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IMPROVEMENT OF INDUSTRIAL EXTRUDED
PIPE COOLING SYSTEM
MAE 4071: THERMAL SYSTEMS DESIGN
BY:
THADDEUS BERGER
MARTIN BONILLA
CLAUDE BROOKS
CLYDE BROWN
ALEXANDER EIERLE
JONAS FUGLAS
ELIZABETH HEEKE
JOHN HILKER
PAUL KEPINSKI
ANDRE-LOUIS POUNDER
AUSTIN SPAGNOLO
NATE VORIS
SUBMITTED:
23 NOV. 2015
INSTRUCTOR:
DR. GROVES
2
CONTENTS
Figures................................................................................................................................................................................................3
Tables.................................................................................................................................................................................................3
Executive Summary .........................................................................................................................................................................4
Introduction......................................................................................................................................................................................5
Problem Statement.....................................................................................................................................................................5
Objectives .....................................................................................................................................................................................5
Conceptual Design...........................................................................................................................................................................5
Proposed Solution.......................................................................................................................................................................5
Fluid and Heat Transfer Analysis...............................................................................................................................................6
Reliability.......................................................................................................................................................................................9
Cost Analysis...............................................................................................................................................................................11
Modeling.....................................................................................................................................................................................12
Results..............................................................................................................................................................................................16
Conclusion.......................................................................................................................................................................................17
Appendix..........................................................................................................................................................................................18
A: Team Responsibilities*........................................................................................................................................................18
B: Budget.....................................................................................................................................................................................19
References.......................................................................................................................................................................................20
3
FIGURES
Figure 1: Original cooling bay in use at industrial plant............................................................................................................5
Figure 2: Proposed cooling bay system schematic....................................................................................................................6
Figure 3: Nozzle..............................................................................................................................................................................10
Figure 4: Chiller..............................................................................................................................................................................10
Figure 5: Centrifugal pump. .........................................................................................................................................................10
Figure 6: Reservoir tank................................................................................................................................................................10
Figure 7: Full system......................................................................................................................................................................11
Figure 8: Original system before modifications.......................................................................................................................12
Figure 9: Modified system............................................................................................................................................................13
Figure 10: Close-up view of modified system...........................................................................................................................13
Figure 11: Close-up view of tanks and piping...........................................................................................................................14
Figure 12: Top view of cooling bay system. ..............................................................................................................................14
Figure 13: Top view system drawing..........................................................................................................................................15
TABLES
Table 1: Castiron pipe data used for system analysis..............................................................................................................7
Table 2: Minor loss factors for pipe fittings................................................................................................................................7
Table 3: Failure rates for system components. ..........................................................................................................................9
Table 4: Table of results................................................................................................................................................................16
Table 5: Team responsibilities.....................................................................................................................................................18
Table 6: Budget for modified system. ........................................................................................................................................19
4
EXECUTIVE SUMMARY
A system to extrude metal pipes coated with thermoplastic for applications in oil rigumbilicalswas originally
cooled usingnozzles which sprayed the pipe with water at 60 F as itmoved down a conveyor in an industrial plant.
The original systemcooled the pipein 52 feet and was not ableto consistently cool the extrusion before the
thermoplastic coatingbegan to melt. To address the issue,nozzle flow rate was increas ed by increasingthewater
pressure,and temperature difference was increased by addingchillersto the system. For an additional $34,838.05,
the solution improved the system by reducingthe length of conveyor required to cool the pipe to 24 feet, reduced
waste, and opened approximately 560 squarefeet of additional spaceon the plantfloor. Given the design of the
existingmanufacturingfloor and its preset coolingbay structurethe closestreduction was brought to 27ft without
drastically alteringthe system. Without consideringthe changes in power and wasted materials (amongother
factors),the additional spacealonewas determined to be enough to balancethe cost of the improvements in less
than one quarter.
5
INTRODUCTION
PROBLEM STATEMENT
Piping for oil rig umbilical’s consists of extruded metal coated in a
protective layer of thermoplastics.The pipe is extruded atabout 2,200 F
and then quenched with room temperature water, cooling it to 325 F.
The pipethen moves to the Steel CoolingBay where 60F water is sprayed
on alternatingsides at 100 psi. This is done to bring the steel down to a
standard manufacturing room temperature of 80 F. Then the steel pipe
proceeds to the thermoplastic extrusion section where a plastic coating
is applied to the outside of the steel pipe for protection. If the pipe does
not reach its target temperature of 80 F then bubbles or deformities will
occur in the plastic extrusion section rendering said product unusable.
This ultimately causes a reduction in manufacturing efficiency,
profitability and increased fluctuations of waste.
OBJECTIVES
The objective of this project is an optimized system which can
consistently and efficiently cool the extruded pipe within the desired
time range so that the thermoplastic being extruded onto the pipe
coatingwill not melt. Ideally,to further optimize the system, the length
of the coolingprocess could bereduced by increasingthe coolingrateof
the steel pipe after the clenching phase. This will shorten the length of
the overall cooling bays and dramatically open plant floor space, which
provides the availability for new manufacturing process and space
availability.This would improvethe overall efficiency and profitability of the plant.
CONCEPTUAL DESIGN
PROPOSED SOLUTION
The proposed solution consisted of chillers in parallel cooling water to be pumped from a reservoir through a high-
flow rate circulation pump.The pump chosen used 1.5 hp and had a flow rate of 40 gpm, which resulted in a 0.3918
gpm flow rate from each of the 32 nozzles.The chillers(5 hp) could operate up to 15 gpm and each had a 36 gallon
capacity.A 60 gallon reservoir was used between the chillers and thepump. A schematic of the solution is shown in
Figure 1, and a more detailed breakdown of the components and their respectivecosts can be found in Appendix B.
