#include stdio.hint main() { int count; FILE myFi.pdf
•
0 likes•7 views
#include int main() { int count; FILE *myFile; myFile = fopen(\"input.txt\",\"r\"); long numbers[8]; int i; for(i=0;i<8;i++) { fscanf(myFile,\"%ld\",&numbers[i]); } for (i=0;i<8;i++) { printf(\"Number is: %ld\ \ \", numbers[i]); } for(i=0;i<8;i++) { count=0; //initialize count=0 for every integer while(numbers[i]!=0) { numbers[i] /= 10; // number[i] = number[i]/10 ++count; } printf(\"Number of digits in numbers[%d] is %d\ \",i,count); } return 0; } Output Number is: 7 Number is: 7 Number is: 5 Number is: 6 Number is:7 Number is: 43 Number is: 444 Number is: 8 Number of digits in numbers[0] is 1 Number of digits in numbers[1] is 1 Number of digits in numbers[2] is 1 Number of digits in numbers[3] is 1 Number of digits in numbers[4] is 1 Number of digits in numbers[5] is 2 Number of digits in numbers[6] is 3 Number of digits in numbers[7] is 1 Solution #include int main() { int count; FILE *myFile; myFile = fopen(\"input.txt\",\"r\"); long numbers[8]; int i; for(i=0;i<8;i++) { fscanf(myFile,\"%ld\",&numbers[i]); } for (i=0;i<8;i++) { printf(\"Number is: %ld\ \ \", numbers[i]); } for(i=0;i<8;i++) { count=0; //initialize count=0 for every integer while(numbers[i]!=0) { numbers[i] /= 10; // number[i] = number[i]/10 ++count; } printf(\"Number of digits in numbers[%d] is %d\ \",i,count); } return 0; } Output Number is: 7 Number is: 7 Number is: 5 Number is: 6 Number is:7 Number is: 43 Number is: 444 Number is: 8 Number of digits in numbers[0] is 1 Number of digits in numbers[1] is 1 Number of digits in numbers[2] is 1 Number of digits in numbers[3] is 1 Number of digits in numbers[4] is 1 Number of digits in numbers[5] is 2 Number of digits in numbers[6] is 3 Number of digits in numbers[7] is 1.
Report
Share
Report
Share
Download to read offline
![#include
int main()
{
int count;
FILE *myFile;
myFile = fopen("input.txt","r");
long numbers[8];
int i;
for(i=0;i<8;i++)
{
fscanf(myFile,"%ld",&numbers[i]);
}
for (i=0;i<8;i++)
{
printf("Number is: %ld ", numbers[i]);
}
for(i=0;i<8;i++)
{
count=0; //initialize count=0 for every integer
while(numbers[i]!=0)
{
numbers[i] /= 10; // number[i] = number[i]/10
++count;
}
printf("Number of digits in numbers[%d] is %d ",i,count);
}
return 0;
}
Output
Number is: 7](https://image.slidesharecdn.com/includestdio-230409025540-6fdb6404/85/include-stdio-hint-main-int-count-FILE-myFi-pdf-1-320.jpg)
![Number is: 7
Number is: 5
Number is: 6
Number
is:7
Number is:
43
Number is:
444
Number is:
8
Number of digits in numbers[0]
is 1
Number of digits in numbers[1]
is 1
Number of digits in numbers[2]
is 1
Number of digits in numbers[3]
is 1
Number of digits in numbers[4]
is 1
Number of digits in numbers[5]
is 2
Number of digits in numbers[6]](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
#include iostream #include fstream #include map #include.pdf
#include
#include
#include
#include
#include
using namespace std;
//Used from
int index_of_largest(const int array[], int startIndex, const int size);
void selectSort(int a[], const int size);
void swap(int& i1, int& it2);
void fileOption();
void inputOption();
void unique(const int inputArray[], int uniqueArray[], int countArray[], const int size);
void printFileScreen(const int uniqueArray[], const int countArray[], const int size);
int main()
{
// int size;
char userInput[5];
//
cout << \"Read file from Input file? (Y/N) \";
cin >> userInput;
if(toupper(userInput[0]) == \'Y\')
{
fileOption();
}
else
{
inputOption();
}
return 0;
}
void selectSort(int array[], const int size)
{
int smallestIndex;
for(int i = 0;i < size - 1;i++)
{
smallestIndex = index_of_largest(array , i , size);
swap(array[i] , array[smallestIndex]);
}
}
void swap(int& i1, int& i2)
{
int temp;
temp = i1;
i1 = i2;
i2 = temp;
}
int index_of_largest(const int array[], int startIndex, const int size)
{
int min = array[startIndex] , index_of_min = startIndex;
for(int i = startIndex + 1;i < size;i++)
if(array[i] > min)
{
min = array[i];
index_of_min = i;
}
return index_of_min;
}
void unique(const int inputArray[], int uniqueArray[], int countArray[], const int size)
{
int number;
int j = 0;
int index;
for(int i = 0;i < size;i++)
{
int flag = 0;
number = inputArray[i];
//for each element in inputArray, check if it is there in uniqueArray
for (int k = 0; k < j; ++k)
{
if(number == uniqueArray[k])
{
flag = 1;
index = k;
}
}
if(flag == 0)
{
//if so, increment the countArray by 1
countArray[j]++;
// copy the element to uniqueArray
uniqueArray[j] = number;
j++;
}
else
countArray[index]++;
}
}
void fileOption()
{
int inputArray[50];
int countArray[50] = {0};
int uniqueArray[50]= {0};
ifstream in_stream;
char fileName[16];
cout << \"What file would you like to obtain input from? \";
cin >> fileName;
in_stream.open(fileName);
if(in_stream.fail())
{
cout << \"Error: Could not open file!\" << endl;
exit(1);
}
int size = 0;
while(in_stream >> inputArray[size])
{
size++;
}
selectSort(inputArray , size);
unique(inputArray , uniqueArray , countArray , size);
printFileScreen(uniqueArray , countArray , size);
}
void inputOption()
{
int inputArray[50];
int countArray[50] = {0};
int uniqueArray[50] = {0};
int size;
cout << \"How many numbers would you like to enter? \";
cin >> size;
cout << \"Enter numbers:\" << endl;
for(int i = 0;i < size;i++)
{
cin >> inputArray[i];
}
selectSort(inputArray , size);
unique(inputArray , uniqueArray , countArray , size);
printFileScreen(uniqueArray , countArray , size);
}
void printFileScreen(const int uniqueArray[], const int countArray[], const int size)
{
//cout << \"jaja\";
ofstream output_file;
output_file.open(\"lab3Exercise2.txt\");
if(output_file.fail())
{
cout << \"Error: Could not open file!\" << endl;
exit(1);
}
output_file << \"N\\t\" << \"count\ \";
for(int i = 0;i < size;i++)
{
if(uniqueArray[i] != 0)
{
output_file << uniqueArray[i] << \"\\t\";
outpu.
C-Program Custom Library, Header File, and Implementation FilesI .pdf
C-Program: Custom Library, Header File, and Implementation Files
I have this main.c file:
#include
#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
{
///Declare Variables
char fileName[30];
float grades[1000]; //to store grades
int i, ArrayCount[10] = {0}; //to store histogram counts
/* Rewrite this line */
int num_grades; //for # of grades in file
///Call Intro Comment
WelcomeToTheProgram();
///Enter Filename
printf(\"\ \ \ Enter the data filename: \");
scanf(\"%s\", &fileName);
//Get # of grades in file
num_grades = readGrades(fileName, grades); //get # of grades in file
///Print Results
printf(\"There are %d grades read\ \", num_grades);
printf(\"Mean = %f\ \", mean(grades, num_grades));
printf(\"Variance = %f \ \", variance(grades, num_grades));
printf(\"Maximum = %f \ \", maximum(grades, num_grades));
printf(\"Minumum = %f \ \", minimum(grades, num_grades));
//Call histogram
histogram(grades, ArrayCount, num_grades);
//Print the histogram
printf(\"Grade Histogram\ \");
for (i = 0; i < 10; i++)
{
if (i != 9)
{
printf(\"\ %d %% - %d %%: %d \", i * 10, ((i + 1) * 10) - 1, ArrayCount[i]);
}
else
{
printf(\"\ 90 %% - 100 %%: %d\ \", ArrayCount[i]);
}
}
return 0;
}
///Reads all grades from the file to array
int readGrades(char fileName[], float grades[])
{
FILE *fpin = fopen(fileName, \"r\");
int num_scores = 0;
float value;
if (fpin == NULL)
{
printf(\"Cannot open the file\ \");
exit(0);
}
while ((fscanf(fpin, \"%f\", &value)) != EOF)
{
grades[num_scores] = value;
num_scores++;
}
return num_scores;
}
void WelcomeToTheProgram()
{
printf(\"***Welcome to the Program Which Involves a Custom Library***\");
printf(\"\ The program finds the minimum value, maximum value, mean,\");
printf(\"variance, and a histogram of the grades of data by calling\");
printf(\"implementation files min(), max(), mean(), variance(), and histogram().\ \");
}
But, the only thing that prints is
Enter the data file name: grades.txt
There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
//stats.h
#ifndef STATS_H
#define STATS_H
float minimum(float grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
void histogram(float grades[], int ArrayCount[], int S.
