Suppose Bob sends an encrypted document to Alice. To be verifiable, .pdf
•
0 likes•2 views
Suppose Bob sends an encrypted document to Alice. To be verifiable, Alice must be able to convince herself that Bob sent the encrypted document. To be non-forgeable, Alice must be able to convince herself that only Bob could have sent the encrypted document Alice must be able to convince someone else that only Bob could have sent the document. To illustrate the latter distinction, suppose Bob and Alice share a secret key, and they are the only ones in the world who know the key. If Alice receives a document that was encrypted with the key, and knows that she did not encrypt the document herself, then the document is known to be verifiable and non- forgeable (assuming a suitably strong encryption system was used). However, Alice can not convince someone else that Bob must have sent the document, since in fact Alice knew the key herself and could have encrypted/sent the document. Solution Suppose Bob sends an encrypted document to Alice. To be verifiable, Alice must be able to convince herself that Bob sent the encrypted document. To be non-forgeable, Alice must be able to convince herself that only Bob could have sent the encrypted document Alice must be able to convince someone else that only Bob could have sent the document. To illustrate the latter distinction, suppose Bob and Alice share a secret key, and they are the only ones in the world who know the key. If Alice receives a document that was encrypted with the key, and knows that she did not encrypt the document herself, then the document is known to be verifiable and non- forgeable (assuming a suitably strong encryption system was used). However, Alice can not convince someone else that Bob must have sent the document, since in fact Alice knew the key herself and could have encrypted/sent the document..
Report
Share
Report
Share
Download to read offline
Recommended
steps are as follows Dissolve the (pressumably.pdf
steps are as follows : Dissolve the (pressumably solid) mixture in an organic
solven,,,,,,, Then, in a seperating funnel, add an (Aqueous) solution of sodium hydroxide. The
Phenol, and benzoic acid, as acids, will react with the base to form phenolate and benzenoate
ions, which will dissolve into the water layer. Collect this layer, and re-precipitate the organic
molecules by adding concentrated Hydrochloric acid. The phenol and Benzoic acid can be
seperated via their varying solubilities, (8.3g/100ml vs 0.34g/100ml. respectively) by heating the
mixture in water to dissolve the phenol, and then filtering of the (practically) insoluble benzoic
acid. The solution can then be acidified (with HCl) to return the phenol..,,,,,,,,,,,,, Now add a
solution of hydrochloric acid to the seperating funnel, which (as before) will react with the basic
anniline dossilving it into the water. Collect the aqueous layer and re-precipitate the anniline
with excess sodium hydroxide. ,,,,,,,,,,,,,,, finally boil off the remaining organic solvent to obtain
the napthalene, which was left untouched by all the acids and bases.,,,,,,,,, Flow chart : Mixture
+ xs HCl ----> anilinium(aq) Mixture - aniline + weak base (Na2CO3) ---> benzoate(aq)
Mixture - aniline - benzoic acid + base (NaOH) ---> p-bromophenoxide(aq) Mixture - aniline -
benzoic acid - p-bromophenol = naphthalene
Solution
steps are as follows : Dissolve the (pressumably solid) mixture in an organic
solven,,,,,,, Then, in a seperating funnel, add an (Aqueous) solution of sodium hydroxide. The
Phenol, and benzoic acid, as acids, will react with the base to form phenolate and benzenoate
ions, which will dissolve into the water layer. Collect this layer, and re-precipitate the organic
molecules by adding concentrated Hydrochloric acid. The phenol and Benzoic acid can be
seperated via their varying solubilities, (8.3g/100ml vs 0.34g/100ml. respectively) by heating the
mixture in water to dissolve the phenol, and then filtering of the (practically) insoluble benzoic
acid. The solution can then be acidified (with HCl) to return the phenol..,,,,,,,,,,,,, Now add a
solution of hydrochloric acid to the seperating funnel, which (as before) will react with the basic
anniline dossilving it into the water. Collect the aqueous layer and re-precipitate the anniline
with excess sodium hydroxide. ,,,,,,,,,,,,,,, finally boil off the remaining organic solvent to obtain
the napthalene, which was left untouched by all the acids and bases.,,,,,,,,, Flow chart : Mixture
+ xs HCl ----> anilinium(aq) Mixture - aniline + weak base (Na2CO3) ---> benzoate(aq)
Mixture - aniline - benzoic acid + base (NaOH) ---> p-bromophenoxide(aq) Mixture - aniline -
benzoic acid - p-bromophenol = naphthalene.
the two features of the asynchronus connection that allow the receiv.pdf
the two features of the asynchronus connection that allow the receiver to stay in sync with the
incoming data stream are the start bit and short frame connections . asynchronus connection are
asynchronus serial communications in which the communicating end points interfaces are not
continously synchronized by common clock signal and the data stream contains synchronization
in the form of start and stop signals before and after each unit of transmission .asynchronus start
and stop signals was widley used for dial up modem sources to time sharing computers and bbs
systems asynchronus start stop is the physical layer is used to connect computers to modems for
many dial up internet access applications using data link frame protocol such as ppp to create
packets made upto out of asynchronous serial characters .the examples that would benefit from
asynchronous connection are modems and usb that are connectedd to interfaces
Solution
the two features of the asynchronus connection that allow the receiver to stay in sync with the
incoming data stream are the start bit and short frame connections . asynchronus connection are
asynchronus serial communications in which the communicating end points interfaces are not
continously synchronized by common clock signal and the data stream contains synchronization
in the form of start and stop signals before and after each unit of transmission .asynchronus start
and stop signals was widley used for dial up modem sources to time sharing computers and bbs
systems asynchronus start stop is the physical layer is used to connect computers to modems for
many dial up internet access applications using data link frame protocol such as ppp to create
packets made upto out of asynchronous serial characters .the examples that would benefit from
asynchronous connection are modems and usb that are connectedd to interfaces.
Telomerase is the enzyme responsible for maintenance of the length o.pdf
Telomerase is the enzyme responsible for maintenance of the length of telomeres by addition of
guanine-rich repetitive sequences, (Zvereva, 2010). Thus Telomerase, is a Specialized
Polymerase That Carries Its Own RNA Template. Thus it accounts for a faithful replication of
chromosomal ends as theTelomerase contains an RNA molecule that acts as a template for
extending the leading strand.
Solution
Telomerase is the enzyme responsible for maintenance of the length of telomeres by addition of
guanine-rich repetitive sequences, (Zvereva, 2010). Thus Telomerase, is a Specialized
Polymerase That Carries Its Own RNA Template. Thus it accounts for a faithful replication of
chromosomal ends as theTelomerase contains an RNA molecule that acts as a template for
extending the leading strand..
probablity = 212 100 = 16.6 Solutionprobablity = 212 10.pdf
probablity = 2/12 * 100 = 16.6 %
Solution
probablity = 2/12 * 100 = 16.6 %.
Platinum complexes like Asplastin are powerful antitumor medications.pdf
Platinum complexes like Asplastin are powerful antitumor medications and they are having
ability to cross the cell membrane and then reaches the nucleus and will attach to DNA and stop
cell growth. The transfer of this Asplastin is facilitated by a copper transporter (Ctr1-membrane-
dwelling protein which main function is to bring copper into cells). The |Ctr1 structure has of
three helical segments which appears to sit in the membrane, and one end can be seen protruding
into the cell, while the other end will be seen on the outside and a channel like structure will be
formed when three such molecules assemble together.
When Asplastin is injected in the body of a cancer patient, the Asplastin which have a central
platinum ion and four ligands (which includes two neighboring chloride ions and two
neighboring amino groups). The Ctr1 will displaces these four ligands from Asplastin and will
bind to the platinum ion itself and it will transfer it through the channel and released in the
cytosol of the cell. In addition to this few amount of Asplastin molecules will interact with the
methionine-rich extracellular end of the copper transporter to form a trimeric channel structure to
get transported as a little interior bubble filled with the outer medium and will released into
various organelles including nucleus.
How it acts on cancer cells: The 4 steps how Asplastin will act is (i) Cellular uptake of drug, (ii)
aquation/activation of Asplastin, (iii) Drug binding to DNA and (iv) Lesions formed on DNA
will make the cell to opt for apoptosis.
N7 sites of deoxyguanosine residues on the DNA are the most nucleophilic positions and are
preferentially platinated. Asplastin will form a monofunctional adducts on DNA (You can see
only one covalent bond to the genomic polymer). Like in second reaction second guanine base
will get substituted by chloride ligand, thus forming a cross-link on the DNA (either on the same
strand or it may be on different strands). The most common lesion are formed from 1,2-d(GpG)
intrastrand cross-links and finally due to drug action we can see bending and unwinding of the
double helix and cells with damaged DNA will be arrested at the G2/M transition of the cell
cycle and undergoes apoptosis.
Solution
Platinum complexes like Asplastin are powerful antitumor medications and they are having
ability to cross the cell membrane and then reaches the nucleus and will attach to DNA and stop
cell growth. The transfer of this Asplastin is facilitated by a copper transporter (Ctr1-membrane-
dwelling protein which main function is to bring copper into cells). The |Ctr1 structure has of
three helical segments which appears to sit in the membrane, and one end can be seen protruding
into the cell, while the other end will be seen on the outside and a channel like structure will be
formed when three such molecules assemble together.