Figure 1: Original cooling bay in use at industrial
plant.
6
Figure 2: Proposed cooling bay system schematic.
From the reservoir,the water will be flowingat 40 gpm due to the centrifugal pump. The coolingwater entering
the chillersis assumed to be at a room temperature of 72.
For the control volume of a chiller,thevolumetric flowrate would be a third of the total flowrate. Then, a pplying
an energy balanceto the control volume:
π‘ž = ( π‘šπ‘Žπ‘ π‘  π‘“π‘™π‘œπ‘€) βˆ— 𝑐 𝑝
( π‘‡π‘œπ‘’π‘‘ βˆ’ 𝑇𝑖𝑛
)
It is found that the outlet temperature from each chiller will be64;therefore, the coolingwater will enter the
nozzles atthe temperature. This is a decent temperature change for a total flowrate of 40 gpm.
FLUID AND HEAT TRANSFER ANALYSIS
The followingassumptions weremade in the analysisof the problem:
1. The nozzles arearrayed around the circumference of the pipeso that they completely cover a section of
pipe 7.14 inches longwith water at 40 F.
2. Water flows with constantvelocity.
3. Neglect heat loss dueto convection of air.
4. Constant coolingrate.
5. The pipe exits the quencher at 325 F.
6. The pipe’s desired ending temperature is 80 F.
7
Piping assumptions
Pipe Type Inner Diameter Friction Factor
CastIron Fittings 0.824 in 0.025
Table 1: Cast iron pipe dataused for system analysis.
Fitting Minor Loss
Threaded Tee 0.9
90 Degree Threaded 1.5
Union Threaded 0.08
Table 2: Minor lossfactorsfor pipe fittings.
The constants used for analysis were:
● ρ = 0.2834 lbm/in3
● cp = 0.12
● Tinfinity = 40F
● Ts, final = 80F
● Ts, initial = 325F
● Thickness = 0.25 in
● k = 7.743 x 10-6 in2/s
● v = 239.616 x 10-5 BTU/s in F
● Pr = 10.518
● Nozzle Spray Swath: 7.14 in
● Nozzle Exit Velocity: 91.11 in/s
● Tube Extrusion Speed: 0.75 in/s
● Nozzle Array Distribution:1 array every 3 ft of cooler length
● z1 = 0 in, centrifugal pump is on floor
● z2 = 36 in,system is 36 in off the floor
● P1 = 25 psi,pump pressureoutput
● P2 = 100 psi,specification pressureof nozzles
● hL = 0, due to no major losses
● a1 = 1, basealpha
● a2 = (1 + 𝜁𝐿/𝐷 + π›΄π‘˜)
8
Usingthe modified Bernoulli equation shown below, we wanted to find the flowrate for all 32 nozzles.
(𝑃1 /πœŒπ‘” + 𝛼1(𝜈1/2𝑔) + 𝑧1) = (𝑃2 /πœŒπ‘” + 𝛼2(𝜈2/2𝑔) + 𝑧2) + β„Ž 𝐿
The area of analysisisfromthe pump to the nozzle head,
𝛼2 = ( 1 + 0.025 βˆ— (30.5/0.824) + 4.22) = 6.145
The pump chosen has a flow rate of 40 GPM thus,
𝑉1 = 40 π‘”π‘π‘š = 9240 𝑖𝑛3
/π‘šπ‘–π‘› ≫ 𝜐1 = (3240𝑖𝑛3
/π‘šπ‘–π‘›) (1/0.53𝑖𝑛2
)(1 π‘šπ‘–π‘›/60 𝑠) = 288 𝑖𝑛/𝑠
Now plugginginto the Bernoulli equation gives,
(25/(0.036 βˆ— 386 ) + (1) 288/ (2 βˆ— 386) + 0 = (100/(0.036 βˆ— 386) + (6.145)𝜐2
/(2 βˆ— 386) + 36) + 0
𝜐2
= 91.11 𝑖𝑛/𝑠 ≫ 𝑉2 = 48.3 𝑖𝑛3
/𝑠 π‘œπ‘Ÿ 12.54 𝐺𝑃𝑀
From our analysis wedetermined the resultingflowrate to 12.54 GPM the combine nozzle flow rate, thus each
individual nozzleexperiences a flowrate of 0.3918 GPM.
Rate of Temperature Loss
Reynolds Number (Length)
Nusselt Number (Length)
Convection Heat Transfer Coefficient (Length)
9
Final Cooler Length
β„Ž π‘₯ = 0.000115063 βˆ— √(91.11 βˆ’ 0.75)/π‘₯
We assumethat the rate of temperature loss isconstant,thus we set dT/dt equal to itself and found:
𝑑𝑇/𝑑𝑑 = [βˆ’0.00230126√91.11 βˆ’ 0.75/π‘₯ (𝑇 βˆ’ 40)]/(0.2834 βˆ— 0.25 βˆ— 0.12)
Thus, we determined the required total spray swath to be 50.77 inches:
285/40 = √ π‘₯1/π‘₯2 β†’ π‘₯1/π‘₯2 = 81225/1600 β†’ π‘₯1 = 50.77π‘₯2
With that we were able to calculatethe Reynolds number, Nusseltnumber and the convection heat transfer at
startof the process 0.0011 BTU/s-F-in2 and the heat transfer atend of the process.That and our constants we
were able to calculatethe final cooler length.
