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5
3
2
3.89,2.178,5.89798
0.006+0.92+0.134
2.05+8.04+7.018
0.62 X 0.3
0.35 / 1.7
(0.3 X0.83)/(0.5 X0.1)+0.35/0.08
0.31 0.12
5.7 ,8.34,6.245
U={1,2,3,4,5,6,7}, A={1,3,5} B={2,4,6} C={3,4,5,6,7} (AUB)’ = (A’ Ո B’)
A B 35 45 (AUB) (A Ո B)
A={3,4,5} B={4,5,6} C={x,y} (A Ո B)xC
P={1,2,3}, Q={3,4} R={x,y} (PUQ) x R (P Ո Q) x R
P={3,5,7} Q={5,7} R=P/Q (P U Q)xR
Q={x,y} R={m,n,l} P(Q) P(R)
A={1,2,3} P(A)
(x-1,y+2)=(y-2,2x+1) x y
(6x-y,13)=(1,3x+ 2y) x y
A={3,4} B={2,4} xꜪA yꜪB A B x>y
  3
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=9 ab+bc+ca=8 (a+b+c)2
a+b+c=2 ab+bc+ca=1 (a+b)2
+(b+c)2
+(c+a)2
x+y+z=10 xy+yz+zx=31 (x+y)2
+(y+z)2
+(z+x)2
(x + 7) (x - 9)
(2x + 3y) (4x – 5y)
2x -
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= 3mn
a+b+c=0 a3
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p-q=r p3
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(i) ab + a –b -1
(ii) a2
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x
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ax
=b, by
=c cz
=a xyz=1
(x) logx324=4
(x) logx =-2
3log102+2log103+log105=log10360
3log102+log105 =log1040
log10 = log102 + 2log105 - log103- 2log107
loge + loge + loge - 3loge𝑏 𝑐
ᴧABC BC D AB+AC>2AD
ABC BA D BA=AD <BCD=
ᴧABC D AB+AC>BD+DC
ᴧABC <B <C O <BOC=900
+1/2<A
ABCD BC CD <B <C <D
60 1200
20 4
2 3
6
10 48
512
160 6
5 500
363
125 5
4 5 360
2
8
21:16:12 87
2400
12 5

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Math Question-2013 to 2023.pdf

  • 1. 5 3 2 3.89,2.178,5.89798 0.006+0.92+0.134 2.05+8.04+7.018 0.62 X 0.3 0.35 / 1.7 (0.3 X0.83)/(0.5 X0.1)+0.35/0.08 0.31 0.12 5.7 ,8.34,6.245 U={1,2,3,4,5,6,7}, A={1,3,5} B={2,4,6} C={3,4,5,6,7} (AUB)’ = (A’ Ո B’) A B 35 45 (AUB) (A Ո B) A={3,4,5} B={4,5,6} C={x,y} (A Ո B)xC P={1,2,3}, Q={3,4} R={x,y} (PUQ) x R (P Ո Q) x R P={3,5,7} Q={5,7} R=P/Q (P U Q)xR Q={x,y} R={m,n,l} P(Q) P(R) A={1,2,3} P(A) (x-1,y+2)=(y-2,2x+1) x y (6x-y,13)=(1,3x+ 2y) x y A={3,4} B={2,4} xꜪA yꜪB A B x>y   3 5 4    x x x f     2 , 1 f f        2 1 f   1 2 1 2    x x x f 1 ) 1 ( 1 ) 1 ( 2 2   x f x f   1 3 1 3    x x x f 1 ) 1 ( 1 ) 1 (   x f x f   2 4 2 1 x x x x g    ) ( ) 1 ( 2 2 x g x g    8 4 2 3     y ky y y f k   0 2   f
  • 2. a2 +b2 +c2 =9 ab+bc+ca=8 (a+b+c)2 a+b+c=2 ab+bc+ca=1 (a+b)2 +(b+c)2 +(c+a)2 x+y+z=10 xy+yz+zx=31 (x+y)2 +(y+z)2 +(z+x)2 (x + 7) (x - 9) (2x + 3y) (4x – 5y) 2x - x 2 = 3 x2 + 2 1 x x - x 1 = 4 x4 - 4 1 x = 322 7   b a 5   b a   24 8 2 2   b a ab a - a 1 = 1 a3 - 3 1 a = 4 2x - x 2 = 3 8 x3 - 3 1 x 63 2 3   a a3 + 3 1 a = 18 3 0 1 3 2    a a a3 + 3 1 a a3 -b3 =513 a-b=3 ab a+b=m, a2 +b2 =n a3 -b3 = p3 m3 +2p3 = 3mn a+b+c=0 a3 +b3 +c3 =3abc p-q=r p3 -q3 -r3 =3pqr (i) ab + a –b -1 (ii) a2 +6a+8-y2 +2y (iii) 16x2 -25y2 -8xy+10yz (iv) 1 27 2 4   a a (v) 4 2 2 4 6 y y x x   (vi) (a2 -b2 )(x2 -y2 )+4abxy (vii) 20 2 4   x x (viii)4x4 – 27x2 – 81 (ix) a x a ax    ) 1 ( 2 2 (x) 3(a2 +2a) – 22(a2 +2a) + 40 (xi) (a-1)x2 +a2xy+(a+1)y2 (xii) 27 8 3 3 b a  (xiii) 8 1 3  a (xiv) 8 1 3  a (xv) 6 5 2 2 3    x x x (xvi) a3 – 6a2 + 12a -9 (xvii) x3 – x -6 (xviii) 24 3   x x 7 650 6 4% 2 1 11 10% 36 72
  • 3. y x 1  . z y 1  . x z 1  (2a-1 + 3b-1 )-1 2 2 2 . 4 2 2 1 4      n n n 1 ) .( ) .( ) (  m l n l n m n m l a a a a a a 1 ) .( ) .( ) ( 1 1 1  ca a c bc c b ab b a x x x x x x ax =b, by =c cz =a xyz=1 (x) logx324=4 (x) logx =-2 3log102+2log103+log105=log10360 3log102+log105 =log1040 log10 = log102 + 2log105 - log103- 2log107 loge + loge + loge - 3loge𝑏 𝑐 ᴧABC BC D AB+AC>2AD ABC BA D BA=AD <BCD= ᴧABC D AB+AC>BD+DC ᴧABC <B <C O <BOC=900 +1/2<A ABCD BC CD <B <C <D
  • 4. 60 1200 20 4 2 3 6 10 48 512 160 6 5 500 363 125 5 4 5 360 2 8 21:16:12 87 2400 12 5