PROVIDE COMMENTS TO FELLOW STUDENTS ANSWERS AND PLEASE DON’T SAY G.docx
PROVIDE COMMENTS TO FELLOW STUDENTS ANSWERS AND PLEASE DON’T SAY GOOD WORK NICE FORMULA OR SOMETHING LIKE THAT, BUT ACTULLY HE CAN USE. THANK YOU.
Hartleys Function Code
Contains unread posts
Actions for Hartleys Function Code
Chad Hartley posted Nov 5, 2015 5:10 PM
Subscribe
This program will add an integer number and a decimal number up to 2 decimal places. I have included notes in the code to explain what each thing does. I hope I did this right. It compiles successfully.
PseudoCode
Start
Declare int O1; Stands for Output1
O1=sum; Sum is the functions name
Int sum()
Declare variables
Int num1;
Float num2;
Write “Enter a number.”
Scanf num1
Write”Enter a decimal number.”
Scanf num2
Return num1+num2
end
C Code
#include <stdio.h>
int sum();//prototype
int main()//calling program
{
//Declare a varaiable
int O1;
O1=sum();//main is calling sum one time.
//if I listed this twice it would run the function 'sum' twice.
// Example: if I add a new int (int O1, O2) and declare O2 to
//be O2=sum then the function would run twice.
}
int sum ()//function 'sum'
{
int num1;// Declare intergers/variables
float num2;
printf("Enter a number.\n");
scanf("%d",&num1);// Take first input and assign it to num1
printf("Enter a decimal number.\n");
scanf("%.2f",&num2);
//Can use the printf statement but when you are calling an integer you can use the return.
//printf("The sum of %d, %d, is %d", num1,num2,num1+num2);
return num1+num2;
}
ADD COMMENT HERE
Chaotic Function
Contains unread posts
Actions for Chaotic Function
Joshua Ray posted Nov 5, 2015 2:33 PM
Subscribe
float tmp
int i
function float chaos(float num)
{
for i < 20
num = 3.9*num*(1-num)
print num
}
main
print "Program description"
print "Request input btw 0 and 1"
tmp = input
chaos(tmp)
/*
* File: main.c
* Author: JaiEllRei
*
* Created on November 5, 2015, 2:04 PM
*/
#include <stdio.h>
#include <stdlib.h>
float chaos(float num);
int main(void)
{
float tmp;
printf("This program illustrates a choatic function. \n");
printf("Input a number between 0 and 1: ");
scanf("%f", &tmp);
chaos(tmp);
}
float chaos(float num)
{
for (int i=0; i<20; i++){
/*Chaotic Formula*/
num = 3.9 * num * (1-num);
printf("%.3f \n", num);
}
}
This program illustrates a choatic function.
Input a number between 0 and 1: .2
0.624
0.915
0.303
0.824
0.566
0.958
0.156
0.514
0.974
0.098
0.345
0.881
0.409
0.943
0.210
0.647
0.891
0.379
0.918
0.293
ADD COMMENT HERE
//MPH to KPH Conversion Function
Function KPHConv(value) as float
Set KPHConv = value*1.609344
End Function
Pseudocode for simple conversion program calling function
//Declare function
// MPH to KPH Conversion Function
Functio ...
#include fstream#include iostream#include cstdlib#includ.docx
#include fstream#include iostream#include cstdlib#includ
Recommended
#include iostream #include fstream #include map #include.pdf
#include
#include
#include
#include
#include
using namespace std;
//Used from
int index_of_largest(const int array[], int startIndex, const int size);
void selectSort(int a[], const int size);
void swap(int& i1, int& it2);
void fileOption();
void inputOption();
void unique(const int inputArray[], int uniqueArray[], int countArray[], const int size);
void printFileScreen(const int uniqueArray[], const int countArray[], const int size);
int main()
{
// int size;
char userInput[5];
//
cout << \"Read file from Input file? (Y/N) \";
cin >> userInput;
if(toupper(userInput[0]) == \'Y\')
{
fileOption();
}
else
{
inputOption();
}
return 0;
}
void selectSort(int array[], const int size)
{
int smallestIndex;
for(int i = 0;i < size - 1;i++)
{
smallestIndex = index_of_largest(array , i , size);
swap(array[i] , array[smallestIndex]);
}
}
void swap(int& i1, int& i2)
{
int temp;
temp = i1;
i1 = i2;
i2 = temp;
}
int index_of_largest(const int array[], int startIndex, const int size)
{
int min = array[startIndex] , index_of_min = startIndex;
for(int i = startIndex + 1;i < size;i++)
if(array[i] > min)
{
min = array[i];
index_of_min = i;
}
return index_of_min;
}
void unique(const int inputArray[], int uniqueArray[], int countArray[], const int size)
{
int number;
int j = 0;
int index;
for(int i = 0;i < size;i++)
{
int flag = 0;
number = inputArray[i];
//for each element in inputArray, check if it is there in uniqueArray
for (int k = 0; k < j; ++k)
{
if(number == uniqueArray[k])
{
flag = 1;
index = k;
}
}
if(flag == 0)
{
//if so, increment the countArray by 1
countArray[j]++;
// copy the element to uniqueArray
uniqueArray[j] = number;
j++;
}
else
countArray[index]++;
}
}
void fileOption()
{
int inputArray[50];
int countArray[50] = {0};
int uniqueArray[50]= {0};
ifstream in_stream;
char fileName[16];
cout << \"What file would you like to obtain input from? \";
cin >> fileName;
in_stream.open(fileName);
if(in_stream.fail())
{
cout << \"Error: Could not open file!\" << endl;
exit(1);
}
int size = 0;
while(in_stream >> inputArray[size])
{
size++;
}
selectSort(inputArray , size);
unique(inputArray , uniqueArray , countArray , size);
printFileScreen(uniqueArray , countArray , size);
}
void inputOption()
{
int inputArray[50];
int countArray[50] = {0};
int uniqueArray[50] = {0};
int size;
cout << \"How many numbers would you like to enter? \";
cin >> size;
cout << \"Enter numbers:\" << endl;
for(int i = 0;i < size;i++)
{
cin >> inputArray[i];
}
selectSort(inputArray , size);
unique(inputArray , uniqueArray , countArray , size);
printFileScreen(uniqueArray , countArray , size);
}
void printFileScreen(const int uniqueArray[], const int countArray[], const int size)
{
//cout << \"jaja\";
ofstream output_file;
output_file.open(\"lab3Exercise2.txt\");
if(output_file.fail())
{
cout << \"Error: Could not open file!\" << endl;
exit(1);
}
output_file << \"N\\t\" << \"count\ \";
for(int i = 0;i < size;i++)
{
if(uniqueArray[i] != 0)
{
output_file << uniqueArray[i] << \"\\t\";
outpu.
C-Program Custom Library, Header File, and Implementation FilesI .pdf
C-Program: Custom Library, Header File, and Implementation Files
I have this main.c file:
#include
#include
#include \"stats.h\"
int readGrades(char fileName[], float grades[]);
//Include this function prototype
void WelcomeToTheProgram();
int main()
{
///Declare Variables
char fileName[30];
float grades[1000]; //to store grades
int i, ArrayCount[10] = {0}; //to store histogram counts
/* Rewrite this line */
int num_grades; //for # of grades in file
///Call Intro Comment
WelcomeToTheProgram();
///Enter Filename
printf(\"\ \ \ Enter the data filename: \");
scanf(\"%s\", &fileName);
//Get # of grades in file
num_grades = readGrades(fileName, grades); //get # of grades in file
///Print Results
printf(\"There are %d grades read\ \", num_grades);
printf(\"Mean = %f\ \", mean(grades, num_grades));
printf(\"Variance = %f \ \", variance(grades, num_grades));
printf(\"Maximum = %f \ \", maximum(grades, num_grades));
printf(\"Minumum = %f \ \", minimum(grades, num_grades));
//Call histogram
histogram(grades, ArrayCount, num_grades);
//Print the histogram
printf(\"Grade Histogram\ \");
for (i = 0; i < 10; i++)
{
if (i != 9)
{
printf(\"\ %d %% - %d %%: %d \", i * 10, ((i + 1) * 10) - 1, ArrayCount[i]);
}
else
{
printf(\"\ 90 %% - 100 %%: %d\ \", ArrayCount[i]);
}
}
return 0;
}
///Reads all grades from the file to array
int readGrades(char fileName[], float grades[])
{
FILE *fpin = fopen(fileName, \"r\");
int num_scores = 0;
float value;
if (fpin == NULL)
{
printf(\"Cannot open the file\ \");
exit(0);
}
while ((fscanf(fpin, \"%f\", &value)) != EOF)
{
grades[num_scores] = value;
num_scores++;
}
return num_scores;
}
void WelcomeToTheProgram()
{
printf(\"***Welcome to the Program Which Involves a Custom Library***\");
printf(\"\ The program finds the minimum value, maximum value, mean,\");
printf(\"variance, and a histogram of the grades of data by calling\");
printf(\"implementation files min(), max(), mean(), variance(), and histogram().\ \");
}
But, the only thing that prints is
Enter the data file name: grades.txt
There are 400 grades read.