𝑅𝑒2 = 0.75 βˆ— 50.77/239.616 βˆ— 10βˆ’5
= 15891.1
𝑁𝑒2 = 0.332(15891.1).5
βˆ— 10.5181/3
= 91.7
β„Ž2 = (7.743 βˆ— 10βˆ’6
/50.77) βˆ— 91.7 = 0.00015 π΅π‘‡π‘ˆ/𝑠𝐹𝑖𝑛2
πΉπ‘–π‘›π‘Žπ‘™ πΏπ‘’π‘›π‘”π‘‘β„Ž = 36𝑖𝑛 βˆ— (50.77𝑖𝑛/7.14𝑖𝑛) = 255.98 π‘–π‘›π‘β„Žπ‘’π‘  = 21.33 𝑓𝑑
This measurement is strictly required by the nozzle array set-up, so takingto accountthe needed empty space,the
actual cooler length comes out to be 24ft.
RELIABILITY
Reliability in Series:
𝑅𝑠 = π‘’βˆ’ βˆ‘ πœ†π‘‘
Reliability in Parallel:
𝑅|| = π‘’βˆ’πœ†1 𝑑
+ π‘’βˆ’πœ†2 𝑑
βˆ’ π‘’βˆ’(πœ†1+πœ†2)𝑑
t = 2000 hours
Part Reliability (rate/hour)
90 Degree Elbow 0.2x10-6
SplittingT 0.5x10-6
Nozzle 10.0x10-6
Pump 60.0x10-6
Chiller 85.0x10-6
Tank 5.0x10-6
Table 3: Failure ratesfor system components.
10
Figure 3: Nozzle.
𝑅𝑠1
= π‘’βˆ’(0.2π‘₯10βˆ’6
+10π‘₯10βˆ’6
)(2000 )
= 0.97
𝑅𝑠2
= π‘’βˆ’(0.2π‘₯10βˆ’6
+0.5π‘₯10βˆ’6
)(2000)
= 0.99
𝑅𝑠3
= π‘’βˆ’(10π‘₯10βˆ’6
)(2000)
= 0.98
𝑅𝑠1 ||𝑠2
= (0.97 + 0.98) βˆ’ (0.97)(0.98) = 0.99
𝑅 𝑇 = (0.99)(0.99) = 0.98
𝑅𝑠17 π‘π‘œπ‘§π‘§π‘™π‘’π‘ 
= 0.9817
= 0.70
𝑅𝑠17 ||𝑠17 = (0.7 + 0.7) βˆ’ 0.72
= 0.91
Figure 4: Chiller.
𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ1 ||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ2
= 2π‘’βˆ’(85π‘₯10βˆ’6
)(2000 )
βˆ’ π‘’βˆ’(2βˆ—85π‘₯10βˆ’6
)(2000 )
= 0.9755
𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ3
= π‘’βˆ’(85π‘₯10βˆ’6
)(2000 )
= 0.84
𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ1 ||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ2||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ3
= (0.9755 + 0.84) βˆ’ (0.84)(0.9755) = 0.996
Figure 5: Centrifugal pump.
𝑅 π‘π‘’π‘šπ‘ = 2π‘’βˆ’(60π‘₯10βˆ’6
)(2000)
βˆ’ π‘’βˆ’(2βˆ—60π‘₯ 10βˆ’6
)(2000)
= 0.9872
𝑅 π‘π‘’π‘šπ‘3
= π‘’βˆ’(60π‘₯10βˆ’6
)(2000)
= 0.8869𝑅 π‘π‘’π‘šπ‘1 ||π‘π‘’π‘šπ‘2||π‘π‘’π‘šπ‘3
= (0.9872 + 0.8869) βˆ’ (0.8869)(0.9872) = 0.998
Figure 6: Reservoir tank.
π‘…π‘‘π‘Žπ‘›π‘˜ = π‘’βˆ’(5π‘₯10βˆ’6
)(2000 )
= 0.99
11
Figure 7: Full system.
π‘…π‘ π‘¦π‘ π‘‘π‘’π‘š = (0.998)(0.996)(0.91)(0.99) = 0.8955
Reliability of System:89.55%
COST ANALYSIS
By reducing the total length of the coolingbay by almosthalf,we have freed up spacein the manufacturingfacility.
The facility is rented at $20 per squarefoot per month. Usingthe renting priceover the opened area,we found the
time to balancethe costof the changes and improvements of the coolingbay is only 2 months and 23 days.
