Let Y be a nonempty topological space and let G be a filter on Y . W.pdf
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Let Y be a nonempty topological space and let G be a filter on Y . We say that the filter F converges to y 2 Y , and we write F ! y, if Ny µ F, where Ny is the collection of all the neighborhoods of y. (1) Prove that for all y 2 Y , Ny is a filter. (2) Prove that for all y 2 Y , Ny ! y. (3) Assume that Y is Hausdorff. Show that the limit of a filter on Y is unique. Solution.
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Find the total cost of making a triangular sail that has a base dime.pdf
Find the total cost of making a triangular sail that has a base dimension of 14 feet and a height of
30 feet if the price for making the sail is $17.50 per square foot.
Solution
Given that , height = 30
base = 14 , price of making the sail is 17.5 per square foot , so we need to calculate the total
surface area
so the area of the traiangle is given as 1/2 * base* height
= 0.5 * 14* 30 = 210 square foot
so total cost is calculated by multiplying the per square foot cost with the total area
210 * 17.5 = $3675.
Explain Charge, Current, Volta Power and Energy. Also explain relatio.pdf
Explain Charge, Current, Volta Power and Energy. Also explain relation between all of them.
Solution
CHARGE:
Electric charge is the physical property of matter that causes it to experience a force when placed
in an electromagnetic field. There are two types of electric charges: positive and negative. Like
charges repel and unlike attract. An object (one not made of antimatter) is negatively charged if
it has an excess of electrons, and is otherwise positively charged or uncharged. The SI derived
unit of electric charge is the coulomb (C). In electrical engineering, it is also common to use the
ampere-hour (Ah), and, in chemistry, it is common to use the elementary charge (e) as a unit.
The symbol Qoften denotes charge. Early knowledge of how charged substances interact is now
called classical electrodynamics, and is still accurate for problems that don\'t require
consideration of quantum effects.
CURRENT:
An electric current is a flow of electric charge. In electric circuits this charge is often carried by
moving electrons in a wire. It can also be carried by ions in an electrolyte, or by both ions and
electrons such as in a plasma.
The SI unit for measuring an electric current is the ampere, which is the flow of electric charge
across a surface at the rate of one coulomb per second. Electric current is measured using a
device called an ammeter.
Electric currents cause Joule heating, which creates light in incandescent light bulbs. They also
create magnetic fields, which are used in motors, inductors and generators.
The particles that carry the charge in an electric current are called charge carriers. In metals, one
or more electrons from each atom are loosely bound to the atom, and can move freely about
within the metal. These conduction electrons are the charge carriers in metal conductors.
VOLTAGE
Voltage, electric potential difference, electric pressure or electric tension (formally denoted V or
U, but more often simply as V or U, for instance in the context of Ohm\'s or Kirchhoff\'s laws) is
the difference in electric potential energy between two points per unit electric charge. The
voltage between two points is equal to the work done per unit of charge against a static electric
field to move the test charge between two points and is measured in units of volts(a joule per
coulomb).
Voltage can be caused by static electric fields, by electric current through a magnetic field, by
time-varying magnetic fields, or some combination of these three. A voltmeter can be used to
measure the voltage (or potential difference) between two points in a system; often a common
reference potential such as the ground of the system is used as one of the points. A voltage may
represent either a source of energy (electromotive force), or lost, used, or stored energy (potential
drop).
POWER:
Electric power is the rate at which electrical energy is transferred by an electric circuit. The SI
unit of power is the watt, one joule per second. Electric power is usua.
Define Managerial Accounting. Why do managers utilize managerial acc.pdf
Define Managerial Accounting. Why do managers utilize managerial accounting?
Solution
Managerial accounting is the planned process of collecting, processing, analyzing, interpreting
and presenting accounting and other information for the purpose of aiding decision making.
Managers utilize managerial accounting so that they can take decisions based on relevant data
analyzed properly..
Describe how a third-generation language (3GL) programming language .pdf
Describe how a third-generation language (3GL) programming language is used in conjunction
with SQL to develop database applications.
Solution
Conjunction of third generation languages with SQL for developing database applications:
There are different alternative of languages that can be used for developing database applications
along with the SQL such C,C++,Java, COBOL, Python and etc. These are known as third
generation languages. All these languages contain the functionality of the databases. Developers
choose the language which is most suitable for the task. A series of pre-compilers are provided
by Oracle to set in SQL or PL/SQL with any language such as C/C++,Java and etc.
Oracle call interface(OCI):
a. It is an Application Program Interface(API) that helps create applications that use function
calls of some third generation language for accessing database of oracle along with controlling
different phases of SQL statement for execution. OCI supports datatypes ,conversions, syntax
and etc.
b. It provides consistent interfaces and authentication ,access to external databases.
Manipulation of data and schemas is done through the conjunction of C and SQL .
Oracle C++ Call Interface(OCCI):
1. It lets the object-oriented features,native classes and various methods of C++ programming
language to access the database.
2. It is also used on the JDBC interface through integration to achieve higher performance.
3. Using this access to database is provided for SQL as these are run on the server to
run,create and manipulate.
4. They can access arrays,references and various objects.
5. To lock ,delete and flush objects,the navidational interface is used.
Oracle type translator(OTT):
1. This generates C language structures automatically through it’s declarations for object
types.
2. It provides C++ classes to the pre-compiler to the server to access package.
Pro* C/C++ Precompiler:
1. This lets the SQL statements to be embedded in high-level program.It takes in the input and
translates the embedded SQL statements into Oracle run-time library calls to generate a program
which can compile and run normally.
2. It embeds SQL statements in C or C++ as input and outputs a C/C++ file that replaces the
embedded SQL statements.
3. Automatic type conversion takes place from database type to C.
4. Using the EXEC SQL syntax,it destroys objects ..
Biologists have very specific terminology (thats one of the things.pdf
Biologists have very specific terminology (that\'s one of the things that makes Biology a difficult
science to learn--it\'s a foreign language). The fact that we have two different terms--(1)
evolution and (2) natural selection--implies that these two terms mean different things. What is
the definition of evolution (according to biologists)? What is the definition of natural selection?
How are these two concepts related to one another? 100 words or more please
Solution
Definition : -.
