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LIMITS
OF
FUNCTIONS
CONTINUITY
Definition 1.5.1 (p. 110)
If one or more of the above conditions fails to hold
at C the function is said to be discontinuous.
DEFINITION: CONTINUITY OF A FUNCTION
Theorem 1.5.3 (p. 113)
Question 8
EXAMPLE
Solution:
( )
( ) ( )2 2 36
3
x xx x
f x
x
+ −− −
= =
− 3x −
( )
2
2 3
x
f x x where x
= +
∴ = − ≠
1. Given the function f defined as ,
draw a sketch of the graph of f, then by observing
where there are breaks in the graph, determine the
values of the independent variable at which the
function is discontinuous and why each is
discontinuous.
( )
2
6
3
x x
f x
x
− −
=
−
•
•
•
•

y
x
Test for continuity: at x=3
1.f(3) is not defined; since the first
condition is not satisfied then f is
discontinuous at x=3.
Question 8
2. Given the function f defined as
draw a sketch of the graph of f, then by observing
where there are breaks in the graph, determine the
values of the independent variable at which the
function is discontinuous and why each is
discontinuous.
EXAMPLE
( )
if
if
2
6
3
3
2 3
x x
x
f x x
x
 − −
≠
= −
 =
•
•
•
•

y
x
•
Solution:
( )
( )( )
( )
3xatousdiscontinuisftherefore
)3(f)x(flimbutexistsitlimThe
2)3(fand5)x(flim.3
523
2xlim
3x
2x3x
lim
3x
6xx
lim)x(flim.2
2toequalisanddefinedis3f.1
:continuityforTest
3x
3x
3x
3x
2
3x3x
=
≠
==
=+=
+=
−
+−
=
−
−−
=
→
→
→
→
→→
Question 8Question 8
EXAMPLE
3. Given the function f defined as ,
draw a sketch of the graph of f, then by observing
where there are breaks in the graph, determine the
values of the independent variable at which the
function is discontinuous and why each is
discontinuous.
( )
if
if
2
1
0
2 0
x
f x x
x

≠
= 
 =
2
0
2
0
1 1
lim
0
1 1
lim
0
0
x
x
x
x
x is a VA
+
−
→
+
→
+
= = +∞
= = +∞
∴ =
VAais0x
0xif
x
1
)x(f
:Graph
2
=
≠=
2
2
1
lim 0
1
lim 0
0
x
x
x
x
y is a HA
→+∞
→−∞
=
=
∴ =
HA
0xatousdiscontinu
isfthensatisfiednotis
conditionondsectheSince
existsnotdoeslim.2
defined;2)0(f.1
:continuityforTest
0x
=
+∞=
=
→
Question 8Question 8
Solution:
y
x
1
-1 1
•
Figure 1.5.1 (p. 110)
The figure above illustrates the
function not defined at x=c,
which violates the first condition.
The figure above illustrates that the limit
coming from the right and left both exist
but are not equal, thus the two sided limit
does not exist which violates the second
condition. This kind of discontinuity is called
jump discontinuity.
Figure 1.51 (p. 110)
The figure above illustrates that the limit
coming from the right and left of c are
both , thus the two sided limit does
not exist which violates the second
condition. This kind of discontinuity is
called infinite discontinuity.
∞+
The figure above illustrates the function
defined at c and that the limit coming from
the right and left of c both exist thus the two
sided limit exist. But
which violates the third condition.
This kind of discontinuity is called
removable discontinuity.
)x(flim)c(f
cx→
≠
2
y
x
)x(fy =
2x
4x
)x(fgiven
;2xatcontinuousisfunctionthewhethereminDeter
2
−
−
=
=

( )( )
( )
2xatcontinuousdishenceand
2xatundefinedis)x(fthus
2xbut;422)2(f
2x)x(f
2x
2x2x
)x(f
=
=
≠=+=
+=
−
−+
=
4
2
4
y
x
)x(gy =
3 •





=
≠
−
−
=
=
2x,3
2x,
2x
4x
)x(ggiven
;2xatcontinuousisfunctionthewhethereminDeter
2
( )( )
( )
2xatcontinuousdishence
)2(g)x(glimthecesin
3)2(g
4)x(glimthus
4)x(glim)x(glim
2x)x(g
2x
2x2x
)x(g
2x
2x
2x2x
=
≠
=
=
==
+=
−
−+
=
→
→
→→ −+

Removable Discontinuity





=
≠
−
−
=
=
2x,4
2x,
2x
4x
)x(hgiven
;2xatcontinuousisfunctionthewhethereminDeter
2
( )( )
( )
2xatcontinuoushence
)2(h)x(hlimthecesin
4)2(h
4)x(hlimthus
4)x(hlim)x(hlim
2x)x(h
2x
2x2x
)x(h
2x
2x
2x2x
=
=
=
=
==
+=
−
−+
=
→
→
→→ −+
2
4
y
x
•

