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MMAATTHHSS PPRROOJJEECCTT 
QQuuaaddrriillaatteerraallss 
-- KKaavviittaa 
KKaannwwaarr 
IIXX--CC
Definition 
• A plane figure bounded by four line 
segments AB,BC,CD and DA is called a 
quadrilateral. 
A B 
D C 
*Quadrilateral 
I have exactly four sides.
In geometry, a quadrilateral is a polygon with four 
sides and four vertices. Sometimes, the term 
quadrangle is used, for etymological symmetry with 
triangle, and sometimes tetragon for consistence with 
pentagon. 
There are over 9,000,000 quadrilaterals. Quadrilaterals 
are either simple (not self-intersecting) or complex 
(self-intersecting). Simple quadrilaterals are either 
convex or concave.
Taxonomic Classification 
The taxonomic classification of quadrilaterals is illustrated by the 
following graph.
Types of Quadrilaterals 
• Parallelogram 
• Trapezium 
• Kite
Parallelogram 
I have: 
2 sets 
of parallel sides 
2 sets of equal sides 
opposite angles equal 
adjacent angles supplementary 
diagonals bisect each other 
diagonals form 2 congruent triangles
Types of Parallelograms 
*Rectangle 
I have all of the 
properties of the 
parallelogram PLUS 
- 4 right angles 
- diagonals congruent 
*Rhombus 
I have all of the 
properties of the 
parallelogram PLUS 
- 4 congruent sides 
- diagonals bisect 
angles 
- diagonals 
perpendicular
*Square 
Hey, look at me! 
I have all of the 
properties of the 
parallelogram AND the 
rectangle AND the 
rhombus. 
I have it all!
Is a square a rectangle? 
Some people define categories exclusively, so that a rectangle is a 
quadrilateral with four right angles that is not a square. This is 
appropriate for everyday use of the words, as people typically use 
the less specific word only when the more specific word will not do. 
Generally a rectangle which isn't a square is an oblong. 
But in mathematics, it is important to define categories inclusively, 
so that a square is a rectangle. Inclusive categories make 
statements of theorems shorter, by eliminating the need for tedious 
listing of cases. For example, the visual proof that vector addition is 
commutative is known as the "parallelogram diagram". If categories 
were exclusive it would have to be known as the "parallelogram (or 
rectangle or rhombus or square) diagram"!
Trapezium 
I have only one set of parallel sides. 
[The median of a trapezium is parallel to the 
bases and equal to one-half the sum of the 
bases.] 
Trapezoid Regular Trapezoid
Kite 
It has two pairs of sides. 
Each pair is made up of adjacent sides (the sides 
meet) that are equal in length. The angles are equal 
where the pairs meet. Diagonals (dashed lines) meet 
at a right angle, and one of the diagonal bisects 
(cuts equally in half) the other.
Some other types of 
quadrilaterals 
Cyclic quadrilateral: the four 
vertices lie on a circumscribed circle. 
Tangential quadrilateral: the four 
edges are tangential to an inscribed 
circle. Another term for a tangential 
polygon is inscriptible. 
Bicentric quadrilateral: both cyclic 
and tangential.
AAnnggllee SSuumm PPrrooppeerrttyy OOff 
QQuuaaddrriillaatteerraall 
The sum of all four angles of a quadrilateral is 360.. 
A 
D 
1 
2 
6 
5 
3 4 
B C 
Given: ABCD is a quadrilateral 
To Prove: Angle (A+B+C+D) =360. 
Construction: Join diagonal BD
Proof: In ABD 
Angle (1+2+6)=180 - (1) 
(angle sum property of ) 
In BCD 
Similarly angle (3+4+5)=180 – (2) 
Adding (1) and (2) 
Angle(1+2+6+3+4+5)=180+180=360 
Thus, Angle (A+B+C+D)= 360
The Mid-Point Theorem 
The line segment joining the mid-points of two sides 
of a triangle is parallel to the third side and is half of 
it. 
D 1 
E F 
A 
3 
2 
4 
B C 
Given: In ABC. D and E are the mid-points of AB and AC respectively 
and DE is joined 
To prove: DE is parallel to BC and DE=1/2 BC
Construction: Extend DE to F such that De=EF and join CF 
Proof: In AED and CEF 
Angle 1 = Angle 2 (vertically opp angles) 
AE = EC (given) 
DE = EF (by construction) 
Thus, By SAS congruence condition AED= CEF 
AD=CF (C.P.C.T) 
And Angle 3 = Angle 4 (C.P.C.T) 
But they are alternate Interior angles for lines AB and CF 
Thus, AB parallel to CF or DB parallel to FC-(1) 
AD=CF (proved) 
Also AD=DB (given) 
Thus, DB=FC -(2) 
From (1) and(2) 
DBCF is a gm 
Thus, the other pair DF is parallel to BC and DF=BC (By construction 
E is the mid-pt of DF) 
Thus, DE=1/2 BC
THE END 
Kavita kanwar 
IX-C 
ROLL NO-16

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479f3df10a8c0 mathsproject quadrilaterals

  • 1. MMAATTHHSS PPRROOJJEECCTT QQuuaaddrriillaatteerraallss -- KKaavviittaa KKaannwwaarr IIXX--CC
  • 2. Definition • A plane figure bounded by four line segments AB,BC,CD and DA is called a quadrilateral. A B D C *Quadrilateral I have exactly four sides.