Bacteria Characteristics Indole oxidase VP Cell Catalase reaction Sha.pdf
Bacteria Characteristics Indole oxidase VP Cell Catalase reaction Shape or Classification or or
organism Alcaligenes Klebsiella axtoca Facultative anaerobe Streptococcus Staphylococcus
epidermidis Kocuria rhizophila Facultative anaerobe Bacillus subtilis
Solution
ANS: Bacteria Characteristics:
1. Alcaligenes faecalis:
Gram negative
Rod shape
Catalase Positive
Obligate aerobe
Indole negative
Oxidase positive
Found in humid areas of hospital
2. Enterobacter aerogenes:
Gram negative
Rod shape
Catalase Positive
Facultative anaerobe
Indole negative
Oxidase negative
Voges proskauer (VP) Negative
Found in human gastro intestinal tract
3. Escherichia coli
Gram negative
Rod shape
Catalase Positive
facultative anaerobe
Indole Positive
Oxidase negative
Voges proskauer (VP) Negative
Found in human intestine
4. Klebsiella oxytoca
Gram negative
Rod shape
Catalase Positive
Facultative anaerobe
Indole Positive
Oxidase negative
Voges proskauer (VP) Positive
Found as plant host.
5. Streptococcus mutans
Gram positive
Round bacteria
Catalase negative
Facultative anaerobe
Found in tooth decay
6. Staphylococcus epidermidis
Gram positive
arranged as grape like cluster
Catalase Positive
Facultative anaerobe
Found in skin flora.
7. Kocuria rhizophila
Gram positive
Cocci shaped
Catalase Positive
Facultative anaerobe
Found in soil
8. Bacillus subtilis
Gram positive
Cocci shaped
Catalase Positive
Rod shaped
Facultative anaerobe
Found in soil and gastrointestinal tract of human.
All of the following interactions can help hold the tertiary structur.pdf
All of the following interactions can help hold the tertiary structure of proteins together
EXCEPT: A. Hydrogen bonds Q B. ionic bonds C. Van der Waals forces D. Hydrophobic
Interactions E. Covalent bonds F. All of the above can help hold the tertiary structure of
proteins together
Solution
Hi,
Answer of above question is:
F. All of the above can help hold the Tertiary structure of proteins together.
Explanation:
I hope my answer is satisfactory.
Thanks!!.
According to the figure below, which of the following statements reg.pdf
According to the figure below, which of the following statements regarding endosymbiosis is
correct?
D) Both red algae and dinoflagellates have three different genomes in a single cell.A)
Cyanobacteria are a common ancestor of red and green algae.B) The red algae have two
genomes, while the apicomplexans will have three.C) A heterotrophic protist that engulfed a
green alga is the common ancestor of the euglenids and chlorarchiniophytes.
D) Both red algae and dinoflagellates have three different genomes in a single cell.
Part A According to the figure below, which of the following statements regarding
endosymbiosis is correct? Cyanobacteria are a common ancestor of red and green algae. The red
algae have two genomes, while the apicomplexans will have three. A heterotrophic protist that
engulfed a green alga is the common ancestor of the euglenids and chlorarchiniophytes. Both red
algae and dinoflagellates have three different genomes in a single cell Submit Hints My Answers
Give Up Review Part Provide Feedback Continue
Solution
(A) The chloroplasts of red algae, green algae, and plants evolved from an endosymbiotic
cyanobacterium living within a mitochondria-containing eukaryotic host cell. The evidence for
this theory is as follows-
(B) The unicellular red alga Cyanidioschyz lacks introns in all but 26 genes. There are only three
copies of ribosomal DNA units that maintain the nucleolus and two dynamin genes that are
involved only in the division of mitochondria and plastids. The Apicomplexa are a large phylum
of parasitic alveolates. Most of them possess a unique form of organelle that comprises a type of
plastid called an apicoplast, and an apical complex structure. Their nucleus is haploid. Hence B
is false.
(C) A protist is a eukaryotic organism that is not a fungus, plant or animal. Heterotrophic protists
decompose organic material, feed on smaller organims such as bacteria or live inside the bodies
of larger species. Euglenids are one of the best-known groups of flagellates, which are Excavate
Eukaryotes of the phylum Euglenophyta. They are commonly found in freshwater, especially
when it is rich in organic materials, with a few marine, and endosymbiotic members. Most
euglenids are unicellular. They have descended from an ancestor that took up green algae by
secondary endosymbiosis.
Chlorarachniophytes are unicellular marine algae with green chloroplasts surrounded by four
membranes,found in tropical oceans and are typically mixotrophic, ingesting bacteria and
smaller protists as well as conducting photosynthesis. A mixotroph is an organism that can use a
mix of different sources of energy and carbon, instead of having a single trophic mode on the
continuum from complete autotrophy at one end to heterotrophy at the other.The ancestor of
chlorarachniophytes is thought to have been a chromalveolate, a eukaryote with a red algal
derived chloroplast.
Hence C is false.
(D) Dinoflagellates are important marine primary producers.They are a lar.
Recommended
Find the total cost of making a triangular sail that has a base dime.pdf
Find the total cost of making a triangular sail that has a base dimension of 14 feet and a height of
30 feet if the price for making the sail is $17.50 per square foot.
Solution
Given that , height = 30
base = 14 , price of making the sail is 17.5 per square foot , so we need to calculate the total
surface area
so the area of the traiangle is given as 1/2 * base* height
= 0.5 * 14* 30 = 210 square foot
so total cost is calculated by multiplying the per square foot cost with the total area
210 * 17.5 = $3675.
Explain Charge, Current, Volta Power and Energy. Also explain relatio.pdf
Explain Charge, Current, Volta Power and Energy. Also explain relation between all of them.
Solution
CHARGE:
Electric charge is the physical property of matter that causes it to experience a force when placed
in an electromagnetic field. There are two types of electric charges: positive and negative. Like
charges repel and unlike attract. An object (one not made of antimatter) is negatively charged if
it has an excess of electrons, and is otherwise positively charged or uncharged. The SI derived
unit of electric charge is the coulomb (C). In electrical engineering, it is also common to use the
ampere-hour (Ah), and, in chemistry, it is common to use the elementary charge (e) as a unit.
The symbol Qoften denotes charge. Early knowledge of how charged substances interact is now
called classical electrodynamics, and is still accurate for problems that don\'t require
consideration of quantum effects.
CURRENT:
An electric current is a flow of electric charge. In electric circuits this charge is often carried by
moving electrons in a wire. It can also be carried by ions in an electrolyte, or by both ions and
electrons such as in a plasma.
The SI unit for measuring an electric current is the ampere, which is the flow of electric charge
across a surface at the rate of one coulomb per second. Electric current is measured using a
device called an ammeter.
Electric currents cause Joule heating, which creates light in incandescent light bulbs. They also
create magnetic fields, which are used in motors, inductors and generators.
