Lets compare and contrast the national cultures of Egypt and Brazi.pdf
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Let\'s compare and contrast the national cultures of Egypt and Brazil. Identify the main differences and similarities between the two countries using project GLOBE (each 9 dimension and give an example) Solution Answer: As per PROJECT GLOBE, there are only 6 dimensions of culturally endorsed implicit leadership and they are as follows, And 9 nos are the cultural competencies..
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A ISCSI SAN consists of Select one or more A. HBA B. LUN C. Fibr.pdf
A ISCSI SAN consists of Select one or more: A. HBA B. LUN C. Fibre Channel switch D.
Storage system E. Storage processor(SP)
Solution
iSCSi SAN is consist of the storage system for the purpose of storage that uses the RAID level.
This uses the fibre channel and consist of switch in that fibre channel.
Logical unit number which is essential for representing the logical device which is a part of
physical ISCSI device..
Which of the following statements about tRNA molecules is TRUEMul.pdf
Which of the following statements about tRNA molecules is TRUE?
Multiple Choice
Bases in the tRNA loops do not pair with any other bases
tRNA assumes a double helical shape
Every base in a tRNA molecule pairs with another base in the same tRNA strand, leading to its
higher levels of structure
All of these are TRUE
The amino acid is attached to the central loop region of the tRNA molecule
Solution
The amino acid is attached to the acceptor stem of tRNA..
Write a C program to simulate the description below using semaphores.pdf
Write a C program to simulate the description below using semaphores to synchronize the
processes/threads.
A group of fraternity brother and sorority sisters is having a party and drinking from a large
communal keg that can hold N servings of soda. When a partier wants to drink, he or she fills a
cup from keg, unless it is empty. If the keg is empty, the partier wakes up the pledge and then
waits until the pledge has returned with a new keg.
Solution
#include
#include
#include
#include
#include
#include
#include
#define MAX 10
//Keg which holds no of servings
int N = MAX;
int brothers,sisters,i=0;
int Bservings,Sservings;
void pledge(int signo);
int main()
{
int pidb,pids;
signal( SIGUSR1, pledge ); //instal signal handler
//for semaphore declaration
int sem_id,j; /* semid of semaphore set */
key_t key = 1234; /* key to pass to semget() */
int nsems = 1; /* nsems to pass to semget() */
//for semaphore operation
struct sembuf sop;
sem_id=semget(key,nsems,IPC_CREAT|0666);
printf(\"No of brothers = \");
scanf(\"%d\",&brothers);
printf(\"No of sisters = \");
scanf(\"%d\",&sisters);
//create no of brothers
while(brothers)
{
pidb = fork();
if( pidb > 0 )
{
printf(\"Parent process\ \");
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
kill(getpid(),SIGUSR1);
for(j=0; j=0 && Bservings<= N)
{
++Bservings;
N-=Bservings;
printf(\"N = %d\ \",N);
printf(\"Servings = %d\ \",Bservings);
printf(\"Brother%d has taken %d servings\ \",i,Bservings);
}
else
{
printf(\"Brorhes else\ \");
kill(getpid(),SIGUSR1);
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
}
}
--brothers;
}
//create no of brothers
i = 0;
while(sisters)
{
pids = fork();
if( pidb > 0 )
{
printf(\"Parent process\ \");
for(j=0; j=0 && Sservings<= N)
{
++Sservings;
N-=Sservings;
printf(\"N = %d\ \",N);
printf(\"Servings = %d\ \",Sservings);
printf(\"Brother%d has taken %d servings\ \",i,Sservings);
}
else
{
printf(\"sisters else\ \");
kill(getpid(),SIGUSR1);
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
}
}
--sisters;
}
}
//if empty execute pledge
void pledge(int signo)
{
//for semaphore operation
struct sembuf sop;
int sem_id; /* semid of semaphore set */
key_t key = 1234; /* key to pass to semget() */
int nsems = 1; /* nsems to pass to semget() */
sem_id=semget(key,nsems,0666);
if (signo == SIGUSR1)
printf(\"received SIGUSR1\ \");
else if (signo == SIGKILL)
printf(\"received SIGKILL\ \");
else if (signo == SIGSTOP)
printf(\"received SIGSTOP\ \");
//set keg to new value
N = MAX;
sop.sem_num = 0;
sop.sem_op = 1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
printf(\"Exiting pledge after setting keg to MAX value\");
}.
When analyzing any particular primary source, historians must consid.pdf
When analyzing any particular primary source, historians must consider all of the following
except:
Select one:
a. the perspectives not included in the source.
b. the source creator\'s bias and what the creator had to gain or lose by creating the source.
c. contrasting or corroborating evidence that will refute/support that source.
d. the historical context of the time at which the source was created.
e. the arguments presented by Wikipedia about that source.
Solution.
What is Linux SecuritySolutionLinux Security is a module in.pdf
What is Linux Security?
Solution
Linux Security is a module in a Linux Operationg System which gives Protection from security
attacks and misuse of Operating Sysytem.It ensure Protection from the Enemy who\'s Bad
Intention is to leak ,steal,change data or Hack your system. There are different types of security
threat as follow:
Reading data - Typically associated with espionage or theft, computer systems often contain
information that needs to be kept confidential or secure. This could vary from emails discussing
the price of a bid for a project to personal information or bank details. The disclosure of this
information could severely damage the company or have legal implications
Changing data - Potentially even more serious is that an attack could gain sufficient access to be
able to update data. This could be for sabotage, as a means of discrediting the organisation or
leaving a calling card. One of the biggest risks is that data could be modified and not noticed.
The cases that tend to get a high profile in this area are where attackers replace web pages with
their own modified versions.
Denial of service - Denial of Service (DoS) attacks are where the attacker disables, or makes
unusable the services provided by the system
Access to computer - Whilst for some systems you may allow other users onto your system
sometimes these user accounts could come under attack. The computer may not contain any
confidential material and the user may not be able to write to any data however they could still
use your system to cause damage. If someone manages to attack a computer that borders between
a secure and insecure network then they could use your machine as a method of traversing
between the two networks.
Linux OS has Security Policy which ensure that you have covered all of the principles
Authorisation, Authenticity, Privacy / Confidentiality, Integrity, Non-repudiation and
Availability as they apply to your system. Also consider how this is going to be implemented by
the users and system administrators. If a security process is hard to implement or restricts
someone from doing their job then you may find that the process gets ignored or is not complied
with.
Linux security Policy Requriments according to Data Protection Act 1998 and ISO 7984-2
International Standards Organisation Security Standard are:
Authorisation - Only allow those that need access to the data
Authenticity - Verifying they are who they say they are
Privacy / Confidentiality - Ensure personal information is not being compromised
Integrity - Ensuring that the data has not been tampered with
Non-repudiation - Confirmation that data is received. The ability to prove it in court
Availability - Ensure that the system can perform it’s required function.
What is the runtime complexity of Adams famous string splitter cod.pdf
What is the runtime complexity of Adam\'s famous string splitter code? Hint: Make sure to look
into the source code for string.find() in the C++ std library. I’ve included that code (downloaded
from GNU). static vector ring text string delimiter vector ring pieces int location text, (delimiter);
inte start 0; //while we find something interesting while location string DRos)f build substring
string piece text substr (start location start); (piece start location 1 //find again location ext find
deli miter start); string piece text substr (start location start); pieseswRush bask (piece return
pieces;
Solution
Assumption is we have text length as N and we have N-1 delimeters in that text.
text.find() -->Takes O(n) time in the worst case to find the delimeter.
vectorpieces; -->O(1)
int location = text.find();delimeter-->At max O(n)
while(location!=string.pos()){ . -> Runs N times
string piece = text.substr(start,location-start); -->At max takes O(N) [Copying that many
characters]*N times for while loop
start = location+1; -->O(1)
location = text.find(delimeter,start);-->At Max O(N) * N times for while loop
So While loop will run N time as we have N-1 delmieters and each time finding substr() and
find() on an average will take O(n). So overall time complexity is O(N2)
}
Thanks, let me know if there is any concern..