When Asplastin is injected in the body of a cancer patient, the Asplastin which have a central
platinum ion and f.
Part 1 1)#include stdio.hint testWhileLoop() ; int testFo.pdf
Part 1:
1)
#include
int testWhileLoop() ;
int testForLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
printf(\"For loop test \ \");
testForLoop();
return 0;
}
Part 2:
1)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
}
}
2)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
3)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer between 5 and 20: \");
scanf(\"%d\",&n);
while(n<5 || n>20)
{
printf(\"Error: You must enter a value between 5 and 20: please renter: \");
scanf(\"%d\",&n);
}
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Part 3:
#include
int testForLoop() ;
int main()
{
printf(\"For loop test \ \");
testForLoop();
return 0;
}
int testForLoop()
{
int count=0;
int n;
int sum=0;
for (count=0;count<10;count++)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Solution
Part 1:
1)
#include
int testWhileLoop() ;
int testForLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
printf(\"For loop test \ \");
testForLoop();
return 0;
}
Part 2:
1)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
}
}
2)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
3)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer between 5 and 20: \");
scanf(\"%d\",&n);
while(n<5 || n>20)
{
printf(\"Error: You must enter a value between 5 and 20: please renter: \");
scanf(\"%d\",&n);
}
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Part 3:
#include
int testForLoop() ;
int main()
{
printf(\"For loop test \ \");
testForLoop();
return 0;
}
int testForLoop()
{
int c.
none of them are correct!Solutionnone of them are correct!.pdf
none of them are correct!
Solution
none of them are correct!.
Recommended
steps are as follows Dissolve the (pressumably.pdf
steps are as follows : Dissolve the (pressumably solid) mixture in an organic
solven,,,,,,, Then, in a seperating funnel, add an (Aqueous) solution of sodium hydroxide. The
Phenol, and benzoic acid, as acids, will react with the base to form phenolate and benzenoate
ions, which will dissolve into the water layer. Collect this layer, and re-precipitate the organic
molecules by adding concentrated Hydrochloric acid. The phenol and Benzoic acid can be
seperated via their varying solubilities, (8.3g/100ml vs 0.34g/100ml. respectively) by heating the
mixture in water to dissolve the phenol, and then filtering of the (practically) insoluble benzoic
acid. The solution can then be acidified (with HCl) to return the phenol..,,,,,,,,,,,,, Now add a
solution of hydrochloric acid to the seperating funnel, which (as before) will react with the basic
anniline dossilving it into the water. Collect the aqueous layer and re-precipitate the anniline
with excess sodium hydroxide. ,,,,,,,,,,,,,,, finally boil off the remaining organic solvent to obtain
the napthalene, which was left untouched by all the acids and bases.,,,,,,,,, Flow chart : Mixture
+ xs HCl ----> anilinium(aq) Mixture - aniline + weak base (Na2CO3) ---> benzoate(aq)
Mixture - aniline - benzoic acid + base (NaOH) ---> p-bromophenoxide(aq) Mixture - aniline -
benzoic acid - p-bromophenol = naphthalene
Solution
steps are as follows : Dissolve the (pressumably solid) mixture in an organic
solven,,,,,,, Then, in a seperating funnel, add an (Aqueous) solution of sodium hydroxide. The
Phenol, and benzoic acid, as acids, will react with the base to form phenolate and benzenoate
ions, which will dissolve into the water layer. Collect this layer, and re-precipitate the organic
molecules by adding concentrated Hydrochloric acid. The phenol and Benzoic acid can be
seperated via their varying solubilities, (8.3g/100ml vs 0.34g/100ml. respectively) by heating the
mixture in water to dissolve the phenol, and then filtering of the (practically) insoluble benzoic
acid. The solution can then be acidified (with HCl) to return the phenol..,,,,,,,,,,,,, Now add a
solution of hydrochloric acid to the seperating funnel, which (as before) will react with the basic
anniline dossilving it into the water. Collect the aqueous layer and re-precipitate the anniline
with excess sodium hydroxide. ,,,,,,,,,,,,,,, finally boil off the remaining organic solvent to obtain
the napthalene, which was left untouched by all the acids and bases.,,,,,,,,, Flow chart : Mixture
+ xs HCl ----> anilinium(aq) Mixture - aniline + weak base (Na2CO3) ---> benzoate(aq)
Mixture - aniline - benzoic acid + base (NaOH) ---> p-bromophenoxide(aq) Mixture - aniline -
benzoic acid - p-bromophenol = naphthalene.
the two features of the asynchronus connection that allow the receiv.pdf
the two features of the asynchronus connection that allow the receiver to stay in sync with the
incoming data stream are the start bit and short frame connections . asynchronus connection are
asynchronus serial communications in which the communicating end points interfaces are not
continously synchronized by common clock signal and the data stream contains synchronization
in the form of start and stop signals before and after each unit of transmission .asynchronus start
and stop signals was widley used for dial up modem sources to time sharing computers and bbs
systems asynchronus start stop is the physical layer is used to connect computers to modems for
many dial up internet access applications using data link frame protocol such as ppp to create
packets made upto out of asynchronous serial characters .the examples that would benefit from
asynchronous connection are modems and usb that are connectedd to interfaces
Solution
the two features of the asynchronus connection that allow the receiver to stay in sync with the
incoming data stream are the start bit and short frame connections . asynchronus connection are
asynchronus serial communications in which the communicating end points interfaces are not
continously synchronized by common clock signal and the data stream contains synchronization
in the form of start and stop signals before and after each unit of transmission .asynchronus start
and stop signals was widley used for dial up modem sources to time sharing computers and bbs
systems asynchronus start stop is the physical layer is used to connect computers to modems for
many dial up internet access applications using data link frame protocol such as ppp to create
packets made upto out of asynchronous serial characters .the examples that would benefit from
asynchronous connection are modems and usb that are connectedd to interfaces.
Telomerase is the enzyme responsible for maintenance of the length o.pdf
Telomerase is the enzyme responsible for maintenance of the length of telomeres by addition of
guanine-rich repetitive sequences, (Zvereva, 2010). Thus Telomerase, is a Specialized
Polymerase That Carries Its Own RNA Template. Thus it accounts for a faithful replication of
chromosomal ends as theTelomerase contains an RNA molecule that acts as a template for
extending the leading strand.
Solution
Telomerase is the enzyme responsible for maintenance of the length of telomeres by addition of
guanine-rich repetitive sequences, (Zvereva, 2010). Thus Telomerase, is a Specialized
Polymerase That Carries Its Own RNA Template. Thus it accounts for a faithful replication of
chromosomal ends as theTelomerase contains an RNA molecule that acts as a template for
extending the leading strand..
probablity = 212 100 = 16.6 Solutionprobablity = 212 10.pdf
probablity = 2/12 * 100 = 16.6 %
Solution
probablity = 2/12 * 100 = 16.6 %.
Platinum complexes like Asplastin are powerful antitumor medications.pdf
Platinum complexes like Asplastin are powerful antitumor medications and they are having
ability to cross the cell membrane and then reaches the nucleus and will attach to DNA and stop
cell growth. The transfer of this Asplastin is facilitated by a copper transporter (Ctr1-membrane-
dwelling protein which main function is to bring copper into cells). The |Ctr1 structure has of
three helical segments which appears to sit in the membrane, and one end can be seen protruding
into the cell, while the other end will be seen on the outside and a channel like structure will be
formed when three such molecules assemble together.
When Asplastin is injected in the body of a cancer patient, the Asplastin which have a central
platinum ion and four ligands (which includes two neighboring chloride ions and two
neighboring amino groups). The Ctr1 will displaces these four ligands from Asplastin and will
bind to the platinum ion itself and it will transfer it through the channel and released in the
cytosol of the cell. In addition to this few amount of Asplastin molecules will interact with the
methionine-rich extracellular end of the copper transporter to form a trimeric channel structure to
get transported as a little interior bubble filled with the outer medium and will released into
various organelles including nucleus.
How it acts on cancer cells: The 4 steps how Asplastin will act is (i) Cellular uptake of drug, (ii)
aquation/activation of Asplastin, (iii) Drug binding to DNA and (iv) Lesions formed on DNA
will make the cell to opt for apoptosis.
N7 sites of deoxyguanosine residues on the DNA are the most nucleophilic positions and are
preferentially platinated. Asplastin will form a monofunctional adducts on DNA (You can see
only one covalent bond to the genomic polymer). Like in second reaction second guanine base
will get substituted by chloride ligand, thus forming a cross-link on the DNA (either on the same
strand or it may be on different strands). The most common lesion are formed from 1,2-d(GpG)
intrastrand cross-links and finally due to drug action we can see bending and unwinding of the
double helix and cells with damaged DNA will be arrested at the G2/M transition of the cell
cycle and undergoes apoptosis.
Solution
Platinum complexes like Asplastin are powerful antitumor medications and they are having
ability to cross the cell membrane and then reaches the nucleus and will attach to DNA and stop
cell growth. The transfer of this Asplastin is facilitated by a copper transporter (Ctr1-membrane-
dwelling protein which main function is to bring copper into cells). The |Ctr1 structure has of
three helical segments which appears to sit in the membrane, and one end can be seen protruding
into the cell, while the other end will be seen on the outside and a channel like structure will be
formed when three such molecules assemble together.
When Asplastin is injected in the body of a cancer patient, the Asplastin which have a central
platinum ion and f.