Then the program just stops, it does not print the min, max, mean, variance, or histogram. Any
ideas? Am I using the custom library wrong, the implementation files (for min, max, mean,
variance, and histogram) all check out with no warnings or errors.
Here is stats.h:
#ifndef STATS_H
#define STATS_H
float minimum(float *grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float *grades[], int Size);
float mean(float *grades[], int Size);
float variance(float *grades[], int Size);
void histogram(float *grades[], int *ArrayCount, int Size);
#endif // STATS_H
And here is the grades file:
Solution
//stats.h
#ifndef STATS_H
#define STATS_H
float minimum(float grades[], int Size); // NOTE: You need to complete the prototypes
float maximum(float grades[], int Size);
float mean(float grades[], int Size);
float variance(float grades[], int Size);
void histogram(float grades[], int ArrayCount[], int S.
PROVIDE COMMENTS TO FELLOW STUDENTS ANSWERS AND PLEASE DON’T SAY G.docx
PROVIDE COMMENTS TO FELLOW STUDENTS ANSWERS AND PLEASE DON’T SAY GOOD WORK NICE FORMULA OR SOMETHING LIKE THAT, BUT ACTULLY HE CAN USE. THANK YOU.
Hartleys Function Code
Contains unread posts
Actions for Hartleys Function Code
Chad Hartley posted Nov 5, 2015 5:10 PM
Subscribe
This program will add an integer number and a decimal number up to 2 decimal places. I have included notes in the code to explain what each thing does. I hope I did this right. It compiles successfully.
PseudoCode
Start
Declare int O1; Stands for Output1
O1=sum; Sum is the functions name
Int sum()
Declare variables
Int num1;
Float num2;
Write “Enter a number.”
Scanf num1
Write”Enter a decimal number.”
Scanf num2
Return num1+num2
end
C Code
#include <stdio.h>
int sum();//prototype
int main()//calling program
{
//Declare a varaiable
int O1;
O1=sum();//main is calling sum one time.
//if I listed this twice it would run the function 'sum' twice.
// Example: if I add a new int (int O1, O2) and declare O2 to
//be O2=sum then the function would run twice.
}
int sum ()//function 'sum'
{
int num1;// Declare intergers/variables
float num2;
printf("Enter a number.\n");
scanf("%d",&num1);// Take first input and assign it to num1
printf("Enter a decimal number.\n");
scanf("%.2f",&num2);
//Can use the printf statement but when you are calling an integer you can use the return.
//printf("The sum of %d, %d, is %d", num1,num2,num1+num2);
return num1+num2;
}
ADD COMMENT HERE
Chaotic Function
Contains unread posts
Actions for Chaotic Function
Joshua Ray posted Nov 5, 2015 2:33 PM
Subscribe
float tmp
int i
function float chaos(float num)
{
for i < 20
num = 3.9*num*(1-num)
print num
}
main
print "Program description"
print "Request input btw 0 and 1"
tmp = input
chaos(tmp)
/*
* File: main.c
* Author: JaiEllRei
*
* Created on November 5, 2015, 2:04 PM
*/
#include <stdio.h>
#include <stdlib.h>
float chaos(float num);
int main(void)
{
float tmp;
printf("This program illustrates a choatic function. \n");
printf("Input a number between 0 and 1: ");
scanf("%f", &tmp);
chaos(tmp);
}
float chaos(float num)
{
for (int i=0; i<20; i++){
/*Chaotic Formula*/
num = 3.9 * num * (1-num);
printf("%.3f \n", num);
}
}
This program illustrates a choatic function.
Input a number between 0 and 1: .2
0.624
0.915
0.303
0.824
0.566
0.958
0.156
0.514
0.974
0.098
0.345
0.881
0.409
0.943
0.210
0.647
0.891
0.379
0.918
0.293
ADD COMMENT HERE
//MPH to KPH Conversion Function
Function KPHConv(value) as float
Set KPHConv = value*1.609344
End Function
Pseudocode for simple conversion program calling function
//Declare function
// MPH to KPH Conversion Function
Functio ...
#include fstream#include iostream#include cstdlib#includ.docx
#include fstream#include iostream#include cstdlib#includ
PCA-2 Programming and Solving 2nd Sem.pdf
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
PCA-2 Programming and Solving 2nd Sem.docx
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
#include stdio.h #include stdlib.h #include time.hdouble.pdf
#include
#include
#include
double total(int array[], int n)
{
int i, sum =0;
for (i = 0; i < n; i++)
{
sum = sum + array[i];
}
return sum;
}
int main()
{
srand(time(NULL));
int i, n, rand_number;
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
int array[n];
for (i = 0; i < n; i++)
{
rand_number = rand() % 1000;
array[i] = rand_number;
}
int max = array[0];
int min = array[0];
int min_pos;
int max_pos;
for (i = 0; i < n; i++)
{
if(array[i] > max)
{
max = array[i];
max_pos = i;
}
if(array[i] < min)
{
min = array[i];
min_pos = i;
}
}
int sum = total(array,n);
double average = sum/n;
printf(\"min: %d pos: %d\ \",min, min_pos);
printf(\"max: %d pos: %d\ \",max, max_pos);
printf(\"sum: %d \ \",sum);
printf(\"average: %lf \ \",average);
printf(\"Pos\\t|\\tval\ \");
printf(\"-----------------------\ \");
for (i = 0; i < n; ++i)
{
printf(\"%d\\t|\\t%d\ \",i,array[i]);
}
printf(\"\ \");
return 0;
}
/*
output:
Enter an integer: 30
min: 5 pos: 28
max: 998 pos: 0
sum: 14093
average: 469.000000
Pos | val
-----------------------
0 | 998
1 | 403
2 | 523
3 | 787
4 | 37
5 | 14
6 | 815
7 | 232
8 | 594
9 | 555
10 | 531
11 | 52
12 | 550
13 | 530
14 | 265
15 | 839
16 | 247
17 | 902
18 | 99
19 | 120
20 | 648
21 | 101
22 | 6
23 | 983
24 | 759
25 | 664
26 | 371
27 | 705
28 | 5
29 | 758
*/
Solution
#include
#include
#include
double total(int array[], int n)
{
int i, sum =0;
for (i = 0; i < n; i++)
{
sum = sum + array[i];
}
return sum;
}
int main()
{
srand(time(NULL));
int i, n, rand_number;
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
int array[n];
for (i = 0; i < n; i++)
{
rand_number = rand() % 1000;
array[i] = rand_number;
}
int max = array[0];
int min = array[0];
int min_pos;
int max_pos;
for (i = 0; i < n; i++)
{
if(array[i] > max)
{
max = array[i];
max_pos = i;
}
if(array[i] < min)
{
min = array[i];
min_pos = i;
}
}
int sum = total(array,n);
double average = sum/n;
printf(\"min: %d pos: %d\ \",min, min_pos);
printf(\"max: %d pos: %d\ \",max, max_pos);
printf(\"sum: %d \ \",sum);
printf(\"average: %lf \ \",average);
printf(\"Pos\\t|\\tval\ \");
printf(\"-----------------------\ \");
for (i = 0; i < n; ++i)
{
printf(\"%d\\t|\\t%d\ \",i,array[i]);
}
printf(\"\ \");
return 0;
}
/*
output:
Enter an integer: 30
min: 5 pos: 28
max: 998 pos: 0
sum: 14093
average: 469.000000
Pos | val
-----------------------
0 | 998
1 | 403
2 | 523
3 | 787
4 | 37
5 | 14
6 | 815
7 | 232
8 | 594
9 | 555
10 | 531
11 | 52
12 | 550
13 | 530
14 | 265
15 | 839
16 | 247
17 | 902
18 | 99
19 | 120
20 | 648
21 | 101
22 | 6
23 | 983
24 | 759
25 | 664
26 | 371
27 | 705
28 | 5
29 | 758
*/.
So basically I worked really hard on this code in my CS150 class and.pdf
So basically I worked really hard on this code in my CS150 class and now I need to change it to
a class, and I thought OK that\'s simple enough, but I cant seem to figure it out at all! I know I
can just make all of the variables inside the class public, but that\'s not what my professor wants.
I am supposed to implement the private variables. I tried making the \"letter\" and \"letterCount\"
variables private and I created some void functions under the public part, I think I might have
been on the right track with that but I wasn\'t sure how to modify the rest of my code in order to
get it to run. Here\'s the original code, still in the struct format. Any help would be GREATLY
appreciated.
P.S. my professor said \"make the member variables private, and impliment functions to manage
those private variables, such as getter and setter functions.\" so that might help you understand
whats expected. Thanks!
I NEED TO GET RID OF THE STRUCT ALLTOGETHER!
my class should be set up like this:
class
{
private:
letter
letterCount
public:
//functions to controll the private variables such as...
void getletter
void getlettercount
}
I just dont know how to impliment that in my code, and what to write in those functions in the
class. Thanks for your help!