What does personalized learning mean to you What does personal.pdf
What does personalized learning mean to you?
What does personalized learning mean to you?
Solution
Personalized learning is an approach to general education.
Kids learn in different ways and at different paces. Personalized learning is a teaching model
based on that premise. Each student gets a “learning plan” based on how he learns, what he
knows, and what his skills and interests are.
With personalized learning, students are an integral part of the learning process. They work with
their teachers to set both short-term and long-term goals, and they take ownership of their own
learning..
What do patients in healthcare expect from their insurance company.pdf
What do patients in healthcare expect from their insurance company?
Solution
Health insurance is insurance against the risk of incurring medical expenses among individuals.
Depending on the type of health insurance coverage, either the insured pays costs out-of-pocket
and is then reimbursed, or the insurer makes payments directly to the provider.
The patients expect from their insurance companies to cover at least following services:-.
Recommended
A ISCSI SAN consists of Select one or more A. HBA B. LUN C. Fibr.pdf
A ISCSI SAN consists of Select one or more: A. HBA B. LUN C. Fibre Channel switch D.
Storage system E. Storage processor(SP)
Solution
iSCSi SAN is consist of the storage system for the purpose of storage that uses the RAID level.
This uses the fibre channel and consist of switch in that fibre channel.
Logical unit number which is essential for representing the logical device which is a part of
physical ISCSI device..
Which of the following statements about tRNA molecules is TRUEMul.pdf
Which of the following statements about tRNA molecules is TRUE?
Multiple Choice
Bases in the tRNA loops do not pair with any other bases
tRNA assumes a double helical shape
Every base in a tRNA molecule pairs with another base in the same tRNA strand, leading to its
higher levels of structure
All of these are TRUE
The amino acid is attached to the central loop region of the tRNA molecule
Solution
The amino acid is attached to the acceptor stem of tRNA..
Write a C program to simulate the description below using semaphores.pdf
Write a C program to simulate the description below using semaphores to synchronize the
processes/threads.
A group of fraternity brother and sorority sisters is having a party and drinking from a large
communal keg that can hold N servings of soda. When a partier wants to drink, he or she fills a
cup from keg, unless it is empty. If the keg is empty, the partier wakes up the pledge and then
waits until the pledge has returned with a new keg.
Solution
#include
#include
#include
#include
#include
#include
#include
#define MAX 10
//Keg which holds no of servings
int N = MAX;
int brothers,sisters,i=0;
int Bservings,Sservings;
void pledge(int signo);
int main()
{
int pidb,pids;
signal( SIGUSR1, pledge ); //instal signal handler
//for semaphore declaration
int sem_id,j; /* semid of semaphore set */
key_t key = 1234; /* key to pass to semget() */
int nsems = 1; /* nsems to pass to semget() */
//for semaphore operation
struct sembuf sop;
sem_id=semget(key,nsems,IPC_CREAT|0666);
printf(\"No of brothers = \");
scanf(\"%d\",&brothers);
printf(\"No of sisters = \");
scanf(\"%d\",&sisters);
//create no of brothers
while(brothers)
{
pidb = fork();
if( pidb > 0 )
{
printf(\"Parent process\ \");
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
kill(getpid(),SIGUSR1);
for(j=0; j=0 && Bservings<= N)
{
++Bservings;
N-=Bservings;
printf(\"N = %d\ \",N);
printf(\"Servings = %d\ \",Bservings);
printf(\"Brother%d has taken %d servings\ \",i,Bservings);
}
else
{
printf(\"Brorhes else\ \");
kill(getpid(),SIGUSR1);
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
}
}
--brothers;
}
//create no of brothers
i = 0;
while(sisters)
{
pids = fork();
if( pidb > 0 )
{
printf(\"Parent process\ \");
for(j=0; j=0 && Sservings<= N)
{
++Sservings;
N-=Sservings;
printf(\"N = %d\ \",N);
printf(\"Servings = %d\ \",Sservings);
printf(\"Brother%d has taken %d servings\ \",i,Sservings);
}
else
{
printf(\"sisters else\ \");
kill(getpid(),SIGUSR1);
sop.sem_num = 0;
sop.sem_op = -1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
}
}
--sisters;
}
}
//if empty execute pledge
void pledge(int signo)
{
//for semaphore operation
struct sembuf sop;
int sem_id; /* semid of semaphore set */
key_t key = 1234; /* key to pass to semget() */
int nsems = 1; /* nsems to pass to semget() */
sem_id=semget(key,nsems,0666);
if (signo == SIGUSR1)
printf(\"received SIGUSR1\ \");
else if (signo == SIGKILL)
printf(\"received SIGKILL\ \");
else if (signo == SIGSTOP)
printf(\"received SIGSTOP\ \");
//set keg to new value
N = MAX;
sop.sem_num = 0;
sop.sem_op = 1;
sop.sem_flg = 0;
if (semop(sem_id, &sop, 1))
{
perror(\"Could not increment semaphore\");
exit(5);
}
printf(\"Exiting pledge after setting keg to MAX value\");
}.
When analyzing any particular primary source, historians must consid.pdf
When analyzing any particular primary source, historians must consider all of the following
except:
Select one:
a. the perspectives not included in the source.
b. the source creator\'s bias and what the creator had to gain or lose by creating the source.
c. contrasting or corroborating evidence that will refute/support that source.
d. the historical context of the time at which the source was created.
e. the arguments presented by Wikipedia about that source.
Solution.
What is Linux SecuritySolutionLinux Security is a module in.pdf
What is Linux Security?
Solution
Linux Security is a module in a Linux Operationg System which gives Protection from security
attacks and misuse of Operating Sysytem.It ensure Protection from the Enemy who\'s Bad
Intention is to leak ,steal,change data or Hack your system. There are different types of security
threat as follow:
Reading data - Typically associated with espionage or theft, computer systems often contain
information that needs to be kept confidential or secure. This could vary from emails discussing
the price of a bid for a project to personal information or bank details. The disclosure of this
information could severely damage the company or have legal implications
Changing data - Potentially even more serious is that an attack could gain sufficient access to be
able to update data. This could be for sabotage, as a means of discrediting the organisation or
leaving a calling card. One of the biggest risks is that data could be modified and not noticed.
The cases that tend to get a high profile in this area are where attackers replace web pages with
their own modified versions.
Denial of service - Denial of Service (DoS) attacks are where the attacker disables, or makes
unusable the services provided by the system
Access to computer - Whilst for some systems you may allow other users onto your system
sometimes these user accounts could come under attack. The computer may not contain any
confidential material and the user may not be able to write to any data however they could still
use your system to cause damage. If someone manages to attack a computer that borders between
a secure and insecure network then they could use your machine as a method of traversing
between the two networks.
Linux OS has Security Policy which ensure that you have covered all of the principles
Authorisation, Authenticity, Privacy / Confidentiality, Integrity, Non-repudiation and
Availability as they apply to your system. Also consider how this is going to be implemented by
the users and system administrators. If a security process is hard to implement or restricts
someone from doing their job then you may find that the process gets ignored or is not complied
with.
Linux security Policy Requriments according to Data Protection Act 1998 and ISO 7984-2
International Standards Organisation Security Standard are:
Authorisation - Only allow those that need access to the data
Authenticity - Verifying they are who they say they are
Privacy / Confidentiality - Ensure personal information is not being compromised
Integrity - Ensuring that the data has not been tampered with
Non-repudiation - Confirmation that data is received. The ability to prove it in court
Availability - Ensure that the system can perform it’s required function.