The particles that carry the charge in an electric current are called charge carriers. In metals, one
or more electrons from each atom are loosely bound to the atom, and can move freely about
within the metal. These conduction electrons are the charge carriers in metal conductors.
VOLTAGE
Voltage, electric potential difference, electric pressure or electric tension (formally denoted V or
U, but more often simply as V or U, for instance in the context of Ohm\'s or Kirchhoff\'s laws) is
the difference in electric potential energy between two points per unit electric charge. The
voltage between two points is equal to the work done per unit of charge against a static electric
field to move the test charge between two points and is measured in units of volts(a joule per
coulomb).
Voltage can be caused by static electric fields, by electric current through a magnetic field, by
time-varying magnetic fields, or some combination of these three. A voltmeter can be used to
measure the voltage (or potential difference) between two points in a system; often a common
reference potential such as the ground of the system is used as one of the points. A voltage may
represent either a source of energy (electromotive force), or lost, used, or stored energy (potential
drop).
POWER:
Electric power is the rate at which electrical energy is transferred by an electric circuit. The SI
unit of power is the watt, one joule per second. Electric power is usua.
Define Managerial Accounting. Why do managers utilize managerial acc.pdf
Define Managerial Accounting. Why do managers utilize managerial accounting?
Solution
Managerial accounting is the planned process of collecting, processing, analyzing, interpreting
and presenting accounting and other information for the purpose of aiding decision making.
Managers utilize managerial accounting so that they can take decisions based on relevant data
analyzed properly..
Describe how a third-generation language (3GL) programming language .pdf
Describe how a third-generation language (3GL) programming language is used in conjunction
with SQL to develop database applications.
Solution
Conjunction of third generation languages with SQL for developing database applications:
There are different alternative of languages that can be used for developing database applications
along with the SQL such C,C++,Java, COBOL, Python and etc. These are known as third
generation languages. All these languages contain the functionality of the databases. Developers
choose the language which is most suitable for the task. A series of pre-compilers are provided
by Oracle to set in SQL or PL/SQL with any language such as C/C++,Java and etc.
Oracle call interface(OCI):
a. It is an Application Program Interface(API) that helps create applications that use function
calls of some third generation language for accessing database of oracle along with controlling
different phases of SQL statement for execution. OCI supports datatypes ,conversions, syntax
and etc.
b. It provides consistent interfaces and authentication ,access to external databases.
Manipulation of data and schemas is done through the conjunction of C and SQL .
Oracle C++ Call Interface(OCCI):
1. It lets the object-oriented features,native classes and various methods of C++ programming
language to access the database.
2. It is also used on the JDBC interface through integration to achieve higher performance.
3. Using this access to database is provided for SQL as these are run on the server to
run,create and manipulate.
4. They can access arrays,references and various objects.
5. To lock ,delete and flush objects,the navidational interface is used.
Oracle type translator(OTT):
1. This generates C language structures automatically through it’s declarations for object
types.
2. It provides C++ classes to the pre-compiler to the server to access package.
Pro* C/C++ Precompiler:
1. This lets the SQL statements to be embedded in high-level program.It takes in the input and
translates the embedded SQL statements into Oracle run-time library calls to generate a program
which can compile and run normally.
2. It embeds SQL statements in C or C++ as input and outputs a C/C++ file that replaces the
embedded SQL statements.
3. Automatic type conversion takes place from database type to C.
4. Using the EXEC SQL syntax,it destroys objects ..
Biologists have very specific terminology (thats one of the things.pdf
Biologists have very specific terminology (that\'s one of the things that makes Biology a difficult
science to learn--it\'s a foreign language). The fact that we have two different terms--(1)
evolution and (2) natural selection--implies that these two terms mean different things. What is
the definition of evolution (according to biologists)? What is the definition of natural selection?
How are these two concepts related to one another? 100 words or more please
Solution
Definition : -.
Bacteria Characteristics Indole oxidase VP Cell Catalase reaction Sha.pdf
Bacteria Characteristics Indole oxidase VP Cell Catalase reaction Shape or Classification or or
organism Alcaligenes Klebsiella axtoca Facultative anaerobe Streptococcus Staphylococcus
epidermidis Kocuria rhizophila Facultative anaerobe Bacillus subtilis
Solution
ANS: Bacteria Characteristics:
1. Alcaligenes faecalis:
Gram negative
Rod shape
Catalase Positive
Obligate aerobe
Indole negative
Oxidase positive
Found in humid areas of hospital
2. Enterobacter aerogenes:
Gram negative
Rod shape
Catalase Positive
Facultative anaerobe
Indole negative
Oxidase negative
Voges proskauer (VP) Negative
Found in human gastro intestinal tract
3. Escherichia coli
Gram negative
Rod shape
Catalase Positive
facultative anaerobe
Indole Positive
Oxidase negative
Voges proskauer (VP) Negative
Found in human intestine
4. Klebsiella oxytoca
Gram negative
Rod shape
Catalase Positive
Facultative anaerobe
Indole Positive
Oxidase negative
Voges proskauer (VP) Positive
Found as plant host.
5. Streptococcus mutans
Gram positive
Round bacteria
Catalase negative
Facultative anaerobe
Found in tooth decay
6. Staphylococcus epidermidis
Gram positive
arranged as grape like cluster
Catalase Positive
Facultative anaerobe
Found in skin flora.
7. Kocuria rhizophila
Gram positive
Cocci shaped
Catalase Positive
Facultative anaerobe
Found in soil
8. Bacillus subtilis
Gram positive
Cocci shaped
Catalase Positive
Rod shaped
Facultative anaerobe
Found in soil and gastrointestinal tract of human.
All of the following interactions can help hold the tertiary structur.pdf
All of the following interactions can help hold the tertiary structure of proteins together
EXCEPT: A. Hydrogen bonds Q B. ionic bonds C. Van der Waals forces D. Hydrophobic
Interactions E. Covalent bonds F. All of the above can help hold the tertiary structure of
proteins together
Solution
Hi,
Answer of above question is:
F. All of the above can help hold the Tertiary structure of proteins together.
Explanation:
I hope my answer is satisfactory.
Thanks!!.
According to the figure below, which of the following statements reg.pdf
According to the figure below, which of the following statements regarding endosymbiosis is
correct?
D) Both red algae and dinoflagellates have three different genomes in a single cell.A)
Cyanobacteria are a common ancestor of red and green algae.B) The red algae have two
genomes, while the apicomplexans will have three.C) A heterotrophic protist that engulfed a
green alga is the common ancestor of the euglenids and chlorarchiniophytes.
D) Both red algae and dinoflagellates have three different genomes in a single cell.
