The half-life of Carbon 14 is 5745 years. Suppose that certain remains are discovered in which the current residual amount of Carbon 14 is 16% of the original amount. Determine the age of the remains. This is from the section of the book on homogenous differential equations. Please help me work this through. Solution Let A = age in years Let R = ratio of (sample C14) / (\"living C14\" ) Let H = half-life of C14 A = -1 * H * (log(R) / log(2) ) here R=0.16 A=15188.953810255793377029970244833yrs.