What is the runtime complexity of Adams famous string splitter cod.pdf
What is the runtime complexity of Adam\'s famous string splitter code? Hint: Make sure to look
into the source code for string.find() in the C++ std library. I’ve included that code (downloaded
from GNU). static vector ring text string delimiter vector ring pieces int location text, (delimiter);
inte start 0; //while we find something interesting while location string DRos)f build substring
string piece text substr (start location start); (piece start location 1 //find again location ext find
deli miter start); string piece text substr (start location start); pieseswRush bask (piece return
pieces;
Solution
Assumption is we have text length as N and we have N-1 delimeters in that text.
text.find() -->Takes O(n) time in the worst case to find the delimeter.
vectorpieces; -->O(1)
int location = text.find();delimeter-->At max O(n)
while(location!=string.pos()){ . -> Runs N times
string piece = text.substr(start,location-start); -->At max takes O(N) [Copying that many
characters]*N times for while loop
start = location+1; -->O(1)
location = text.find(delimeter,start);-->At Max O(N) * N times for while loop
So While loop will run N time as we have N-1 delmieters and each time finding substr() and
find() on an average will take O(n). So overall time complexity is O(N2)
}
Thanks, let me know if there is any concern..
What does personalized learning mean to you What does personal.pdf
What does personalized learning mean to you?
What does personalized learning mean to you?
Solution
Personalized learning is an approach to general education.
Kids learn in different ways and at different paces. Personalized learning is a teaching model
based on that premise. Each student gets a “learning plan” based on how he learns, what he
knows, and what his skills and interests are.
With personalized learning, students are an integral part of the learning process. They work with
their teachers to set both short-term and long-term goals, and they take ownership of their own
learning..
What do patients in healthcare expect from their insurance company.pdf
What do patients in healthcare expect from their insurance company?
Solution
Health insurance is insurance against the risk of incurring medical expenses among individuals.
Depending on the type of health insurance coverage, either the insured pays costs out-of-pocket
and is then reimbursed, or the insurer makes payments directly to the provider.
The patients expect from their insurance companies to cover at least following services:-.
Use Table A to find the number z such that the proportion of observa.pdf
Use Table A to find the number z such that the proportion of observations that are less than z in a
standard Normal distribution is 0.26.
z (±0.01) =
Find the number z such that 34% of all observations from a standard Normal distribution are
greater than z.
z (±0.01) =
Solution
1. Z=0.64
2. Z=0.41
I looked in the table Z.
Two of the main political systems are democracy and totalitarianism..pdf
Two of the main political systems are democracy and totalitarianism. Define in your own words.
Solution
Democracy can be defined as a freedom of the people in a nation to opt for whatever they want.
The citizens of the country have the right to all the resources of the country. The majority of the
country decides the direction and the fate of the country. In a democracy, the leaders and
government are selected by the election process and it can also be removed if the public opposes
the government in power.
Opposite of the democracy is authoritarian and the totalitarian type of governance. In these types
of governance style, the leadership of the country remains with a single individual or a group
leading the entire country. These can be seen as a dictatorship.
In case of a totalitarian regime, the individual who holds the power or the dictator has the
influence of his charisma over the people. The citizens are attracted by his prophetic leadership
which makes these citizens perform and follow the wishes and orders of the dictator. Examples:-
Joseph Stalin of USSR, Benito Mussolini of Italy, and Adolf Hitler of Germany. There is a sense
of connection between the citizens and the dictators and this is how the dictator is able to rule the
country. A sense of ideology is mutually shared by the citizens and the totalitarian.
The procedure of transferring journal entries to the ledger accounts .pdf
The procedure of transferring journal entries to the ledger accounts is called journalizing.
analyzing. reporting. posting.
Solution
Answer is Posting.
Explanation:
The process of recording the debit and credit aspect of each journal entry in the respective ledger
accounts is known as Posting of entries to ledger accounts..
The ProblemUsing C programming language write a program that simul.pdf
The Problem
Using C programming language write a program that simulates the Tiny Machine Architecture.
Your code must implement the basic instruction set that the Tiny Machine Architecture adheres
to (LOAD[1], ADD[2], STORE[3], SUB[4], IN[5], OUT[6], END[7], JMP[8], SKIPZ[9]). Each
piece of the architecture must be accurately represented in your code (Instruction Register,
Program Counter, Memory Address Register, Data Memory, Memory Data Register, and
Accumulator). Data Memory will be represented by a 0-9 array. Your Program Counter will
begin at 10.
For the sake of simplicity Program Memory and Data Memory may be implemented as separate
arrays.
Hint: Implementing a struct for your Instructions and an array of these structs as your Program
Memory greatly simplifies this program.
Example:
typedef struct {
int opCode, deviceOrAddress;
} Instruction;
Instruction programMemory[MAXPROGRAMSIZE];
Input Specifications
Your simulator must run from the command line with a single input file as a parameter to main.
This file will contain a sequence of instructions for your simulator to assemble (store in
“program memory”) and then run via the fetch/execute cycle.
Example:
5 5 //IN 5
6 7 //OUT 7
3 0 //STORE 0
5 5 //IN 5
6 7 //OUT 7
3 1 //STORE 1
1 0 //LOAD 0
4 1 //SUB 1
3 0 //STORE 0
6 7 //OUT 7
1 1 //LOAD 1
6 7 //OUT 7
7 0 //END
Output Specifications
Your simulator should provide output according to the input file. Along with this output your
program should provide status messages identifying details on the workings of your simulator.
Output text does not have to reflect my example word-for-word, but please provide detail on the
program as it runs in a readable format that does not conflict with the actual output of your
simulator. After each instruction print the current state of the Program Counter, Accumulator,
and Data Memory. The INPUT instruction is the only one that should prompt an interaction from
the user.
Example:
Assembling Program…
Program Assembled.
Run.
PC = 10 | A = NULL | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* input value */
X
PC = 11 | A = X | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* outputting accumulator to screen */
X
PC = 12 | A = X | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* storing accumulator to memory location 0 */
PC = 13 | A = X | MEM = [X, 0, 0, 0, 0, 0, 0, 0, 0, 0]
… etc
Program complete.
Grading
Your simulator will be graded on the above criteria. Your program should compile and run from
the command line with one input file parameter. Please note that your program will not just be
graded on whether or not it runs successfully; accurate simulation and a thorough demonstration
of your understanding on the workings of this architecture will constitute a large portion of this
grade. As that is the case it is in your best interest to comment your program in a concise and
readable way. However, if your program does not run or compile the maximum points possible
will be 50 (up to 25 may be recovered by debugging and demonstrating a.
5. Joe and Sam are using Public Key encryption. Joe’s public and pri.pdf
5. Joe and Sam are using Public Key encryption. Joe’s public and private keys are named Joe-
Pub and Joe-Priv. Sam’s public and private keys are named Sam-Pub and Sam-Priv. a) (5 points)
Assume Sam is sending encrypted data to Joe. What key (out of the 4 keys listed above) does
Sam use to encrypt the data? What key does Joe use to decrypt the data? b) (5 points) Now
assume Sam is putting digital signatures on his messages to Joe to prove his identity. He does
this by encrypting the HMAC hash code at the end of the message. What key does Sam use to
encrypt this HMAC code? What key does Joe use to decrypt the encrypted HMAC code that he
receives?
Solution
Suppose A(sender) wants to send some data to B(receiver) using public-private key encryption.
Then A(sender) has to encrypt the data using public key of B(receiver). When B(receiver) will
get the data, he will decrypt it using his own private key.
So answer to first question (a) is that:
Sam will be using Joe-Pub to encrypt the data to be sent to Joe. And Joe will use Joe-Priv to
decrypt the data.
For question(b), the case is similar to question(a).
Sam will be using Joe-Pub key to encrypt the HMAC and Joe will be using Joe-Priv to decryp
the HMAC of Sam..
