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(Mutually exclusive projects and NPV) You have been assigned the task of evaluating two mutually exclusive projects with the following projected cash flows: (Click on the icon in order to copy its contents into a spreadsheet.) If the appropriate discount rate on these projects is 11 percent, which would be chosen and why? .

(Mutually exclusive projects and NPV) You have been assigned the task of evaluating two
mutually exclusive projects with the following projected cash flows: (Click on the icon in order
to copy its contents into a spreadsheet.) If the appropriate discount rate on these projects is 11
percent, which would be chosen and why?

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***HINT> Consider the case when n=3. Professor Kelp decides to write a procedure that produces at random any permutation except the identity permutation, in which every element ends up where it started. He proposes the procedure PeRMUTE-WithOUt-IdENTITY. Does this procedure do what Professor Kelp intends? PERMUTE-Without-IdEntity ( A , n ) for i = 1 to n 1 swap A [ i ] with A [ RANDOM ( i + 1 , n )] .

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- With your partner, list at least two tangible resources, two intangible resources, and two organizational capabilities for each of the following firms and assess how valuable, rare, difficult to imitate, and substitutable they are. Be sure to state your assumptions. - Apple - Disney Firm Resources and Sustainable Competitive Advantages Resources that can provide a firm with the potential for a sustainable competitive advantage have four attributes. 1. Valuable in formulating and implementing strategies to improve efficiency or effectiveness. 2. Rare or uncommon; difficult to exploit. 3. Difficult to imitate or copy due to physical uniqueness, path dependency, causal ambiguity, or social complexity. 4. Difficult to substitute with strategically equivalent resources or capabilities. Disney: Tangible Resources: - Intangible Resources: Organizational Capabilities: .

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(4 Points) Construct to scale a diagram (likethe one used in lecture for calf weaning weights) showing the following hypothetical sample of records for live (market) weight in lambs (assume = 130 lb ). Be sure to lobel completely. Lambs 1 and 3 have similar market weights, but for different reasons. Briefly, explain. A New Model The basic genetic model for quantitative traits can now be expanded to include breeding value (BV) and gene combination value (GCV): P = + B V + GC V + E The weaning weights of the three calves depicted in Figure 1 are shown again in Figure 4, this time with their (hypothetical) breeding values and gene combination values included. Calf \#1 has the heaviest weaning weight, but note that most of his superior performance is due to either environment or genetic effects that cannot be transmitted to offspring. If heavier weaning weights are desirable, the best breeding animal should be Calf \#3. Despite his mediocre individual performance, he has the highest breeding value. Figure 4. Contributions of breeding value, gene combination value, and environmental effect to the weaning weights of the three calves depicted in Figure 1. The new model for quantitative traits retains many of the characteristics of the basic model. Like genotypic value, breeding value and gene combination value are expressed as positive and negative deviations from a population mean. The average of breeding values and the average of gene combination values across an entire population are, therefore, zero. Furthermore, breeding values and gene combination values are considered independent of environment effects and each other. It is possible to have highly inbred animals that suffer inbreeding depression (unfavorable gene combination value) and, Calf \#1 weighs 600 lb (100 lb above average), has a higher then average genotypic value ( l ), and experienced a better than averoge environmental effect ( 5 ). Colf m2 weighs 450 lb ( 50 lb below average), has a lower than average genotypic value, and experienced a worse than average environmental effect. Calf 3 weighs 460 lb . His genotypic volue for weaning weight is higher than average, but his actual performance is below average due to a very poor environment. Figure 5. Contributions of components of the genetic model for repeated traits for tw o records on a single dairy cow for 305-d lactation yield. Appendix B Partitioning the Genotypic Value Where is the breeding value? As defined in the body of this section, the basic genetic model for quantitative traits is: P = + G + E where P = the phenotypic value or performance of an individual animal for a particular trait. = (Greek letter m u ) the population mean or average phenotypic value for the trait for all animals in the population. G m the genotypic value of the individual for the trait. E = the environmental effect on the individual's performance for the trait. We said this model would help us understand breeding value, which we defined as the value .

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(14 minutes) Amer Company purchases an investment in stock that represents a 30% interest in another company with the ability to exercise significant control. The investment costs $40 , 000 . At the date of purchase on 1/1/22 , the investee's balance sheet included: Assets not subject to depreciation $30 , 000 (same as fair value) Assets subject to depreciation $40 , 000 (fair value $49 , 000 , 10 year remaining useful life) Liabilities $10 , 000 (same as fair value) The investee company reported net income of $20 , 000 and declared and paid a total cash dividend of $50 , 000 . Amer reports the following amount in its 2022 financial statements: Balance Sheet: Noncurrent Asset \$45,730; Income Statement: Investment Income $21 , 000 Other/Nonoperating - Regular Income. Balance Sheet: Current Asset $30 , 730 ; Income Statement: Investment Income $15 , 000 Other/Nonoperating Regular Income and $6 , 000 Other Comprehensive income. Balance Sheet Current Asset $45 , 730 ; Income Statement: Investment Income $6 , 000 Other/Nonoperating Regular Income. Balance Sheet: Noncurrent Asset $30 , 730 ; Income Statement: Investment Income $5 , 730 Other/Nonoperoting - Regular Income. .

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(1) Thinking about numbers of alleles, not just frequency. A further step towards chi-square test Consider a diploid population with 12,500 individuals consisting of genotype frequencies f ( CC ) = 0.87 , f ( C c ) = 0.11 , and f ( cc ) = 0.02 . Genotype cc suffers from a lethal genetic disease; C is dominant to c . (A) How many recessive alleles are there in this population? Provide a number for c alleles, not frequency. Hint: Think about which genotypes carry them, and how many are carried by each. Justify your answer / show your work. (B) How of those alleles are contained in individuals having the genotype that will die from the genetic disease? How many copies are 'hiding' in genotypes that will not die? Justify your answer / show your work / label clearly .

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