Part 1 1)#include stdio.hint testWhileLoop() ; int testFo.pdf
Part 1:
1)
#include
int testWhileLoop() ;
int testForLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
printf(\"For loop test \ \");
testForLoop();
return 0;
}
Part 2:
1)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
}
}
2)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
3)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer between 5 and 20: \");
scanf(\"%d\",&n);
while(n<5 || n>20)
{
printf(\"Error: You must enter a value between 5 and 20: please renter: \");
scanf(\"%d\",&n);
}
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Part 3:
#include
int testForLoop() ;
int main()
{
printf(\"For loop test \ \");
testForLoop();
return 0;
}
int testForLoop()
{
int count=0;
int n;
int sum=0;
for (count=0;count<10;count++)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Solution
Part 1:
1)
#include
int testWhileLoop() ;
int testForLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
printf(\"For loop test \ \");
testForLoop();
return 0;
}
Part 2:
1)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
}
}
2)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
3)
#include
int testWhileLoop() ;
int main()
{
printf(\"While loop test \ \");
testWhileLoop();
return 0;
}
int testWhileLoop()
{
int count=0;
int n;
int sum=0;
while (count<10)
{
printf(\"Enter an integer between 5 and 20: \");
scanf(\"%d\",&n);
while(n<5 || n>20)
{
printf(\"Error: You must enter a value between 5 and 20: please renter: \");
scanf(\"%d\",&n);
}
printf(\"You Entered: %d\ \",n);
count++;
sum=sum+n;
}
printf(\"Total sum of integers is: %d\ \",sum);
}
Part 3:
#include
int testForLoop() ;
int main()
{
printf(\"For loop test \ \");
testForLoop();
return 0;
}
int testForLoop()
{
int c.
none of them are correct!Solutionnone of them are correct!.pdf
none of them are correct!
Solution
none of them are correct!.
Negative control plate with no DNA transforms competent cells withou.pdf
Negative control plate with no DNA transforms competent cells without any DNA on selection
media. , If more colonies are produced, shows the problem with antibiotic in the agar plate.
No ligase control plates provide information about digestion efficiency. it transform competent
cells withdigested plasmid or DNA. If several colonies are found, it shows that digestion did not
completed properly.
Solution
Negative control plate with no DNA transforms competent cells without any DNA on selection
media. , If more colonies are produced, shows the problem with antibiotic in the agar plate.
No ligase control plates provide information about digestion efficiency. it transform competent
cells withdigested plasmid or DNA. If several colonies are found, it shows that digestion did not
completed properly..
Modifications highlighted in bold lettersDropOutStack.javaim.pdf
//Modifications highlighted in bold letters
//DropOutStack.java
import java.util.Arrays;
public class DropOutStack {
/**
* Defines the interface to a stack collection.
*
* @author Java Foundations
* @version 4.0
*/
public interface StackADT {
/**
* Adds the specified element to the top of this stack.
*
* @param element
* element to be pushed onto the stack
*/
public void push(T element);
/**
* Removes and returns the top element from this stack.
*
* @return the element removed from the stack
*/
public T pop();
/**
* Returns without removing the top element of this stack.
*
* @return the element on top of the stack
*/
public T peek();
/**
* Returns true if this stack contains no elements.
*
* @return true if the stack is empty
*/
public boolean isEmpty();
/**
* Returns the number of elements in this stack.
*
* @return the number of elements in the stack
*/
public int size();
/**
* Returns a string representation of this stack.
*
* @return a string representation of the stack
*/
public String toString();
}
/**
* Represents the situation in which a collection is empty.
*
* @author Java Foundations
* @version 4.0
*/
public static class EmptyCollectionException extends RuntimeException {
/**
* Sets up this exception with an appropriate message.
*
* @param collection
* the name of the collection
*/
public EmptyCollectionException(String collection) {
super(\"The \" + collection + \" is empty.\");
}
}
/**
* Program entry point for stack testing.
*
* @param args
* Argument list.
*/
public static void main(String[] args) {
ArrayDropOutStack stack = new ArrayDropOutStack(4);
System.out.println(\"DROP-OUT STACK TESTING\");
stack.push(1);
stack.push(2);
stack.push(3);
stack.push(4);
System.out.println(\"Stack : \"+stack.toString());
System.out.println(\"pushing 5 element \");
stack.push(5);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
System.out.println(\"The size of the stack is: \" + stack.size());
if (!stack.isEmpty())
System.out.println(\"The stack contains:\ \" + stack.toString());
stack.pop();
System.out.println(\"poping element 5\"+stack.toString());
System.out.println(\"The size of the stack is: \" + stack.size());
System.out.println(\"pushing 7 element \");
stack.push(7);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
System.out.println(\"pushing 8 element \");
stack.push(8);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
if (!stack.isEmpty())
System.out.println(\"The stack contains:\ \" + stack.toString());
}
/**
* An array implementation of a stack in which the bottom of the stack is
* fixed at index 0.
*
* @author Java Foundations
* @version 4.0
*/
public static class ArrayDropOutStack implements StackADT {
private final static int DEFAULT_CAPACITY = 100;
private int top;
private T[] stack;
/**
* Creates an empty stack using the default capacity.
*/
public ArrayDropOutStack() {
this(DEFAULT_CAPACITY);
}
/**
* Creates an empty stack using.
Message types used by the DHCP boot sequenceop Message type.h.pdf
Message types used by the DHCP boot sequence
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority (IANA).
hlen
: Hardware address length, in octets.
hops
: Value set to zero by DHCP clients. Optionally used to count the number of relay agents that
forwarded the message.
xid
: A random number used to associate messages and responses between a client and a server.
secs
: Seconds elapsed since client began address acquisition or renewal process.
flags
: Flags set by client. The Broadcast flag is set if the client cannot receive unicast IP datagrams
(for example, before it is configured with an IP address).
ciaddr
: Used if the client has an IP address and can respond to Address Resolution Protocol (ARP)
requests.
yiaddr
: Address given to the DHCP client by the DHCP server.
siaddr
: IP address of the server that is offering a lease.
giaddr
: DHCP relay agent IP address.
chaddr
: Client hardware address.
sname
: Optional server host name. Not used in Windows Server 2008.
file
: The name of the file containing the boot image for a BOOTP client.
options
: Optional parameters field. In the DHCP protocol packet, each option begins with a single octet
tag, which holds the option code, and a second octet, which describes the option data length, in
bytes. For a complete list of the DHCP options available by default on a DHCP server running
on Windows Server 2008, see DHCP Tools and Options.
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority (IANA).
hlen
: Hardware address length, in octets.
hops
: Value set to zero by DHCP clients. Optionally used to count the number of relay agents that
forwarded the message.
xid
: A random number used to associate messages and responses between a client and a server.
secs
: Seconds elapsed since client began address acquisition or renewal process.
flags
: Flags set by client. The Broadcast flag is set if the client cannot receive unicast IP datagrams
(for example, before it is configured with an IP address).
ciaddr
: Used if the client has an IP address and can respond to Address Resolution Protocol (ARP)
requests.
yiaddr
: Address given to the DHCP client by the DHCP server.
siaddr
: IP address of the server that is offering a lease.
giaddr
: DHCP relay agent IP address.
chaddr
: Client hardware address.
sname
: Optional server host name. Not used in Windows Server 2008.
file
: The name of the file containing the boot image for a BOOTP client.
options
: Optional parameters field. In the DHCP protocol packet, each option begins with a single octet
tag, which holds the option code, and a second octet, which describes the option data length, in
bytes. For a complete list of the DHCP options available by default on a DHCP server running
on Windows Server 2008, see DHCP Tools and Options.
Solution
Message types used by the DHCP boot sequence
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority.
Law of conservation of matter(mass)In any closed system subjected .pdf
Law of conservation of matter(mass)
In any closed system subjected to no external forces,the mass is constant irrespective of its
changes in different form. Matter cannot be created or destroyed in an isolated system. It only
changes from one form into another.
Solution
Law of conservation of matter(mass)
In any closed system subjected to no external forces,the mass is constant irrespective of its
changes in different form. Matter cannot be created or destroyed in an isolated system. It only
changes from one form into another..
It is a unit of measurement for the amount of substance.The mole is .pdf
It is a unit of measurement for the amount of substance.The mole is defined as the amount of
substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as
there are atoms in 12 g of the isotope carbon-12. The experimentally determined value of a mole
as adopted 6.02 × 1023.
Solution
It is a unit of measurement for the amount of substance.The mole is defined as the amount of
substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as
there are atoms in 12 g of the isotope carbon-12. The experimentally determined value of a mole
as adopted 6.02 × 1023..
In insurance, the term risk pooling refers to the spreading of f.pdf
In insurance, the term \"risk pooling\" refers to the spreading of financial risks evenly among a
large number of contributors to the program. Insurance is the transference of risks from
individuals or corporations who cannot bear a possible unplanned financial catastrophe to the
capital markets, which can bear them easily -- at least in theory.
Pure risk is a category of risk in which loss is the only possible outcome, which is the opposite of
speculative risk. There are products that can be purchased to mitigate pure risk, such as home
insurance being used to protect homeowners against their homes being destroyed. Other
examples of pure risk events include premature death, identity theft and career-ending
disabilities.1) in cases of home insurance and health insurance risk pooling can be effectively
used as of all the individuals who invest in the insurance by the law of large number a miniscule
probability of the people actually suffer the real risk. 2) Risk pooling is an important concept in
supply chain management . It suggests that demand variability is reduced if one aggregates
demand across locations because, as demand is aggregated across different locations, it becomes
more likely that high demand from one customer will be offset by low demand from another.