Part A According to the figure below, which of the following statements regarding
endosymbiosis is correct? Cyanobacteria are a common ancestor of red and green algae. The red
algae have two genomes, while the apicomplexans will have three. A heterotrophic protist that
engulfed a green alga is the common ancestor of the euglenids and chlorarchiniophytes. Both red
algae and dinoflagellates have three different genomes in a single cell Submit Hints My Answers
Give Up Review Part Provide Feedback Continue
Solution
(A) The chloroplasts of red algae, green algae, and plants evolved from an endosymbiotic
cyanobacterium living within a mitochondria-containing eukaryotic host cell. The evidence for
this theory is as follows-
(B) The unicellular red alga Cyanidioschyz lacks introns in all but 26 genes. There are only three
copies of ribosomal DNA units that maintain the nucleolus and two dynamin genes that are
involved only in the division of mitochondria and plastids. The Apicomplexa are a large phylum
of parasitic alveolates. Most of them possess a unique form of organelle that comprises a type of
plastid called an apicoplast, and an apical complex structure. Their nucleus is haploid. Hence B
is false.
(C) A protist is a eukaryotic organism that is not a fungus, plant or animal. Heterotrophic protists
decompose organic material, feed on smaller organims such as bacteria or live inside the bodies
of larger species. Euglenids are one of the best-known groups of flagellates, which are Excavate
Eukaryotes of the phylum Euglenophyta. They are commonly found in freshwater, especially
when it is rich in organic materials, with a few marine, and endosymbiotic members. Most
euglenids are unicellular. They have descended from an ancestor that took up green algae by
secondary endosymbiosis.
Chlorarachniophytes are unicellular marine algae with green chloroplasts surrounded by four
membranes,found in tropical oceans and are typically mixotrophic, ingesting bacteria and
smaller protists as well as conducting photosynthesis. A mixotroph is an organism that can use a
mix of different sources of energy and carbon, instead of having a single trophic mode on the
continuum from complete autotrophy at one end to heterotrophy at the other.The ancestor of
chlorarachniophytes is thought to have been a chromalveolate, a eukaryote with a red algal
derived chloroplast.
Hence C is false.
(D) Dinoflagellates are important marine primary producers.They are a lar.
3. A plant breeder crosses an inbred soybean cultivar with herbicide.pdf
3. A plant breeder crosses an inbred soybean cultivar with herbicide tolerance (recessive allele)
and susceptibility to a fungal pathogen (dominant allele) to an inbred soybean cultivar that is
susceptible to herbicides (dominant allele) but is resistant to the fungal pathogen (recessive
allele). The plant breeder generates F2 individuals and evaluates these individuals for herbicide
tolerance and resistance to the fungal pathogen. The plant breeder generates thousands of F2
individuals which he inbreeds to generate purelines. The plant breeder finds that almost every
plant that has herbicide tolerance is susceptible to the pathogen. What term is used to describe
this phenomenon?
A few of the F2 individuals described in question 3 are both herbicide tolerant and resistant to
the fungal pathogen. What likely happened to the DNA in these plants in order for this to occur?
Solution
The phenomenon produced can be termed as epistatis where herbicide tolerance (hh, recessive
allele) and susceptibility to a fungal pathogen (F(F/f),dominant allele) interact to show a mixed
Dominant recessive epistasis i.e The F along with h masked the susceptible to herbicides
(H,dominant allele) but is resistant to the fungal pathogen (ff, recessive allele). Therefore, most
of the offspings of F2 generation were showing herbicide tolerance is susceptible to the pathogen
F masked the effect of H .
The plans with ff only showed both herbicide tolerant and resistant to the fungal pathogen.The
DNA of these plants expressed the protein needed to express the reistant to fungal pathogen in
absence of F..
A mirror faces a cliff located some distance away. Mounted on the cli.pdf
A mirror faces a cliff located some distance away. Mounted on the cliff is a second mirror,
directly opposite the first mirror and facing toward it. A gun is fired very close to the first mirror.
The speed of sound is 343 m/s. How many times does the flash of the gunshot travel the round-
trip distance between the mirrors before the echo of the gunshot is heard
Solution
lets assume that echo is heard after t time. distance covered:
by light = 3*10^8 * t
by sound = 343*t
So, number of trips = 3*10^8/343 = 8.75*10^5.
Why is it important to identify Classes early in the Unified Process.pdf
Why is it important to identify Classes early in the Unified Process methodology?
Solution
it is also known as software development process which the development is done incrementally
in
step by step manner
=>classe plays main role in the unified process,because unified process uses object oreinted
techonology
for analysis and desing of the software architecture.but before doing this he want build classes
according to
the client requirement in the architecture design. if we do analysis and design with proper define
of classes
the whole architecture may get in to trouble.
A male Drosophila melanogaster has the genotype Aa; Bb; Cc; XDY..pdf
A male Drosophila melanogaster has the genotype A/a; B/b; C/c; XD/Y. How many different
sperm genotypes can it produce through meiosis of one single pre-gametic (2n) cell?
The answer is 16 but i dont understand how to get to that answer. Can someone explain?
Solution
16 different gametes are produced.
Formula-2^n
n is the number of heterozygous pairs =4.
Which of the following facilitated the endosymbiotic acquisition of .pdf
Which of the following facilitated the endosymbiotic acquisition of cyanobacteria that became
modern chloroplasts?
Question 1 options:
ability of eukaryotes to carry out endocytosis
similarity in biochemical pathways between chloroplasts and cyanobacteria
reduction of cyanobacterial genome size
conjugation between cyanobacteria and eukaryotic cell
ability of eukaryotes to carry out endocytosis
similarity in biochemical pathways between chloroplasts and cyanobacteria
reduction of cyanobacterial genome size
conjugation between cyanobacteria and eukaryotic cell
Solution
ability of eukaryotes to carry out endocytosis ....
as cyanobacteria was endocytosed in endosymbiotic way it turned to chloroplast over an
evolutionary time course .... this is called endosymbiontic theory.
Which of the following is true about replication The lagging s.pdf
Which of the following is true about replication?
The lagging strand is synthesized in a continuous fashion and the leading strand is not
Helicase unwinds RNA
Primases lay down the primers on the lagging strand
Topoisomerase unwinds DNA
Solution
The only correct statement among the four in the given question is \'Topoisomerase unwinds
DNA\'.
Explanation for others are; leading strand is synthesized in continuous fashion whereas lagging
strand is not, helicase unwinds DNA (which is double stranded) not the RNA (which is single
stranded), primases lay down the primers on both, the leading as well as the lagging strands..