  • 3. In geometry, a quadrilateral is a polygon with four sides and four vertices. Sometimes, the term quadrangle is used, for etymological symmetry with triangle, and sometimes tetragon for consistence with pentagon. There are over 9,000,000 quadrilaterals. Quadrilaterals are either simple (not self-intersecting) or complex (self-intersecting). Simple quadrilaterals are either convex or concave.
  • 4. Taxonomic Classification The taxonomic classification of quadrilaterals is illustrated by the following graph.
  • 5. Types of Quadrilaterals • Parallelogram • Trapezium • Kite
  • 6.
  • 7. Parallelogram I have: 2 sets of parallel sides 2 sets of equal sides opposite angles equal adjacent angles supplementary diagonals bisect each other diagonals form 2 congruent triangles
  • 8. Types of Parallelograms *Rectangle I have all of the properties of the parallelogram PLUS - 4 right angles - diagonals congruent *Rhombus I have all of the properties of the parallelogram PLUS - 4 congruent sides - diagonals bisect angles - diagonals perpendicular
  • 9. *Square Hey, look at me! I have all of the properties of the parallelogram AND the rectangle AND the rhombus. I have it all!
  • 10. Is a square a rectangle? Some people define categories exclusively, so that a rectangle is a quadrilateral with four right angles that is not a square. This is appropriate for everyday use of the words, as people typically use the less specific word only when the more specific word will not do. Generally a rectangle which isn't a square is an oblong. But in mathematics, it is important to define categories inclusively, so that a square is a rectangle. Inclusive categories make statements of theorems shorter, by eliminating the need for tedious listing of cases. For example, the visual proof that vector addition is commutative is known as the "parallelogram diagram". If categories were exclusive it would have to be known as the "parallelogram (or rectangle or rhombus or square) diagram"!
  • 11. Trapezium I have only one set of parallel sides. [The median of a trapezium is parallel to the bases and equal to one-half the sum of the bases.] Trapezoid Regular Trapezoid
  • 12. Kite It has two pairs of sides. Each pair is made up of adjacent sides (the sides meet) that are equal in length. The angles are equal where the pairs meet. Diagonals (dashed lines) meet at a right angle, and one of the diagonal bisects (cuts equally in half) the other.
  • 13. Some other types of quadrilaterals Cyclic quadrilateral: the four vertices lie on a circumscribed circle. Tangential quadrilateral: the four edges are tangential to an inscribed circle. Another term for a tangential polygon is inscriptible. Bicentric quadrilateral: both cyclic and tangential.
  • 14. AAnnggllee SSuumm PPrrooppeerrttyy OOff QQuuaaddrriillaatteerraall The sum of all four angles of a quadrilateral is 360.. A D 1 2 6 5 3 4 B C Given: ABCD is a quadrilateral To Prove: Angle (A+B+C+D) =360. Construction: Join diagonal BD
  • 15. Proof: In ABD Angle (1+2+6)=180 - (1) (angle sum property of ) In BCD Similarly angle (3+4+5)=180 – (2) Adding (1) and (2) Angle(1+2+6+3+4+5)=180+180=360 Thus, Angle (A+B+C+D)= 360
  • 16. The Mid-Point Theorem The line segment joining the mid-points of two sides of a triangle is parallel to the third side and is half of it. D 1 E F A 3 2 4 B C Given: In ABC. D and E are the mid-points of AB and AC respectively and DE is joined To prove: DE is parallel to BC and DE=1/2 BC
  • 17. Construction: Extend DE to F such that De=EF and join CF Proof: In AED and CEF Angle 1 = Angle 2 (vertically opp angles) AE = EC (given) DE = EF (by construction) Thus, By SAS congruence condition AED= CEF AD=CF (C.P.C.T) And Angle 3 = Angle 4 (C.P.C.T) But they are alternate Interior angles for lines AB and CF Thus, AB parallel to CF or DB parallel to FC-(1) AD=CF (proved) Also AD=DB (given) Thus, DB=FC -(2) From (1) and(2) DBCF is a gm Thus, the other pair DF is parallel to BC and DF=BC (By construction E is the mid-pt of DF) Thus, DE=1/2 BC
  • 18. THE END Kavita kanwar IX-C ROLL NO-16