green, red/green,
                                                                 PIN 5 ALARM OUTPUT
                                                                                                               red/green, red/green
                                                                                                       5       Green, green, green/red,
                                                                                                               green/red
  Figure 2 Pin 6 and the corresponding display-format numbers set the boundar-
                                                                                                       4       Green, red, green/red
  ies and their possible spans.
                                                                                                       3       Green, green, green, red
ing derived from Pin 6 result in 31,           no/go applications or other needs. The                  2       Green, green, red
the first display-format step, in this ap-­    circuit may also find a use in airflow or               1       Green
plication, which occurs when the mea-­         other physical-parameter monitors.
                                                                                                21             Red
sured input deviates more than the de-­          Using the controller’s ADC, you
viation/boundary-table value times the         can monitor any parameter that you               22             Red, red, green
scale derived from Pin 6 times 1/256           can represent with a voltage. You can            23             Red, red, red, green
times the drain-to-drain voltage equals        modify the code-based tables to ac-­
                                                                                                24             Red, green, red/green
235/25631, or 39 mV.                           commodate a variety of other display
   You can change the display-sequence         sequences, parameter nonlinearities, or          25             Red, red, red/green,
formats for the five positive boundaries,      error distributions.                                            red/green
beginning in a green-LED flash, and              You can download Listing 1, code               ,,<<   <5      Red, red/green,
five negative boundaries, beginning in         for the error monitor, from www.edn.                            red/greeen, red/green
a red-LED flash, to suit simpler go or         com/100422dic.EDN




                                                                                                            April 22, 2010 | EDN 79

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6726481

  • 1. designideas Edited By Martin Rowe and Fran Granville readerS SOLVE DESIGN PROBLEMS Read multiple switches and D Is Inside a potentiometer setting 72 Three-transistor modulator- with one microcontroller input pin amplifier circuit works with swept- control frequencies Kevin Fodor, Palatine, IL 76 Tables ease microcontroller  The circuit in this Design Idea multistep process, and a spreadsheet, programming provides a way to convey mixed which you can download at www.edn. 76 Monitor alarm and indicator analog and digital inputs into a micro-­ com/100422dia, aids in performing the display multiple deviation controller using one input pin. The out-­ calculations. Say, for example, that you boundaries put of the circuit connects to a micro-­ want 5-kV potentiometer RADJ to pro-­ controller’s ADC-input pin. The circuit duce a 0 to 100% value into the micro-­ ETo see all of EDN’s Design comprises a single variable resistor and controller. Typically, you would map Ideas, visit www.edn.com/ a number of SPST (single-pole/single- the sampled value of 0 to 255 into a designideas. throw) switches (Figure 1). The push-­ 0 to 100 value to represent a percent-­ buttons allow the user to select modes, age. However, by selecting the values states, or options, and the analog