Which is a common trait among all land plantsVascular tissues tra.pdf
Which is a common trait among all land plants?
Vascular tissues transport water and nutrients, and provide support
Seeds facilitate survival and dispersal of the species
Flowers facilitate cross-pollination
The embryo is protected within maternal tissues
The haploid phase of the life cycle is the dominant phase
Flowers facilitate cross-pollination
The embryo is protected within maternal tissues
The haploid phase of the life cycle is the dominant phase
Solution
First we see common traits of land plants and then see listed traits in details one by one:
1. Ability to withstand desiccation. Extant land plants have a cuticle and guard cells.
2. Ability to withstand the effects of more intense radiation, particularly DNA-damaging
radiation. Extant land plants have several compounds in their vacuoles that absorb UV. Since the
vacuole of a plant occupies most of a mature cell, this helps protect the DNA in other organelles.
3. Ability to protect their spores from desiccation. Early land plants have spores that are encased
in a sporopollenin wall. Sporopollenin is a very resistant polymer, resistant to UV and almost
everything including desiccation, squashing, etc. To remove sporopollenin from spores, one boils
them in a mixture of acetic and hydrochloric acid.
4. Ability to move solutions from the ground to portions of the plant that are not in contact with
the ground, and from the photosynthetic portions of the plant to non-photosynthetic portions.
Some land plants do this better than others.
5. Ability to support themselves. Aquatic plants float; terrestrial plants cannot do so. Most
terrestrial plants have lignin in some of their conducting cells. There is some debate as to
whether this was selected for by the advantages of growing tall or the need to protect against
embolism in the conducting cells. Since both are important, it seems most realistic to accept that
both contributed to the success of plants with the ability to manufacture lignin, the tracheophytes
or vascular plants.
6. Ability to acquire the carbon dioxide required for photosynthesis from the atmosphere. This
ability is associated with stomatal cells, specialized cells that surround openings (stomates) in the
outer cell layer of land plants.
Now we see Options given one by one:
Vascular tissues transport water and nutrients, and provide support
Transport of Water and Minerals:
The xylem tissue transports water and minerals. It consists of interconnected vessels and
tracheids organized into continuous conducting tubes stretching from the roots to the leaves.
These tubes carry water and minerals to all parts of the plant.
Plants absorb water from the soil through the root and transport it to the stem, leaves and
flowers. Roots have root hairs that are unicellular, thin-walled outgrowths of the epiblema (skin
of the root).
The root hairs are in close contact with the thin film of water surrounding the soil particles.
There are mineral salts such as nitrates, chlorides, sulphates, phos.
Which of the following is an example of company whose business model .pdf
Which of the following is an example of company whose business model is based on access to
large databases through the web? Fortune Facebook Cartner Microsoft 18M
Solution
Answer:
As we are alrready aware about the fact that Facebook features vedios , music , profiles with lot
of information supplied by almost 1.71 billion of users , their every information like : age , DOB
, marital stattus, bio and all . It maintains a huge database to manage all these information of
billion users..
what role(s) played by the Equatorial Segment Protein 1 (ESP1) durin.pdf
what role(s) played by the Equatorial Segment Protein 1 (ESP1) during fertilization.
Solution
The structure of a spermatozoa consists of three parts. They are,
Acrosome is the elongated head region of the sperm containing 2/3rd of the nucleus. The
enzymes present in the acrosome are essential for the penetration of a sperm into a secondary
oocyte (egg). The acrosomal layer necessary for the fusion and penetration into the oocyte is
deficient in mice lacking Equatorial Segment Protein 1 (ESP1). This indicates that ESP1 is
necessary for the development of \"fusion-competent sperm.\".
What are the similarities and differences between simple linear regr.pdf
What are the similarities and differences between simple linear regression analysis and multiple
regression analysis?
Solution
In statistics, linear regression models the relationship between a dependent variable and one or
more explanatory variables using a linear function. If two or more explanatory variables have a
linear relationship with the dependent variable, the regression is called a multiple linear
regression. Multiple regression, on the other hand, is a broader class of regressions that
encompasses linear and nonlinear regressions with multiple explanatory variables.
Regression analysis is a common way to discover a relationship between dependent and
explanatory variables. However, this statistical relationship does not mean that the explanatory
variables cause the dependent variable; it rather speaks of some significant association in the
data. Linear regression attempts to draw a line that comes closest to the data by finding the slope
and intercept that define the line and minimize regression errors. However, many relationships in
data do not follow a straight line, so statisticians use nonlinear regression instead.
It is rare that a dependent variable is explained by only one variable. In this case, an analyst uses
multiple regression, which attempts to explain dependent variable using more than one
independent variable. Multiple regressions can be linear and nonlinear..
What does it mean if a human female oocyte is no longer arrested in .pdf
What does it mean if a human female oocyte is no longer arrested in metaphase II of meiosis?
Solution
Answer:
Primary oocytes forms prenatally and remain suspended in prophase of meiosis I until it reaches
puberty. An oocyte completes meiosis I as its follicle matures resulting in a secondary oocyte
and the first polar body. After ovulation, each oocyte continues to meiosis II metaphase. Meiosis
II is completed only if fertilization occurs. This results in a fertilized mature ovum and the
second polar body.
Thus, the human female oocyte is arrested in metaphase II until fertilization by a sperm takes
place..
What is so important about the cells in the HeLo cell cultureWhat.pdf
What is so important about the cells in the HeLo cell culture?
What book was written about this person?
Solution
Ans. HeLa cells are cancerous cells isolated from cervical cancer biopsy sample of Henrieta
Lacks.
It is the most widely used human cell lines for research purpose in the field of drug testing (John
Salks tested polio vaccine on HeLa cells, 1950), cellular processes, mechanism of viral
pathogenesis, and almost all other aspects. It has benn distributed to every corner of the world.
Due to its extensive use, and its fast-growing (cancerous) nature, the cell line is also said to be
‘immortal.
The book on Her: \'The Immortal Henrietta Lacks\' by Rebecca Skloot.
What are the advantages and disadvantages to patients of increasing .pdf
What are the advantages and disadvantages to patients of increasing the number of physicians
who limit their activities to narrower fields of practice?
Solution
Advantage- physician can focus on the patient and diagnosed the problem properly.
Disadvantages- physicians can\'t interact with different varieties of case...... Can\'t practice on
different case.
