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Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. J Operations Scheduling For Operations Management, 9e by Krajewski/Ritzman/Malhotra © 2010 Pearson Education PowerPoint Slides by Jeff Heyl
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. The scheduling techniques cut across the various process types found in services and manufacturing Front-office process with high customer contact, divergent work flows, customization, and a complex scheduling environment Back-office process has low customer involvement, uses more line work flows, and provides standardized services Scheduling Service and Manufacturing Processes
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Performance Measures Flow time is the amount of time a job spends in the service or manufacturing system Past due (tardiness) is the amount of time by which a job missed its due date Makespan is the total amount of time required to complete a group of jobs
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Performance Measures Total inventory is used to measure the effectiveness of schedules for manufacturing processes. ,[object Object],[object Object]
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Sequencing Jobs An operation with line flow is often called a flow shop Medium- to high-volume production Utilizes line or continuous flow processes The back office would be the equivalent for a service provider  Tasks are easier to schedule because the jobs have a common flow pattern through the system
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Shipping Department Raw Materials Legend: Batch of parts Workstation Job Shop Sequencing Figure J.1 – Diagram of a Manufacturing Job Shop Process
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. First-come, first-served (FCFS)  Earliest due date (EDD) Critical ratio (CR) Priority Sequencing Rules (Due date) – (Today’s date) Total shop time remaining CR = ,[object Object]
A ratio greater than 1.0 implies the job is ahead of schedule
The job with the lowest CR is scheduled next,[object Object],[object Object]
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules EXAMPLE J.1 The Taylor Machine Shop rebores engine blocks. Currently, five engine blocks are waiting for processing. At any time, the company has only one engine expert on duty who can do this type of work. The engine problems have been diagnosed, and the processing times for the jobs have been estimated. Expected completion times have been agreed upon with the shop’s customers. The accompanying table shows the current situation. Because the Taylor Machine Shop is open from 8:00 A.M. until 5:00 P.M. each weekday, plus weekend hours as needed, the customer pickup times are measured in business hours from the current time. Determine the schedule for the engine expert by using (a) the EDD rule and (b) the SPT rule. For each rule, calculate the average flow time, average hours early, and average hours past due. If average past due is most important, which rule should be chosen?
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules SOLUTION a.	The EDD rule states that the first engine block in the sequence is the one with the closest due date. Consequently, the Ranger engine block is processed first. The Thunderbird engine block, with its due date furthest in the future, is processed last. The sequence is shown in the following table, along with the flow times, the hours early, and the hours past due.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules The flow time for each job is its finish time, plus the time since the job arrived.1 For example, the Explorer engine block’s finish time will be 14 hours from now (8 hours waiting time before the engine expert started to work on it plus 6 hours processing). Adding the 10 hours since the order arrived at this workstation (before the processing of this group of orders began) results in a flow time of 24 hours. You might think of the sum of flow times as the total job hours spent by the engine blocks since their orders arrived at the workstation until they were processed.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules 20 + 24 + 20 + 33 + 44 5 = 28.2 hrs 2 + 0 + 1 + 0 + 0 5 = 0.6 hrs 0 + 2 + 0 + 12 + 22 5 = 7.2 hrs The performance measures for the EDD schedule for the five engine blocks are Average flow time = Average hours early = Average hours past due =
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules b.	Under the SPT rule, the sequence starts with the engine block that has the shortest processing time, the Econoline 150, and it ends with the engine block that has the longest processing time, the Bronco. The sequence, along with the flow times, early hours, and past due hours, is contained in the following table:
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules 6 + 19 + 29 + 29 + 45 5 = 25.6 hrs 15 + 3 + 0 + 0 + 0 5 = 3.6 hrs 0 + 0 + 7 + 7 + 24 5 = 7.6 hrs The performance measures are Average flow time = Average hours early = Average hours past due =
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing Sequencing Rules EDD rule Performs well with respect to the percentage of jobs past due and the variance of hours past due Popular with firms that are sensitive to achieving due dates ,[object Object]
Tends to minimize the mean flow and maximize shop utilization
For single-workstations will always provide the lowest mean finish time
Could increase total inventory
Tends to produce a large variance in past due hours
FCFS rule
Considered fair
It performs poorly with respect to all performance measures,[object Object]
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.1
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Multiple-Dimension Rules The priority rules CR and S/RO incorporate information about the remaining workstations ,[object Object]
CR results in longer job flow times than SPT, but CR also results in less variance in the distribution of past due hours
No choice is clearly best; each rule should be tested in the environment for which it is intended,[object Object]