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L6 continuity

  • 3. Definition 1.5.1 (p. 110) If one or more of the above conditions fails to hold at C the function is said to be discontinuous. DEFINITION: CONTINUITY OF A FUNCTION
  • 5. Question 8 EXAMPLE Solution: ( ) ( ) ( )2 2 36 3 x xx x f x x + −− − = = − 3x − ( ) 2 2 3 x f x x where x = + ∴ = − ≠ 1. Given the function f defined as , draw a sketch of the graph of f, then by observing where there are breaks in the graph, determine the values of the independent variable at which the function is discontinuous and why each is discontinuous. ( ) 2 6 3 x x f x x − − = −
  • 6. • • • •  y x Test for continuity: at x=3 1.f(3) is not defined; since the first condition is not satisfied then f is discontinuous at x=3.
  • 7. Question 8 2. Given the function f defined as draw a sketch of the graph of f, then by observing where there are breaks in the graph, determine the values of the independent variable at which the function is discontinuous and why each is discontinuous. EXAMPLE ( ) if if 2 6 3 3 2 3 x x x f x x x  − − ≠ = −  =
  • 9. ( ) ( )( ) ( ) 3xatousdiscontinuisftherefore )3(f)x(flimbutexistsitlimThe 2)3(fand5)x(flim.3 523 2xlim 3x 2x3x lim 3x 6xx lim)x(flim.2 2toequalisanddefinedis3f.1 :continuityforTest 3x 3x 3x 3x 2 3x3x = ≠ == =+= += − +− = − −− = → → → → →→
  • 10. Question 8Question 8 EXAMPLE 3. Given the function f defined as , draw a sketch of the graph of f, then by observing where there are breaks in the graph, determine the values of the independent variable at which the function is discontinuous and why each is discontinuous. ( ) if if 2 1 0 2 0 x f x x x  ≠ =   =
  • 11. 2 0 2 0 1 1 lim 0 1 1 lim 0 0 x x x x x is a VA + − → + → + = = +∞ = = +∞ ∴ = VAais0x 0xif x 1 )x(f :Graph 2 = ≠= 2 2 1 lim 0 1 lim 0 0 x x x x y is a HA →+∞ →−∞ = = ∴ = HA 0xatousdiscontinu isfthensatisfiednotis conditionondsectheSince existsnotdoeslim.2 defined;2)0(f.1 :continuityforTest 0x = +∞= = →
  • 13. Figure 1.5.1 (p. 110) The figure above illustrates the function not defined at x=c, which violates the first condition. The figure above illustrates that the limit coming from the right and left both exist but are not equal, thus the two sided limit does not exist which violates the second condition. This kind of discontinuity is called jump discontinuity.
  • 14. Figure 1.51 (p. 110) The figure above illustrates that the limit coming from the right and left of c are both , thus the two sided limit does not exist which violates the second condition. This kind of discontinuity is called infinite discontinuity. ∞+ The figure above illustrates the function defined at c and that the limit coming from the right and left of c both exist thus the two sided limit exist. But which violates the third condition. This kind of discontinuity is called removable discontinuity. )x(flim)c(f cx→ ≠
  • 15. 2 y x )x(fy = 2x 4x )x(fgiven ;2xatcontinuousisfunctionthewhethereminDeter 2 − − = =  ( )( ) ( ) 2xatcontinuousdishenceand 2xatundefinedis)x(fthus 2xbut;422)2(f 2x)x(f 2x 2x2x )x(f = = ≠=+= += − −+ = 4
  • 16. 2 4 y x )x(gy = 3 •      = ≠ − − = = 2x,3 2x, 2x 4x )x(ggiven ;2xatcontinuousisfunctionthewhethereminDeter 2 ( )( ) ( ) 2xatcontinuousdishence )2(g)x(glimthecesin 3)2(g 4)x(glimthus 4)x(glim)x(glim 2x)x(g 2x 2x2x )x(g 2x 2x 2x2x = ≠ = = == += − −+ = → → →→ −+  Removable Discontinuity
  • 17.      = ≠ − − = = 2x,4 2x, 2x 4x )x(hgiven ;2xatcontinuousisfunctionthewhethereminDeter 2 ( )( ) ( ) 2xatcontinuoushence )2(h)x(hlimthecesin 4)2(h 4)x(hlimthus 4)x(hlim)x(hlim 2x)x(h 2x 2x2x )x(h 2x 2x 2x2x = = = = == += − −+ = → → →→ −+ 2 4 y x •