input of bias resistor RBIAS, you arrive at a di-­ The computed value of RBIAS is provides a method of conveying an ad-­ rect analog input centered on the 0 to 3875V. Using a standard value of 3.3 justable parameter. The implementa-­ 255 range of the ADC—for example, kV, the potentiometer’sdi 4591 rang-­ Equations for edn100401 input Equations for edn100401di 4591 tion requires you to analyze a parallel 78 to 178. es from 73 to 182. This range yields a resistor circuit and a voltage divider. To compute the appropriate high- larger dynamic range than you need but If you carefully select the resistor val-­ Equations for edn100401di allows for 1 guard range between the and low-side bias-resistor values, the4591 Equation a ues, the circuit for edn100401di 4591 Equations provides a discernible following 1 Equation equations solve this circuit potentiometer’s values and the push-­ analog input as well as a number of dis-­ as a simple voltage divider: buttons’ values. Because the position crete pushbutton-input states. Equation 1 of RADJ affects R overall resistance the R BIA BIAS di 4591 V the = = BIAS ++ 2 × Ryou V × VMAX; VHIGH = R Selecting the resistor values is a R edn VLOW R sees when circuit R ADJ press either Equation 1 Equations for BIAS100401× V VLOW = R ADJ × R ADJ + 2 × R BIAS MAX; HIGH switch, the microcontroller must .inter-­ R ADJ + 2 × R BIAS BIAS MAX ADJ V pret a range of values for + R switch. R BIAS each R BIAS ADJ Equations for edn100401di 4591 VLOW =+ R Equation R BIAS R ADJ+ 2 × R 1 × VMAX; VHIGH =the switch resistance, MAX . To determine ×V R BIAS Equation 2 S R ADJ,+ 2 ×use a paral-­ R BIAS VLOW = × VMAX; VHIGH = ADJ × VMAX . RSW, for either 1 or S2 you BIAS R ADJ + 2 ×RR BIAS R Equation 2 ADJ + 2 × R BIAS R SW BIAS lel-resistor network at both extremes of the potentiometer’s position. Equation 1 R solving for R Substituting andBIAS R BIAS +S R V press R ADJ ADJ R at the S2 VLOW = Equation 2 × VMAX VR When you LOW × 1 and R×= is ADJ × (VHIGHVMAX BIAS HIGH = ADJ VMAX . VLOW × maximum R ADJ × (;VHIGHVMAX ) + 2 × the effective resis-­ R ADJ + R × R BIAS voltage maximumV 2 ADJ BIAS =R ADJ Equation 2 MICROCONTROLLER RADJ and given that the R BIAS = = =2 R BIAS position,× V MAX 3875V. LOW VMAX2 × VHIGH ADC reports a value 2255,LOW maximum 2 × VHIGH bottom leg of the divider VMAXof × V the VMAX tance of the S1 R BIAS low voltage reports aRvalue +× R the R RSW× (V BIAS R ADJ VLOWof 78, × V isADJ in parallel with the series combi-­ VLOW = × VMAX; VHIGH = ADJ MAX . HIGHVMAX ) VLOW R ADJ + 2 ×RBIASADJ maximum high voltage value reported = nation of2 × V RBIAS. = 3875V. × RSW R ADJ RR Equation MAX = V R2 BIAS × (VHIGHVBIAS ) R ADJ +×× V 2 R BIAS 2 VMAX R and At the mini-­ Equation 3ADJ the effective resistance u position, HIGH R BIAS = = MAX = a value LOW is 178, and RADJ has 3875V. of 5 kV mum VMAX2 × VLOW Equation 3 u 2× V VMAXthe following equation: yield HIGH is RSW in parallel with RBIAS: Equation 2 EquVLOW × R ADJ = R ADJ × (VHIGHVMAX ) =×3875V. + R BIAS ) R BIAS = R ation (3 u R SW (R ADJ R VMAX2 ×= R = R VMAX× 2 × VLOW BIAS ) ; R R EFFMAXSW × R BIAS . SW R ADJ + R VHIGH ; R EFFMIN = SW Equation 3 u Figure 1 This circuit allows one R EFFMAX = EFFMIN SW + R ADJ + R BIAS R SW R SW + R ADJ + R BIAS R SW + R BIAS microcontroller pin to read multiple VLOW × R ADJ R ADJ × (VHIGHVMAX ) × (R R BIAS = switches and edn100401di45911 DIANE a potentiometer = R SW 3875V. + R BIAS ) = ADJ R × R BIAS ×THE ADJ × VLOW R SW VMAX2+ R BIAS ) (R 4-8 FOLDER) EquMAX2SW × R= R R3×V Vation EFFMAX u ; R EFFMIN = SW . value. R HIGH SW + R ADJ + R BIAS BIAS . Equation 4 R SW + R BIAS = R EFFMAX(PLACED IN ; R EFFMIN = R SW + R ADJ + R BIAS Equation 4 R SW + R BIAS Equation 3 u R SW × (R ADJ + R BIAS ) × R SW R R BIAS Equation 4 R EFFMAX = EFFMIN = ; RV S1MAX = R EFFMAX. Equation 4 VS1MAX = R EFFMAX ADJ + R BIAS R SW + R × VMAX . + R BIAS2010 × VMAX .71 April + R EFFMAX22,R BIAS | EDN SW R EFFMAX + R BIAS R SW × (R ADJ + R BIAS ) R × R BIAS R = ;R = SW R EFFMAX .