[code]
#include
#include
#include
#include
using namespace std;
//Struct definition
struct letterType
{
char letter;
int letterCount;
};
//Function to open I/O files
void openFile(ifstream& inFile, ofstream& outFile);
//Function to fill the array of structs and keep track of the amount of uppercase/lowercase letters
void count(ifstream& inFile, letterType letterList[], int& totalBig, int& totalSmall);
//Function to print the letters, the occurences, and the percentages
void printResult(ofstream& outFile, letterType letterList[], int totalBig, int totalSmall);
//Function to create an output file that contains programmer info
void Info (ofstream& outputFile);
int main()
{
ofstream fout;
ifstream input; //object to read the text
ofstream output; //object to write the results
int totalCapital = 0; //variable to store the total number of uppercase
int totalLower = 0; //variable to store the total number of lowercase
letterType letterObj[52]; //array of structs of type letterType to hold the information
//Input and process data
Info (fout);
openFile(input, output);
count(input, letterObj, totalCapital, totalLower);
printResult(output, letterObj, totalCapital, totalLower);
//Close files
input.close();
output.close();
return 0;
}
void openFile(ifstream& inFile, ofstream& outFile)
{
string inFileName;
string outFileName;
cout << \"Enter the name of the input file: \";
cin >> inFileName;
inFile.open(inFileName.c_str());
cout << endl;
cout << \"Enter the name of the output file: \";
cin >> outFileName;
outFile.open(outFileName.c_str());
cout << endl;
}
void count(ifstream& inFile, letterType letterList[], int& totalBig, int& totalSmall)
{
char ch;
//Loop to initialize the array of structs; set letterCount to zero
for(.
VIT351 Software Development VI Unit2
COURSE TITLE: SOFTWARE DEVELOPMENT VI
COURSE CODE: VIT 351
TOPICS COVERED:
ARRAYS
TYPES OF ARRAYS
MULTIDIMENSIONAL ARRAYS
CHARACTER HANDLING IN C
STRING HANDLING IN C
QUIZ SET 2
We will be making 4 classes Main - for testing the code Hi.pdf
/*
We will be making 4 classes:
Main - for testing the code
HighscoreManager - to manage the high-scores
HighscoreComparator - I will explain this when we get there
Score - also this I will explain later
all this classes will be in the package \"highscores\"/*
//The Score Class
package highscores;
import java.io.Serializable;
public class Score implements Serializable {
private int score;
private String naam;
public int getScore() {
return score;
}
public String getNaam() {
return naam;
}
public Score(String naam, int score) {
this.score = score;
this.naam = naam;
}
}/*This class makes us able to make an object (an arraylist in our case) of the type Score that
contains the name and score of a player.
We implement serializable to be able to sort this type./*
//The ScoreComparator Class
package highscores;
import java.util.Comparator;
public class ScoreComparator implements Comparator {
public int compare(Score score1, Score score2) {
int sc1 = score1.getScore();
int sc2 = score2.getScore();
if (sc1 > sc2){
return -1;
}else if (sc1 < sc2){
return +1;
}else{
return 0;
}
}
}
/*This class is used to tell Java how it needs to compare 2 objects of the type score.
-1 means the first score is greater than the 2nd one, +1 (or you can just put 1) means it\'s smaller
and 0 means it\'s equal./*
//The HighscoreManager Class
/*First we will be making the HighscoreManager Class, this class will do the most important part
of the high-score system.
We will be using this as our base for the class:/*
package highscores;
import java.util.*;
import java.io.*;
public class HighscoreManager {
// An arraylist of the type \"score\" we will use to work with the scores inside the class
private ArrayList scores;
// The name of the file where the highscores will be saved
private static final String HIGHSCORE_FILE = \"scores.dat\";
//Initialising an in and outputStream for working with the file
ObjectOutputStream outputStream = null;
ObjectInputStream inputStream = null;
public HighscoreManager() {
//initialising the scores-arraylist
scores = new ArrayList();
}
}
/*I have added comments to explain what\'s already in the class.
We will be using a binary file to keep the high-scores in, this will avoid cheating.
To work with the scores we will use an arraylist. An arraylist is one of the great things that java
has and it\'s much better to use in this case than a regular array.
Now we will add some methods and functions./*
public ArrayList getScores() {
loadScoreFile();
sort();
return scores;
}
/*This is a function that will return an arraylist with the scores in it. It contains calls to the
function loadScoreFile() and sort(), these functions will make sure you have the scores from your
high-score file in a sorted order. We will be writing these functions later on./*
private void sort() {
ScoreComparator comparator = new ScoreComparator();
Collections.sort(scores, comparator);
}
/*This function will create a new object \"comparator\" from the class ScoreComparator.
the Colle.
More Related Content
Similar to #include stdio.hint main() { int count; FILE myFi.pdf
PCA-2 Programming and Solving 2nd Sem.pdf
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
PCA-2 Programming and Solving 2nd Sem.docx
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
#include stdio.h #include stdlib.h #include time.hdouble.pdf
#include
#include
#include
double total(int array[], int n)
{
int i, sum =0;
for (i = 0; i < n; i++)
{
sum = sum + array[i];
}
return sum;
}
int main()
{
srand(time(NULL));
int i, n, rand_number;
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
int array[n];
for (i = 0; i < n; i++)
{
rand_number = rand() % 1000;
array[i] = rand_number;
}
int max = array[0];
int min = array[0];
int min_pos;
int max_pos;
for (i = 0; i < n; i++)
{
if(array[i] > max)
{
max = array[i];
max_pos = i;
}
if(array[i] < min)
{
min = array[i];
min_pos = i;
}
}
int sum = total(array,n);
double average = sum/n;
printf(\"min: %d pos: %d\ \",min, min_pos);
printf(\"max: %d pos: %d\ \",max, max_pos);
printf(\"sum: %d \ \",sum);
printf(\"average: %lf \ \",average);
printf(\"Pos\\t|\\tval\ \");
printf(\"-----------------------\ \");
for (i = 0; i < n; ++i)
{
printf(\"%d\\t|\\t%d\ \",i,array[i]);
}
printf(\"\ \");
return 0;
}
/*
output:
Enter an integer: 30
min: 5 pos: 28
max: 998 pos: 0
sum: 14093
average: 469.000000
Pos | val
-----------------------
0 | 998
1 | 403
2 | 523
3 | 787
4 | 37
5 | 14
6 | 815
7 | 232
8 | 594
9 | 555
10 | 531
11 | 52
12 | 550
13 | 530
14 | 265
15 | 839
16 | 247
17 | 902
18 | 99
19 | 120
20 | 648
21 | 101
22 | 6
23 | 983
24 | 759
25 | 664
26 | 371
27 | 705
28 | 5
29 | 758
*/
Solution
#include
#include
#include
double total(int array[], int n)
{
int i, sum =0;
for (i = 0; i < n; i++)
{
sum = sum + array[i];
}
return sum;
}
int main()
{
srand(time(NULL));
int i, n, rand_number;
printf(\"Enter an integer: \");
scanf(\"%d\",&n);
int array[n];
for (i = 0; i < n; i++)
{
rand_number = rand() % 1000;
array[i] = rand_number;
}
int max = array[0];
int min = array[0];
int min_pos;
int max_pos;
for (i = 0; i < n; i++)
{
if(array[i] > max)
{
max = array[i];
max_pos = i;
}
if(array[i] < min)
{
min = array[i];
min_pos = i;
}
}
int sum = total(array,n);
double average = sum/n;
printf(\"min: %d pos: %d\ \",min, min_pos);
printf(\"max: %d pos: %d\ \",max, max_pos);
printf(\"sum: %d \ \",sum);
printf(\"average: %lf \ \",average);
printf(\"Pos\\t|\\tval\ \");
printf(\"-----------------------\ \");
for (i = 0; i < n; ++i)
{
printf(\"%d\\t|\\t%d\ \",i,array[i]);
}
printf(\"\ \");
return 0;
}
/*
output:
Enter an integer: 30
min: 5 pos: 28
max: 998 pos: 0
sum: 14093
average: 469.000000
Pos | val
-----------------------
0 | 998
1 | 403
2 | 523
3 | 787
4 | 37
5 | 14
6 | 815
7 | 232
8 | 594
9 | 555
10 | 531
11 | 52
12 | 550
13 | 530
14 | 265
15 | 839
16 | 247
17 | 902
18 | 99
19 | 120
20 | 648
21 | 101
22 | 6
23 | 983
24 | 759
25 | 664
26 | 371
27 | 705
28 | 5
29 | 758
*/.
So basically I worked really hard on this code in my CS150 class and.pdf
So basically I worked really hard on this code in my CS150 class and now I need to change it to
a class, and I thought OK that\'s simple enough, but I cant seem to figure it out at all! I know I
can just make all of the variables inside the class public, but that\'s not what my professor wants.
I am supposed to implement the private variables. I tried making the \"letter\" and \"letterCount\"
variables private and I created some void functions under the public part, I think I might have
been on the right track with that but I wasn\'t sure how to modify the rest of my code in order to
get it to run. Here\'s the original code, still in the struct format. Any help would be GREATLY
appreciated.