However,consider the 1)\"high risk pools\", which simply means separating out the sickest, most
expensive people in the country and dumping them into a separate program.With the \"bad
apples\" (ie, human beings with terrible medical problems) safely tucked out of the way, the
average cost of treating everyone else supposedly suddenly becomes less pricey.This is the exact
opposite of the entire point of health insurance in the first place...spreading the risk and hence
risk pooling fails here.
2)Liability risk includes economic losses from being held responsible for harming others or their
property. This cannot be covered by risk pooling.
Solution
In insurance, the term \"risk pooling\" refers to the spreading of financial risks evenly among a
large number of contributors to the program. Insurance is the transference of risks from
individuals or corporations who cannot bear a possible unplanned financial catastrophe to the
capital markets, which can bear them easily -- at least in theory.
Pure risk is a category of risk in which loss is the only possible outcome, which is the opposite of
speculative risk. There are products that can be purchased to mitigate pure risk, such as home
insurance being used to protect homeowners against their homes being destroyed. Other
examples of pure risk events include premature death, identity theft and career-ending
disabilities.1) in cases of home insurance and health insurance risk pooling can be effectively
used as of all the individuals who invest in the insurance by the law of large number a miniscule
probability of the people actually suffer the real risk. 2) Risk pooling is an important concept in
supply chain management . It suggests that.
Some CO is Added The Pressure of CH4 and H2O will.pdf
Some CO is Added The Pressure of CH4 and H2O will Increase Equilibrium will
shift to the Left Some CH4 is Removed Pressure of H2O will Increase Pressure of CO will
Decrease Equilibrium will shift to the Left The Volume of Vessel is Reduced Pressure of CH4
will Increase Pressure of H2O will Increase Equilibrium will shift to the Left
Solution
Some CO is Added The Pressure of CH4 and H2O will Increase Equilibrium will
shift to the Left Some CH4 is Removed Pressure of H2O will Increase Pressure of CO will
Decrease Equilibrium will shift to the Left The Volume of Vessel is Reduced Pressure of CH4
will Increase Pressure of H2O will Increase Equilibrium will shift to the Left.
Comments Figures are not properly numbered. Further signal of figur.pdf
Comments: Figures are not properly numbered. Further signal of figure 1 is not shown and hence
the above figure (assumed to figure 2) can not be simulated.
Solution
Comments: Figures are not properly numbered. Further signal of figure 1 is not shown and hence
the above figure (assumed to figure 2) can not be simulated..
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.j.pdf
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.java
import java.util.*;
import java.util.LinkedList;
class Test {
HashSet uniqueStates;
void letsRoll() {
/*
* The capacity of jug1(jug1 capacity is greater than jug2 capacity)
*/
int jug1 = 3;
/*
* The capacity of jug two
*/
int jug2 = 2;
/*
* Final Amount needed in jug1
*/
int amtNeeded = 2;
State initialState = new State(0, 0);
State finalState = new State(amtNeeded, 0);
State finalPath = null;
uniqueStates = new HashSet();
/*
* Change queue to stack to convert to DFS
*/
LinkedList queue = new LinkedList();
queue.add(initialState);
while (!queue.isEmpty()) {
State currState = queue.poll();
if (currState.equals(finalState)) {
finalPath = currState;
break;
}
// if x is zero fill it
if (currState.x == 0) {
State nextState = new State(jug1, currState.y, currState);
//System.out.println(currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if y is empty fill it
if (currState.y == 0) {
State nextState = new State(currState.x, jug2, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if x is not empty , empty it
if (currState.x > 0) {
State nextState = new State(0, currState.y, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if y is not empty, empty it
if (currState.y > 0) {
State nextState = new State(currState.x, 0, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// transfer from x to y, when x non empty and y is not full
if (currState.x > 0 && currState.y < jug2) {
int amtToTransfer = Math.min(currState.x, jug2 - currState.y);
State nextState = new State(currState.x - amtToTransfer, currState.y
+ amtToTransfer,
currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// transfer from y to x, when y is not empty and x is not full
if (currState.y > 0 && currState.x < jug1) {
int amtToTransfer = Math.min(currState.y, jug1 - currState.x);
State nextState = new State(currState.x + amtToTransfer, currState.y
- amtToTransfer,
currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
}
if (finalPath != null) {
System.out.println(\"Final Result\");
System.out.println(\"J1 J2\");
System.out.println(finalPath);
}
else{
System.out.println(\"Not Possible\");
}
}
/*
* Checks whether State toCheck has been generated before, if not it is
* added to queue and uniqueStates Set
*/
void checkUniqueStates(HashSet uniqueStates, State toCheck,
LinkedList queue) {
if (!uniqueStates.contains(toCheck)) {
uniqueStates.add(toCheck);
queue.add(toCheck);
}
}
public static void main(String[] args) {
new Test().letsRoll();
}
}
2 State.java
class State {
/*
* Amount in jug1 for current State
*/
int x;
/*
* Amount in jug2 for current State
*/
int y;
/*
* Parent of current State
*/
State pre;
public State(int x, int y) {
super();
this.x = x;
this.y = y;
}
public State(int x, int y, State pre) {
super();
this.x = x;
this.y = y;
this.pre = pre;
System.out.println(\"(\"+x+\",\"+y+\")\");
}
@Override
public int hashCode() {
final int .
Balance sheetBalance sheet is the statement of financial position .pdf
Balance sheet
Balance sheet is the statement of financial position which reports all the assets, liabilities and
equity held by the company at a specific date. It helps in telling about the investments, resources,
claims and owner’s equity of the company. It revolves around the equation i.e. Assets =
Liabilities + equity.
What is shown in balance sheet:
The balance sheet has three major categories which includes Assets, liabilities and equity. All
these are calssified on the basis of their nature.
Assets can be said as the resources of the company and are classified as: Current assets, long
term investment, property, plant and equipment, intangible assets and other assets
Assets includes:
•Current assets – Cash, accounts receivables, prepaid expenses, inventories
•Long term investments – investment in stock
•Plant property and equipment – Land, building, equipment
•Intangible assets – Goodwill, patents, trademarks
Liabilities are the claims and can be classified as current liabilities, long term liabilities
Liabilities includes:
•Current liabilities: Accounts payable, income tax payable. Salaries payable, accrued expenses,
unearned revenue, current portion of long term debt due
•Long term liabilities- bonds payable, notes payable
Owner;s equity can be classified as the Capital stock which includes common stock and
preferred stock
It also includes Additional paid in capital, Retained earnings
Retained earnings are the accumulated earnings of the company. It is calculated as Beginning
balance, Add: Net income less: Dividends
Importance:
Balance sheet is important in every business. Considering the hospitality firm, it is important to
analyze different aspects of teh firm to know its financial postion. As the hospitality firm
emphasize on services, it is important to know the financial position of the company through its
financial statements. the hospitality firms like hotel needs to report their assets (building) held by
the company along with other assets, liabilities and equity.
Balance sheet is the statement which helps in analysing the financial position of the company, it
can also help in predicting the cash flows and the financial position of the company. With the
help of the balance sheet we can help in analysing the ability of the firm to pay off its short term
and long term debts.
Balance sheet reports its assets and liabilities on historical basis and uses different estimates to
analyse the amounts like uncollectibles
Solution
Balance sheet
Balance sheet is the statement of financial position which reports all the assets, liabilities and
equity held by the company at a specific date. It helps in telling about the investments, resources,
claims and owner’s equity of the company. It revolves around the equation i.e. Assets =
Liabilities + equity.
What is shown in balance sheet:
The balance sheet has three major categories which includes Assets, liabilities and equity. All
these are calssified on the basis of their nature.
Assets can be .
Answer BaSO4K+ is always soluble because it is an alkaline metal..pdf
Answer: BaSO4
K+ is always soluble because it is an alkaline metal. NO3- is also always soluble.
SO4 is usually soluble except when it is paired with Sr, Ba, Ca, or Pb.
Solution
Answer: BaSO4
K+ is always soluble because it is an alkaline metal. NO3- is also always soluble.
SO4 is usually soluble except when it is paired with Sr, Ba, Ca, or Pb..
Answer is B because he copied the member A and say that he is innoce.pdf
Answer is B because he copied the member A and say that he is innocent
and also here we can\'t give you a exact soln. because of the in appropriate format of the question
details
Solution
Answer is B because he copied the member A and say that he is innocent
and also here we can\'t give you a exact soln. because of the in appropriate format of the question
details.
A nephron consists of a renal corpuscle and a renal tubule. So the a.pdf
A nephron consists of a renal corpuscle and a renal tubule. So the answer is option 1.
Solution
A nephron consists of a renal corpuscle and a renal tubule. So the answer is option 1..
30). e). All of theseDifferent biotechnological methods such as ge.pdf
30). e). All of these
Different biotechnological methods such as gene cloning, DNA amplification, recombinant DNA
technology, are used during the process of DNA isolation and sequencing. For example, the
copies of genome are amplified by the process of DNA amplification, which we observe in PCR
(polymerase chain reaction). The resulting genome can be sequenced.