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. CR = =          = 2.46 Time remaining until the due date Shop time remaining 15 6.1 Sequencing with the CR and S/RO Rules SOLUTION a.	Using CR to schedule the machine, we divide the time remaining until the due date by the shop time remaining to get the priority index for each job. For job 1, By arranging the jobs in sequence with the lowest critical ratio first, we determine that the sequence of jobs to be processed by the engine lathe is 4, 2, 3, and finally 1, assuming that no other jobs arrive in the meantime.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. S/RO = =                  = 0.89 Time remaining until the due date Shop time remaining – 15 – 6.1 10 Number of operations remaining  Sequencing with the CR and S/RO Rules b.	Using S/RO, we divide the difference between the time remaining until the due date and the shop time remaining by the number of remaining operations. For job 1, Arranging the jobs by starting with the lowest S/RO yields a 4, 3, 1, 2 sequence of jobs.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Sequencing with the CR and S/RO Rules
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.2 The following four jobs have just arrived at an idle drill process and must be scheduled. *  including drill press Create the sequences for two schedules, one using the Critical Ratio rule and one using the S/RO rule.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.2
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Identifying the best priority rule to use at a particular operation in a process is a complex problem because the output from one operation becomes the input to another Computer simulation models are effective tools to determine which priority rules work best in a given situation Multiple Workstations
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. In single-workstation scheduling, the makespan is the same regardless of the priority rule chosen In the scheduling of two or more workstations in a flow shop, the makespan varies according to the sequence chosen Determining a production sequence for a group of jobs to minimize the makespan has two advantages The group of jobs is completed in minimum time The utilization of the two-station flow shop is maximized Scheduling a Two-Station Flow Shop
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Johnson’s Rule Minimizes makespan when scheduling a group of jobs on two workstations Step 1:	Scan the processing time at each workstation and find the shortest processing time among the jobs not yet scheduled. If two or more jobs are tied, choose one job arbitrarily. Step 2:	If the shortest processing time is on workstation 1, schedule the corresponding job as early as possible.  If the shortest processing time is on workstation 2, schedule the corresponding job as late as possible. Step 3:	Eliminate the last job scheduled from further consideration.  Repeat steps 1 and 2 until all jobs have been scheduled.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations EXAMPLE J.3 The Morris Machine Company just received an order to refurbish five motors for materials handling equipment that were damaged in a fire. The motors have been delivered and are available for processing. The motors will be repaired at two workstations in the following manner. Workstation 1:	Dismantle the motor and clean the parts. Workstation 2:	Replace the parts as necessary, test the motor, and make adjustments.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations The customer’s shop will be inoperable until all the motors have been repaired, so the plant manager is interested in developing a schedule that minimizes the makespan and has authorized around-the-clock operations until the motors have been repaired. The estimated time to repair each motor is shown in the following table:
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations SOLUTION The logic for the optimal sequence is shown in the following table:
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Workstation M2  M1  M4  M5  M3  Idle—available  1 (4) (12) (15) (10) (5) for further work M2  M1  M4  M5  M3  Idle Idle 2 (5) (22) (16) (8) (3) 0 5 10 15 20 25 30 35 40 45 50 55 60 65 Hour Scheduling Jobs on Two Workstations Figure J.2 – Gantt Chart for the Morris Machine Company Repair Schedule
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.3 Use the following data to schedule two workstations arranged as a flow shop C B E D A
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.3
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. The resource constraint is the amount of labor available, not the number of machines or workstations The scheduler must also assign workers to their next workstations Labor-Limited Environment ,[object Object]
Assign personnel to the workstation with the job that has been in the system longest
Assign personnel to the workstation with the most jobs waiting for processing
Assign personnel to the workstation with the largest standard work content
Assign personnel to the workstation with the job that has the earliest due date,[object Object]
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 a.	Develop separate schedules by using the SPT and EDD rules b.	Compare the two schedules on the basis of average flow time, percentage of past due jobs, and maximum past due days for any engine
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 SOLUTION a.	Using the SPT rule, we obtain the following schedule:
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 Using the EDD rule we obtain this schedule:
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 b.	Performance measures are as follows: Average flow time is 16.6 (or 83/5) days for SPT and 22.0 (or 110/5) days for EDD. The percentage of past due jobs is 40 percent (2/5) for SPT and 60 percent (3/5) for EDD. For this set of jobs, the EDD schedule minimizes the maximum days past due but has a greater flow time and causes more jobs to be past due.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 The following data were reported by the shop floor control system for order processing at the edge grinder. The current date is day 150. The number of remaining operations and the total work remaining include the operation at the edge grinder. All orders are available for processing, and none have been started yet. Assume the jobs were available for processing at the same time.
Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 a.	Specify the priorities for each job if the shop floor control system uses slack per remaining operations (S/RO) or critical ratio (CR). b.	For each priority rule, calculate the average flow time per job at the edge grinder.

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  • 1. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. J Operations Scheduling For Operations Management, 9e by Krajewski/Ritzman/Malhotra © 2010 Pearson Education PowerPoint Slides by Jeff Heyl
  • 2. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. The scheduling techniques cut across the various process types found in services and manufacturing Front-office process with high customer contact, divergent work flows, customization, and a complex scheduling environment Back-office process has low customer involvement, uses more line work flows, and provides standardized services Scheduling Service and Manufacturing Processes
  • 3. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Performance Measures Flow time is the amount of time a job spends in the service or manufacturing system Past due (tardiness) is the amount of time by which a job missed its due date Makespan is the total amount of time required to complete a group of jobs
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  • 5. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Sequencing Jobs An operation with line flow is often called a flow shop Medium- to high-volume production Utilizes line or continuous flow processes The back office would be the equivalent for a service provider Tasks are easier to schedule because the jobs have a common flow pattern through the system
  • 6. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Shipping Department Raw Materials Legend: Batch of parts Workstation Job Shop Sequencing Figure J.1 – Diagram of a Manufacturing Job Shop Process
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  • 8. A ratio greater than 1.0 implies the job is ahead of schedule
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  • 10. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules EXAMPLE J.1 The Taylor Machine Shop rebores engine blocks. Currently, five engine blocks are waiting for processing. At any time, the company has only one engine expert on duty who can do this type of work. The engine problems have been diagnosed, and the processing times for the jobs have been estimated. Expected completion times have been agreed upon with the shop’s customers. The accompanying table shows the current situation. Because the Taylor Machine Shop is open from 8:00 A.M. until 5:00 P.M. each weekday, plus weekend hours as needed, the customer pickup times are measured in business hours from the current time. Determine the schedule for the engine expert by using (a) the EDD rule and (b) the SPT rule. For each rule, calculate the average flow time, average hours early, and average hours past due. If average past due is most important, which rule should be chosen?
  • 11. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules
  • 12. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules SOLUTION a. The EDD rule states that the first engine block in the sequence is the one with the closest due date. Consequently, the Ranger engine block is processed first. The Thunderbird engine block, with its due date furthest in the future, is processed last. The sequence is shown in the following table, along with the flow times, the hours early, and the hours past due.
  • 13. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules The flow time for each job is its finish time, plus the time since the job arrived.1 For example, the Explorer engine block’s finish time will be 14 hours from now (8 hours waiting time before the engine expert started to work on it plus 6 hours processing). Adding the 10 hours since the order arrived at this workstation (before the processing of this group of orders began) results in a flow time of 24 hours. You might think of the sum of flow times as the total job hours spent by the engine blocks since their orders arrived at the workstation until they were processed.