Use the Limit definition to compute f(a) and find the equation of .pdf
Use the Limit definition to compute f\'(a) and find the equation of the tangent line for f(x) = x +
x^-1, a=4
Solution
f\'(x)= lim h approaches 0 of [f(x+h)- f(x)]/h So here we have ((x+h) + 1/(x+h) -x-
1/x )/h Simplifying and putting over a common denominator we have [h - h/x(x+h)]/h= 1 -
1/x(x+h) As h approaches 0 we have 1- 1/x^2 So f(4)= 1-1/16= 15/16 At (4, 17/4) we have 17/4
= 15/16 *4 +B B= 17/4-15/4= 2/4= 1/2 So equation of tanfent line is Y= 15/16 x +1/2.
under which condition would a cell membrane be most likely to be in .pdf
under which condition would a cell membrane be most likely to be in liquid, crystalline state, in
which an individual phospholipids can rotate around its axis or move laterally through the plane
of the bilayer
Solution
The cell membrane is critical to temperature. The membrane is stabilized at the lower
temperature and is in an ordered way. When the temperatures shoot up the membranes begin to
attain a fluid state and began to break up. The phospholipids are in the liquid crystalline state
specifically at the warm temperature such as at 37-degree Celcius..
Two numbers together add to 300. One number is twice the size of the.pdf
Two numbers together add to 300. One number is twice the size of the other. What are the two
numbers?
A. 25; 50
B. 50; 100
C. 75; 150
D. 100; 200
Solution
D. Set this up as an equation. A number plus 2 times that number is 300.
x + 2x = 300
Solve for x.
3x=300
X=100
So one number is 100 and the other is twice that, or 200..
The stockholders interest in a corporation is called O Liabilities.pdf
The stockholders\' interest in a corporation is called: O Liabilities O Dividends 0 Stockholders\'
equity. O Assets
Solution
The answer is stockholder\'s equity. Stockholder\'s equity basically represents the amount
invested by them in the company. It gives them right to receive dividends and right to vote in the
general meetings of the company. Thus they represent a stockholder\'s interest in any company
or corporation.
The other terms mentioned can be defined as follows:
LIABILITIES: These are the sums that are payable to external parties by a company like
creditors, banks, etc.
Dividend: This is the amount paid to the shareholders as return on their investment in the
company.
Assets: These are the physical assets, cash and other receivables owned by the company..
Suggest topics to write a term paper for Software Engineeering subje.pdf
Suggest topics to write a term paper for Software Engineeering subject.
Solution
The topic related to software engineering can be various phases of software engineering like
requirement gathering,development ,testing,maintainance.If we discuss testing then it involves
basically unit testing,system testing,user acceptance testing,regression testing and thus we can
explain testings like unit testing which is done individually,user acceptance testing which is done
at the end and system testing which is used to test all the modules in the system..
Standardize terminologies, i.e. Vocabularies, are used to represent c.pdf
Standardize terminologies, i.e. Vocabularies, are used to represent concepts and to communicate
them would include diagnoses, procedures, health status but not symptoms. A point-of-care
system may include order entry decision support systems? Which of the following would not be
considered a classification system a. ICD-10-CM b. MeHIMA c. SNOMED
Solution
1) False : Standardised teminologies creates a standard nominclature which help in
understanding concpets and communicates inluding diagonises, health status, symptoms,
procedure.
2) True : One of the feature of point of care system is computer physician order entries which
allows practicioner to input instructions and plans at system
3) MeHIMA is not a classification system.
15--The Securities and Exchange Commission’s (SEC’s) adoption of rul.pdf
15--The Securities and Exchange Commission’s (SEC’s) adoption of rules and regulations
relating to financial and other information furnished to the Commission comes under its ______
power.
A. quasi-judicial
B. federal
C. quasi-executive
D. quasi-legislative
E. bargaining
16 --Which of the following statements is true of an environmental impact statement (EIS)?
A. The National Environmental Policy Act requires federal agencies to follow the conclusions of
the EIS.
B. An EIS can be in any language as long as it is clear and to the point.
C. An EIS is to be included in every recommendation or report on proposals for legislation and
other major federal actions significantly affecting the quality of the human environment.
D. An EIS should include technical jargon to clearly explain all the points mentioned in the
statement.
E. The EIS is usually a short list of points that hints at the pros of the economic profits that are
outcomes of transactions concerning the human environment.
Solution
15) federal
16)
An EIS should include technical jargon to clearly explain all the points mentioned in the
statement ..
Bed Making ( Introduction, Purpose, Types, Articles, Scientific principles, N...
Topic : Bed making
Subject : Nursing Foundation
The History of Stoke Newington Street Names
Presented at the Stoke Newington Literary Festival on 9th June 2024
www.StokeNewingtonHistory.com
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3. A plant breeder crosses an inbred soybean cultivar with herbicide.pdf
3. A plant breeder crosses an inbred soybean cultivar with herbicide tolerance (recessive allele)
and susceptibility to a fungal pathogen (dominant allele) to an inbred soybean cultivar that is
susceptible to herbicides (dominant allele) but is resistant to the fungal pathogen (recessive
allele). The plant breeder generates F2 individuals and evaluates these individuals for herbicide
tolerance and resistance to the fungal pathogen. The plant breeder generates thousands of F2
individuals which he inbreeds to generate purelines. The plant breeder finds that almost every
plant that has herbicide tolerance is susceptible to the pathogen. What term is used to describe
this phenomenon?
A few of the F2 individuals described in question 3 are both herbicide tolerant and resistant to
the fungal pathogen. What likely happened to the DNA in these plants in order for this to occur?
Solution
The phenomenon produced can be termed as epistatis where herbicide tolerance (hh, recessive
allele) and susceptibility to a fungal pathogen (F(F/f),dominant allele) interact to show a mixed
Dominant recessive epistasis i.e The F along with h masked the susceptible to herbicides
(H,dominant allele) but is resistant to the fungal pathogen (ff, recessive allele). Therefore, most
of the offspings of F2 generation were showing herbicide tolerance is susceptible to the pathogen
F masked the effect of H .
The plans with ff only showed both herbicide tolerant and resistant to the fungal pathogen.The
DNA of these plants expressed the protein needed to express the reistant to fungal pathogen in
absence of F..
A mirror faces a cliff located some distance away. Mounted on the cli.pdf
A mirror faces a cliff located some distance away. Mounted on the cliff is a second mirror,
directly opposite the first mirror and facing toward it. A gun is fired very close to the first mirror.
The speed of sound is 343 m/s. How many times does the flash of the gunshot travel the round-
trip distance between the mirrors before the echo of the gunshot is heard
Solution
lets assume that echo is heard after t time. distance covered:
by light = 3*10^8 * t
by sound = 343*t
So, number of trips = 3*10^8/343 = 8.75*10^5.