QUESTION 7 When using the indirect method to prepare the statement of.pdf
QUESTION 7 When using the indirect method to prepare the statement of cash flows,
depreciation expense should be presented as a(n): O addition to net income. o cash flow from
financing activities cash flow from investing activities. O deduction from net income. O
investing and financing activity not affecting cash.
Solution
A. addition to net income.
Depreciation is added back in cash flow statement because it is a non-cash item, which had
reduced the net income, and thus should be added back..
Q.1. Define noncontrolling (minority) interest. List three methods th.pdf
Q.1. Define noncontrolling (minority) interest. List three methods that might be used for
reporting the noncontrolling interest in a consolidated
Solution
Non Controlling Interest also known as Minority Interest is that portion of the subsidiary\'s
equity capital which is not held or own or controlled by the parent company. Parent company
here means who has a controlling interest of 50% or more in the subsidiary and who consolidates
their financial statements with its own.
Three methods to report NCI are:.
Picking a fruit-flavored or primary colored bean. overlapping event .pdf
Picking a fruit-flavored or primary colored bean. overlapping event mutually exclusive event
compound event dependent Picking a red or green or fruit-flavored bean, dependent
compound event mutually exclusive event overlapping event
Solution
13. picking a fruit flavoured or primary cloured bean is a compound event
compound event is a event with two or more favourable outcomes.
Part F - Viral Evolution and LysogenyOne hypothesis regarding the .pdf
Part F - Viral Evolution and Lysogeny
One hypothesis regarding the origin of viruses suggests that early viruses may have had
primarily latent life cycles and that they served a function by helping to transfer genes from one
cell to another. This hypothesis suggests that perhaps the lytic life cycle evolved later to allow
the viruses to more rapidly spread from one cell to another. How could the researchers studying
the archaeal RNA viruses determine whether those viruses have lytic or latent life cycles?
Choose all of the correct answers.
1. They could examine the genomes that they have assembled to determine whether genes
associated with lysogeny were present.
3. There is no way to determine the life cycle of the archaeal RNA viruses without observing the
viruses causing infection
4.They could examine the genomes of the archaeal RNA viruses to look for evidence of
uncoating genes.
1. They could examine the genomes that they have assembled to determine whether genes
associated with lysogeny were present.2. They could consider the life cycles of more well-known
archaeal viruses, which are rarely lysogenic, and compare the new viruses with known lysogenic
archaeal viruses.
3. There is no way to determine the life cycle of the archaeal RNA viruses without observing the
viruses causing infection
4.They could examine the genomes of the archaeal RNA viruses to look for evidence of
uncoating genes.
Solution
Answer : 2
Molecular mechanisms underlying the various stages of the viral life cycle remain poorly
understood in Archaea. (Quentin et al., 2014). Cell surface , environmental adaptibility, nature of
cell wall of archaea has great influence on the viral entry.
Hence, the approach of comparing the new virus with well known lysogenic archaea virus is
considered better..
Match the following Data vs Information Reliability as it adds value .pdf
Match the following Data vs Information Reliability as it adds value to information The IPO
model A Takes raw input and turns it into something meaningful vthile still allowing an
opportunity for adjustment of results. B. True C. Responding to different cultural needs/desires. \'
A critical component of a CBS A CBIS used to perform and record business related exchanges.
Are the Internet and the WWW the same thing? TPS A strategy for attaining competitive
advantage Financial evaluation is an important part of evaluation IS E False F. r: Providing
choices; varety; or higher quality The difference between raw facts and those that are organized
and processed in a way that adds value. projects H Is responsible for equipment, personnel,
finance, accounting and value or IS. Establishes trust; can be dependent on its source; can be a A
global challenge for information systems victim of poor data collection An organized collection
of facts and information-usually maintained in two or more related files.
Solution
Data vs information:- G:_ The difference between raw facts and those that are organized and
processed in a way that adds value
Reliability as it adds value to information:- I:- Establish trust; can dependent on its siurce; can be
a victim of poor data collection
The IPO model:- A:- Takes raw input and turns into something meaningful while still allowing
and opportunity for adjustment of results.
A critical component of CBIS:- J:- an organized collection of facts and information0usually
maintained iin two or more related files
Are the internet and www the same thing :- E:- FALSE
TPS:- D:- A CBIS used to perform and record business related exchanges
A strategy for attaining competitive advantage:- F:- Providing choices; variety or higher quality
Financial evaluation is an importance part of evaluation IS projects:- B:- True
CIO:- H:- is responsible for equipment, personnel, finance, accounting and value or IS
A global challenge for information systems:- C:- responding to different cultural needs/desires.
Many organizations invest substantial resources in creating their ow.pdf
Many organizations invest substantial resources in creating their own project methodologies,
which are sets of templates, process maps, and procedures that show the normal flow of a project
from start to finish. Other organizations have no formal project management methods, and it is
difficult for project managers and team members to be certain about what phase the project is in.
If informal project management can get the job done, why do we need fancy methods and
processes and terminology? Have you ever been involved in a project that didn’t follow the
standard cycle of initiating, planning, executing, and closing? Is it ethical to under plan or over
plan a project? Why or why not?
Solution
Q1) Informal project management doesn\'t have a detailed project plan outlining the phases,
resources and budget. It is followed by small companies where the project scale is low. The
phases begin and end in a flow rather than being preplanned. Though informal project
management can get the job done for small scale projects with not much budget involved and
relatively lesser sense of urgency for completion, for a project to be successful in all aspects, a
formal project management methodology needs to be in place. Below are the reasons -
1. Though project exceeds the cost expected and gets delayed to a small extent, it is difficult to
quantify and estimate in informal project management methodology and hence the firm doesn\'t
even know the loss being incurred.
2. Allocating, monitoring and controlling resources becomes difficult in informal methods.
3. Lack of accountability results in not owning any issues that might occur in the project.
Q2) Example of a project that is informal -
Quality circles formed by a group of employees from various departments or functions to
improve overall quality of the product and eliminate deviations from the process.
The project starts with identifying quality issue and random inputs pour in from all the functional
departments that are collected by a moderator who keeps scheduling recurring meetings to
ensure the rootcause of the issue is identified and the alternatives are prepared. The solution then
is identified by testing all the three alternatives at a pilot scale and the best alternative is
implemented.
Q3) Underplanning or overplanning a project is never known in advance and is known while
project is in progress. Individuals never wilfully over or under plan for the project; sometimes it
might happen to over plan if the project manager wants to keep a buffer of time, resources and
budget. Underplanning is purely a deviation from the project and as far as ethics is concerned, it
is not something which is expected though it doesn\'t wilfully happen..
Great alveolar (type II) cells of the alveoli secrete a _______ t.pdf
Great alveolar (type II) cells of the alveoli secrete a _______ that decreases the surface tension
and prevent alveoli collapse when exhaling .
Great alveolar (type II) cells of the alveoli secrete a _______ that decreases the surface tension
and prevent alveoli collapse when exhaling .
Solution
Ans- pulmonary surfactant .
Pulmonary surfactant
Type II alveolar cells cover a small fraction of the alveolar surface area. Their function is of
major importance in the secretion of Pulmonary surfactant which decreases the surface tension
within the alveoli. They are also capable of cellular division, giving rise to more type I alveolar
cells when the lung tissue is damaged. These cells are granular and roughly cuboidal. Type II
alveolar cells are typically found at the blood-air barrier Although they only comprise 5% of the
alveolar surface, they are relatively numerous (60% of alveolar epithelial cells)
Development:-
Type II cells start to develop at about 26 weeks of gestation, secreting small amounts of
surfactant. However, adequate amounts of surfactant are not secreted until about 35 weeks of
gestation - this is the main reason for increased rates of infant respiratory distress syndrome,
which drastically reduces at ages above 35 weeks gestation.