  • 2. R BIAS = = = 3875V. VMAX2 × VLOW VMAX2 × VHIGH designideas Equation 3 SW × (R ADJ + R BIAS ) u R EFFMAX = R R ; R EFFMIN = SW × R BIAS . Equation SW + R ADJ + R BIAS u R3 R SW + R BIAS R SW × R EFFMAX = value + R BIAS ) You determine the (R ADJ when you; R R SW × R BIAS EFFMIN = . Equation by evaluating R ADJ + R BIAS ) press S1 4 R SW + × (R ADJ + R BIAS R SW the voltage di-­ R SW + R BIAS R SW × R BIAS viderR EFFMAX =and RRFFMAX form:R that RBIAS R ; R EFFMIN = . SW + R ADJ + BIAS R SW + R BIAS Equation 4 R EFFMAX VS1MAX = × VMAX . R EFFMAX + R BIAS Equation 4 Observe that when RADJ is at its max-­ R EFFMAX imum value and you press S1, it×must . VS1MAX = VMAX produce 5 R EFFMAX + R BIAS Equation a value less R EFFMAX smallest than the VS = ×V . value R1MAX R EFFMAX + toBIAS ADJ produces by itself R unique-­ MAX ly determine that you have pressed the Equation 5 R 2 switch. So the maximum effective re-­ BIAS sistance, <EFFMAX, must produce a value R EFFMAXR Equation BIAS + R ADJ R 5 . less than the maximum low voltage, as the following equation shows: R 2 R EFFMAX < BIAS . Equation 6 + 2 R BIAS R R ADJ R EFFMAX < BIAS . R BIAS + R ADJ Figure 2 The circuit can have 10 pushbuttons and one potentiometer. Equation 6 3 + R Substituting and solving2this ADJ R BIAS BIAS × R equation values is not necessary, it minimizes two pushbuttons, but the number of R SW < switch resistance yields: . for the the number of calculations you need pushbuttons can vary. Input ranges Equation + 2 × R 2 6 R ADJ ADJ × R BIAS to perform and simplifies the design. are available for as many as 10 push-­ 3 2 R BIAS + R BIAS × R ADJ Furthermore, selecting smaller series buttons and one potentiometer, all of R SW < 3 2 . switch resistors opens the guard range which share the same input pin (Fig- 2 R R BIAS ×+ R BIAS R× R ADJ between them and the potentiometer, + 2 R ADJ × BIAS ure 2). Although the computed rang-­ R SW <ADJ . R ADJ2 + 2 × R ADJ × R BIAS which may be desirable if the result-­ es do not overlap and are unique, it Using the spreadsheet to compute ing values are too close together. The is doubtful that your ADC hardware the switch resistance yields 1558V, microcontroller uses a small subrou-­ can reliably distinguish these bands and you can choose a nominal 1.5- tine, Listing 1, which you can down-­ under all circumstances. Choosing kV resistor. This selection causes S1 to load at www.edn.com/100422dia, to smaller resistor values keeps these produce a range of 28 to 71 when you determine both switch positions and bands farther apart, creating a larger press it, depending on the potentiom-­ the potentiometer’s setting. guard range. eter’s position. Likewise, choosing the The limitation of this technique is Using this technique with four same value for S2 produces a range of that you cannot press more than one pushbuttons and one potentiometer 184 to 227. These ranges are bands of pushbutton at any time. In addition, is well within reason. Experimenting values that you can use to determine the microcontroller can read the po-­ with the spreadsheet helps make quick which switch you pressed regardless tentiometer’s position only when you work of determining just the right se-­ of the potentiometer’s position. Al-­ are not pressing any other pushbut-­ ries-resistor values for each switch and though selecting symmetrical resistor tons. This example shows how to use its output range.EDN Three-transistor modulator- tion is not important in these applica-­ tions. When you drive a piezoelectric amplifier circuit works load, its natural resonance removes any frequency components other than the with swept-control frequencies fundamental. This circuit combines a modulator and an amplifier into a sin-­ Horia-Nicolai L Teodorescu and Victor Cojocaru, gle stage. The compactness of the cir-­ Gheorghe Asachi Technical University, Iasi, Romania cuit makes it appropriate for portable-  Many applications require a electric generator in a robot. Other ap-­ system applications. circuit to perform pulse mod-­ plications include driving small motors The load is in series with two switch-­ ulation and voltage amplification to or LEDs. Echolocation and ultrasound es (Figure 1). The input signal controls drive a load with a train of impulses. A visualization use a sweeping-frequen-­ S2, S3 controls S1, and the modulating typical application is driving a piezo-­ cy, or chirp, signal. Nonlinear distor-­ signal controls S3. This circuit’s mod-­ 72 EDN | April 22, 2010