L = length of coolingblock
W = width of coolingblock area
p = priceper squarefoot
π‘‚π‘Ÿπ‘–π‘”π‘–π‘›π‘Žπ‘™ πΆπ‘œπ‘ π‘‘ π‘π‘’π‘Ÿ π‘€π‘œπ‘›π‘‘β„Ž = 𝐿 βˆ— π‘Š βˆ— π‘π‘Ÿπ‘–π‘π‘’ = 52 βˆ— 48 βˆ— $20.00 = $49,920.00 π‘π‘’π‘Ÿ π‘šπ‘œπ‘›π‘‘β„Ž
𝑁𝑒𝑀 πΆπ‘œπ‘ π‘‘ π‘π‘’π‘Ÿ π‘€π‘œπ‘›π‘‘β„Ž = 27 βˆ— 20 βˆ— $20.00 = $25,920.00 π‘π‘’π‘Ÿ π‘šπ‘œπ‘›π‘‘β„Ž
Cost of changes = $34,838.05
π‘‡π‘–π‘šπ‘’ π‘‘π‘œ π‘…π‘’π‘π‘’π‘π‘’π‘Ÿπ‘Žπ‘‘π‘’ πΆβ„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 πΆπ‘œπ‘ π‘‘ = πΆπ‘œπ‘ π‘‘ π‘œπ‘“ π‘β„Žπ‘Žπ‘›π‘”π‘’π‘  Γ· πΆβ„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 π‘π‘œπ‘ π‘‘ = 34,838 Γ· (49,920 βˆ’ 25,920)
= 1.45 π‘šπ‘œπ‘›π‘‘β„Žπ‘ 
12
MODELING
The CAD modeling of the solution was done in SolidWorks.Theassembly can be seen on the followingpages.Figure
7 illustrates the plant if the assembly were to stay at its given length of 52 ft long. The current setup utilizes 4
recycling tanks which collect all of the drained water after it has come in with the hot steel pipe. There are 3 low
gradeheat exchangers which then cool the water and feed them back into the nozzles.Figure 8 illustrates thesystem
after the heat transfer process has been overhauled to be more efficient. This system incorporates two recycling
tanks, 3 pumps and 3 heat exchangers of high quality. The water first is collected through the drains in the steel
coolingbays and funneled into the recyclingtanks (Figure 10). From there the recycled water is then sucked out of
the tanks and into the (chiller) heatexchanger so that the 80F water can be cooled down to 40F (Figures 9 and 11).
After the water has been chilled itis thesucked out of the heat exchanger by use of the pump atroughly 15 gpm per
pump and into the nozzle spray apparatuses (Figures 9 and 11). Then through the use of pipereducers, the water is
funneled from ΒΎ in pipeto β…› in nozzles where the psi is drastically increased (Figure 9). From there the nozzles then
spray the steel pipes in a manner at which 50% of one sideis sprayed and then 50%of the other sideis then sprayed
at a 100 psi and 40F. The water is then once again drained from the coolingbays and repeated over and over again
in an open-loop heattransfer process. The drawing(Figure12,pg.16) of the assembly demonstrates the dimensional
Figure 8: Original system before modifications.
13
analysisof the final reduced system. The overhaul of the system reduced the steel coolingbay from 52 ft longto 27
ft long.This left the system with 3 total heat exchangers,3 15 Gpm pumps, and two tanks being used.
Figure 9: Modified system.
Figure 10: Close-up view ofmodified system.
14
Figure 11: Close-up view oftanksand piping.
Figure 12: Top view ofcooling bay system.
15
Figure 13: Top view system drawing.
16
RESULTS
The final results of the modified system are shown below:
Required Total Spray Swath 50.77 Inches
Final Cooler Length 24 Feet
Rate of Temperature Loss 10.35 F/s
Initial Convection Heat Transfer Coefficient 0.00015 BTU/s-in2-F
Final Convection Heat Transfer Coefficient 0.0011 BTU/s-in2-F
Total Flow Rate 12.54 GPM
Individual NozzleFlow rate 0.3918 GPM
System Reliability 79.58%
Cost $34,838.05
Time to Recover Cost 3.11 months
Table 4: Table ofresults.
17
CONCLUSION
By increasingthepressureand addingchillers to thesystem, the length of the coolingbay was reduced by 52%, while
consistently coolingtheextruded pipe to 80 F before addingthe thermoplastic coating.Thenew system will improve
plant profitability by reducing waste and opening additional space on the plant floor. The reliability of the system
was found to be about 89%. The improved design will cost an additional $34,838.05, which is more than balanced
by the improved ability of the system to cool the extruded pipe consistently to an acceptabletemperature and the
additional floor spacethatbecomes availableas a resultof shorteningthe coolingbay.In fact, the extra spacealone
can balanceout the costof the improvements in its firstquarter of use.
18
APPENDIX
A: TEAM RESPONSIBILI TIES*
*Everyone helped with the presentations.
Name Position Responsibility
Thaddeus Berger Technical Writing Lead Writing
Martin Bonilla CAD Analyst CAD
Claude Brooks Technical Writer Writing
Clyde Brown Team Lead CAD
Alexander Eierle Reliability Calculations Calculations
Jonas Fuglas CAD Analyst CAD
Elizabeth Heeke Technical Writer Writing
John Hilker Cost Calculations Calculations
Paul Kepinski Fluids Calculations Calculations
Andre-Louis Pounder Heat Calculations Calculations
Austin Spagnolo Calculations CAD
Nate Voris Heat Calculations Calculations
Table 5: Team responsibilities.
19
B: BUDGET
Part Unit Price Quantity Total Price
Circulation Pump for
water, 1.5 hp 208-
240/460 V AC, 40 gpm
flow rate
$661.95 3 $1985.85
High-Flow, Circulating
Process Chiller,60
kBTU/hr, 460 V/3 PH, 5
hp, 15 gpm flow rate, 36
gal tank
$10,619.44 3 $31,858.32
Horizontal Polyethylene
Tank w/ Legs, 60 gal w/
drain,38.5” length
$496.94 2 $993.88
Total $34,838.05
Table 6: Budget for modified system.
20
REFERENCES
ο‚· Incropera,F.P., DeWitt, D.P., Bergman T., and LavineA., Fundamentals of Heat and Mass Transfer,6th
Edition, Wiley (2006).
ο‚· Cengel, Y.A., and J.M. Cimbala,Fluid Mechanics –Fundamentals and Applications,3rd Ed., McGraw-Hill
(2014).
ο‚· Parts:
"Circulation Pumps." McMaster-Carr. N.p., n.d. Web.
"Easy-Drain Cylindrical Tanks." McMaster-Carr. N.p., n.d. Web.
"Polyethylene Tanks." McMaster-Carr. N.p., n.d. Web.