P.S. my professor said \"make the member variables private, and impliment functions to manage
those private variables, such as getter and setter functions.\" so that might help you understand
whats expected. Thanks!
I NEED TO GET RID OF THE STRUCT ALLTOGETHER!
my class should be set up like this:
class
{
private:
letter
letterCount
public:
//functions to controll the private variables such as...
void getletter
void getlettercount
}
I just dont know how to impliment that in my code, and what to write in those functions in the
class. Thanks for your help!
[code]
#include
#include
#include
#include
using namespace std;
//Struct definition
struct letterType
{
char letter;
int letterCount;
};
//Function to open I/O files
void openFile(ifstream& inFile, ofstream& outFile);
//Function to fill the array of structs and keep track of the amount of uppercase/lowercase letters
void count(ifstream& inFile, letterType letterList[], int& totalBig, int& totalSmall);
//Function to print the letters, the occurences, and the percentages
void printResult(ofstream& outFile, letterType letterList[], int totalBig, int totalSmall);
//Function to create an output file that contains programmer info
void Info (ofstream& outputFile);
int main()
{
ofstream fout;
ifstream input; //object to read the text
ofstream output; //object to write the results
int totalCapital = 0; //variable to store the total number of uppercase
int totalLower = 0; //variable to store the total number of lowercase
letterType letterObj[52]; //array of structs of type letterType to hold the information
//Input and process data
Info (fout);
openFile(input, output);
count(input, letterObj, totalCapital, totalLower);
printResult(output, letterObj, totalCapital, totalLower);
//Close files
input.close();
output.close();
return 0;
}
void openFile(ifstream& inFile, ofstream& outFile)
{
string inFileName;
string outFileName;
cout << \"Enter the name of the input file: \";
cin >> inFileName;
inFile.open(inFileName.c_str());
cout << endl;
cout << \"Enter the name of the output file: \";
cin >> outFileName;
outFile.open(outFileName.c_str());
cout << endl;
}
void count(ifstream& inFile, letterType letterList[], int& totalBig, int& totalSmall)
{
char ch;
//Loop to initialize the array of structs; set letterCount to zero
for(.
VIT351 Software Development VI Unit2
COURSE TITLE: SOFTWARE DEVELOPMENT VI
COURSE CODE: VIT 351
TOPICS COVERED:
ARRAYS
TYPES OF ARRAYS
MULTIDIMENSIONAL ARRAYS
CHARACTER HANDLING IN C
STRING HANDLING IN C
QUIZ SET 2
Similar to #include stdio.hint main() { int count; FILE myFi.pdf (20)
Practical write a c program to reverse a given number
Practical write a c program to reverse a given number
Practical write a c program to reverse a given number
Practical write a c program to reverse a given number
#include stdio.h #include stdlib.h #include time.hdouble.pdf
#include stdio.h #include stdlib.h #include time.hdouble.pdf
So basically I worked really hard on this code in my CS150 class and.pdf
So basically I worked really hard on this code in my CS150 class and.pdf
More from anithareadymade
We will be making 4 classes Main - for testing the code Hi.pdf
/*
We will be making 4 classes:
Main - for testing the code
HighscoreManager - to manage the high-scores
HighscoreComparator - I will explain this when we get there
Score - also this I will explain later
all this classes will be in the package \"highscores\"/*
//The Score Class
package highscores;
import java.io.Serializable;
public class Score implements Serializable {
private int score;
private String naam;
public int getScore() {
return score;
}
public String getNaam() {
return naam;
}
public Score(String naam, int score) {
this.score = score;
this.naam = naam;
}
}/*This class makes us able to make an object (an arraylist in our case) of the type Score that
contains the name and score of a player.
We implement serializable to be able to sort this type./*
//The ScoreComparator Class
package highscores;
import java.util.Comparator;
public class ScoreComparator implements Comparator {
public int compare(Score score1, Score score2) {
int sc1 = score1.getScore();
int sc2 = score2.getScore();
if (sc1 > sc2){
return -1;
}else if (sc1 < sc2){
return +1;
}else{
return 0;
}
}
}
/*This class is used to tell Java how it needs to compare 2 objects of the type score.
-1 means the first score is greater than the 2nd one, +1 (or you can just put 1) means it\'s smaller
and 0 means it\'s equal./*
//The HighscoreManager Class
/*First we will be making the HighscoreManager Class, this class will do the most important part
of the high-score system.
We will be using this as our base for the class:/*
package highscores;
import java.util.*;
import java.io.*;
public class HighscoreManager {
// An arraylist of the type \"score\" we will use to work with the scores inside the class
private ArrayList scores;
// The name of the file where the highscores will be saved
private static final String HIGHSCORE_FILE = \"scores.dat\";
//Initialising an in and outputStream for working with the file
ObjectOutputStream outputStream = null;
ObjectInputStream inputStream = null;
public HighscoreManager() {
//initialising the scores-arraylist
scores = new ArrayList();
}
}
/*I have added comments to explain what\'s already in the class.
We will be using a binary file to keep the high-scores in, this will avoid cheating.
To work with the scores we will use an arraylist. An arraylist is one of the great things that java
has and it\'s much better to use in this case than a regular array.
Now we will add some methods and functions./*
public ArrayList getScores() {
loadScoreFile();
sort();
return scores;
}
/*This is a function that will return an arraylist with the scores in it. It contains calls to the
function loadScoreFile() and sort(), these functions will make sure you have the scores from your
high-score file in a sorted order. We will be writing these functions later on./*
private void sort() {
ScoreComparator comparator = new ScoreComparator();
Collections.sort(scores, comparator);
}
/*This function will create a new object \"comparator\" from the class ScoreComparator.
the Colle.
ITs both by the way... it depends on the situatio.pdf
ITs both by the way... it depends on the situation... is at +3 oxidation state and can
go to +1 or 0; or to +5.
Solution
ITs both by the way... it depends on the situation... is at +3 oxidation state and can
go to +1 or 0; or to +5..
I believe you are correct. The phase transfer cat.pdf
I believe you are correct. The phase transfer catalyst aids in the solubility of
inorganic layer with organic layer. By adding sodium ions you are \"filling up\" the aqueous
solution with ions which forces the quarternary ammonium salt back into the organic layer.
Solution
I believe you are correct. The phase transfer catalyst aids in the solubility of
inorganic layer with organic layer. By adding sodium ions you are \"filling up\" the aqueous
solution with ions which forces the quarternary ammonium salt back into the organic layer..
There are 7 stages in Software Development LifeCycle. Coming to SDLC.pdf
There are 7 stages in Software Development LifeCycle. Coming to SDLC it is a standaed method
to develop software step by step. It serves as a blue print to design software.
The stages help to design a software,the most important thing is to take security measures while
buidling itself because post production if we need to change anything it takes lot of money and
time.
Stage 1: Planning:
It is advised to address common threats and vulnerabilities that can come in the scope of the
project and plan accordingly beforehand. Most important theats to be addressed in this stage are
legal and compliance risks,process gaps etc.
Stage 2: Requirements and analysis:
Taking decisions about the selection of the favourable framworks,softwares.languages is very
crucial. Carefully analyze the vulnerabilities in the frameworks,languages,softwares that can be
used for your project and select one which has minimum threats. your team must be up-to-date
with software security standards to reduce insecure design and development practices. Business
security executive signs the full document and checks whether all the legal threats are
minimized.
Stage-3: Architecture and Design:
Design flaws if not properly identified beforehand can cause major threats to the whole project
and are very tough to repair. Use architecture risk analysis and other standard modeling
fundamental models to do threat modeling. these two can detect the design flaws. There are
many people working for the project in many roles so a nice technique is to document role
specific security training which can help the project to analyze threats accurately.
Stage-4: Development:
this phase is the most crucial phase of the project because it takes most of our time and
resources.By adhering to standard coding standards we can be safe against common threats. One
most important thing in this phase is the code reviews. Generally code is reviewed from time to
time by trained experts to verify it against all vulnerabilities, but by using ongoing reviewing, ie
the code is reviewed constantly because by reviewing the code during long intervals it is difficult
for us to eliminate the problems in the code and the problem is embedded into the code deeply.
Stage-5 :Testing:
In this phase the bugs which the developers have overlooked are targetted. Specific testing tools
are used which subject the code to multiple verifications and look for bugs.Static and dynamic
testing tools are used to check the working of the code is real time scenarios.Penetration tests are
very powerful tests which can identify the authorize attacks,input handling,security posture etc.
Stage-6: Deployment/implementation:
In the deployment phase we need to take care such that the consumer gets all the prerequisite
information he needs.The detail plan of the environment where the product works,configuration
details,launch details must be properly addressed.It is also advised to lauch a standard Q and A
where the standard possible doubts the use.
The correct statements are1. the oxygen atom has a greater attrac.pdf
The correct statements are:
1. the oxygen atom has a greater attraction for electrons than the hydrogen atom does.
2. the electrons of the covalent bond are not shared equally between the hydrogen and oxygen
atoms.