31). b). Cloning vectors
The purpose of cloning vectors is gene amplification. Cloning vectors are small pieces of DNA
isolated from a virus or any other higher organism. A close is inserted with a foreign DNA that
can be used for the purpose of cloning. Thus, a cloning vector must allow the gene editing by
using the restriction enzymes.
Solution
30). e). All of these
Different biotechnological methods such as gene cloning, DNA amplification, recombinant DNA
technology, are used during the process of DNA isolation and sequencing. For example, the
copies of genome are amplified by the process of DNA amplification, which we observe in PCR
(polymerase chain reaction). The resulting genome can be sequenced.
31). b). Cloning vectors
The purpose of cloning vectors is gene amplification. Cloning vectors are small pieces of DNA
isolated from a virus or any other higher organism. A close is inserted with a foreign DNA that
can be used for the purpose of cloning. Thus, a cloning vector must allow the gene editing by
using the restriction enzymes..
1) surrounds the meninges and CNSAllows the nutrients to pass from.pdf
1) surrounds the meninges and CNS
Allows the nutrients to pass from the general cirulation to CNS
Comprises endothelial cells in capillaries
2)ventricles- production of cerebrospinal fluid
Cerebellum- maintaining balance
Brain stem - regulation of digestion
Cognition - cerebral cortex
Midbrain- sleep cycles
Diencephalon - initial processing of vision
Solution
1) surrounds the meninges and CNS
Allows the nutrients to pass from the general cirulation to CNS
Comprises endothelial cells in capillaries
2)ventricles- production of cerebrospinal fluid
Cerebellum- maintaining balance
Brain stem - regulation of digestion
Cognition - cerebral cortex
Midbrain- sleep cycles
Diencephalon - initial processing of vision.
1. Sternum.Bone by which ribs are attached on frontal side .2. R.pdf
1. Sternum.
Bone by which ribs are attached on frontal side .
2. Ribs.
3. Liver.
It is the largest gland in the body located on the right side below diaphragm .
Solution
1. Sternum.
Bone by which ribs are attached on frontal side .
2. Ribs.
3. Liver.
It is the largest gland in the body located on the right side below diaphragm ..
-Included in the capital account are a. No short term assets are i.pdf
-Included in the capital account are
a. No short term assets are included in capital account
b. Long-term financial assets only- correct
c. No short term assets are included in capital account
d. No short term assets are included in capital account
e. It also includes other investments apart from FDI
The current account balance is not directly affected by
a. Government restrictions. It affects because it affects the rates of goods
b. Exchange rate movements.It affects the pricing of imports and exports
c. National income- It does not have direct effect
d. Inflation- It affects because again it affects currency exchange rates
e. Interest rates-It affects because again it affects currency exchange rates
Which of the following factors does probably not directly affect a country\'s capital account and
its components?
a. Exchange rate movements- It affects because it affects value of foreign currency reserves
b. Interest rates- It affect exchange rates
c. Withholding taxes on foreign income- It has a direct effect
d. Inflation- It does not have direct effect
Which of the following statements is not true?
a. Sometimes, trade policies are used to punish countries for various actions.
b. Tariffs imposed by the EU have caused some friction between EU countries that commonly
import products and other EU countries.
c. Exporters may complain that they are being mistreated because the currency of their country is
too weak. For exporters it is better to have a weak currency as their exports becaome cheaper
d. Outsourcing affects the balance of trade because it means that a service is purchased in
another country.
e. All of these choices are true
Transfer payments represent aid, grants, and gifts from one country to another. Hence option d is
correct
7-A special drawing right (SDR) is a unit of account established by a. The Asian governments. b.
The Federal Reserve. c. The Bank of England. d. MNCs. e. The IMF
option e is correct
8)Like the International Monetary Fund (IMF), the ________ is composed of a collection of
nations as members. However, unlike the IMF, it uses the private rather than the government
sector to achieve its objectives.
a. International Financial Corporation (IFC)
Solution
-Included in the capital account are
a. No short term assets are included in capital account
b. Long-term financial assets only- correct
c. No short term assets are included in capital account
d. No short term assets are included in capital account
e. It also includes other investments apart from FDI
The current account balance is not directly affected by
a. Government restrictions. It affects because it affects the rates of goods
b. Exchange rate movements.It affects the pricing of imports and exports
c. National income- It does not have direct effect
d. Inflation- It affects because again it affects currency exchange rates
e. Interest rates-It affects because again it affects currency exchange rates
Which of the following factors does probably not directly affect a .
C++ Program to Implement Doubly Linked List #includei.pdf
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
struct node
{
int info;
struct node *next;
struct node *prev;
}*head;
/*
Class Declaration
*/
class dll
{
public:
void create(int value);
void append(int value);
void insert(int value, int index);
void del(int value);
void display();
dll()
{
head = NULL;
}
/* destructor*/
~dll()
{
node *ptr;
ptr = head;
while(ptr!=0){
node *next = ptr->next;
delete ptr;
ptr = next;
}
}
};
/*
* Main: Conatins Menu
*/
int main()
{
int option, element, index;
dll dl;
while (1)
{
cout<>option;
switch ( option )
{
case 1:
cout<<\"Enter the element: \";
cin>>element;
dl.create(element);
cout<>element;
dl.append(element);
cout<>element;
cout<<\"Insert Element after postion: \";
cin>>index;
dl.insert(element, index);
cout<>element;
dl.del(element);
cout<info = value;
temp->next = NULL;
if (head == NULL)
{
temp->prev = NULL;
head = temp;
}
else
{
s = head;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Insertion at the beginning
*/
void dll::append(int value)
{
if (head == NULL)
{
cout<<\"First Create the list.\"<prev = NULL;
temp->info = value;
temp->next = head;
head->prev = temp;
head = temp;
cout<<\"Element Inserted\"<next;
if (q == NULL)
{
cout<<\"There are less than \";
cout<info = value;
if (q->next == NULL)
{
q->next = tmp;
tmp->next = NULL;
tmp->prev = q;
}
else
{
tmp->next = q->next;
tmp->next->prev = tmp;
q->next = tmp;
tmp->prev = q;
}
cout<<\"Element Inserted\"<info == value)
{
tmp = head;
head = head->next;
head->prev = NULL;
cout<<\"Element Deleted\"<next->next != NULL)
{
/*Element deleted in between*/
if (q->next->info == value)
{
tmp = q->next;
q->next = tmp->next;
tmp->next->prev = q;
cout<<\"Element Deleted\"<next;
}
/*last element deleted*/
if (q->next->info == value)
{
tmp = q->next;
free(tmp);
q->next = NULL;
cout<<\"Element Deleted\"<info<<\" <-> \";
q = q->next;
}
cout<<\"NULL\"<
Solution
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
struct node
{
int info;
struct node *next;
struct node *prev;
}*head;
/*
Class Declaration
*/
class dll
{
public:
void create(int value);
void append(int value);
void insert(int value, int index);
void del(int value);
void display();
dll()
{
head = NULL;
}
/* destructor*/
~dll()
{
node *ptr;
ptr = head;
while(ptr!=0){
node *next = ptr->next;
delete ptr;
ptr = next;
}
}
};
/*
* Main: Conatins Menu
*/
int main()
{
int option, element, index;
dll dl;
while (1)
{
cout<>option;
switch ( option )
{
case 1:
cout<<\"Enter the element: \";
cin>>element;
dl.create(element);
cout<>element;
dl.append(element);
cout<>element;
cout<<\"Insert Element after postion: \";
cin>>index;
dl.insert(element, index);
cout<>element;
dl.del(element);
cout<info = value;
temp->next = NULL;
if (head == NULL)
{
temp->prev = NULL;
head = temp;
}
else
{
s = head;
while (s->next != NULL)
s = s->next;
s->next = temp;
t.
The geography of Taylor Swift - some ideas
Geographical themes connected with Taylor Swift's ERAS tour - coming to the UK in June 2024
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
More Related Content
More from Lalkamal2
Negative control plate with no DNA transforms competent cells withou.pdf
Negative control plate with no DNA transforms competent cells without any DNA on selection
media. , If more colonies are produced, shows the problem with antibiotic in the agar plate.
No ligase control plates provide information about digestion efficiency. it transform competent
cells withdigested plasmid or DNA. If several colonies are found, it shows that digestion did not
completed properly.
Solution
Negative control plate with no DNA transforms competent cells without any DNA on selection
media. , If more colonies are produced, shows the problem with antibiotic in the agar plate.
No ligase control plates provide information about digestion efficiency. it transform competent
cells withdigested plasmid or DNA. If several colonies are found, it shows that digestion did not
completed properly..
Modifications highlighted in bold lettersDropOutStack.javaim.pdf
//Modifications highlighted in bold letters
//DropOutStack.java
import java.util.Arrays;
public class DropOutStack {
/**
* Defines the interface to a stack collection.
*
* @author Java Foundations
* @version 4.0
*/
public interface StackADT {
/**
* Adds the specified element to the top of this stack.
*
* @param element
* element to be pushed onto the stack
*/
public void push(T element);
/**
* Removes and returns the top element from this stack.
*
* @return the element removed from the stack
*/
public T pop();
/**
* Returns without removing the top element of this stack.
*
* @return the element on top of the stack
*/
public T peek();
/**
* Returns true if this stack contains no elements.