Functions-
Type II cells are responsible for the production and secretion of pulmonary surfactant (the
majority of which are dipalmitoyphosphatidylcholine), a group of phospholipids that reduce the
alveolar surface tension. Surfactant phospholipids are stored in type II alveolar cells in lamellar
bodies, which are specialized vesicles. Release of surfactant in lamellar bodies occurs from an
infant\'s first breath onwards.
Type II pneumocytes can replicate in the alveoli and will replicate to replace damaged type I
cells.
MUC1 a human gene associated with type II pneumocytes, has been identified as a marker in
lung cancer.
Give a detailed explanation and introduction to Polarization Microsc.pdf
Give a detailed explanation and introduction to Polarization Microscopy.
Solution
Polarized light microscopy
Polarized light is a contrast-enhancing technique that improves the quality of the image obtained
with birefringent materials when compared to other techniques such as darkfield and brightfield
illumination, differential interference contrast, phase contrast, Hoffman modulation contrast, and
fluorescence. Polarized light microscopes have a high degree of sensitivity and can be utilized
for both quantitative and qualitative studies targeted at a wide range of anisotropic specimens.
Qualitative polarizing microscopy is very popular in practice, with numerous volumes dedicated
to the subject. In contrast, the quantitative aspects of polarized light microscopy, which is
primarily employed in crystallography, represent a far more difficult subject that is usually
restricted to geologists, mineralogists, and chemists. However, steady advances made over the
past few years have enabled biologists to study the birefringent character of many anisotropic
sub-cellular assemblies.
The polarized light microscope is designed to observe and photograph specimens that are visible
primarily due to their optically anisotropic character. In order to accomplish this task, the
microscope must be equipped with both a polarizer, positioned in the light path somewhere
before the specimen, and an analyzer (a second polarizer, placed in the optical pathway between
the objective rear aperture and the observation tubes or camera port. Image contrast arises from
the interaction of plane-polarized light with a birefringent (or doubly-refracting) specimen to
produce two individual wave components that are each polarized in mutually perpendicular
planes. The velocities of these components, which are termed the ordinary and the extraordinary
wavefronts , are different and vary with the propagation direction through the specimen. After
exiting the specimen, the light components become out of phase, but are recombined with
constructive and destructive interference when they pass through the analyzer.
olarized light microscopy is capable of providing information on absorption color and optical
path boundaries between minerals of differing refractive indices, in a manner similar to
brightfield illumination, but the technique can also distinguish between isotropic and anisotropic
substances. Furthermore, the contrast-enhancing technique exploits the optical properties specific
to anisotropy and reveals detailed information concerning the structure and composition of
materials that are invaluable for identification and diagnostic purposes..
Fill in the Morphology column in the following table. Then use the in.pdf
Fill in the Morphology column in the following table. Then use the information to construct a
flowchart for these bacteria. Draw your flowchart in the box below the table.
Solution
ANSWER:
Clostridium - straight or slightly curved
Enterobacter - rod-shaped
Klebsiella - rod-shaped
Lactobacillus - rod shaped
Staphylococcus - round shaped
Streptococcus - pairs or chains.
Do you need to know the registers and flags in a computer architectur.pdf
Do you need to know the registers and flags in a computer architecture to write C programs?
Solution
Answer:
No,
Because C program is compiled by compiler, and we just define and use variable as many as we
want, and its duty of compiler to know about registers and flags like things, in short we don\'t
need to know about registers and flags while writing c program..
Discrete MathLet A be a set and P(A) be the power set of A. True .pdf
Discrete Math:
Let A be a set and P(A) be the power set of A. True or false with explanation
a. There is an injection from A to P(A).
b. There is a surjection from A to P(A).
Solution
Cardinality of power set P(A) is more than set A
a. Injection from A to P(A) is true as an element P(A) is connected with atmost one element of
A.
b.
Surjection from A to P(A) is false at there is elements in P(A) which are not connected with A..
Describe two mechanisms that contribute to anterior-posterior axis e.pdf
Describe two mechanisms that contribute to anterior-posterior axis elongation.
Solution
The anterior posterior axis elongation takes place by formation of primitive streak (PS).
Convergent extension (CE) movements by cell intercalation and epithelial-mesenchymal
transition (EMT) also contribute to anterior posterior axis elongation.Apart from this,Wnt
ligands such as Wnt 11 and Wnt 5a also contribute to anterior posterior elongation..
Create an implementation of a binary tree using the recursive appr.pdf
\"Create an implementation of a binary tree using the recursive approach introduced in the
chapter. In this approach, each node is a binary tree. Thus a binary tree contains a reference to
the element stored at its root as well as references to its left and right subtrees. You may also
want to include a reference to its parent.\" p.741
You need to use the locally implemented binary tree. This means you need to have a \"jsjf\"
subfolder with at least these files: BinaryTreeADT.java, LinkedBinaryTree.java,
BinaryTreeNode.java, and the exceptions sub-subfolder.
Test/demonstrate your binary tree by doing the following:
Request file name from user,
Read an infix expression from file,
Build binary expression tree,
Display binary expression tree,
Evaluate binary expression tree,
Display result.
##############################################
Note a typical input file can be found here
##############################################
# Version 0.2, fully parenthesized.
# This is a comment
((9 + 4) * 5) + (4 - (6 + 3))
# Note first expression should evaluate to 60
((42 + ( 10 - 2 )) + ( 5 * 3 )) / 6
# Note second expression should evaluate to 65 / 6 or 10 (integer division)
##############################################
My program is below but the out put is incorrect
##############################################
StringTree.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Iterator;
import java.util.Scanner;
import java.util.Stack;
import jsjf.BinaryTreeNode;
import jsjf.LinkedBinaryTree;
public class StringTree extends LinkedBinaryTree {
public StringTree(String rootStr, StringTree leftSubtree, StringTree rightSubtree) {
root = new BinaryTreeNode(rootStr, leftSubtree, rightSubtree);
} // StringTree
public StringTree(File f) {
Stack leftStack = new Stack(), rightStack = new Stack();
// stacks of left and right subtrees of nodes
Scanner scan;
// scanner for reading from the file
String nodeType,
nodeStr;
// string contained in the current node
boolean hasLeftChild, hasRightChild;
// true if the current node has a left or right child
StringTree leftSubtree, rightSubtree,
// left and right subtrees of the current node
subtree;
// subtree having the current node as its root
// Create a scanner for reading from the file.
try {
scan = new Scanner(f);
} catch (FileNotFoundException e) {
System.out.println(e.getMessage());
root = null;
System.out.println(\"\ \"+\"The program has terminated......\");
System.exit(0);
return;
}
// Read the file and build a tree from the bottom up.
while (scan.hasNext()) {
// Input information about a tree node.
nodeType = scan.next();
hasLeftChild = (scan.next().equalsIgnoreCase(\"y\"));
hasRightChild = (scan.next().equalsIgnoreCase(\"y\"));
nodeStr = scan.next();
// Determine the left and right subtrees of the subtree
// having the node as its root.
if (hasLeftChild)
leftSubtree = leftStack.pop();
else
leftSubtree = null;
if (hasRightChild)
rightSubtree = rightStack.pop();
else
rightSubtree = null;
.
A common symptom of pharyngitis is swelling of the anterior cervi.pdf
A common symptom of pharyngitis is swelling of the anterior cervical lymph nodes. Why might
lymph nodes swell in the presence of an infection? What else may cause swollen lymph nodes?
Explain why conditions that cause destruction of B lymphocytes and/or T lymphocytes cause
malfunctioning of both the specific and nonspecific immune responses.
Solution
Lymph node swelling occurs in infection because they dikter lymph whuch circulates in the body
through lymphatic system . Now whenever any foreign antigen enters into the body, rhe number
of white blood cells increase in response to that antigen. They attack bacteria, virus, whoever
enters into the body . And while this fighting occurs body makes more of these cells taht causes
swelling.