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Thermal Systems Design

  • 1. 1 IMPROVEMENT OF INDUSTRIAL EXTRUDED PIPE COOLING SYSTEM MAE 4071: THERMAL SYSTEMS DESIGN BY: THADDEUS BERGER MARTIN BONILLA CLAUDE BROOKS CLYDE BROWN ALEXANDER EIERLE JONAS FUGLAS ELIZABETH HEEKE JOHN HILKER PAUL KEPINSKI ANDRE-LOUIS POUNDER AUSTIN SPAGNOLO NATE VORIS SUBMITTED: 23 NOV. 2015 INSTRUCTOR: DR. GROVES
  • 2. 2 CONTENTS Figures................................................................................................................................................................................................3 Tables.................................................................................................................................................................................................3 Executive Summary .........................................................................................................................................................................4 Introduction......................................................................................................................................................................................5 Problem Statement.....................................................................................................................................................................5 Objectives .....................................................................................................................................................................................5 Conceptual Design...........................................................................................................................................................................5 Proposed Solution.......................................................................................................................................................................5 Fluid and Heat Transfer Analysis...............................................................................................................................................6 Reliability.......................................................................................................................................................................................9 Cost Analysis...............................................................................................................................................................................11 Modeling.....................................................................................................................................................................................12 Results..............................................................................................................................................................................................16 Conclusion.......................................................................................................................................................................................17 Appendix..........................................................................................................................................................................................18 A: Team Responsibilities*........................................................................................................................................................18 B: Budget.....................................................................................................................................................................................19 References.......................................................................................................................................................................................20
  • 3. 3 FIGURES Figure 1: Original cooling bay in use at industrial plant............................................................................................................5 Figure 2: Proposed cooling bay system schematic....................................................................................................................6 Figure 3: Nozzle..............................................................................................................................................................................10 Figure 4: Chiller..............................................................................................................................................................................10 Figure 5: Centrifugal pump. .........................................................................................................................................................10 Figure 6: Reservoir tank................................................................................................................................................................10 Figure 7: Full system......................................................................................................................................................................11 Figure 8: Original system before modifications.......................................................................................................................12 Figure 9: Modified system............................................................................................................................................................13 Figure 10: Close-up view of modified system...........................................................................................................................13 Figure 11: Close-up view of tanks and piping...........................................................................................................................14 Figure 12: Top view of cooling bay system. ..............................................................................................................................14 Figure 13: Top view system drawing..........................................................................................................................................15 TABLES Table 1: Castiron pipe data used for system analysis..............................................................................................................7 Table 2: Minor loss factors for pipe fittings................................................................................................................................7 Table 3: Failure rates for system components. ..........................................................................................................................9 Table 4: Table of results................................................................................................................................................................16 Table 5: Team responsibilities.....................................................................................................................................................18 Table 6: Budget for modified system. ........................................................................................................................................19
  • 4. 4 EXECUTIVE SUMMARY A system to extrude metal pipes coated with thermoplastic for applications in oil rigumbilicalswas originally cooled usingnozzles which sprayed the pipe with water at 60 F as itmoved down a conveyor in an industrial plant. The original systemcooled the pipein 52 feet and was not ableto consistently cool the extrusion before the thermoplastic coatingbegan to melt. To address the issue,nozzle flow rate was increas ed by increasingthewater pressure,and temperature difference was increased by addingchillersto the system. For an additional $34,838.05, the solution improved the system by reducingthe length of conveyor required to cool the pipe to 24 feet, reduced waste, and opened approximately 560 squarefeet of additional spaceon the plantfloor. Given the design of the existingmanufacturingfloor and its preset coolingbay structurethe closestreduction was brought to 27ft without drastically alteringthe system. Without consideringthe changes in power and wasted materials (amongother factors),the additional spacealonewas determined to be enough to balancethe cost of the improvements in less than one quarter.
  • 5. 5 INTRODUCTION PROBLEM STATEMENT Piping for oil rig umbilical’s consists of extruded metal coated in a protective layer of thermoplastics.The pipe is extruded atabout 2,200 F and then quenched with room temperature water, cooling it to 325 F. The pipethen moves to the Steel CoolingBay where 60F water is sprayed on alternatingsides at 100 psi. This is done to bring the steel down to a standard manufacturing room temperature of 80 F. Then the steel pipe proceeds to the thermoplastic extrusion section where a plastic coating is applied to the outside of the steel pipe for protection. If the pipe does not reach its target temperature of 80 F then bubbles or deformities will occur in the plastic extrusion section rendering said product unusable. This ultimately causes a reduction in manufacturing efficiency, profitability and increased fluctuations of waste. OBJECTIVES The objective of this project is an optimized system which can consistently and efficiently cool the extruded pipe within the desired time range so that the thermoplastic being extruded onto the pipe coatingwill not melt. Ideally,to further optimize the system, the length of the coolingprocess could bereduced by increasingthe coolingrateof the steel pipe after the clenching phase. This will shorten the length of the overall cooling bays and dramatically open plant floor space, which provides the availability for new manufacturing process and space availability.This would improvethe overall efficiency and profitability of the plant. CONCEPTUAL DESIGN PROPOSED SOLUTION The proposed solution consisted of chillers in parallel cooling water to be pumped from a reservoir through a high- flow rate circulation pump.The pump chosen used 1.5 hp and had a flow rate of 40 gpm, which resulted in a 0.3918 gpm flow rate from each of the 32 nozzles.The chillers(5 hp) could operate up to 15 gpm and each had a 36 gallon capacity.A 60 gallon reservoir was used between the chillers and thepump. A schematic of the solution is shown in Figure 1, and a more detailed breakdown of the components and their respectivecosts can be found in Appendix B. Figure 1: Original cooling bay in use at industrial plant.
