This document discusses a game theory case involving two players, A and B, who must choose between multiple options. Player A can choose between options A1, A2, and A3, while Player B can choose between B1 and B2. There is no saddle point, so the optimal strategies are calculated to be Player A choosing A1 with probability 5/19 and A2 with probability 14/19, while Player B chooses B1 with probability 6/19 and B2 with 13/19. The value of the game is determined to be 168/19.
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Unit No.3.
DECISION SCIENCE
Presented By:
Dr. V. M. Tidake
Ph. D (Financial Management), MBA(FM), MBA(HRM) BE(Chem)
Dean, EDP & Associate Professor MBA
1
Sanjivani College of Engineering, Kopargaon
Department of MBA
www.sanjivanimba.org.in
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302-DECISION SCIENCE
Unit No.3. Games Theory
3.2.10 Case 5: Games
Theory
Presented By:
Dr. V. M. Tidake
Ph. D (Financial Management), MBA(FM), MBA(HRM) BE(Chem)
Dean EDP & Associate Professor MBA
2
Sanjivani College of Engineering, Kopargaon
Department of MBA
www.sanjivanimba.org.in
10. www.sanjivanimba.org.in
GAMES THEORY
Hence,
The Optimal Strategy for player A is (p, 1-p) i.e. (5/19,
14/19,0)
The Optimal Strategy for player B is (q, 1-q) i.e. (6/19,
13/19)
The Value of the Game is 168/19 i.e. Player A will get Rs.
168/19 from Player B.