b.secant
Recall:
1. Define:
a. tangent
a line in the plane of a circle that
intersects the circle in exactly one point.
a line in the plane of a circle
that intersects the circle in exactly
one point.
c. Tangent circles
coplanar circles that intersect in
one point
d. Concentric circles
coplanar circles that have the
same center.
e. Common tangent
a line or segment that is tangent
to two coplanar circles
f. Common internal tangent
intersects the segment that joins
the centers of the two circles
g. Commonexternal tangent
does not intersect the segment
that joins the centers of the two
circles
h. Point of tangency
the point at which a tangent line intersects
the circle to which it is tangent
Angles formed by intersecting secants
and tangents
Case 1: Vertex On Circle
Find each measure:
m<BCD
mABC
Tangent-Chord Theorem
If a tangent and a chord intersect at a point on a circle,
then the measure of each angle formed is one half the
measure of its intercepted arc.
2
1
B
A
C
m1 =
1
2
mAB
m2 =
1
2
mBCA
Example 1
m
102
T
R
S
Line m is tangent to the circle. Find mRST
mRST = 2(102)
mRST = 204
Try This!
Line m is tangent to the circle. Find m1
m
150
1
T
R
m1 =
1
2
(150)
m1 = 75
Example 2
(9x+20)
5x
D
B
C
A
BC is tangent to the circle. Find mCBD.
2(5x) = 9x + 20
10x = 9x + 20
x = 20
mCBD = 5(20)
mCBD = 100
Case 2: Vertex Inside Circle
Find the angle measure:
m<SQR
Interior Intersection Theorem
If two chords intersect in the interior of a circle, then the
measure of each angle is one half the sum of the
measures of the arcs intercepted by the angle and its
vertical angle.
m1 =
1
2
(mCD + mAB)
m2 =
1
2
(mAD + mBC)
2
1
A
C
D
B
Example 3
Find the value of x.
174
106
x
P
R
Q
S
x =
1
2
(mPS + mRQ)
x =
1
2
(106+174)
x =
1
2
(280)
x = 140
Try This!
Find the value of x.
120
40
x
T
R
S
U
x =
1
2
(mST + mRU)
x =
1
2
(40+120)
x =
1
2
(160)
x = 80
Case 3: Vertex Outside Circle
 Find the value of x:
Exterior Intersection Theorem
If a tangent and a secant, two tangents, or
two secants intersect in the exterior of a
circle, then the measure of the angle
formed is one half the difference of the
measures of the intercepted arcs.
Diagrams for Exterior
Intersection Theorem
1
B
A
C
m1 =
1
2
(mBC - mAC)
2
P
R
Q
m2 =
1
2
(mPQR - mPR)
3
X
W
Y
Z
m3 =
1
2
(mXY - mWZ)
Example 4
Find the value of x.
200
x
72
72 =
1
2
(200 - x)
144 = 200 - x
x = 56
Example 5
Find the value of x.
mABC = 360 - 92
mABC = 268 x
92
C
A
B
x =
1
2
(268 - 92)
x =
1
2
(176)
x = 88
Summary
You try!
Remember
-Vertex On Circle = ½ measure of the arc.
-Vertex Inside Circle = ½ sum of the intercepted arcs.
-Vertex Outside Circle = ½ difference of the intercepted arcs.

secant-221124043201-a852a9f7 secant-221124043201-a852a9f7 33.ppt

  • 2.
    b.secant Recall: 1. Define: a. tangent aline in the plane of a circle that intersects the circle in exactly one point. a line in the plane of a circle that intersects the circle in exactly one point.
  • 3.
    c. Tangent circles coplanarcircles that intersect in one point d. Concentric circles coplanar circles that have the same center. e. Common tangent a line or segment that is tangent to two coplanar circles
  • 4.
    f. Common internaltangent intersects the segment that joins the centers of the two circles g. Commonexternal tangent does not intersect the segment that joins the centers of the two circles
  • 5.
    h. Point oftangency the point at which a tangent line intersects the circle to which it is tangent
  • 6.
    Angles formed byintersecting secants and tangents
  • 7.
    Case 1: VertexOn Circle Find each measure: m<BCD mABC
  • 8.
    Tangent-Chord Theorem If atangent and a chord intersect at a point on a circle, then the measure of each angle formed is one half the measure of its intercepted arc. 2 1 B A C m1 = 1 2 mAB m2 = 1 2 mBCA
  • 9.
    Example 1 m 102 T R S Line mis tangent to the circle. Find mRST mRST = 2(102) mRST = 204
  • 10.
    Try This! Line mis tangent to the circle. Find m1 m 150 1 T R m1 = 1 2 (150) m1 = 75
  • 11.
    Example 2 (9x+20) 5x D B C A BC istangent to the circle. Find mCBD. 2(5x) = 9x + 20 10x = 9x + 20 x = 20 mCBD = 5(20) mCBD = 100
  • 12.
    Case 2: VertexInside Circle Find the angle measure: m<SQR
  • 13.
    Interior Intersection Theorem Iftwo chords intersect in the interior of a circle, then the measure of each angle is one half the sum of the measures of the arcs intercepted by the angle and its vertical angle. m1 = 1 2 (mCD + mAB) m2 = 1 2 (mAD + mBC) 2 1 A C D B
  • 14.
    Example 3 Find thevalue of x. 174 106 x P R Q S x = 1 2 (mPS + mRQ) x = 1 2 (106+174) x = 1 2 (280) x = 140
  • 15.
    Try This! Find thevalue of x. 120 40 x T R S U x = 1 2 (mST + mRU) x = 1 2 (40+120) x = 1 2 (160) x = 80
  • 16.
    Case 3: VertexOutside Circle  Find the value of x:
  • 17.
    Exterior Intersection Theorem Ifa tangent and a secant, two tangents, or two secants intersect in the exterior of a circle, then the measure of the angle formed is one half the difference of the measures of the intercepted arcs.
  • 18.
    Diagrams for Exterior IntersectionTheorem 1 B A C m1 = 1 2 (mBC - mAC) 2 P R Q m2 = 1 2 (mPQR - mPR) 3 X W Y Z m3 = 1 2 (mXY - mWZ)
  • 19.
    Example 4 Find thevalue of x. 200 x 72 72 = 1 2 (200 - x) 144 = 200 - x x = 56
  • 20.
    Example 5 Find thevalue of x. mABC = 360 - 92 mABC = 268 x 92 C A B x = 1 2 (268 - 92) x = 1 2 (176) x = 88
  • 21.
  • 22.
    You try! Remember -Vertex OnCircle = ½ measure of the arc. -Vertex Inside Circle = ½ sum of the intercepted arcs. -Vertex Outside Circle = ½ difference of the intercepted arcs.