*
* @return true if the stack is empty
*/
public boolean isEmpty();
/**
* Returns the number of elements in this stack.
*
* @return the number of elements in the stack
*/
public int size();
/**
* Returns a string representation of this stack.
*
* @return a string representation of the stack
*/
public String toString();
}
/**
* Represents the situation in which a collection is empty.
*
* @author Java Foundations
* @version 4.0
*/
public static class EmptyCollectionException extends RuntimeException {
/**
* Sets up this exception with an appropriate message.
*
* @param collection
* the name of the collection
*/
public EmptyCollectionException(String collection) {
super(\"The \" + collection + \" is empty.\");
}
}
/**
* Program entry point for stack testing.
*
* @param args
* Argument list.
*/
public static void main(String[] args) {
ArrayDropOutStack stack = new ArrayDropOutStack(4);
System.out.println(\"DROP-OUT STACK TESTING\");
stack.push(1);
stack.push(2);
stack.push(3);
stack.push(4);
System.out.println(\"Stack : \"+stack.toString());
System.out.println(\"pushing 5 element \");
stack.push(5);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
System.out.println(\"The size of the stack is: \" + stack.size());
if (!stack.isEmpty())
System.out.println(\"The stack contains:\ \" + stack.toString());
stack.pop();
System.out.println(\"poping element 5\"+stack.toString());
System.out.println(\"The size of the stack is: \" + stack.size());
System.out.println(\"pushing 7 element \");
stack.push(7);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
System.out.println(\"pushing 8 element \");
stack.push(8);
System.out.println(\"Now stack elements\");
System.out.println(stack.toString());
if (!stack.isEmpty())
System.out.println(\"The stack contains:\ \" + stack.toString());
}
/**
* An array implementation of a stack in which the bottom of the stack is
* fixed at index 0.
*
* @author Java Foundations
* @version 4.0
*/
public static class ArrayDropOutStack implements StackADT {
private final static int DEFAULT_CAPACITY = 100;
private int top;
private T[] stack;
/**
* Creates an empty stack using the default capacity.
*/
public ArrayDropOutStack() {
this(DEFAULT_CAPACITY);
}
/**
* Creates an empty stack using.
Message types used by the DHCP boot sequenceop Message type.h.pdf
Message types used by the DHCP boot sequence
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority (IANA).
hlen
: Hardware address length, in octets.
hops
: Value set to zero by DHCP clients. Optionally used to count the number of relay agents that
forwarded the message.
xid
: A random number used to associate messages and responses between a client and a server.
secs
: Seconds elapsed since client began address acquisition or renewal process.
flags
: Flags set by client. The Broadcast flag is set if the client cannot receive unicast IP datagrams
(for example, before it is configured with an IP address).
ciaddr
: Used if the client has an IP address and can respond to Address Resolution Protocol (ARP)
requests.
yiaddr
: Address given to the DHCP client by the DHCP server.
siaddr
: IP address of the server that is offering a lease.
giaddr
: DHCP relay agent IP address.
chaddr
: Client hardware address.
sname
: Optional server host name. Not used in Windows Server 2008.
file
: The name of the file containing the boot image for a BOOTP client.
options
: Optional parameters field. In the DHCP protocol packet, each option begins with a single octet
tag, which holds the option code, and a second octet, which describes the option data length, in
bytes. For a complete list of the DHCP options available by default on a DHCP server running
on Windows Server 2008, see DHCP Tools and Options.
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority (IANA).
hlen
: Hardware address length, in octets.
hops
: Value set to zero by DHCP clients. Optionally used to count the number of relay agents that
forwarded the message.
xid
: A random number used to associate messages and responses between a client and a server.
secs
: Seconds elapsed since client began address acquisition or renewal process.
flags
: Flags set by client. The Broadcast flag is set if the client cannot receive unicast IP datagrams
(for example, before it is configured with an IP address).
ciaddr
: Used if the client has an IP address and can respond to Address Resolution Protocol (ARP)
requests.
yiaddr
: Address given to the DHCP client by the DHCP server.
siaddr
: IP address of the server that is offering a lease.
giaddr
: DHCP relay agent IP address.
chaddr
: Client hardware address.
sname
: Optional server host name. Not used in Windows Server 2008.
file
: The name of the file containing the boot image for a BOOTP client.
options
: Optional parameters field. In the DHCP protocol packet, each option begins with a single octet
tag, which holds the option code, and a second octet, which describes the option data length, in
bytes. For a complete list of the DHCP options available by default on a DHCP server running
on Windows Server 2008, see DHCP Tools and Options.
Solution
Message types used by the DHCP boot sequence
op
: Message type.
htype
: Hardware address type defined at Internet Assigned Numbers Authority.
Law of conservation of matter(mass)In any closed system subjected .pdf
Law of conservation of matter(mass)
In any closed system subjected to no external forces,the mass is constant irrespective of its
changes in different form. Matter cannot be created or destroyed in an isolated system. It only
changes from one form into another.
Solution
Law of conservation of matter(mass)
In any closed system subjected to no external forces,the mass is constant irrespective of its
changes in different form. Matter cannot be created or destroyed in an isolated system. It only
changes from one form into another..
It is a unit of measurement for the amount of substance.The mole is .pdf
It is a unit of measurement for the amount of substance.The mole is defined as the amount of
substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as
there are atoms in 12 g of the isotope carbon-12. The experimentally determined value of a mole
as adopted 6.02 × 1023.
Solution
It is a unit of measurement for the amount of substance.The mole is defined as the amount of
substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as
there are atoms in 12 g of the isotope carbon-12. The experimentally determined value of a mole
as adopted 6.02 × 1023..
In insurance, the term risk pooling refers to the spreading of f.pdf
In insurance, the term \"risk pooling\" refers to the spreading of financial risks evenly among a
large number of contributors to the program. Insurance is the transference of risks from
individuals or corporations who cannot bear a possible unplanned financial catastrophe to the
capital markets, which can bear them easily -- at least in theory.
Pure risk is a category of risk in which loss is the only possible outcome, which is the opposite of
speculative risk. There are products that can be purchased to mitigate pure risk, such as home
insurance being used to protect homeowners against their homes being destroyed. Other
examples of pure risk events include premature death, identity theft and career-ending
disabilities.1) in cases of home insurance and health insurance risk pooling can be effectively
used as of all the individuals who invest in the insurance by the law of large number a miniscule
probability of the people actually suffer the real risk. 2) Risk pooling is an important concept in
supply chain management . It suggests that demand variability is reduced if one aggregates
demand across locations because, as demand is aggregated across different locations, it becomes
more likely that high demand from one customer will be offset by low demand from another.
However,consider the 1)\"high risk pools\", which simply means separating out the sickest, most
expensive people in the country and dumping them into a separate program.With the \"bad
apples\" (ie, human beings with terrible medical problems) safely tucked out of the way, the
average cost of treating everyone else supposedly suddenly becomes less pricey.This is the exact
opposite of the entire point of health insurance in the first place...spreading the risk and hence
risk pooling fails here.
2)Liability risk includes economic losses from being held responsible for harming others or their
property. This cannot be covered by risk pooling.
Solution
In insurance, the term \"risk pooling\" refers to the spreading of financial risks evenly among a
large number of contributors to the program. Insurance is the transference of risks from
individuals or corporations who cannot bear a possible unplanned financial catastrophe to the
capital markets, which can bear them easily -- at least in theory.
Pure risk is a category of risk in which loss is the only possible outcome, which is the opposite of
speculative risk. There are products that can be purchased to mitigate pure risk, such as home
insurance being used to protect homeowners against their homes being destroyed. Other
examples of pure risk events include premature death, identity theft and career-ending
disabilities.1) in cases of home insurance and health insurance risk pooling can be effectively
used as of all the individuals who invest in the insurance by the law of large number a miniscule
probability of the people actually suffer the real risk. 2) Risk pooling is an important concept in
supply chain management . It suggests that.
Some CO is Added The Pressure of CH4 and H2O will.pdf
Some CO is Added The Pressure of CH4 and H2O will Increase Equilibrium will
shift to the Left Some CH4 is Removed Pressure of H2O will Increase Pressure of CO will
Decrease Equilibrium will shift to the Left The Volume of Vessel is Reduced Pressure of CH4
will Increase Pressure of H2O will Increase Equilibrium will shift to the Left
Solution
Some CO is Added The Pressure of CH4 and H2O will Increase Equilibrium will
shift to the Left Some CH4 is Removed Pressure of H2O will Increase Pressure of CO will
Decrease Equilibrium will shift to the Left The Volume of Vessel is Reduced Pressure of CH4
will Increase Pressure of H2O will Increase Equilibrium will shift to the Left.
Comments Figures are not properly numbered. Further signal of figur.pdf
Comments: Figures are not properly numbered. Further signal of figure 1 is not shown and hence
the above figure (assumed to figure 2) can not be simulated.
Solution
Comments: Figures are not properly numbered. Further signal of figure 1 is not shown and hence
the above figure (assumed to figure 2) can not be simulated..