  • 6. 6 Figure 2: Proposed cooling bay system schematic. From the reservoir,the water will be flowingat 40 gpm due to the centrifugal pump. The coolingwater entering the chillersis assumed to be at a room temperature of 72. For the control volume of a chiller,thevolumetric flowrate would be a third of the total flowrate. Then, a pplying an energy balanceto the control volume: π‘ž = ( π‘šπ‘Žπ‘ π‘  π‘“π‘™π‘œπ‘€) βˆ— 𝑐 𝑝 ( π‘‡π‘œπ‘’π‘‘ βˆ’ 𝑇𝑖𝑛 ) It is found that the outlet temperature from each chiller will be64;therefore, the coolingwater will enter the nozzles atthe temperature. This is a decent temperature change for a total flowrate of 40 gpm. FLUID AND HEAT TRANSFER ANALYSIS The followingassumptions weremade in the analysisof the problem: 1. The nozzles arearrayed around the circumference of the pipeso that they completely cover a section of pipe 7.14 inches longwith water at 40 F. 2. Water flows with constantvelocity. 3. Neglect heat loss dueto convection of air. 4. Constant coolingrate. 5. The pipe exits the quencher at 325 F. 6. The pipe’s desired ending temperature is 80 F.
  • 7. 7 Piping assumptions Pipe Type Inner Diameter Friction Factor CastIron Fittings 0.824 in 0.025 Table 1: Cast iron pipe dataused for system analysis. Fitting Minor Loss Threaded Tee 0.9 90 Degree Threaded 1.5 Union Threaded 0.08 Table 2: Minor lossfactorsfor pipe fittings. The constants used for analysis were: ● ρ = 0.2834 lbm/in3 ● cp = 0.12 ● Tinfinity = 40F ● Ts, final = 80F ● Ts, initial = 325F ● Thickness = 0.25 in ● k = 7.743 x 10-6 in2/s ● v = 239.616 x 10-5 BTU/s in F ● Pr = 10.518 ● Nozzle Spray Swath: 7.14 in ● Nozzle Exit Velocity: 91.11 in/s ● Tube Extrusion Speed: 0.75 in/s ● Nozzle Array Distribution:1 array every 3 ft of cooler length ● z1 = 0 in, centrifugal pump is on floor ● z2 = 36 in,system is 36 in off the floor ● P1 = 25 psi,pump pressureoutput ● P2 = 100 psi,specification pressureof nozzles ● hL = 0, due to no major losses ● a1 = 1, basealpha ● a2 = (1 + 𝜁𝐿/𝐷 + π›΄π‘˜)
  • 8. 8 Usingthe modified Bernoulli equation shown below, we wanted to find the flowrate for all 32 nozzles. (𝑃1 /πœŒπ‘” + 𝛼1(𝜈1/2𝑔) + 𝑧1) = (𝑃2 /πœŒπ‘” + 𝛼2(𝜈2/2𝑔) + 𝑧2) + β„Ž 𝐿 The area of analysisisfromthe pump to the nozzle head, 𝛼2 = ( 1 + 0.025 βˆ— (30.5/0.824) + 4.22) = 6.145 The pump chosen has a flow rate of 40 GPM thus, 𝑉1 = 40 π‘”π‘π‘š = 9240 𝑖𝑛3 /π‘šπ‘–π‘› ≫ 𝜐1 = (3240𝑖𝑛3 /π‘šπ‘–π‘›) (1/0.53𝑖𝑛2 )(1 π‘šπ‘–π‘›/60 𝑠) = 288 𝑖𝑛/𝑠 Now plugginginto the Bernoulli equation gives, (25/(0.036 βˆ— 386 ) + (1) 288/ (2 βˆ— 386) + 0 = (100/(0.036 βˆ— 386) + (6.145)𝜐2 /(2 βˆ— 386) + 36) + 0 𝜐2 = 91.11 𝑖𝑛/𝑠 ≫ 𝑉2 = 48.3 𝑖𝑛3 /𝑠 π‘œπ‘Ÿ 12.54 𝐺𝑃𝑀 From our analysis wedetermined the resultingflowrate to 12.54 GPM the combine nozzle flow rate, thus each individual nozzleexperiences a flowrate of 0.3918 GPM. Rate of Temperature Loss Reynolds Number (Length) Nusselt Number (Length) Convection Heat Transfer Coefficient (Length)
  • 9. 9 Final Cooler Length β„Ž π‘₯ = 0.000115063 βˆ— √(91.11 βˆ’ 0.75)/π‘₯ We assumethat the rate of temperature loss isconstant,thus we set dT/dt equal to itself and found: 𝑑𝑇/𝑑𝑑 = [βˆ’0.00230126√91.11 βˆ’ 0.75/π‘₯ (𝑇 βˆ’ 40)]/(0.2834 βˆ— 0.25 βˆ— 0.12) Thus, we determined the required total spray swath to be 50.77 inches: 285/40 = √ π‘₯1/π‘₯2 β†’ π‘₯1/π‘₯2 = 81225/1600 β†’ π‘₯1 = 50.77π‘₯2 With that we were able to calculatethe Reynolds number, Nusseltnumber and the convection heat transfer at startof the process 0.0011 BTU/s-F-in2 and the heat transfer atend of the process.That and our constants we were able to calculatethe final cooler length. 𝑅𝑒2 = 0.75 βˆ— 50.77/239.616 βˆ— 10βˆ’5 = 15891.1 𝑁𝑒2 = 0.332(15891.1).5 βˆ— 10.5181/3 = 91.7 β„Ž2 = (7.743 βˆ— 10βˆ’6 /50.77) βˆ— 91.7 = 0.00015 π΅π‘‡π‘ˆ/𝑠𝐹𝑖𝑛2 πΉπ‘–π‘›π‘Žπ‘™ πΏπ‘’π‘›π‘”π‘‘β„Ž = 36𝑖𝑛 βˆ— (50.77𝑖𝑛/7.14𝑖𝑛) = 255.98 π‘–π‘›π‘β„Žπ‘’π‘  = 21.33 𝑓𝑑 This measurement is strictly required by the nozzle array set-up, so takingto accountthe needed empty space,the actual cooler length comes out to be 24ft. RELIABILITY Reliability in Series: 𝑅𝑠 = π‘’βˆ’ βˆ‘ πœ†π‘‘ Reliability in Parallel: 𝑅|| = π‘’βˆ’πœ†1 𝑑 + π‘’βˆ’πœ†2 𝑑 βˆ’ π‘’βˆ’(πœ†1+πœ†2)𝑑 t = 2000 hours Part Reliability (rate/hour) 90 Degree Elbow 0.2x10-6 SplittingT 0.5x10-6 Nozzle 10.0x10-6 Pump 60.0x10-6 Chiller 85.0x10-6 Tank 5.0x10-6 Table 3: Failure ratesfor system components.
