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Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
Chapter 6.1 6.2
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Chapter 6.1 6.2

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  • 1.   An equation of a line can be written in slopeintercept form y = mx + b where m is the slope and b is the yintercept. The y-intercept is where a line crosses the yaxis.
  • 2.  Suppose the slope of a line is 5 and the yintercept is 2. How would this you write the equation of this line in slope-intercept form?  First write the slope-intercept form. y = mx + b  Now substitute 5 for m and 2 for b. y = 5x + 2
  • 3.   y = mx + b y = 2x + (-4) y = 2x -4 Where does the line cross the y-axis? ◦ At the point (0, -4) ◦ The y-intercept is -4. What is the slope of the line? ◦ The graph also crosses the x-axis at (2, 0). ◦ We can use the slope formula to find our slope. m = -4 – 0 = -4 = 2 0 – 2 -2 We know our slope is 2 and our y-intercept is -4, what is the equation of our line?
  • 4.  Write the equation of a line with a slope of -2 and a y-intercept of 6.   y = mx + b y = -2x + 6  Write the equation of a line with a slope of -4/3 and a y-intercept of 1.   y = mx + b y = (-4/3) + 1
  • 5.  Where does the line cross the y-axis? ◦ ◦   At the point (0, 2) So the y-intercept b is 2. The line also passes through the point (3, 0). We can use these points to find the slope of the line. How? What formula do we use? ◦ ◦ Using the slope formula, we find that the slope m is -2/3. Write the equation of the line.   y= mx + b y = (-2/3)x + 2
  • 6.  Step 1:  First find the y-intercept. Substitute the slope m and the coordinates of the given point (x, y) into the slope-intercept form, y = mx + b. Then solve for the y-intercept b.  Step 2:  Then write the equation of the line. Substitute the slope m and the y-intercept b into the slopeintercept form, y = mx + b.
  • 7.  Suppose we have a slope of -3 and it passes through the point (1, 2). ◦ We first need to find the y-intercept. We can do this by substituting our information into slope-intercept form and solving for b.     y = mx + b 2 = -3(1) + b 2 = -3 + b 5=b is 5.   y = mx + b y = -3x + 5 Add 3 to both sides. Now we know that the y-intercept
  • 8.  Suppose we have a line with a slope of -1 and passes through the point (3, 4).        y = mx + b 4 = (-1)3 + b 4 = -3 + b 7=b y = mx + b y = (-1)x + 7 y = -x + 7  Suppose we have a line with a slope of 2 and passes through the point (1, 3).       y = mx + b 3 = 2(1) + b 3=2+b 1=b y = mx + b y = 2x + 1
  • 9.  Write an equation f the line that passes through (-2,5) and (2,1).

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