Lymph nodes directly come into contact with lot of germs inside the body, so they can get
swollen even then.
The other causes could be lymphoma tumour, cancer, tuberculosis, any problem with immune
system, leukemia etc
Inflammatory response occurs when tissues are attacked by pathogens such as virus, bacteria etc.
The damaged cells release chemicals such as bradykinin, prostaglandin, histamine, which cause
vessels to leak fluid into tissues causing swelling.
11. During an audit of a clients capital cycle, the auditor checks .pdf
11. During an audit of a client\'s capital cycle, the auditor checks whether preferred stock and
bonds are adequately backed by sinking funds. This procedure most likely is designed to achieve
the specific audit objective of a. existence. b. completeness. c. valuation and allocation. d.
understandability.
Solution.
How to Setup Warehouse & Location in Odoo 17 Inventory
In this slide, we'll explore how to set up warehouses and locations in Odoo 17 Inventory. This will help us manage our stock effectively, track inventory levels, and streamline warehouse operations.
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective UpskillingExcellence Foundation for South Sudan
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.More Related Content
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Use Table A to find the number z such that the proportion of observa.pdf
Use Table A to find the number z such that the proportion of observations that are less than z in a
standard Normal distribution is 0.26.
z (±0.01) =
Find the number z such that 34% of all observations from a standard Normal distribution are
greater than z.
z (±0.01) =
Solution
1. Z=0.64
2. Z=0.41
I looked in the table Z.
Two of the main political systems are democracy and totalitarianism..pdf
Two of the main political systems are democracy and totalitarianism. Define in your own words.
Solution
Democracy can be defined as a freedom of the people in a nation to opt for whatever they want.
The citizens of the country have the right to all the resources of the country. The majority of the
country decides the direction and the fate of the country. In a democracy, the leaders and
government are selected by the election process and it can also be removed if the public opposes
the government in power.
Opposite of the democracy is authoritarian and the totalitarian type of governance. In these types
of governance style, the leadership of the country remains with a single individual or a group
leading the entire country. These can be seen as a dictatorship.
In case of a totalitarian regime, the individual who holds the power or the dictator has the
influence of his charisma over the people. The citizens are attracted by his prophetic leadership
which makes these citizens perform and follow the wishes and orders of the dictator. Examples:-
Joseph Stalin of USSR, Benito Mussolini of Italy, and Adolf Hitler of Germany. There is a sense
of connection between the citizens and the dictators and this is how the dictator is able to rule the
country. A sense of ideology is mutually shared by the citizens and the totalitarian.
The procedure of transferring journal entries to the ledger accounts .pdf
The procedure of transferring journal entries to the ledger accounts is called journalizing.
analyzing. reporting. posting.
Solution
Answer is Posting.
Explanation:
The process of recording the debit and credit aspect of each journal entry in the respective ledger
accounts is known as Posting of entries to ledger accounts..
The ProblemUsing C programming language write a program that simul.pdf
The Problem
Using C programming language write a program that simulates the Tiny Machine Architecture.
Your code must implement the basic instruction set that the Tiny Machine Architecture adheres
to (LOAD[1], ADD[2], STORE[3], SUB[4], IN[5], OUT[6], END[7], JMP[8], SKIPZ[9]). Each
piece of the architecture must be accurately represented in your code (Instruction Register,
Program Counter, Memory Address Register, Data Memory, Memory Data Register, and
Accumulator). Data Memory will be represented by a 0-9 array. Your Program Counter will
begin at 10.
For the sake of simplicity Program Memory and Data Memory may be implemented as separate
arrays.
Hint: Implementing a struct for your Instructions and an array of these structs as your Program
Memory greatly simplifies this program.
Example:
typedef struct {
int opCode, deviceOrAddress;
} Instruction;
Instruction programMemory[MAXPROGRAMSIZE];
Input Specifications
Your simulator must run from the command line with a single input file as a parameter to main.
This file will contain a sequence of instructions for your simulator to assemble (store in
“program memory”) and then run via the fetch/execute cycle.
Example:
5 5 //IN 5
6 7 //OUT 7
3 0 //STORE 0
5 5 //IN 5
6 7 //OUT 7
3 1 //STORE 1
1 0 //LOAD 0
4 1 //SUB 1
3 0 //STORE 0
6 7 //OUT 7
1 1 //LOAD 1
6 7 //OUT 7
7 0 //END
Output Specifications
Your simulator should provide output according to the input file. Along with this output your
program should provide status messages identifying details on the workings of your simulator.
Output text does not have to reflect my example word-for-word, but please provide detail on the
program as it runs in a readable format that does not conflict with the actual output of your
simulator. After each instruction print the current state of the Program Counter, Accumulator,
and Data Memory. The INPUT instruction is the only one that should prompt an interaction from
the user.
Example:
Assembling Program…
Program Assembled.
Run.
PC = 10 | A = NULL | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* input value */
X
PC = 11 | A = X | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* outputting accumulator to screen */
X
PC = 12 | A = X | MEM = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/* storing accumulator to memory location 0 */
PC = 13 | A = X | MEM = [X, 0, 0, 0, 0, 0, 0, 0, 0, 0]
… etc
Program complete.
Grading
Your simulator will be graded on the above criteria. Your program should compile and run from
the command line with one input file parameter. Please note that your program will not just be
graded on whether or not it runs successfully; accurate simulation and a thorough demonstration
of your understanding on the workings of this architecture will constitute a large portion of this
grade. As that is the case it is in your best interest to comment your program in a concise and
readable way. However, if your program does not run or compile the maximum points possible
will be 50 (up to 25 may be recovered by debugging and demonstrating a.
5. Joe and Sam are using Public Key encryption. Joe’s public and pri.pdf
5. Joe and Sam are using Public Key encryption. Joe’s public and private keys are named Joe-
Pub and Joe-Priv. Sam’s public and private keys are named Sam-Pub and Sam-Priv. a) (5 points)
Assume Sam is sending encrypted data to Joe. What key (out of the 4 keys listed above) does
Sam use to encrypt the data? What key does Joe use to decrypt the data? b) (5 points) Now
assume Sam is putting digital signatures on his messages to Joe to prove his identity. He does
this by encrypting the HMAC hash code at the end of the message. What key does Sam use to
encrypt this HMAC code? What key does Joe use to decrypt the encrypted HMAC code that he
receives?
Solution
Suppose A(sender) wants to send some data to B(receiver) using public-private key encryption.
Then A(sender) has to encrypt the data using public key of B(receiver). When B(receiver) will
get the data, he will decrypt it using his own private key.
So answer to first question (a) is that:
Sam will be using Joe-Pub to encrypt the data to be sent to Joe. And Joe will use Joe-Priv to
decrypt the data.
For question(b), the case is similar to question(a).
Sam will be using Joe-Pub key to encrypt the HMAC and Joe will be using Joe-Priv to decryp
the HMAC of Sam..
QUESTION 7 When using the indirect method to prepare the statement of.pdf
QUESTION 7 When using the indirect method to prepare the statement of cash flows,
depreciation expense should be presented as a(n): O addition to net income. o cash flow from
financing activities cash flow from investing activities. O deduction from net income. O
investing and financing activity not affecting cash.
Solution
A. addition to net income.
Depreciation is added back in cash flow statement because it is a non-cash item, which had
reduced the net income, and thus should be added back..
Q.1. Define noncontrolling (minority) interest. List three methods th.pdf
Q.1. Define noncontrolling (minority) interest. List three methods that might be used for
reporting the noncontrolling interest in a consolidated
Solution
Non Controlling Interest also known as Minority Interest is that portion of the subsidiary\'s
equity capital which is not held or own or controlled by the parent company. Parent company
here means who has a controlling interest of 50% or more in the subsidiary and who consolidates
their financial statements with its own.