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.j.pdf
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.java
import java.util.*;
import java.util.LinkedList;
class Test {
HashSet uniqueStates;
void letsRoll() {
/*
* The capacity of jug1(jug1 capacity is greater than jug2 capacity)
*/
int jug1 = 3;
/*
* The capacity of jug two
*/
int jug2 = 2;
/*
* Final Amount needed in jug1
*/
int amtNeeded = 2;
State initialState = new State(0, 0);
State finalState = new State(amtNeeded, 0);
State finalPath = null;
uniqueStates = new HashSet();
/*
* Change queue to stack to convert to DFS
*/
LinkedList queue = new LinkedList();
queue.add(initialState);
while (!queue.isEmpty()) {
State currState = queue.poll();
if (currState.equals(finalState)) {
finalPath = currState;
break;
}
// if x is zero fill it
if (currState.x == 0) {
State nextState = new State(jug1, currState.y, currState);
//System.out.println(currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if y is empty fill it
if (currState.y == 0) {
State nextState = new State(currState.x, jug2, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if x is not empty , empty it
if (currState.x > 0) {
State nextState = new State(0, currState.y, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// if y is not empty, empty it
if (currState.y > 0) {
State nextState = new State(currState.x, 0, currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// transfer from x to y, when x non empty and y is not full
if (currState.x > 0 && currState.y < jug2) {
int amtToTransfer = Math.min(currState.x, jug2 - currState.y);
State nextState = new State(currState.x - amtToTransfer, currState.y
+ amtToTransfer,
currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
// transfer from y to x, when y is not empty and x is not full
if (currState.y > 0 && currState.x < jug1) {
int amtToTransfer = Math.min(currState.y, jug1 - currState.x);
State nextState = new State(currState.x + amtToTransfer, currState.y
- amtToTransfer,
currState);
checkUniqueStates(uniqueStates, nextState, queue);
}
}
if (finalPath != null) {
System.out.println(\"Final Result\");
System.out.println(\"J1 J2\");
System.out.println(finalPath);
}
else{
System.out.println(\"Not Possible\");
}
}
/*
* Checks whether State toCheck has been generated before, if not it is
* added to queue and uniqueStates Set
*/
void checkUniqueStates(HashSet uniqueStates, State toCheck,
LinkedList queue) {
if (!uniqueStates.contains(toCheck)) {
uniqueStates.add(toCheck);
queue.add(toCheck);
}
}
public static void main(String[] args) {
new Test().letsRoll();
}
}
2 State.java
class State {
/*
* Amount in jug1 for current State
*/
int x;
/*
* Amount in jug2 for current State
*/
int y;
/*
* Parent of current State
*/
State pre;
public State(int x, int y) {
super();
this.x = x;
this.y = y;
}
public State(int x, int y, State pre) {
super();
this.x = x;
this.y = y;
this.pre = pre;
System.out.println(\"(\"+x+\",\"+y+\")\");
}
@Override
public int hashCode() {
final int .
Balance sheetBalance sheet is the statement of financial position .pdf
Balance sheet
Balance sheet is the statement of financial position which reports all the assets, liabilities and
equity held by the company at a specific date. It helps in telling about the investments, resources,
claims and owner’s equity of the company. It revolves around the equation i.e. Assets =
Liabilities + equity.
What is shown in balance sheet:
The balance sheet has three major categories which includes Assets, liabilities and equity. All
these are calssified on the basis of their nature.
Assets can be said as the resources of the company and are classified as: Current assets, long
term investment, property, plant and equipment, intangible assets and other assets
Assets includes:
•Current assets – Cash, accounts receivables, prepaid expenses, inventories
•Long term investments – investment in stock
•Plant property and equipment – Land, building, equipment
•Intangible assets – Goodwill, patents, trademarks
Liabilities are the claims and can be classified as current liabilities, long term liabilities
Liabilities includes:
•Current liabilities: Accounts payable, income tax payable. Salaries payable, accrued expenses,
unearned revenue, current portion of long term debt due
•Long term liabilities- bonds payable, notes payable
Owner;s equity can be classified as the Capital stock which includes common stock and
preferred stock
It also includes Additional paid in capital, Retained earnings
Retained earnings are the accumulated earnings of the company. It is calculated as Beginning
balance, Add: Net income less: Dividends
Importance:
Balance sheet is important in every business. Considering the hospitality firm, it is important to
analyze different aspects of teh firm to know its financial postion. As the hospitality firm
emphasize on services, it is important to know the financial position of the company through its
financial statements. the hospitality firms like hotel needs to report their assets (building) held by
the company along with other assets, liabilities and equity.
Balance sheet is the statement which helps in analysing the financial position of the company, it
can also help in predicting the cash flows and the financial position of the company. With the
help of the balance sheet we can help in analysing the ability of the firm to pay off its short term
and long term debts.
Balance sheet reports its assets and liabilities on historical basis and uses different estimates to
analyse the amounts like uncollectibles
Solution
Balance sheet
Balance sheet is the statement of financial position which reports all the assets, liabilities and
equity held by the company at a specific date. It helps in telling about the investments, resources,
claims and owner’s equity of the company. It revolves around the equation i.e. Assets =
Liabilities + equity.
What is shown in balance sheet:
The balance sheet has three major categories which includes Assets, liabilities and equity. All
these are calssified on the basis of their nature.
Assets can be .
Answer BaSO4K+ is always soluble because it is an alkaline metal..pdf
Answer: BaSO4
K+ is always soluble because it is an alkaline metal. NO3- is also always soluble.
SO4 is usually soluble except when it is paired with Sr, Ba, Ca, or Pb.
Solution
Answer: BaSO4
K+ is always soluble because it is an alkaline metal. NO3- is also always soluble.
SO4 is usually soluble except when it is paired with Sr, Ba, Ca, or Pb..
Answer is B because he copied the member A and say that he is innoce.pdf
Answer is B because he copied the member A and say that he is innocent
and also here we can\'t give you a exact soln. because of the in appropriate format of the question
details
Solution
Answer is B because he copied the member A and say that he is innocent
and also here we can\'t give you a exact soln. because of the in appropriate format of the question
details.
A nephron consists of a renal corpuscle and a renal tubule. So the a.pdf
A nephron consists of a renal corpuscle and a renal tubule. So the answer is option 1.
Solution
A nephron consists of a renal corpuscle and a renal tubule. So the answer is option 1..
30). e). All of theseDifferent biotechnological methods such as ge.pdf
30). e). All of these
Different biotechnological methods such as gene cloning, DNA amplification, recombinant DNA
technology, are used during the process of DNA isolation and sequencing. For example, the
copies of genome are amplified by the process of DNA amplification, which we observe in PCR
(polymerase chain reaction). The resulting genome can be sequenced.
31). b). Cloning vectors
The purpose of cloning vectors is gene amplification. Cloning vectors are small pieces of DNA
isolated from a virus or any other higher organism. A close is inserted with a foreign DNA that
can be used for the purpose of cloning. Thus, a cloning vector must allow the gene editing by
using the restriction enzymes.
Solution
30). e). All of these
Different biotechnological methods such as gene cloning, DNA amplification, recombinant DNA
technology, are used during the process of DNA isolation and sequencing. For example, the
copies of genome are amplified by the process of DNA amplification, which we observe in PCR
(polymerase chain reaction). The resulting genome can be sequenced.
31). b). Cloning vectors
The purpose of cloning vectors is gene amplification. Cloning vectors are small pieces of DNA
isolated from a virus or any other higher organism. A close is inserted with a foreign DNA that
can be used for the purpose of cloning. Thus, a cloning vector must allow the gene editing by
using the restriction enzymes..
1) surrounds the meninges and CNSAllows the nutrients to pass from.pdf
1) surrounds the meninges and CNS
Allows the nutrients to pass from the general cirulation to CNS
Comprises endothelial cells in capillaries
2)ventricles- production of cerebrospinal fluid
Cerebellum- maintaining balance
Brain stem - regulation of digestion
Cognition - cerebral cortex
Midbrain- sleep cycles
Diencephalon - initial processing of vision
Solution
1) surrounds the meninges and CNS
Allows the nutrients to pass from the general cirulation to CNS
Comprises endothelial cells in capillaries
2)ventricles- production of cerebrospinal fluid
Cerebellum- maintaining balance
Brain stem - regulation of digestion
Cognition - cerebral cortex
Midbrain- sleep cycles
Diencephalon - initial processing of vision.
1. Sternum.Bone by which ribs are attached on frontal side .2. R.pdf
1. Sternum.
Bone by which ribs are attached on frontal side .
2. Ribs.
3. Liver.
It is the largest gland in the body located on the right side below diaphragm .
Solution
1. Sternum.
Bone by which ribs are attached on frontal side .
2. Ribs.
3. Liver.
It is the largest gland in the body located on the right side below diaphragm ..
-Included in the capital account are a. No short term assets are i.pdf
-Included in the capital account are
a. No short term assets are included in capital account
b. Long-term financial assets only- correct
c. No short term assets are included in capital account
d. No short term assets are included in capital account
e. It also includes other investments apart from FDI
The current account balance is not directly affected by
a. Government restrictions. It affects because it affects the rates of goods
b. Exchange rate movements.It affects the pricing of imports and exports
c. National income- It does not have direct effect
d. Inflation- It affects because again it affects currency exchange rates
e. Interest rates-It affects because again it affects currency exchange rates
Which of the following factors does probably not directly affect a country\'s capital account and
its components?
a. Exchange rate movements- It affects because it affects value of foreign currency reserves
b. Interest rates- It affect exchange rates
c. Withholding taxes on foreign income- It has a direct effect
d. Inflation- It does not have direct effect
Which of the following statements is not true?
a. Sometimes, trade policies are used to punish countries for various actions.
b. Tariffs imposed by the EU have caused some friction between EU countries that commonly
import products and other EU countries.
c. Exporters may complain that they are being mistreated because the currency of their country is
too weak. For exporters it is better to have a weak currency as their exports becaome cheaper
d. Outsourcing affects the balance of trade because it means that a service is purchased in
another country.
e. All of these choices are true
Transfer payments represent aid, grants, and gifts from one country to another. Hence option d is
correct
7-A special drawing right (SDR) is a unit of account established by a. The Asian governments. b.