Solution
The correct statements are:
1. the oxygen atom has a greater attraction for electrons than the hydrogen atom does.
2. the electrons of the covalent bond are not shared equally between the hydrogen and oxygen
atoms..
This is a bit complex to answer as we have HCl and NaOH present, the.pdf
This is a bit complex to answer as we have HCl and NaOH present, they will undergo
neutralization reaction to form NaCl and water.
so inevitably water is also in system.
acetyl chloride and water, they will react to form HCl and Acetic acid which is will react with
NaOH to form sodium acetate.
Considering all these cases. I think the answer should be
benzene in CH2Cl2 layer, as benzene only
acetyl chloride in NaOH layer as CH3COO-Na+
AlCl3 will be NaOH layer in the form of AlCl4- ion, reason being NaOH and HCl have reacted
to give Na+ and Cl- ions and AlCl3 in presence of chloride ions gives AlCl4-
HCl will be in NaOH in form of NaCl ... dissociated into Na+ and Cl- ions ultimately
Solution
This is a bit complex to answer as we have HCl and NaOH present, they will undergo
neutralization reaction to form NaCl and water.
so inevitably water is also in system.
acetyl chloride and water, they will react to form HCl and Acetic acid which is will react with
NaOH to form sodium acetate.
Considering all these cases. I think the answer should be
benzene in CH2Cl2 layer, as benzene only
acetyl chloride in NaOH layer as CH3COO-Na+
AlCl3 will be NaOH layer in the form of AlCl4- ion, reason being NaOH and HCl have reacted
to give Na+ and Cl- ions and AlCl3 in presence of chloride ions gives AlCl4-
HCl will be in NaOH in form of NaCl ... dissociated into Na+ and Cl- ions ultimately.
The possible causative agent is Corynebacterium diptheriaeSore thr.pdf
The possible causative agent is Corynebacterium diptheriae
Sore throat, fever, shaking and chills, difficulty in breathing are all symptoms typically
assocaited with C. diptheriae. The bacterium is Gram positive bacillus, non capsulated, non
motile, toxin producing. They produce exotoxin called diptheria toxin, which is encoded by a
prophage. The bacteria adheres to mucosal epithelium and infect them. The toxtosin released by
endosomes stimulate localized inflammation followed by tissue destruction. Necrosis results
from tissue destruction. The toxin belongs to AB toxin class. The B fragment binds to host cell
and the A fragment toxin is innserted into the membrane and transported. It is proteolytically
activated inside the cell. The toxin binds to a histidine residue of elongation factor 2 or eEF2.
The active A fragment inhibits translocation of growing peptide chain on the ribosome. Thus, it
inhibits protein synthesis. The toxin transfers NAD to dipthamide (elongation factor 2) to
inactivate the elongation factor. Local tissue destruction makes the bacteria gain access into the
circulation, anters the lymphatic and blood stream, to spread to other parts of the body. Systemic
spreading causes diptheria toxin act on vital organs like kidney, myocardium, and nervous
system.
Innate immune responses against the bacterium includes Macrophages as the first line of defense.
They use pattern specific receptors to attach and engulf bacteria. Neutrophils also mediate the
same response. Macrophages further release cytokines to mediate inflammation.
Solution
The possible causative agent is Corynebacterium diptheriae
Sore throat, fever, shaking and chills, difficulty in breathing are all symptoms typically
assocaited with C. diptheriae. The bacterium is Gram positive bacillus, non capsulated, non
motile, toxin producing. They produce exotoxin called diptheria toxin, which is encoded by a
prophage. The bacteria adheres to mucosal epithelium and infect them. The toxtosin released by
endosomes stimulate localized inflammation followed by tissue destruction. Necrosis results
from tissue destruction. The toxin belongs to AB toxin class. The B fragment binds to host cell
and the A fragment toxin is innserted into the membrane and transported. It is proteolytically
activated inside the cell. The toxin binds to a histidine residue of elongation factor 2 or eEF2.
The active A fragment inhibits translocation of growing peptide chain on the ribosome. Thus, it
inhibits protein synthesis. The toxin transfers NAD to dipthamide (elongation factor 2) to
inactivate the elongation factor. Local tissue destruction makes the bacteria gain access into the
circulation, anters the lymphatic and blood stream, to spread to other parts of the body. Systemic
spreading causes diptheria toxin act on vital organs like kidney, myocardium, and nervous
system.
Innate immune responses against the bacterium includes Macrophages as the first line of defense.
They use pattern specific recep.
The answer is E) 1,2, and 3.The solubility of a gas in solvents de.pdf
The answer is E) 1,2, and 3.
The solubility of a gas in solvents depends on their intermolecular interactions, which is affected
by the nature of gas and the solvent as well as the temperature. So all three factors are relevant.
Solution
The answer is E) 1,2, and 3.
The solubility of a gas in solvents depends on their intermolecular interactions, which is affected
by the nature of gas and the solvent as well as the temperature. So all three factors are relevant..
RainfallTest.java import java.util.Arrays; import java.util.Sc.pdf
RainfallTest.java
import java.util.Arrays;
import java.util.Scanner;
public class RainfallTest {
/**
* @param args
*/
static String month[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public static void main(String[] args) {
// TODO Auto-generated method stub
int months[] = new int[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println(\"The minimum rainfall is :\"+min);
System.out.println(\"The minimum rainfall month is :\"+month[minIndex]);
}
public static void updaeRainFallForMonth(int months[]){
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a month (1-12) for rainfall update:\");
int month = scan.nextInt();
System.out.println(\"Enter rainfall for update:\");
int rainfall = scan.nextInt();
months[month-1] = rainfall;
}
public static void exit(){
System.exit(0);
}
}
Output:
Enter Rainfall for the month 1:
55
Enter Rainfall for the month 2:
66
Enter Rainfall for the month 3:
77
Enter Rainfall for the month 4:
44
Enter Rainfall for the month 5:
33
Enter Rainfall for the month 6:
22
Enter Rainfall for the month 7:
11
Enter Rainfall for the month 8:
99
Enter Rainfall for the month 9:
88
Enter Rainfall for the month 10:
45
Enter Rainfall for the month 11:
56
Enter Rainfall for the month 12:
67
Entered rainfall details [55, 66, 77, 44, 33, 22, 11, 99, 88, 45, 56, 67]
Enter your choice:
1.the rainfall for each month
2.the total rainfall for the year
3.find the average monthly rainfall
4.the name of the month with the most rain
.5.the name of the month with the least rain.
6.update the amount of rain in any given month
7.quit
1
January: 55
Fabruary: 66
March: 77
April: 44
May: 33
June: 22
July: 11
August: 99
September: 88
October: 45
November: 56
December: 67
Enter your choice:
1.the rainfall for each month
2.the total rainfall for the year
3.find the average monthly rainfall
4.the name of the month with the most rain
.5.the name of the month with the least rain.
6.update the amount of rain in any given month
7.quit
2
The total rainfall is :663
Enter your choice:
1.the rainfall for each month
2.the total rainfall for the year
3.find the average monthly rainfall
4.the name of the month with the most rain
.5.the name of the month with the least rain.
6.update the amount of rain in any given month
7.quit
3
The average rainfall is :55.25
Enter your choice:
1.the rainfall for each month
2.the total rainfall for the year
3.find the average monthly rainfall
4.the name of the month with the most rain
.5.the name of the month with the least rain.
6.update the amount of rain in any given month
7.quit
4
The maximum rainfall is :99
The maximum rainfall month is :August
Enter your choice:
1.the rainfall for each month
2.the total rainfall for the year
3.find the average monthly rainfall
4.the name of the month with the most rain
.5.the name of the month with the least rai.
by taking p1,p2,p3 as points in cordinate system.. displavement can .pdf
by taking p1,p2,p3 as points in cordinate system.. displavement can be found out
Solution
by taking p1,p2,p3 as points in cordinate system.. displavement can be found out.