Why is it important to identify Classes early in the Unified Process.pdf
Why is it important to identify Classes early in the Unified Process methodology?
Solution
it is also known as software development process which the development is done incrementally
in
step by step manner
=>classe plays main role in the unified process,because unified process uses object oreinted
techonology
for analysis and desing of the software architecture.but before doing this he want build classes
according to
the client requirement in the architecture design. if we do analysis and design with proper define
of classes
the whole architecture may get in to trouble.
A male Drosophila melanogaster has the genotype Aa; Bb; Cc; XDY..pdf
A male Drosophila melanogaster has the genotype A/a; B/b; C/c; XD/Y. How many different
sperm genotypes can it produce through meiosis of one single pre-gametic (2n) cell?
The answer is 16 but i dont understand how to get to that answer. Can someone explain?
Solution
16 different gametes are produced.
Formula-2^n
n is the number of heterozygous pairs =4.
Which of the following facilitated the endosymbiotic acquisition of .pdf
Which of the following facilitated the endosymbiotic acquisition of cyanobacteria that became
modern chloroplasts?
Question 1 options:
ability of eukaryotes to carry out endocytosis
similarity in biochemical pathways between chloroplasts and cyanobacteria
reduction of cyanobacterial genome size
conjugation between cyanobacteria and eukaryotic cell
ability of eukaryotes to carry out endocytosis
similarity in biochemical pathways between chloroplasts and cyanobacteria
reduction of cyanobacterial genome size
conjugation between cyanobacteria and eukaryotic cell
Solution
ability of eukaryotes to carry out endocytosis ....
as cyanobacteria was endocytosed in endosymbiotic way it turned to chloroplast over an
evolutionary time course .... this is called endosymbiontic theory.
Which of the following is true about replication The lagging s.pdf
Which of the following is true about replication?
The lagging strand is synthesized in a continuous fashion and the leading strand is not
Helicase unwinds RNA
Primases lay down the primers on the lagging strand
Topoisomerase unwinds DNA
Solution
The only correct statement among the four in the given question is \'Topoisomerase unwinds
DNA\'.
Explanation for others are; leading strand is synthesized in continuous fashion whereas lagging
strand is not, helicase unwinds DNA (which is double stranded) not the RNA (which is single
stranded), primases lay down the primers on both, the leading as well as the lagging strands..
Which is a common trait among all land plantsVascular tissues tra.pdf
Which is a common trait among all land plants?
Vascular tissues transport water and nutrients, and provide support
Seeds facilitate survival and dispersal of the species
Flowers facilitate cross-pollination
The embryo is protected within maternal tissues
The haploid phase of the life cycle is the dominant phase
Flowers facilitate cross-pollination
The embryo is protected within maternal tissues
The haploid phase of the life cycle is the dominant phase
Solution
First we see common traits of land plants and then see listed traits in details one by one:
1. Ability to withstand desiccation. Extant land plants have a cuticle and guard cells.
2. Ability to withstand the effects of more intense radiation, particularly DNA-damaging
radiation. Extant land plants have several compounds in their vacuoles that absorb UV. Since the
vacuole of a plant occupies most of a mature cell, this helps protect the DNA in other organelles.
3. Ability to protect their spores from desiccation. Early land plants have spores that are encased
in a sporopollenin wall. Sporopollenin is a very resistant polymer, resistant to UV and almost
everything including desiccation, squashing, etc. To remove sporopollenin from spores, one boils
them in a mixture of acetic and hydrochloric acid.
4. Ability to move solutions from the ground to portions of the plant that are not in contact with
the ground, and from the photosynthetic portions of the plant to non-photosynthetic portions.
Some land plants do this better than others.
5. Ability to support themselves. Aquatic plants float; terrestrial plants cannot do so. Most
terrestrial plants have lignin in some of their conducting cells. There is some debate as to
whether this was selected for by the advantages of growing tall or the need to protect against
embolism in the conducting cells. Since both are important, it seems most realistic to accept that
both contributed to the success of plants with the ability to manufacture lignin, the tracheophytes
or vascular plants.
6. Ability to acquire the carbon dioxide required for photosynthesis from the atmosphere. This
ability is associated with stomatal cells, specialized cells that surround openings (stomates) in the
outer cell layer of land plants.
Now we see Options given one by one:
Vascular tissues transport water and nutrients, and provide support
Transport of Water and Minerals:
The xylem tissue transports water and minerals. It consists of interconnected vessels and
tracheids organized into continuous conducting tubes stretching from the roots to the leaves.
These tubes carry water and minerals to all parts of the plant.
Plants absorb water from the soil through the root and transport it to the stem, leaves and
flowers. Roots have root hairs that are unicellular, thin-walled outgrowths of the epiblema (skin
of the root).
The root hairs are in close contact with the thin film of water surrounding the soil particles.
There are mineral salts such as nitrates, chlorides, sulphates, phos.
Which of the following is an example of company whose business model .pdf
Which of the following is an example of company whose business model is based on access to
large databases through the web? Fortune Facebook Cartner Microsoft 18M
Solution
Answer:
As we are alrready aware about the fact that Facebook features vedios , music , profiles with lot
of information supplied by almost 1.71 billion of users , their every information like : age , DOB
, marital stattus, bio and all . It maintains a huge database to manage all these information of
billion users..
what role(s) played by the Equatorial Segment Protein 1 (ESP1) durin.pdf
what role(s) played by the Equatorial Segment Protein 1 (ESP1) during fertilization.
Solution
The structure of a spermatozoa consists of three parts. They are,
Acrosome is the elongated head region of the sperm containing 2/3rd of the nucleus. The
enzymes present in the acrosome are essential for the penetration of a sperm into a secondary
oocyte (egg). The acrosomal layer necessary for the fusion and penetration into the oocyte is
deficient in mice lacking Equatorial Segment Protein 1 (ESP1). This indicates that ESP1 is
necessary for the development of \"fusion-competent sperm.\".
What are the similarities and differences between simple linear regr.pdf
What are the similarities and differences between simple linear regression analysis and multiple
regression analysis?
Solution
In statistics, linear regression models the relationship between a dependent variable and one or
more explanatory variables using a linear function. If two or more explanatory variables have a
linear relationship with the dependent variable, the regression is called a multiple linear
regression. Multiple regression, on the other hand, is a broader class of regressions that
encompasses linear and nonlinear regressions with multiple explanatory variables.
