The document discusses the calculation of tangential and longitudinal stresses in thin-walled cylindrical shells subjected to internal pressure, including specific formulas. It provides a practical example involving a steel pressure vessel to compute these stresses under given conditions and explores limits on internal pressure. Additionally, it prompts considerations on the nature of fracture if the pressure exceeds the material's stress limit.

1. Energy Science & Engineering
ME 2113
Solid Mechanics
Credit hour: 3.00
Arup Kumar Debnath
Lecturer
Department of Mechanical Engineering,
Khulna University of Engineering & Technology

2. 8. Show that, the tangential stress in a thin walled cylindrical shell of diameter ‘D’ and wall thickness ‘t’
subjected to internal pressure p is given by 𝜎𝑡 =
𝑝𝐷
2𝑡

3. 8. Show that, the tangential stress in a thin walled cylindrical shell of diameter ‘D’ and wall thickness ‘t’
subjected to internal pressure p is given by 𝜎𝑡 =
𝑝𝐷
2𝑡

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6. 9. Show that, the longitudinal stress in a thin walled cylindrical shell of diameter ‘D’ and wall thickness
‘t’ subjected to internal pressure p is given by 𝜎𝑙 =
𝑝𝐷
4𝑡

7. 10. A cylindrical steel pressure vessel 400 mm in diameter with a wall thickness of 20 mm, is subjected
to an internal pressure of 4.5 MN/m2. (a) Calculate the tangential and longitudinal stresses in the steel.
(b) To what value may the internal pressure be increased if the stress in the steel is limited to 120
MN/m2? (c) If the internal pressure were increased until the vessel burst, sketch the type of fracture
that would occur.

8. 11. The tank shown in Fig. is fabricated from 10mm steel plate. Calculate the maximum longitudinal
and circumferential stress caused by an internal pressure of 1.2 MPa.