Three methods to report NCI are:.
Picking a fruit-flavored or primary colored bean. overlapping event .pdf
Picking a fruit-flavored or primary colored bean. overlapping event mutually exclusive event
compound event dependent Picking a red or green or fruit-flavored bean, dependent
compound event mutually exclusive event overlapping event
Solution
13. picking a fruit flavoured or primary cloured bean is a compound event
compound event is a event with two or more favourable outcomes.
Part F - Viral Evolution and LysogenyOne hypothesis regarding the .pdf
Part F - Viral Evolution and Lysogeny
One hypothesis regarding the origin of viruses suggests that early viruses may have had
primarily latent life cycles and that they served a function by helping to transfer genes from one
cell to another. This hypothesis suggests that perhaps the lytic life cycle evolved later to allow
the viruses to more rapidly spread from one cell to another. How could the researchers studying
the archaeal RNA viruses determine whether those viruses have lytic or latent life cycles?
Choose all of the correct answers.
1. They could examine the genomes that they have assembled to determine whether genes
associated with lysogeny were present.
3. There is no way to determine the life cycle of the archaeal RNA viruses without observing the
viruses causing infection
4.They could examine the genomes of the archaeal RNA viruses to look for evidence of
uncoating genes.
1. They could examine the genomes that they have assembled to determine whether genes
associated with lysogeny were present.2. They could consider the life cycles of more well-known
archaeal viruses, which are rarely lysogenic, and compare the new viruses with known lysogenic
archaeal viruses.
3. There is no way to determine the life cycle of the archaeal RNA viruses without observing the
viruses causing infection
4.They could examine the genomes of the archaeal RNA viruses to look for evidence of
uncoating genes.
Solution
Answer : 2
Molecular mechanisms underlying the various stages of the viral life cycle remain poorly
understood in Archaea. (Quentin et al., 2014). Cell surface , environmental adaptibility, nature of
cell wall of archaea has great influence on the viral entry.
Hence, the approach of comparing the new virus with well known lysogenic archaea virus is
considered better..
Match the following Data vs Information Reliability as it adds value .pdf
Match the following Data vs Information Reliability as it adds value to information The IPO
model A Takes raw input and turns it into something meaningful vthile still allowing an
opportunity for adjustment of results. B. True C. Responding to different cultural needs/desires. \'
A critical component of a CBS A CBIS used to perform and record business related exchanges.
Are the Internet and the WWW the same thing? TPS A strategy for attaining competitive
advantage Financial evaluation is an important part of evaluation IS E False F. r: Providing
choices; varety; or higher quality The difference between raw facts and those that are organized
and processed in a way that adds value. projects H Is responsible for equipment, personnel,
finance, accounting and value or IS. Establishes trust; can be dependent on its source; can be a A
global challenge for information systems victim of poor data collection An organized collection
of facts and information-usually maintained in two or more related files.
Solution
Data vs information:- G:_ The difference between raw facts and those that are organized and
processed in a way that adds value
Reliability as it adds value to information:- I:- Establish trust; can dependent on its siurce; can be
a victim of poor data collection
The IPO model:- A:- Takes raw input and turns into something meaningful while still allowing
and opportunity for adjustment of results.
A critical component of CBIS:- J:- an organized collection of facts and information0usually
maintained iin two or more related files
Are the internet and www the same thing :- E:- FALSE
TPS:- D:- A CBIS used to perform and record business related exchanges
A strategy for attaining competitive advantage:- F:- Providing choices; variety or higher quality
Financial evaluation is an importance part of evaluation IS projects:- B:- True
CIO:- H:- is responsible for equipment, personnel, finance, accounting and value or IS
A global challenge for information systems:- C:- responding to different cultural needs/desires.
Many organizations invest substantial resources in creating their ow.pdf
Many organizations invest substantial resources in creating their own project methodologies,
which are sets of templates, process maps, and procedures that show the normal flow of a project
from start to finish. Other organizations have no formal project management methods, and it is
difficult for project managers and team members to be certain about what phase the project is in.
If informal project management can get the job done, why do we need fancy methods and
processes and terminology? Have you ever been involved in a project that didn’t follow the
standard cycle of initiating, planning, executing, and closing? Is it ethical to under plan or over
plan a project? Why or why not?
Solution
Q1) Informal project management doesn\'t have a detailed project plan outlining the phases,
resources and budget. It is followed by small companies where the project scale is low. The
phases begin and end in a flow rather than being preplanned. Though informal project
management can get the job done for small scale projects with not much budget involved and
relatively lesser sense of urgency for completion, for a project to be successful in all aspects, a
formal project management methodology needs to be in place. Below are the reasons -
1. Though project exceeds the cost expected and gets delayed to a small extent, it is difficult to
quantify and estimate in informal project management methodology and hence the firm doesn\'t
even know the loss being incurred.
2. Allocating, monitoring and controlling resources becomes difficult in informal methods.
3. Lack of accountability results in not owning any issues that might occur in the project.
Q2) Example of a project that is informal -
Quality circles formed by a group of employees from various departments or functions to
improve overall quality of the product and eliminate deviations from the process.
The project starts with identifying quality issue and random inputs pour in from all the functional
departments that are collected by a moderator who keeps scheduling recurring meetings to
ensure the rootcause of the issue is identified and the alternatives are prepared. The solution then
is identified by testing all the three alternatives at a pilot scale and the best alternative is
implemented.
Q3) Underplanning or overplanning a project is never known in advance and is known while
project is in progress. Individuals never wilfully over or under plan for the project; sometimes it
might happen to over plan if the project manager wants to keep a buffer of time, resources and
budget. Underplanning is purely a deviation from the project and as far as ethics is concerned, it
is not something which is expected though it doesn\'t wilfully happen..
Great alveolar (type II) cells of the alveoli secrete a _______ t.pdf
Great alveolar (type II) cells of the alveoli secrete a _______ that decreases the surface tension
and prevent alveoli collapse when exhaling .
Great alveolar (type II) cells of the alveoli secrete a _______ that decreases the surface tension
and prevent alveoli collapse when exhaling .
Solution
Ans- pulmonary surfactant .
Pulmonary surfactant
Type II alveolar cells cover a small fraction of the alveolar surface area. Their function is of
major importance in the secretion of Pulmonary surfactant which decreases the surface tension
within the alveoli. They are also capable of cellular division, giving rise to more type I alveolar
cells when the lung tissue is damaged. These cells are granular and roughly cuboidal. Type II
alveolar cells are typically found at the blood-air barrier Although they only comprise 5% of the
alveolar surface, they are relatively numerous (60% of alveolar epithelial cells)
Development:-
Type II cells start to develop at about 26 weeks of gestation, secreting small amounts of
surfactant. However, adequate amounts of surfactant are not secreted until about 35 weeks of
gestation - this is the main reason for increased rates of infant respiratory distress syndrome,
which drastically reduces at ages above 35 weeks gestation.
Functions-
Type II cells are responsible for the production and secretion of pulmonary surfactant (the
majority of which are dipalmitoyphosphatidylcholine), a group of phospholipids that reduce the
alveolar surface tension. Surfactant phospholipids are stored in type II alveolar cells in lamellar
bodies, which are specialized vesicles. Release of surfactant in lamellar bodies occurs from an
infant\'s first breath onwards.
Type II pneumocytes can replicate in the alveoli and will replicate to replace damaged type I
cells.
MUC1 a human gene associated with type II pneumocytes, has been identified as a marker in
lung cancer.
Give a detailed explanation and introduction to Polarization Microsc.pdf
Give a detailed explanation and introduction to Polarization Microscopy.
Solution
Polarized light microscopy
Polarized light is a contrast-enhancing technique that improves the quality of the image obtained
with birefringent materials when compared to other techniques such as darkfield and brightfield
illumination, differential interference contrast, phase contrast, Hoffman modulation contrast, and
fluorescence. Polarized light microscopes have a high degree of sensitivity and can be utilized
for both quantitative and qualitative studies targeted at a wide range of anisotropic specimens.
Qualitative polarizing microscopy is very popular in practice, with numerous volumes dedicated
to the subject. In contrast, the quantitative aspects of polarized light microscopy, which is
primarily employed in crystallography, represent a far more difficult subject that is usually
restricted to geologists, mineralogists, and chemists. However, steady advances made over the
past few years have enabled biologists to study the birefringent character of many anisotropic
sub-cellular assemblies.
The polarized light microscope is designed to observe and photograph specimens that are visible
primarily due to their optically anisotropic character. In order to accomplish this task, the
microscope must be equipped with both a polarizer, positioned in the light path somewhere
before the specimen, and an analyzer (a second polarizer, placed in the optical pathway between
the objective rear aperture and the observation tubes or camera port. Image contrast arises from
the interaction of plane-polarized light with a birefringent (or doubly-refracting) specimen to
produce two individual wave components that are each polarized in mutually perpendicular
planes. The velocities of these components, which are termed the ordinary and the extraordinary
wavefronts , are different and vary with the propagation direction through the specimen. After
exiting the specimen, the light components become out of phase, but are recombined with
constructive and destructive interference when they pass through the analyzer.
olarized light microscopy is capable of providing information on absorption color and optical
path boundaries between minerals of differing refractive indices, in a manner similar to
brightfield illumination, but the technique can also distinguish between isotropic and anisotropic
substances. Furthermore, the contrast-enhancing technique exploits the optical properties specific
to anisotropy and reveals detailed information concerning the structure and composition of
materials that are invaluable for identification and diagnostic purposes..
Fill in the Morphology column in the following table. Then use the in.pdf
Fill in the Morphology column in the following table. Then use the information to construct a
flowchart for these bacteria. Draw your flowchart in the box below the table.
Solution
ANSWER:
Clostridium - straight or slightly curved
Enterobacter - rod-shaped
Klebsiella - rod-shaped
Lactobacillus - rod shaped
Staphylococcus - round shaped
Streptococcus - pairs or chains.
Do you need to know the registers and flags in a computer architectur.pdf
Do you need to know the registers and flags in a computer architecture to write C programs?
Solution
Answer:
No,
Because C program is compiled by compiler, and we just define and use variable as many as we
want, and its duty of compiler to know about registers and flags like things, in short we don\'t
need to know about registers and flags while writing c program..
Discrete MathLet A be a set and P(A) be the power set of A. True .pdf
Discrete Math:
Let A be a set and P(A) be the power set of A. True or false with explanation
a. There is an injection from A to P(A).
b. There is a surjection from A to P(A).
Solution
Cardinality of power set P(A) is more than set A
a. Injection from A to P(A) is true as an element P(A) is connected with atmost one element of
A.
b.
Surjection from A to P(A) is false at there is elements in P(A) which are not connected with A..
Describe two mechanisms that contribute to anterior-posterior axis e.pdf
Describe two mechanisms that contribute to anterior-posterior axis elongation.
Solution
The anterior posterior axis elongation takes place by formation of primitive streak (PS).
Convergent extension (CE) movements by cell intercalation and epithelial-mesenchymal
transition (EMT) also contribute to anterior posterior axis elongation.Apart from this,Wnt
ligands such as Wnt 11 and Wnt 5a also contribute to anterior posterior elongation..
Create an implementation of a binary tree using the recursive appr.pdf
\"Create an implementation of a binary tree using the recursive approach introduced in the
chapter. In this approach, each node is a binary tree. Thus a binary tree contains a reference to
the element stored at its root as well as references to its left and right subtrees. You may also
want to include a reference to its parent.\" p.741
You need to use the locally implemented binary tree. This means you need to have a \"jsjf\"
subfolder with at least these files: BinaryTreeADT.java, LinkedBinaryTree.java,
BinaryTreeNode.java, and the exceptions sub-subfolder.
Test/demonstrate your binary tree by doing the following:
Request file name from user,
Read an infix expression from file,
Build binary expression tree,
Display binary expression tree,
Evaluate binary expression tree,
Display result.
##############################################
Note a typical input file can be found here
##############################################
# Version 0.2, fully parenthesized.
# This is a comment
((9 + 4) * 5) + (4 - (6 + 3))
# Note first expression should evaluate to 60
((42 + ( 10 - 2 )) + ( 5 * 3 )) / 6
# Note second expression should evaluate to 65 / 6 or 10 (integer division)
##############################################
My program is below but the out put is incorrect
##############################################
StringTree.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Iterator;
import java.util.Scanner;
import java.util.Stack;
import jsjf.BinaryTreeNode;
import jsjf.LinkedBinaryTree;
public class StringTree extends LinkedBinaryTree {
public StringTree(String rootStr, StringTree leftSubtree, StringTree rightSubtree) {
root = new BinaryTreeNode(rootStr, leftSubtree, rightSubtree);
} // StringTree
public StringTree(File f) {
Stack leftStack = new Stack(), rightStack = new Stack();
// stacks of left and right subtrees of nodes
Scanner scan;
// scanner for reading from the file
String nodeType,
nodeStr;
// string contained in the current node
boolean hasLeftChild, hasRightChild;
// true if the current node has a left or right child
StringTree leftSubtree, rightSubtree,
// left and right subtrees of the current node
subtree;
// subtree having the current node as its root
// Create a scanner for reading from the file.
try {
scan = new Scanner(f);
} catch (FileNotFoundException e) {
System.out.println(e.getMessage());
root = null;
System.out.println(\"\ \"+\"The program has terminated......\");
System.exit(0);
return;
}
// Read the file and build a tree from the bottom up.
while (scan.hasNext()) {
// Input information about a tree node.
nodeType = scan.next();
hasLeftChild = (scan.next().equalsIgnoreCase(\"y\"));
hasRightChild = (scan.next().equalsIgnoreCase(\"y\"));
nodeStr = scan.next();
// Determine the left and right subtrees of the subtree
// having the node as its root.
if (hasLeftChild)
leftSubtree = leftStack.pop();
else
leftSubtree = null;
if (hasRightChild)
rightSubtree = rightStack.pop();
else
rightSubtree = null;
.
A common symptom of pharyngitis is swelling of the anterior cervi.pdf
A common symptom of pharyngitis is swelling of the anterior cervical lymph nodes. Why might
lymph nodes swell in the presence of an infection? What else may cause swollen lymph nodes?
Explain why conditions that cause destruction of B lymphocytes and/or T lymphocytes cause
malfunctioning of both the specific and nonspecific immune responses.
Solution
Lymph node swelling occurs in infection because they dikter lymph whuch circulates in the body
through lymphatic system . Now whenever any foreign antigen enters into the body, rhe number
of white blood cells increase in response to that antigen. They attack bacteria, virus, whoever
enters into the body . And while this fighting occurs body makes more of these cells taht causes
swelling.
Lymph nodes directly come into contact with lot of germs inside the body, so they can get
swollen even then.
The other causes could be lymphoma tumour, cancer, tuberculosis, any problem with immune
system, leukemia etc
Inflammatory response occurs when tissues are attacked by pathogens such as virus, bacteria etc.
The damaged cells release chemicals such as bradykinin, prostaglandin, histamine, which cause
vessels to leak fluid into tissues causing swelling.
11. During an audit of a clients capital cycle, the auditor checks .pdf
11. During an audit of a client\'s capital cycle, the auditor checks whether preferred stock and
bonds are adequately backed by sinking funds. This procedure most likely is designed to achieve
the specific audit objective of a. existence. b. completeness. c. valuation and allocation. d.
understandability.
Solution.
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