  • 14. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules 20 + 24 + 20 + 33 + 44 5 = 28.2 hrs 2 + 0 + 1 + 0 + 0 5 = 0.6 hrs 0 + 2 + 0 + 12 + 22 5 = 7.2 hrs The performance measures for the EDD schedule for the five engine blocks are Average flow time = Average hours early = Average hours past due =
  • 15. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules b. Under the SPT rule, the sequence starts with the engine block that has the shortest processing time, the Econoline 150, and it ends with the engine block that has the longest processing time, the Bronco. The sequence, along with the flow times, early hours, and past due hours, is contained in the following table:
  • 16. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Comparing EDD and SPT Rules 6 + 19 + 29 + 29 + 45 5 = 25.6 hrs 15 + 3 + 0 + 0 + 0 5 = 3.6 hrs 0 + 0 + 7 + 7 + 24 5 = 7.6 hrs The performance measures are Average flow time = Average hours early = Average hours past due =
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  • 18. Tends to minimize the mean flow and maximize shop utilization
  • 19. For single-workstations will always provide the lowest mean finish time
  • 20. Could increase total inventory
  • 21. Tends to produce a large variance in past due hours
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  • 25. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.1
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  • 27. CR results in longer job flow times than SPT, but CR also results in less variance in the distribution of past due hours
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  • 29. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. CR = = = 2.46 Time remaining until the due date Shop time remaining 15 6.1 Sequencing with the CR and S/RO Rules SOLUTION a. Using CR to schedule the machine, we divide the time remaining until the due date by the shop time remaining to get the priority index for each job. For job 1, By arranging the jobs in sequence with the lowest critical ratio first, we determine that the sequence of jobs to be processed by the engine lathe is 4, 2, 3, and finally 1, assuming that no other jobs arrive in the meantime.
  • 30. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. S/RO = = = 0.89 Time remaining until the due date Shop time remaining – 15 – 6.1 10 Number of operations remaining Sequencing with the CR and S/RO Rules b. Using S/RO, we divide the difference between the time remaining until the due date and the shop time remaining by the number of remaining operations. For job 1, Arranging the jobs by starting with the lowest S/RO yields a 4, 3, 1, 2 sequence of jobs.
  • 31. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Sequencing with the CR and S/RO Rules
  • 32. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.2 The following four jobs have just arrived at an idle drill process and must be scheduled. * including drill press Create the sequences for two schedules, one using the Critical Ratio rule and one using the S/RO rule.
  • 33. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.2
  • 34. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Identifying the best priority rule to use at a particular operation in a process is a complex problem because the output from one operation becomes the input to another Computer simulation models are effective tools to determine which priority rules work best in a given situation Multiple Workstations
  • 35. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. In single-workstation scheduling, the makespan is the same regardless of the priority rule chosen In the scheduling of two or more workstations in a flow shop, the makespan varies according to the sequence chosen Determining a production sequence for a group of jobs to minimize the makespan has two advantages The group of jobs is completed in minimum time The utilization of the two-station flow shop is maximized Scheduling a Two-Station Flow Shop
  • 36. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Johnson’s Rule Minimizes makespan when scheduling a group of jobs on two workstations Step 1: Scan the processing time at each workstation and find the shortest processing time among the jobs not yet scheduled. If two or more jobs are tied, choose one job arbitrarily. Step 2: If the shortest processing time is on workstation 1, schedule the corresponding job as early as possible. If the shortest processing time is on workstation 2, schedule the corresponding job as late as possible. Step 3: Eliminate the last job scheduled from further consideration. Repeat steps 1 and 2 until all jobs have been scheduled.
  • 37. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations EXAMPLE J.3 The Morris Machine Company just received an order to refurbish five motors for materials handling equipment that were damaged in a fire. The motors have been delivered and are available for processing. The motors will be repaired at two workstations in the following manner. Workstation 1: Dismantle the motor and clean the parts. Workstation 2: Replace the parts as necessary, test the motor, and make adjustments.