Regression analysis is a common way to discover a relationship between dependent and
explanatory variables. However, this statistical relationship does not mean that the explanatory
variables cause the dependent variable; it rather speaks of some significant association in the
data. Linear regression attempts to draw a line that comes closest to the data by finding the slope
and intercept that define the line and minimize regression errors. However, many relationships in
data do not follow a straight line, so statisticians use nonlinear regression instead.
It is rare that a dependent variable is explained by only one variable. In this case, an analyst uses
multiple regression, which attempts to explain dependent variable using more than one
independent variable. Multiple regressions can be linear and nonlinear..
What does it mean if a human female oocyte is no longer arrested in .pdf
What does it mean if a human female oocyte is no longer arrested in metaphase II of meiosis?
Solution
Answer:
Primary oocytes forms prenatally and remain suspended in prophase of meiosis I until it reaches
puberty. An oocyte completes meiosis I as its follicle matures resulting in a secondary oocyte
and the first polar body. After ovulation, each oocyte continues to meiosis II metaphase. Meiosis
II is completed only if fertilization occurs. This results in a fertilized mature ovum and the
second polar body.
Thus, the human female oocyte is arrested in metaphase II until fertilization by a sperm takes
place..
What is so important about the cells in the HeLo cell cultureWhat.pdf
What is so important about the cells in the HeLo cell culture?
What book was written about this person?
Solution
Ans. HeLa cells are cancerous cells isolated from cervical cancer biopsy sample of Henrieta
Lacks.
It is the most widely used human cell lines for research purpose in the field of drug testing (John
Salks tested polio vaccine on HeLa cells, 1950), cellular processes, mechanism of viral
pathogenesis, and almost all other aspects. It has benn distributed to every corner of the world.
Due to its extensive use, and its fast-growing (cancerous) nature, the cell line is also said to be
‘immortal.
The book on Her: \'The Immortal Henrietta Lacks\' by Rebecca Skloot.
What are the advantages and disadvantages to patients of increasing .pdf
What are the advantages and disadvantages to patients of increasing the number of physicians
who limit their activities to narrower fields of practice?
Solution
Advantage- physician can focus on the patient and diagnosed the problem properly.
Disadvantages- physicians can\'t interact with different varieties of case...... Can\'t practice on
different case.
Use the Limit definition to compute f(a) and find the equation of .pdf
Use the Limit definition to compute f\'(a) and find the equation of the tangent line for f(x) = x +
x^-1, a=4
Solution
f\'(x)= lim h approaches 0 of [f(x+h)- f(x)]/h So here we have ((x+h) + 1/(x+h) -x-
1/x )/h Simplifying and putting over a common denominator we have [h - h/x(x+h)]/h= 1 -
1/x(x+h) As h approaches 0 we have 1- 1/x^2 So f(4)= 1-1/16= 15/16 At (4, 17/4) we have 17/4
= 15/16 *4 +B B= 17/4-15/4= 2/4= 1/2 So equation of tanfent line is Y= 15/16 x +1/2.
under which condition would a cell membrane be most likely to be in .pdf
under which condition would a cell membrane be most likely to be in liquid, crystalline state, in
which an individual phospholipids can rotate around its axis or move laterally through the plane
of the bilayer
Solution
The cell membrane is critical to temperature. The membrane is stabilized at the lower
temperature and is in an ordered way. When the temperatures shoot up the membranes begin to
attain a fluid state and began to break up. The phospholipids are in the liquid crystalline state
specifically at the warm temperature such as at 37-degree Celcius..
Two numbers together add to 300. One number is twice the size of the.pdf
Two numbers together add to 300. One number is twice the size of the other. What are the two
numbers?
A. 25; 50
B. 50; 100
C. 75; 150
D. 100; 200
Solution
D. Set this up as an equation. A number plus 2 times that number is 300.
x + 2x = 300
Solve for x.
3x=300
X=100
So one number is 100 and the other is twice that, or 200..
The stockholders interest in a corporation is called O Liabilities.pdf
The stockholders\' interest in a corporation is called: O Liabilities O Dividends 0 Stockholders\'
equity. O Assets
Solution
The answer is stockholder\'s equity. Stockholder\'s equity basically represents the amount
invested by them in the company. It gives them right to receive dividends and right to vote in the
general meetings of the company. Thus they represent a stockholder\'s interest in any company
or corporation.
The other terms mentioned can be defined as follows:
LIABILITIES: These are the sums that are payable to external parties by a company like
creditors, banks, etc.
Dividend: This is the amount paid to the shareholders as return on their investment in the
company.
Assets: These are the physical assets, cash and other receivables owned by the company..
Suggest topics to write a term paper for Software Engineeering subje.pdf
Suggest topics to write a term paper for Software Engineeering subject.
Solution
The topic related to software engineering can be various phases of software engineering like
requirement gathering,development ,testing,maintainance.If we discuss testing then it involves
basically unit testing,system testing,user acceptance testing,regression testing and thus we can
explain testings like unit testing which is done individually,user acceptance testing which is done
at the end and system testing which is used to test all the modules in the system..
Standardize terminologies, i.e. Vocabularies, are used to represent c.pdf
Standardize terminologies, i.e. Vocabularies, are used to represent concepts and to communicate
them would include diagnoses, procedures, health status but not symptoms. A point-of-care
system may include order entry decision support systems? Which of the following would not be
considered a classification system a. ICD-10-CM b. MeHIMA c. SNOMED
Solution
1) False : Standardised teminologies creates a standard nominclature which help in
understanding concpets and communicates inluding diagonises, health status, symptoms,
procedure.
2) True : One of the feature of point of care system is computer physician order entries which
allows practicioner to input instructions and plans at system
3) MeHIMA is not a classification system.
15--The Securities and Exchange Commission’s (SEC’s) adoption of rul.pdf
15--The Securities and Exchange Commission’s (SEC’s) adoption of rules and regulations
relating to financial and other information furnished to the Commission comes under its ______
power.
A. quasi-judicial
B. federal
C. quasi-executive
D. quasi-legislative
E. bargaining
16 --Which of the following statements is true of an environmental impact statement (EIS)?
A. The National Environmental Policy Act requires federal agencies to follow the conclusions of
the EIS.
B. An EIS can be in any language as long as it is clear and to the point.
C. An EIS is to be included in every recommendation or report on proposals for legislation and
other major federal actions significantly affecting the quality of the human environment.
D. An EIS should include technical jargon to clearly explain all the points mentioned in the
statement.
E. The EIS is usually a short list of points that hints at the pros of the economic profits that are
outcomes of transactions concerning the human environment.
Solution
15) federal
16)
An EIS should include technical jargon to clearly explain all the points mentioned in the
statement ..
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