  • 3. designideas ulation operation is similar to that of an AND gate. The switches must have If the load imped- RLOAD internal resistance to dissipate the har-­ monics that the resonant load reflects. ance varies, the S3 This circuit uses transistors Q1 and Q2 circuit does S1 as switches, although they operate in not degrade the the active region (Figure 2). Their op-­ eration resembles that of controlled re-­ impulse shape. S2 sistors, and they perform voltage and current amplification. You drive Q2 with a 42-kHz signal that matches the the state of Q2. Q1 and Q2 operate con-­ load’s resonance. You modulate the Q3 jointly; Q1 conducts only when Q2 is transistor with a periodic low-frequen-­ conducting. You can view this scheme cy impulse signal. These impulses open as a differential amplifier in which the Figure 1 This simple modulator Q3, which drives Q1 and Q2 toward sat-­ signal in one branch controls the load uses three switches. uration. When Q3 opens, it drops the of another branch. voltage across the base of Q1, blocking Q2 and Q3 operate over large signals yet remain in the active region most of the time. The resistor values in the base MURATA MA40B8R and collector of Q1 are critical. When edn100401di46181 DIANE the frequency of the signal is higher THE 4-8L1 (PLACED IN 1 FOLDER) 2 than the load’s resonant frequency, D1 protects Q1 from the effects of L1 and + R1 25V dc of harmonics on the LC circuit. The 100 – V1 collector voltage has a spectrum rich in C1 R5 62F R2 harmonics due to the nonlinear behav-­ 100 5k ior of transistors. This characteristic is R4 90k not a serious disadvantage because the 2 resonant load removes the harmonics. D1 The value of R1 is critical to the cur-­ 1 1N6392 Q1 rent and voltage amplification of the BC516 Q1/Q2 stage. The swing of voltage in Q2 the collector of Q1 is sensitive to the BC517 R5 R5 value of R1 (Figure 3). Q1 operates in 100k 100k the active mode because its collector voltage increases slowly toward the maximal value. The significant glitch Q3 BC517 at small collector voltages shows that the blocking process partly occurs in the active regions of Q2 and Q3. If the Figure 2 A three-transistor modulator with a resonant load works over a large load impedance varies, the circuit does input range. not degrade the impulse shape. This situation is true even at twice the load’s resonant frequency. The circuit func-­ tions with input voltages of 4.5 and 11V. This voltage range allows you to drive the circuit with a 5V microcon-­ troller (Reference 1).EDN R e fe r e nce 1 Teodorescu, Horia-Nicolai L, “Algo- rithm for Adaptive Distance Estima- tors for Echolocation in Air,” Interna- tional Solid-State Circuits Confer- Figure 3 Changing the value of R1 yields different response waveforms. ence, 2009, www.adbiosonar.ugal.ro/ ad/content/funding. 74 EDN | April 22, 2010
  • 4. designideas When working with tables, you Tables ease should always use indexed addressing microcontroller programming mode. It provides access to data using variable addresses. Most microcon-­ trollers have two index registers, X and Abel Raynus, Armatron International, Malden, MA H. Register X contains the low byte of  When creating microcontroller the conditional address of the operand; START firmware, you often need to H contains the high byte. The algo-­ work with data arrays. Tables make rithm of working with tables is straight-­ CLEAR REGISTER X easy work of data arrays, such as those CLEAR REGISTER H forward. After you detect the input for digital-code transformation, correc-­ value, you should then compare it with tion for sensor linearity, sophisticated GET THE INPUT VALUE, V the table’s input data. The X index de-­ calculations, and multiple output orga-­ termines this value, starting with X50 nization. Table 1 shows how you can and ending with X5N. In this exam-­ organize data in a table. Outputs A, B, V=VX? YES ple, N54. When you find table data and C have values based on the input equal to the input value, you use the NO value, V. AX�REGISTER A corresponding X as an index to load the When using a lookup table, choose X>N? YES BX�REGISTER B output registers with their values. In the CX�REGISTER C the proper microcontroller input and case of 2-byte numbers, you should load outputs. Assign values for input and NO the output registers separately, first with outputs data in Table 2. These data can INCREMENT X a high byte and then with a low one. consist of constants in binary, hexadec-­ Figure 1 illustrates this process. imal, or decimal format or names. For END The listing of assembler code is names, you should assign a constant available from the online version of value to each one. For example: this Design Idea at www.edn.com/ data1 equ $0a Figure 1 You can use a look-up table article/100422dib. In the listing, you data2 equ $0b in microcontroller code. can double-check the table content data3 equ $0c in memory at addresses $F800 through data3 equ $0d ORG ROM $F813. The listing uses Freescale (www. Next, put the data from Table 2 in ei-­ Vx FCB 0T,2T,4T,6T freescale.com) assembler because most ther the beginning or the end of ROM, Ax FCB data1,data2,data3,data4 of the appropriate applications employ which makes the data easy to find. For Bx FCB $aa,$bb,$cc,$dd inexpensive, 8-bit microcontrollers edn100401di46341 DIANE definition of 1-byte