  • 10. 10 Figure 3: Nozzle. 𝑅𝑠1 = π‘’βˆ’(0.2π‘₯10βˆ’6 +10π‘₯10βˆ’6 )(2000 ) = 0.97 𝑅𝑠2 = π‘’βˆ’(0.2π‘₯10βˆ’6 +0.5π‘₯10βˆ’6 )(2000) = 0.99 𝑅𝑠3 = π‘’βˆ’(10π‘₯10βˆ’6 )(2000) = 0.98 𝑅𝑠1 ||𝑠2 = (0.97 + 0.98) βˆ’ (0.97)(0.98) = 0.99 𝑅 𝑇 = (0.99)(0.99) = 0.98 𝑅𝑠17 π‘π‘œπ‘§π‘§π‘™π‘’π‘  = 0.9817 = 0.70 𝑅𝑠17 ||𝑠17 = (0.7 + 0.7) βˆ’ 0.72 = 0.91 Figure 4: Chiller. 𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ1 ||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ2 = 2π‘’βˆ’(85π‘₯10βˆ’6 )(2000 ) βˆ’ π‘’βˆ’(2βˆ—85π‘₯10βˆ’6 )(2000 ) = 0.9755 𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ3 = π‘’βˆ’(85π‘₯10βˆ’6 )(2000 ) = 0.84 𝑅 π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ1 ||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ2||π‘β„Žπ‘–π‘™π‘™π‘’π‘Ÿ3 = (0.9755 + 0.84) βˆ’ (0.84)(0.9755) = 0.996 Figure 5: Centrifugal pump. 𝑅 π‘π‘’π‘šπ‘ = 2π‘’βˆ’(60π‘₯10βˆ’6 )(2000) βˆ’ π‘’βˆ’(2βˆ—60π‘₯ 10βˆ’6 )(2000) = 0.9872 𝑅 π‘π‘’π‘šπ‘3 = π‘’βˆ’(60π‘₯10βˆ’6 )(2000) = 0.8869𝑅 π‘π‘’π‘šπ‘1 ||π‘π‘’π‘šπ‘2||π‘π‘’π‘šπ‘3 = (0.9872 + 0.8869) βˆ’ (0.8869)(0.9872) = 0.998 Figure 6: Reservoir tank. π‘…π‘‘π‘Žπ‘›π‘˜ = π‘’βˆ’(5π‘₯10βˆ’6 )(2000 ) = 0.99
  • 11. 11 Figure 7: Full system. π‘…π‘ π‘¦π‘ π‘‘π‘’π‘š = (0.998)(0.996)(0.91)(0.99) = 0.8955 Reliability of System:89.55% COST ANALYSIS By reducing the total length of the coolingbay by almosthalf,we have freed up spacein the manufacturingfacility. The facility is rented at $20 per squarefoot per month. Usingthe renting priceover the opened area,we found the time to balancethe costof the changes and improvements of the coolingbay is only 2 months and 23 days. L = length of coolingblock W = width of coolingblock area p = priceper squarefoot π‘‚π‘Ÿπ‘–π‘”π‘–π‘›π‘Žπ‘™ πΆπ‘œπ‘ π‘‘ π‘π‘’π‘Ÿ π‘€π‘œπ‘›π‘‘β„Ž = 𝐿 βˆ— π‘Š βˆ— π‘π‘Ÿπ‘–π‘π‘’ = 52 βˆ— 48 βˆ— $20.00 = $49,920.00 π‘π‘’π‘Ÿ π‘šπ‘œπ‘›π‘‘β„Ž 𝑁𝑒𝑀 πΆπ‘œπ‘ π‘‘ π‘π‘’π‘Ÿ π‘€π‘œπ‘›π‘‘β„Ž = 27 βˆ— 20 βˆ— $20.00 = $25,920.00 π‘π‘’π‘Ÿ π‘šπ‘œπ‘›π‘‘β„Ž Cost of changes = $34,838.05 π‘‡π‘–π‘šπ‘’ π‘‘π‘œ π‘…π‘’π‘π‘’π‘π‘’π‘Ÿπ‘Žπ‘‘π‘’ πΆβ„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 πΆπ‘œπ‘ π‘‘ = πΆπ‘œπ‘ π‘‘ π‘œπ‘“ π‘β„Žπ‘Žπ‘›π‘”π‘’π‘  Γ· πΆβ„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 π‘π‘œπ‘ π‘‘ = 34,838 Γ· (49,920 βˆ’ 25,920) = 1.45 π‘šπ‘œπ‘›π‘‘β„Žπ‘ 
  • 12. 12 MODELING The CAD modeling of the solution was done in SolidWorks.Theassembly can be seen on the followingpages.Figure 7 illustrates the plant if the assembly were to stay at its given length of 52 ft long. The current setup utilizes 4 recycling tanks which collect all of the drained water after it has come in with the hot steel pipe. There are 3 low gradeheat exchangers which then cool the water and feed them back into the nozzles.Figure 8 illustrates thesystem after the heat transfer process has been overhauled to be more efficient. This system incorporates two recycling tanks, 3 pumps and 3 heat exchangers of high quality. The water first is collected through the drains in the steel coolingbays and funneled into the recyclingtanks (Figure 10). From there the recycled water is then sucked out of the tanks and into the (chiller) heatexchanger so that the 80F water can be cooled down to 40F (Figures 9 and 11). After the water has been chilled itis thesucked out of the heat exchanger by use of the pump atroughly 15 gpm per pump and into the nozzle spray apparatuses (Figures 9 and 11). Then through the use of pipereducers, the water is funneled from ΒΎ in pipeto β…› in nozzles where the psi is drastically increased (Figure 9). From there the nozzles then spray the steel pipes in a manner at which 50% of one sideis sprayed and then 50%of the other sideis then sprayed at a 100 psi and 40F. The water is then once again drained from the coolingbays and repeated over and over again in an open-loop heattransfer process. The drawing(Figure12,pg.16) of the assembly demonstrates the dimensional Figure 8: Original system before modifications.
