Problem 3- Take array size from user as an input and insert those numb.pdf
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Problem 3: Take array size from user as an input and insert those number of elements in the array. Finally print the sum of all number inside array which are divisible by 3. [20 points] Example: The size of int array is 7 (input from user) then insert values inside the array: Then the output will be: 48.
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![Problem 3: Take array size from user as an input and insert those number of elements in the
array. Finally print the sum of all number inside array which are divisible by 3. [20 points]
Example: The size of int array is 7 (input from user) then insert values inside the array: Then the
output will be: 48](https://image.slidesharecdn.com/problem3-takearraysizefromuserasaninputandinsertthosenumb-230311113316-913f86c7/85/Problem-3-Take-array-size-from-user-as-an-input-and-insert-those-numb-pdf-1-320.jpg)
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Problem: Describe an algorithm for concatenating two singly linked lists L and M, into a single
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PLEASE PLEASE USE THE CODE BELOW..... THANK YOU
public class SinglyLinkedList<E> implements Cloneable {
//---------------- nested Node class ----------------
/**
* Node of a singly linked list, which stores a reference to its
* element and to the subsequent node in the list (or null if this
* is the last node).
*/
private static class Node<E> {
/** The element stored at this node */
private E element; // reference to the element stored at this node
/** A reference to the subsequent node in the list */
private Node<E> next; // reference to the subsequent node in the list
/**
* Creates a node with the given element and next node.
*
* @param e the element to be stored
* @param n reference to a node that should follow the new node
*/
public Node(E e, Node<E> n) {
element = e;
next = n;
}
// Accessor methods
/**
* Returns the element stored at the node.
* @return the element stored at the node
*/
public E getElement() { return element; }
/**
* Returns the node that follows this one (or null if no such node).
* @return the following node
*/
public Node<E> getNext() { return next; }
// Modifier methods
/**
* Sets the node's next reference to point to Node n.
* @param n the node that should follow this one
*/
public void setNext(Node<E> n) { next = n; }
} //----------- end of nested Node class -----------
// instance variables of the SinglyLinkedList
/** The head node of the list */
private Node<E> head = null; // head node of the list (or null if empty)
/** The last node of the list */
private Node<E> tail = null; // last node of the list (or null if empty)
/** Number of nodes in the list */
private int size = 0; // number of nodes in the list
/** Constructs an initially empty list. */
public SinglyLinkedList() { } // constructs an initially empty list
// access methods
/**
* Returns the number of elements in the linked list.
* @return number of elements in the linked list
*/
public int size() { return size; }
/**
* Tests whether the linked list is empty.
* @return true if the linked list is empty, false otherwise
*/
public boolean isEmpty() { return size == 0; }
/**
* Returns (but does not remove) the first element of the list
* @return element at the front of the list (or null if empty)
*/
public E first() { // returns (but does not remove) the first element
if (isEmpty()) return null;
return head.getElement();
}
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* Returns (but does not remove) the last element of the list.
* @return element at the end of the list (or null if empty)
*/
public E last() { // returns (but does not remove) the last element
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}
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/**
* Adds an element to the front of the list.
* @param e the new element to add
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PLEASE PLEASE USE THE CODE BELOW..... THANK YOU
public class SinglyLinkedList<E> implements Cloneable {
//---------------- nested Node class ----------------
/**
* Node of a singly linked list, which stores a reference to its
* element and to the subsequent node in the list (or null if this
* is the last node).
*/
private static class Node<E> {
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/** A reference to the subsequent node in the list */
private Node<E> next; // reference to the subsequent node in the list
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* Creates a node with the given element and next node.
*
* @param e the element to be stored
* @param n reference to a node that should follow the new node
*/
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element = e;
next = n;
}
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/**
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* @return the element stored at the node
*/
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* Returns the node that follows this one (or null if no such node).
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*/
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* @param n the node that should follow this one
*/
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/** The head node of the list */
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