data storage, use Cx FDBTHE 4-8 FOLDER) (PLACED IN $1122,$3344,$5566,$7788 from Freescale’s HC08 Nitron family. pseudo operators FCB or DB. For stor-­ Note that commas separate the data. You can, however, use this approach age of data comprising 2 bytes, use FDB Don’t place a comma after the last with any type of microcontroller and or DW, as in the following example: data, or it will be considered as $00. assembly language.EDN Table 1 Output values versus input values Table 2 Input and output values Input V Output A Output B Output C Input V Output A Output B Output C V1 A1 B1 C1 V1=0T data1 $aa $1122 V2 A2 B2 C2 V2=2T data2 $bb $3344 .... .... .... .... V3=4T data3 $cc $5566 VN AN BN CN V4=6T data4 $dd $7788 indication of both the direction and Monitor alarm and indicator display the magnitude of the temperature’s de-­ multiple deviation boundaries viation from a user-set mean in a sol-­ der pot. Using a Microchip (www.mi-­ crochip.com) 12F675 controller, the William Grill, Riverhead Systems, Lenexa, KS coded sequences allow the user to both  A low-cost monitor can visu-­ high- or low-temperature characteris-­ set the mean and scale the range of the ally indicate a process problem, tic. The microcontroller-based circuit monitored variation. The application such as a failed cabinet fan or other in Figure 1 provided a simple visual uses the controller’s internal clock and 76 EDN | April 22, 2010
  • 5. designideas two of the controller’s four ADCs. scaled boundaries to a corresponding quences of one or both LEDs. The Asserting switch S1 on Pin 4 copies display format. The processor moni-­ monitor also asserts an output on Pin 5 the input voltage under test from Pin tors both the input under test and a when the measured variation exceeds 7, which becomes the mean value. The second analog level, on Pin 6, to scale the third tabled boundary. code then evaluates the input-voltage the internal deviation/boundary tables. The circuit provides independent deviation from the mean and applies It then schedules as many as four se-­ positive- and negative-deviation ta-­ bles and multiplies the ranges by inter-­ preting the voltage on Pin 6, resulting 10 �F in the application of a multiple from 1N4148 7 TO 12V one to eight on the boundary limits. 78L05 You configure the converter reference 4.7 �F 4.7k 1 8 to use the controller’s VDD voltage. RED LED 470 Using only 8 bits of the controller’s 7 2 PARAMETER/VOLTAGE UNDER TEST 12F675 10-bit ADC, the deviation can be as 6 3 470 SCALER-SET VOLTAGE small as one step or 1/2563VDD, the GREEN LED 470 4.7k 4 5 drain-to-drain voltage. For a 5V ref-­ ALARM/ERROR erence, this voltage is approximately S1 SET MEAN RED LED 9 mV. Figure 2 shows the boundaries and their possible spans, which Pin 6 and corresponding display-format num-­ bers set (Table 1). Using the provid-­ Figure 1 This microcontroller-based circuit provides a simple visual indication of ed minimum value of the deviation/ both the direction and the magnitude of the temperature’s deviation from a user- boundary table, neglecting the error set mean in a solder pot. that results from the use of the 78L05 as a reference, and assuming the scal-­ edn100401di46321 DIANE (PLACED IN THE 4-8 FOLDER) 78 EDN | April 22, 2010
  • 6. MEAN SETPOINT Table 1 Display-format �1 (DERIVED FROM PIN 6) numbers and table-based sequence DISPLAY-FORMAT �5 �4 �3 �2 �1 1 2 3 4 5 NUMBER Display-format 20 14 9 5 2 2 5 9 14 20 DEVIATION/ number Sequence BOUNDARY COUNT �1 ADC-BIT DEVIATION FROM MEASURED VALUE TO MEAN >5 Green, red/green, PIN 5 ALARM OUTPUT red/green, red/green 5 Green, green, green/red, green/red Figure 2 Pin 6 and the corresponding display-format numbers set the boundar- 4 Green, red, green/red ies and their possible spans. 3 Green, green, green, red ing derived from Pin 6 result in 31, no/go applications or other needs. The 2 Green, green, red the first display-format step, in this ap-­ circuit may also find a use in airflow or 1 Green plication, which occurs when the mea-­ other physical-parameter monitors. 21 Red sured input deviates more than the de-­ Using the controller’s ADC, you viation/boundary-table value times the can monitor any parameter that you 22 Red, red, green scale derived from Pin 6 times 1/256 can represent with a voltage. You can 23 Red, red, red, green times the drain-to-drain voltage equals modify the code-based tables to ac-­ 24 Red, green, red/green 235/25631, or 39 mV. commodate a variety of other display You can change the display-sequence sequences, parameter nonlinearities, or 25 Red, red, red/green, formats for the five positive boundaries, error distributions. red/green beginning in a green-LED flash, and You can download Listing 1, code ,,<< <5 Red, red/green, five negative boundaries, beginning in for the error monitor, from www.edn. red/greeen, red/green a red-LED flash, to suit simpler go or com/100422dic.EDN April 22, 2010 | EDN 79