  • 13. 13 analysisof the final reduced system. The overhaul of the system reduced the steel coolingbay from 52 ft longto 27 ft long.This left the system with 3 total heat exchangers,3 15 Gpm pumps, and two tanks being used. Figure 9: Modified system. Figure 10: Close-up view ofmodified system.
  • 14. 14 Figure 11: Close-up view oftanksand piping. Figure 12: Top view ofcooling bay system.
  • 15. 15 Figure 13: Top view system drawing.
  • 16. 16 RESULTS The final results of the modified system are shown below: Required Total Spray Swath 50.77 Inches Final Cooler Length 24 Feet Rate of Temperature Loss 10.35 F/s Initial Convection Heat Transfer Coefficient 0.00015 BTU/s-in2-F Final Convection Heat Transfer Coefficient 0.0011 BTU/s-in2-F Total Flow Rate 12.54 GPM Individual NozzleFlow rate 0.3918 GPM System Reliability 79.58% Cost $34,838.05 Time to Recover Cost 3.11 months Table 4: Table ofresults.
  • 17. 17 CONCLUSION By increasingthepressureand addingchillers to thesystem, the length of the coolingbay was reduced by 52%, while consistently coolingtheextruded pipe to 80 F before addingthe thermoplastic coating.Thenew system will improve plant profitability by reducing waste and opening additional space on the plant floor. The reliability of the system was found to be about 89%. The improved design will cost an additional $34,838.05, which is more than balanced by the improved ability of the system to cool the extruded pipe consistently to an acceptabletemperature and the additional floor spacethatbecomes availableas a resultof shorteningthe coolingbay.In fact, the extra spacealone can balanceout the costof the improvements in its firstquarter of use.
  • 18. 18 APPENDIX A: TEAM RESPONSIBILI TIES* *Everyone helped with the presentations. Name Position Responsibility Thaddeus Berger Technical Writing Lead Writing Martin Bonilla CAD Analyst CAD Claude Brooks Technical Writer Writing Clyde Brown Team Lead CAD Alexander Eierle Reliability Calculations Calculations Jonas Fuglas CAD Analyst CAD Elizabeth Heeke Technical Writer Writing John Hilker Cost Calculations Calculations Paul Kepinski Fluids Calculations Calculations Andre-Louis Pounder Heat Calculations Calculations Austin Spagnolo Calculations CAD Nate Voris Heat Calculations Calculations Table 5: Team responsibilities.
  • 19. 19 B: BUDGET Part Unit Price Quantity Total Price Circulation Pump for water, 1.5 hp 208- 240/460 V AC, 40 gpm flow rate $661.95 3 $1985.85 High-Flow, Circulating Process Chiller,60 kBTU/hr, 460 V/3 PH, 5 hp, 15 gpm flow rate, 36 gal tank $10,619.44 3 $31,858.32 Horizontal Polyethylene Tank w/ Legs, 60 gal w/ drain,38.5” length $496.94 2 $993.88 Total $34,838.05 Table 6: Budget for modified system.
  • 20. 20 REFERENCES ο‚· Incropera,F.P., DeWitt, D.P., Bergman T., and LavineA., Fundamentals of Heat and Mass Transfer,6th Edition, Wiley (2006). ο‚· Cengel, Y.A., and J.M. Cimbala,Fluid Mechanics –Fundamentals and Applications,3rd Ed., McGraw-Hill (2014). ο‚· Parts: "Circulation Pumps." McMaster-Carr. N.p., n.d. Web. "Easy-Drain Cylindrical Tanks." McMaster-Carr. N.p., n.d. Web. "Polyethylene Tanks." McMaster-Carr. N.p., n.d. Web.