import java.util.; public class DecimalToBinary { public stat.pdf
import java.util.*;
public class DecimalToBinary {
public static int[] printBinaryFormat(int number){
int binary[] = new int[7];
int index = 0;
while(number > 0){
binary[index++] = number%2;
number = number/2;
}
return binary;
}
public static void main(String a[]){
DecimalToBinary dtb = new DecimalToBinary();
int a1[]=new int[7];
int b1[]=new int[7];
Scanner sc=new Scanner(System.in);
System.out.println(\"Enter First Number\");
int m=sc.nextInt();
System.out.println(\"Enter Second Number\");
int n=sc.nextInt();
a1=printBinaryFormat(m);
b1=printBinaryFormat(n);
int t=sum(a1,b1);
System.out.println();
if(t>0)
System.out.println(\"The Sum is \"+t);
else
System.out.println(\"Overflow\");
}
static int sum(int x[],int y[])
{
int carry=0;
int s1,s2,a,i;
int r[]=new int[8];
i=0;
int c=0;
while(i<7)
{
a=carry+x[i]+y[i];
if(a==3)
{
r[c]=1;
carry=1;
}
else if(a==2)
{
r[c]=0;
carry=1;
}
else if(a==1)
{
r[c]=1;
carry=0;
}
else
{
r[c]=0;
carry=0;
}
i++;
c++;
}
r[c]=carry;
if(carry==1)
return -1;
else
{
int e=0;
System.out.println(\"Result Number in Binary\");
for(i=6;i>=0;i--)
System.out.print(r[i]);
for(i=6;i>=0;i--)
e+=r[i]*Math.pow(2,i);
return e;
}
}
}
Solution
import java.util.*;
public class DecimalToBinary {
public static int[] printBinaryFormat(int number){
int binary[] = new int[7];
int index = 0;
while(number > 0){
binary[index++] = number%2;
number = number/2;
}
return binary;
}
public static void main(String a[]){
DecimalToBinary dtb = new DecimalToBinary();
int a1[]=new int[7];
int b1[]=new int[7];
Scanner sc=new Scanner(System.in);
System.out.println(\"Enter First Number\");
int m=sc.nextInt();
System.out.println(\"Enter Second Number\");
int n=sc.nextInt();
a1=printBinaryFormat(m);
b1=printBinaryFormat(n);
int t=sum(a1,b1);
System.out.println();
if(t>0)
System.out.println(\"The Sum is \"+t);
else
System.out.println(\"Overflow\");
}
static int sum(int x[],int y[])
{
int carry=0;
int s1,s2,a,i;
int r[]=new int[8];
i=0;
int c=0;
while(i<7)
{
a=carry+x[i]+y[i];
if(a==3)
{
r[c]=1;
carry=1;
}
else if(a==2)
{
r[c]=0;
carry=1;
}
else if(a==1)
{
r[c]=1;
carry=0;
}
else
{
r[c]=0;
carry=0;
}
i++;
c++;
}
r[c]=carry;
if(carry==1)
return -1;
else
{
int e=0;
System.out.println(\"Result Number in Binary\");
for(i=6;i>=0;i--)
System.out.print(r[i]);
for(i=6;i>=0;i--)
e+=r[i]*Math.pow(2,i);
return e;
}
}
}.
Hello!!!!!!! This answer will help you ) H2Se would occur in a .pdf
Hello!!!!!!! This answer will help you :)
H2Se would occur in a bent formation similar to water, H2O. The asymmetry of this structure
causes the molecule to be polar.
The geometry of BeCl2 is linear with a symmetric charge distribution.
Therefore this molecule is non polar.
NF5 is a non polar.
Co2
It is a non-polar molecule. But it has polar covalent bonds between its atoms.
Solution
Hello!!!!!!! This answer will help you :)
H2Se would occur in a bent formation similar to water, H2O. The asymmetry of this structure
causes the molecule to be polar.
The geometry of BeCl2 is linear with a symmetric charge distribution.
Therefore this molecule is non polar.
NF5 is a non polar.
Co2
It is a non-polar molecule. But it has polar covalent bonds between its atoms.
.
Here is the code for youimport java.util.Scanner; import java.u.pdf
Here is the code for you:
import java.util.Scanner;
import java.util.Random;
public class TicTacToeGame {
static char[] [] board = new char[3][3];
static Scanner input=new Scanner(System.in);
//Object of Stats class to maintain statistics
static Stats stat = new Stats();
/**
* Prints the TicTacToe board
* @param arr: The board so far
*/
public static void printBoard(char [][] arr){
System.out.println();
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
System.out.print(arr[i][j]);
if(j!=2)
//Print the | for readable output
System.out.print(\" \" + \"|\" + \" \");
}
System.out.println();
if(i!=2) {
System.out.print(\"_ _ _ \"); // Print _ for readability
System.out.println();;
}
}
}
/**
* Clear the TicTacToe board before starting a new game
* @param arr: The board so far
*/
public static void clearBoard(char [][] arr){
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
arr[i][j]=\' \';
}
}
}
/** Determines if the player with the specified token wins
*
* @param symbol: Specifies whether the player is X or O
* @return true if player has won, false otherwise
*/
public static boolean isWon(char symbol) {
for (int i = 0; i < 3; i++) //horizontal
if (board[i][0] == symbol
&& board[i][1] == symbol
&& board[i][2] == symbol) {
return true;
}
//TODO!!! Also check for vertical and the two diagonals
for (int i = 0; i < 3; i++) //vertical
if (board[0][i] == symbol
&& board[1][i] == symbol
&& board[2][i] == symbol) {
return true;
}
//Leading diagonal
if (board[0][0] == symbol
&& board[1][1] == symbol
&& board[2][2] == symbol) {
return true;
}
//Trailing diagonal
if (board[0][2] == symbol
&& board[1][1] == symbol
&& board[2][0] == symbol) {
return true;
}
return false;
}
/** Determines if the cell is occupied
*
* @param row: Row of the cell to be checked
* @param col: Column of the cell to be checked
* @return true if the cell is occupied, false otherwise
*/
public static boolean isOccupied(int row, int col){
if (board[row][col]!=\' \') return false;
else return true;
}
/** Determines who starts the game
*/
public static int whoStarts(){
//TODO: Randomly chooses between 0 and 1 and returns the choice
return (int)(Math.random() + 0.5 );
}
/** takes care of the human\'s move
* 1. Prompt for a cell, then column
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a human wins: prints, updates stats and returns true
* 5. If not a win yet, returns false */
public static boolean humanTurn(char symbol){
//Prompt for a cell. User must enter
//row and column with a space in between.
System.out.print(\"\ \ Enter your move: (row column): \" );
int row = input.nextInt();
int col = input.nextInt();
//TODO!!! Mark user move in the board, print
//the board and check if user has won!
board[row][col] = symbol;
printBoard(board);
if(isWon(symbol))
return true;
return false;
}
/** takes care of the computer\'s move
* 1. Generates numbers until finds an empty cell
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a comp .
Following are the changes mentioned in bold in order to obtain the r.pdf
Following are the changes mentioned in bold in order to obtain the required result and stop
scrolling in the background.
#include \"SDL/SDL.h\"
#include
//The attributes of the screen can be defined as follows
const int SCN_WIDTH = 640;
const int SCN_HEIGHT = 480;
const int SCN_BPP = 32;
//BPP defines bits per pixel
SDL_Surface* Background = NULL;
SDL_Surface* SpriteImage = NULL;
SDL_Surface* Backbuffer = NULL;
int SpriteFrame = 0;
int FrameCounter = 0;
const int MaxSpriteFrame = 12;
const int FrameDelay = 2;
int BackgroundX = 0;
SDL_Surface* LoadImage(char* fileName);
bool LoadFiles();
void FreeFiles();
void DrawImage(SDL_Surface* image, SDL_Surface* destSurface, int x, int y);
void DrawImageFrame(SDL_Surface* image, SDL_Surface* destSurface, int x, int y, int width,
int height, int frame);
bool ProgramIsRunning();
int main(int argc, char* args[])
{
if(SDL_Init(SDL_INIT_EVERYTHING) < 0)
{
printf(\"Failed to initialize SDL!\ \");
return 0;
}
Backbuffer = SDL_SetVideoMode(800, 600, 32, SDL_SWSURFACE);
SDL_WM_SetCaption(\"Image Animation\", NULL);
if(!LoadFiles())
{
printf(\"Failed to load all files!\ \");
FreeFiles();
SDL_Quit();
return 0;
}
while(ProgramIsRunning())
{
//Update\'s the sprites frame
FrameCounter++;
if(FrameCounter > FrameDelay)
{
FrameCounter = 0;
SpriteFrame++;
}
if(SpriteFrame > MaxSpriteFrame)
SpriteFrame = 0;
//Background scrolling can be removed from this position
//Render the scene
DrawImage(Background,Backbuffer, BackgroundX, 0);
DrawImage(Background,Backbuffer, BackgroundX+800, 0);
DrawImageFrame(SpriteImage, Backbuffer, 350,250, 150, 120, SpriteFrame);
SDL_Delay(20);
SDL_Flip(Backbuffer);
}
FreeFiles();
SDL_Quit();
return 0;
}
SDL_Surface* LoadImage(char* fileName)
{
SDL_Surface* imageLoaded = NULL;
SDL_Surface* processedImage = NULL;
imageLoaded = SDL_LoadBMP(fileName);
if(imageLoaded != NULL)
{
processedImage = SDL_DisplayFormat(imageLoaded);
SDL_FreeSurface(imageLoaded);
if(processedImage != NULL)
{
//Here we map the color key
Uint32 colorKey = SDL_MapRGB(processedImage->format, 0, 0xFF, 0xFF);
//Now, set all the pixels of color R 0,G 0*FF,B 0*FF to be transparent
SDL_SetColorKey(processedImage, SDL_SRCCOLORKEY, colorKey);
}
}
return processedImage;
}
bool LoadFiles()
{
Background = LoadImage(\"graphics/background.bmp\");
if(Background == NULL)
return false;
SpriteImage = LoadImage(\"graphics/bat.bmp\");
//The file should be preloaded and linked with the required libraries in SDL
if(SpriteImage == NULL)
return false;
else
return true;
}
void FreeFiles()
{
SDL_FreeSurface(Background);
SDL_FreeSurface(SpriteImage);
}
void DrawImage(SDL_Surface* image, SDL_Surface* destSurface, int x, int y)
//A temporary rectangle is used to hold the offsets
{
SDL_Rect destRect;
//Giving the offsets to the rectangle
destRect.x = x;
destRect.y = y;
//Blit the surface
SDL_BlitSurface(image, NULL, destSurface, &destRect);
}
//Here, we need to start the main function:
int main(int argc,char** args)
//Now, initialize all SDL subsystems
if .
