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Challenge 1 Qn. Mensuration Solution
1.
2. Solution : The shaded region gives the common area that both horses can graze. A B C D 6 6 6 6
3. In order to get a better idea about this region, join BD B and D are centers of two intersecting circles of radius 6 cms each. Length of BD = 6 cms each Length of BD = A B C D
4. BE = 6 m BD = 6 BD = BD is the r bisector of EF (common chord) EGB is art EG 2 + BG 2 = BE2 => EG = 3m => EF = 6m BEF is equilateral E G J D B H F
5. Area of segment EJF = area (sector EJFB) – area ( BEF) = = 6 - 9 Common area that they can graze = 2 x (area of segment EJF) = 2 x (6 - 9 ) = 12 - 18 B F E J