The Federal Reserve. c. The Bank of England. d. MNCs. e. The IMF
option e is correct
8)Like the International Monetary Fund (IMF), the ________ is composed of a collection of
nations as members. However, unlike the IMF, it uses the private rather than the government
sector to achieve its objectives.
a. International Financial Corporation (IFC)
Solution
-Included in the capital account are
a. No short term assets are included in capital account
b. Long-term financial assets only- correct
c. No short term assets are included in capital account
d. No short term assets are included in capital account
e. It also includes other investments apart from FDI
The current account balance is not directly affected by
a. Government restrictions. It affects because it affects the rates of goods
b. Exchange rate movements.It affects the pricing of imports and exports
c. National income- It does not have direct effect
d. Inflation- It affects because again it affects currency exchange rates
e. Interest rates-It affects because again it affects currency exchange rates
Which of the following factors does probably not directly affect a .
C++ Program to Implement Doubly Linked List #includei.pdf
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
struct node
{
int info;
struct node *next;
struct node *prev;
}*head;
/*
Class Declaration
*/
class dll
{
public:
void create(int value);
void append(int value);
void insert(int value, int index);
void del(int value);
void display();
dll()
{
head = NULL;
}
/* destructor*/
~dll()
{
node *ptr;
ptr = head;
while(ptr!=0){
node *next = ptr->next;
delete ptr;
ptr = next;
}
}
};
/*
* Main: Conatins Menu
*/
int main()
{
int option, element, index;
dll dl;
while (1)
{
cout<>option;
switch ( option )
{
case 1:
cout<<\"Enter the element: \";
cin>>element;
dl.create(element);
cout<>element;
dl.append(element);
cout<>element;
cout<<\"Insert Element after postion: \";
cin>>index;
dl.insert(element, index);
cout<>element;
dl.del(element);
cout<info = value;
temp->next = NULL;
if (head == NULL)
{
temp->prev = NULL;
head = temp;
}
else
{
s = head;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Insertion at the beginning
*/
void dll::append(int value)
{
if (head == NULL)
{
cout<<\"First Create the list.\"<prev = NULL;
temp->info = value;
temp->next = head;
head->prev = temp;
head = temp;
cout<<\"Element Inserted\"<next;
if (q == NULL)
{
cout<<\"There are less than \";
cout<info = value;
if (q->next == NULL)
{
q->next = tmp;
tmp->next = NULL;
tmp->prev = q;
}
else
{
tmp->next = q->next;
tmp->next->prev = tmp;
q->next = tmp;
tmp->prev = q;
}
cout<<\"Element Inserted\"<info == value)
{
tmp = head;
head = head->next;
head->prev = NULL;
cout<<\"Element Deleted\"<next->next != NULL)
{
/*Element deleted in between*/
if (q->next->info == value)
{
tmp = q->next;
q->next = tmp->next;
tmp->next->prev = q;
cout<<\"Element Deleted\"<next;
}
/*last element deleted*/
if (q->next->info == value)
{
tmp = q->next;
free(tmp);
q->next = NULL;
cout<<\"Element Deleted\"<info<<\" <-> \";
q = q->next;
}
cout<<\"NULL\"<
Solution
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
struct node
{
int info;
struct node *next;
struct node *prev;
}*head;
/*
Class Declaration
*/
class dll
{
public:
void create(int value);
void append(int value);
void insert(int value, int index);
void del(int value);
void display();
dll()
{
head = NULL;
}
/* destructor*/
~dll()
{
node *ptr;
ptr = head;
while(ptr!=0){
node *next = ptr->next;
delete ptr;
ptr = next;
}
}
};
/*
* Main: Conatins Menu
*/
int main()
{
int option, element, index;
dll dl;
while (1)
{
cout<>option;
switch ( option )
{
case 1:
cout<<\"Enter the element: \";
cin>>element;
dl.create(element);
cout<>element;
dl.append(element);
cout<>element;
cout<<\"Insert Element after postion: \";
cin>>index;
dl.insert(element, index);
cout<>element;
dl.del(element);
cout<info = value;
temp->next = NULL;
if (head == NULL)
{
temp->prev = NULL;
head = temp;
}
else
{
s = head;
while (s->next != NULL)
s = s->next;
s->next = temp;
t.
More from Lalkamal2 (20)
Negative control plate with no DNA transforms competent cells withou.pdf
Negative control plate with no DNA transforms competent cells withou.pdf
Modifications highlighted in bold lettersDropOutStack.javaim.pdf
Modifications highlighted in bold lettersDropOutStack.javaim.pdf
Message types used by the DHCP boot sequenceop Message type.h.pdf
Message types used by the DHCP boot sequenceop Message type.h.pdf
Law of conservation of matter(mass)In any closed system subjected .pdf
Law of conservation of matter(mass)In any closed system subjected .pdf
It is a unit of measurement for the amount of substance.The mole is .pdf
It is a unit of measurement for the amount of substance.The mole is .pdf
In insurance, the term risk pooling refers to the spreading of f.pdf
In insurance, the term risk pooling refers to the spreading of f.pdf
Some CO is Added The Pressure of CH4 and H2O will.pdf
Some CO is Added The Pressure of CH4 and H2O will.pdf
Comments Figures are not properly numbered. Further signal of figur.pdf
Comments Figures are not properly numbered. Further signal of figur.pdf
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.j.pdf
Change the value of jug1 and jug 2 accordingly. 1 File WaterJugBSF.j.pdf
Balance sheetBalance sheet is the statement of financial position .pdf
Balance sheetBalance sheet is the statement of financial position .pdf
Answer BaSO4K+ is always soluble because it is an alkaline metal..pdf
Answer BaSO4K+ is always soluble because it is an alkaline metal..pdf
Answer is B because he copied the member A and say that he is innoce.pdf
Answer is B because he copied the member A and say that he is innoce.pdf
A nephron consists of a renal corpuscle and a renal tubule. So the a.pdf
A nephron consists of a renal corpuscle and a renal tubule. So the a.pdf
30). e). All of theseDifferent biotechnological methods such as ge.pdf
30). e). All of theseDifferent biotechnological methods such as ge.pdf
1) surrounds the meninges and CNSAllows the nutrients to pass from.pdf
1) surrounds the meninges and CNSAllows the nutrients to pass from.pdf
1. Sternum.Bone by which ribs are attached on frontal side .2. R.pdf
1. Sternum.Bone by which ribs are attached on frontal side .2. R.pdf
-Included in the capital account are a. No short term assets are i.pdf
-Included in the capital account are a. No short term assets are i.pdf
C++ Program to Implement Doubly Linked List #includei.pdf
C++ Program to Implement Doubly Linked List #includei.pdf
Recently uploaded
The geography of Taylor Swift - some ideas
Geographical themes connected with Taylor Swift's ERAS tour - coming to the UK in June 2024
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The Roman Empire A Historical Colossus.pdf
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Instructions for Submissions thorugh G- Classroom.pptx
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Protectable subject matters, Protection in biotechnology, Protection of other biological materials, Ownership and period of protection
Honest Reviews of Tim Han LMA Course Program.pptx
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
Overview on Edible Vaccine: Pros & Cons with Mechanism
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
Recently uploaded (20)
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
Suppose Bob sends an encrypted document to Alice. To be verifiable, .pdf
- 1. Suppose Bob sends an encrypted document to Alice. To be verifiable, Alice must be able to convince herself that Bob sent the encrypted document. To be non-forgeable, Alice must be able to convince herself that only Bob could have sent the encrypted document Alice must be able to convince someone else that only Bob could have sent the document. To illustrate the latter distinction, suppose Bob and Alice share a secret key, and they are the only ones in the world who know the key. If Alice receives a document that was encrypted with the key, and knows that she did not encrypt the document herself, then the document is known to be verifiable and non- forgeable (assuming a suitably strong encryption system was used). However, Alice can not convince someone else that Bob must have sent the document, since in fact Alice knew the key herself and could have encrypted/sent the document. Solution Suppose Bob sends an encrypted document to Alice. To be verifiable, Alice must be able to convince herself that Bob sent the encrypted document. To be non-forgeable, Alice must be able to convince herself that only Bob could have sent the encrypted document Alice must be able to convince someone else that only Bob could have sent the document. To illustrate the latter distinction, suppose Bob and Alice share a secret key, and they are the only ones in the world who know the key. If Alice receives a document that was encrypted with the key, and knows that she did not encrypt the document herself, then the document is known to be verifiable and non- forgeable (assuming a suitably strong encryption system was used). However, Alice can not convince someone else that Bob must have sent the document, since in fact Alice knew the key herself and could have encrypted/sent the document.