During meiosis, each member of a pair of genes tends to be randomly .pdf
During meiosis, each member of a pair of genes tends to be randomly distributed into gametes
(receive alleles) independently of how other chromosomes are distributed. Genes that are having
their loci nearer to each other are not generally separated during chromosomal crossover and are
inherited together to the offspring. These genes are known as linked genes (two different
chromosomes), and they always have multiple alleles.
Incompletely linked genes undergo crossing over, and the frequency of crossing over depends
upon their distance. In contrast, the completely linked genes do not undergo crossing over at all.
Means, they do not produce recombinant gametes.
If two linked genes are separated by 10 cM (centi morgans or map units), the percent
recombinants produced by this cross is always equal to the 10% and the remaining 90% will be
identical to the parental genotype. And, in case of cross between the linked genes, the highest
percent of offspring indicates (always, equal to or more than 50%) the paretnal and the remaining
are recombinants.
Solution
During meiosis, each member of a pair of genes tends to be randomly distributed into gametes
(receive alleles) independently of how other chromosomes are distributed. Genes that are having
their loci nearer to each other are not generally separated during chromosomal crossover and are
inherited together to the offspring. These genes are known as linked genes (two different
chromosomes), and they always have multiple alleles.
Incompletely linked genes undergo crossing over, and the frequency of crossing over depends
upon their distance. In contrast, the completely linked genes do not undergo crossing over at all.
Means, they do not produce recombinant gametes.
If two linked genes are separated by 10 cM (centi morgans or map units), the percent
recombinants produced by this cross is always equal to the 10% and the remaining 90% will be
identical to the parental genotype. And, in case of cross between the linked genes, the highest
percent of offspring indicates (always, equal to or more than 50%) the paretnal and the remaining
are recombinants..
B parents marital statusSolutionB parents marital status.pdf
B parents marital status
Solution
B parents marital status.
ANSWERS12. B collecting ducts13. B efferent arteriol15. juxtag.pdf
ANSWERS
12. B collecting ducts
13. B efferent arteriol
15. juxtaglomerular cells
16. A can be active or passive
17. C loop of Henle
18. D proximal convoluted tubule
19. .C increase the surface area of the mucosa of the small intestine
20. D submucosa of the duodenum
21. E myenteric plexus
22. D secretion - gall bladder epithelial cells
( I AM NOT SURE ABOUT QUESTION NO .14 , )
Solution
ANSWERS
12. B collecting ducts
13. B efferent arteriol
15. juxtaglomerular cells
16. A can be active or passive
17. C loop of Henle
18. D proximal convoluted tubule
19. .C increase the surface area of the mucosa of the small intestine
20. D submucosa of the duodenum
21. E myenteric plexus
22. D secretion - gall bladder epithelial cells
( I AM NOT SURE ABOUT QUESTION NO .14 , ).
Array- Arrays is a collection of data items with same data type and.pdf
Array:- Arrays is a collection of data items with same data type and access using a common
name.
Linked List:-A linked list is a linear data structure where each element is a separate object. Each
element(node) of a list is comprising of two items - the data and a reference to the next node.
Both Arrays and Linked Lists having advantages and disadvantages.
Solution
Array:- Arrays is a collection of data items with same data type and access using a common
name.
Linked List:-A linked list is a linear data structure where each element is a separate object. Each
element(node) of a list is comprising of two items - the data and a reference to the next node.
Both Arrays and Linked Lists having advantages and disadvantages..
More from anithareadymade (20)
We will be making 4 classes Main - for testing the code Hi.pdf
We will be making 4 classes Main - for testing the code Hi.pdf
ITs both by the way... it depends on the situatio.pdf
ITs both by the way... it depends on the situatio.pdf
I believe you are correct. The phase transfer cat.pdf
I believe you are correct. The phase transfer cat.pdf
There are 7 stages in Software Development LifeCycle. Coming to SDLC.pdf
There are 7 stages in Software Development LifeCycle. Coming to SDLC.pdf
The correct statements are1. the oxygen atom has a greater attrac.pdf
The correct statements are1. the oxygen atom has a greater attrac.pdf
This is a bit complex to answer as we have HCl and NaOH present, the.pdf
This is a bit complex to answer as we have HCl and NaOH present, the.pdf
The possible causative agent is Corynebacterium diptheriaeSore thr.pdf
The possible causative agent is Corynebacterium diptheriaeSore thr.pdf
The answer is E) 1,2, and 3.The solubility of a gas in solvents de.pdf
The answer is E) 1,2, and 3.The solubility of a gas in solvents de.pdf
RainfallTest.java import java.util.Arrays; import java.util.Sc.pdf
RainfallTest.java import java.util.Arrays; import java.util.Sc.pdf
by taking p1,p2,p3 as points in cordinate system.. displavement can .pdf
by taking p1,p2,p3 as points in cordinate system.. displavement can .pdf
import java.util.; public class DecimalToBinary { public stat.pdf
import java.util.; public class DecimalToBinary { public stat.pdf
Hello!!!!!!! This answer will help you ) H2Se would occur in a .pdf
Hello!!!!!!! This answer will help you ) H2Se would occur in a .pdf
Here is the code for youimport java.util.Scanner; import java.u.pdf
Here is the code for youimport java.util.Scanner; import java.u.pdf
Following are the changes mentioned in bold in order to obtain the r.pdf
Following are the changes mentioned in bold in order to obtain the r.pdf
During meiosis, each member of a pair of genes tends to be randomly .pdf
During meiosis, each member of a pair of genes tends to be randomly .pdf
B parents marital statusSolutionB parents marital status.pdf
B parents marital statusSolutionB parents marital status.pdf
ANSWERS12. B collecting ducts13. B efferent arteriol15. juxtag.pdf
ANSWERS12. B collecting ducts13. B efferent arteriol15. juxtag.pdf
Array- Arrays is a collection of data items with same data type and.pdf
Array- Arrays is a collection of data items with same data type and.pdf
Recently uploaded
Model Attribute Check Company Auto Property
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdfFundacja Rozwoju Społeczeństwa Przedsiębiorczego
Wolontariat grupowyCambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
for studentd in cabridge board
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Home assignment II on Spectroscopy 2024 Answers.pdf
Answers to Home assignment on UV-Visible spectroscopy: Calculation of wavelength of UV-Visible absorption
Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
Template Jadual Bertugas Kelas (Boleh Edit)
Jadual Bertugas kelas dalam bentuk softcopy PowerPoint. Cikgu boleh download >> edit >> print >> laminate. Semoga bermanfaat.
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
Recently uploaded (20)
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
#include stdio.hint main() { int count; FILE myFi.pdf
- 1. #include int main() { int count; FILE *myFile; myFile = fopen("input.txt","r"); long numbers[8]; int i; for(i=0;i<8;i++) { fscanf(myFile,"%ld",&numbers[i]); } for (i=0;i<8;i++) { printf("Number is: %ld ", numbers[i]); } for(i=0;i<8;i++) { count=0; //initialize count=0 for every integer while(numbers[i]!=0) { numbers[i] /= 10; // number[i] = number[i]/10 ++count; } printf("Number of digits in numbers[%d] is %d ",i,count); } return 0; } Output Number is: 7
- 2. Number is: 7 Number is: 5 Number is: 6 Number is:7 Number is: 43 Number is: 444 Number is: 8 Number of digits in numbers[0] is 1 Number of digits in numbers[1] is 1 Number of digits in numbers[2] is 1 Number of digits in numbers[3] is 1 Number of digits in numbers[4] is 1 Number of digits in numbers[5] is 2 Number of digits in numbers[6]
- 3. is 3 Number of digits in numbers[7] is 1 Solution #include int main() { int count; FILE *myFile; myFile = fopen("input.txt","r"); long numbers[8]; int i; for(i=0;i<8;i++) { fscanf(myFile,"%ld",&numbers[i]); } for (i=0;i<8;i++) { printf("Number is: %ld ", numbers[i]); } for(i=0;i<8;i++) { count=0; //initialize count=0 for every integer while(numbers[i]!=0) { numbers[i] /= 10; // number[i] = number[i]/10 ++count; } printf("Number of digits in numbers[%d] is %d ",i,count); } return 0; }
- 4. Output Number is: 7 Number is: 7 Number is: 5 Number is: 6 Number is:7 Number is: 43 Number is: 444 Number is: 8 Number of digits in numbers[0] is 1 Number of digits in numbers[1] is 1 Number of digits in numbers[2] is 1 Number of digits in numbers[3] is 1 Number of digits in numbers[4]
- 5. is 1 Number of digits in numbers[5] is 2 Number of digits in numbers[6] is 3 Number of digits in numbers[7] is 1