  • 38. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations The customer’s shop will be inoperable until all the motors have been repaired, so the plant manager is interested in developing a schedule that minimizes the makespan and has authorized around-the-clock operations until the motors have been repaired. The estimated time to repair each motor is shown in the following table:
  • 39. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Scheduling Jobs on Two Workstations SOLUTION The logic for the optimal sequence is shown in the following table:
  • 40. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Workstation M2 M1 M4 M5 M3 Idle—available 1 (4) (12) (15) (10) (5) for further work M2 M1 M4 M5 M3 Idle Idle 2 (5) (22) (16) (8) (3) 0 5 10 15 20 25 30 35 40 45 50 55 60 65 Hour Scheduling Jobs on Two Workstations Figure J.2 – Gantt Chart for the Morris Machine Company Repair Schedule
  • 41. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.3 Use the following data to schedule two workstations arranged as a flow shop C B E D A
  • 42. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Application J.3
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  • 44. Assign personnel to the workstation with the job that has been in the system longest
  • 45. Assign personnel to the workstation with the most jobs waiting for processing
  • 46. Assign personnel to the workstation with the largest standard work content
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  • 48. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 a. Develop separate schedules by using the SPT and EDD rules b. Compare the two schedules on the basis of average flow time, percentage of past due jobs, and maximum past due days for any engine
  • 49. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 SOLUTION a. Using the SPT rule, we obtain the following schedule:
  • 50. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 Using the EDD rule we obtain this schedule:
  • 51. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 1 b. Performance measures are as follows: Average flow time is 16.6 (or 83/5) days for SPT and 22.0 (or 110/5) days for EDD. The percentage of past due jobs is 40 percent (2/5) for SPT and 60 percent (3/5) for EDD. For this set of jobs, the EDD schedule minimizes the maximum days past due but has a greater flow time and causes more jobs to be past due.
  • 52. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 The following data were reported by the shop floor control system for order processing at the edge grinder. The current date is day 150. The number of remaining operations and the total work remaining include the operation at the edge grinder. All orders are available for processing, and none have been started yet. Assume the jobs were available for processing at the same time.
  • 53. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 a. Specify the priorities for each job if the shop floor control system uses slack per remaining operations (S/RO) or critical ratio (CR). b. For each priority rule, calculate the average flow time per job at the edge grinder.
  • 54. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 SOLUTION a. We specify the priorities for each job using the two sequencing rules. The sequence for S/RO is shown in the brackets.
  • 55. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 The sequence of production for CR is shown in the brackets.
  • 56. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 2 b. We are sequencing a set of jobs at a single machine, so each job’s finish time equals the finish time of the job just prior to it in sequence plus its own processing time. Further, all jobs were available for processing at the same time, so each job’s finish time equals its flow time. Consequently, the average flow times at this single machine are In this example, the average flow time per job is lower for the CR rule, which is not always the case. For example, the critical ratios for B272 and A101 are tied at 1.33. If we arbitrarily assigned A101 before B272, the average flow time would increase to (8 + 12 + 22 + 29 + 44)/5 = 23.0 hours.
  • 57. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 3 The Rocky Mountain Arsenal, formerly a chemical warfare manufacturing site, is said to be one of the most polluted locations in the United States. Cleanup of chemical waste storage basins will involve two operations. Operation 1: Drain and dredge basin. Operation 2: Incinerate materials. Management estimates that each operation will require the following amounts of time (in days):
  • 58. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 3 Management’s objective is to minimize the makespan of the cleanup operations. All storage basins are available for processing right now. First, find a schedule that minimizes the makespan. Then calculate the average flow time of a storage basin through the two operations. What is the total elapsed time for cleaning all 10 basins? Display the schedule in a Gantt machine chart. SOLUTION We can use Johnson’s rule to find the schedule that minimizes the total makespan. Four jobs are tied for the shortest process time: A, D, E, and H. E and H are tied for first place, while A and D are tied for last place. We arbitrarily choose to start with basin E, the first on the list for the drain and dredge operation. The 10 steps used to arrive at a sequence are as follows:
  • 59. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 3
  • 60. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. Solved Problem 3 Several optimal solutions are available to this problem because of the ties at the start of the scheduling procedure. However, all have the same makespan. The schedule would be as follows:
  • 61. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall. E H G F B J I C D A Dredge E H G F B J I C D A Solved Problem 3 Incinerate The makespan is 36 days. The average flow time is the sum of incineration finish times divided by 10, or 200/10 = 20 days. The Gantt machine chart for this schedule is given in Figure J.3. Storage Basin Figure J.3
  • 62. Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall.