In carrying out their engagements- which financial advisor would NOT b.pdf
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In carrying out their engagements, which financial advisor would NOT be subject to the Preparer penaity? a) George, who is preparing a tax return for Mario b) Sandra, who is providing tax advice to Frank c) Allan, who is providing financial planning advice to Joan d) Margo, who is preparing an appraisal report to be filed with the income tax returns of the partners in Sleepy Hollow Golf Course.
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-------------- PriorityQueue -------------
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//doublyLinked.cpp
//demonstrates doubly-linked list
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
class Link {
public:
double dData; //data item
Link * pNext; //next link in list
Link * pPrevious; //previous link in list
public:
//-------------------------------------------------------------
Link(double dd): //constructor
dData(dd), pNext(NULL), pPrevious(NULL) {}
//-------------------------------------------------------------
void displayLink() //display this link
{
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}
//-------------------------------------------------------------
}; //end class Link
////////////////////////////////////////////////////////////////
class DoublyLinkedList {
private:
Link * pFirst; //pointer to first item
Link * pLast; //pointer to last item
public:
//-------------------------------------------------------------
DoublyLinkedList(): //constructor
pFirst(NULL), pLast(NULL) {}
//-------------------------------------------------------------
~DoublyLinkedList() //destructor (deletes links)
{
Link * pCurrent = pFirst; //start at beginning of list
while (pCurrent != NULL) //until end of list,
{
Link * pOldCur = pCurrent; //save current link
pCurrent = pCurrent -> pNext; //move to next link
delete pOldCur; //delete old current
}
}
//-------------------------------------------------------------
bool isEmpty() //true if no links
{
return pFirst == NULL;
}
//-------------------------------------------------------------
void insertFirst(double dd) //insert at front of list
{
Link * pNewLink = new Link(dd); //make new link
if (isEmpty()) //if empty list,
pLast = pNewLink; //newLink <-- last
else
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Implement a priority queue using a doublyLinked.cpp where the node with the highest
priority (key) is the right-most node.
The remove (de-queue) operation returns the node with the highest priority (key).
If displayForward() displays List (first-->last) : 10 30 40 55
remove() would return the node with key 55.
please only code in c++ not anything else. keep it simple and thank you!!
Demonstrate by inserting keys at random, displayForward(), call remove then
displayForward() again.
int main()
{
DoublyLinkedList pqList;
pqList.priorityInsert(50);
pqList.priorityInsert(40);
pqList.priorityInsert(30);
pqList.priorityInsert(20);
pqList.priorityInsert(10);
cout<<"-------------- PriorityQueue -------------"<<endl;
pqList.displayForward();
cout<<"calling priorityRemove()"<<endl;
double key = pqList.priorityRemove();
cout<<"Removed node with key "<<key<<endl;
pqList.displayForward();
key = pqList.priorityRemove();
cout<<"Removed node with key "<<key<<endl;
pqList.displayForward();
return 0;
}
Sample output"
-------------- PriorityQueue -------------
List (first-->last): 10 20 30 40 50
calling priorityRemove()
Removed node with key 50
List (first-->last): 10 20 30 40
Removed node with key 40
List (first-->last): 10 20 30
I may change numbers when grading.
doublyLinked.cpp
//doublyLinked.cpp
//demonstrates doubly-linked list
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
class Link {
public:
double dData; //data item
Link * pNext; //next link in list
Link * pPrevious; //previous link in list
public:
//-------------------------------------------------------------
Link(double dd): //constructor
dData(dd), pNext(NULL), pPrevious(NULL) {}
//-------------------------------------------------------------
void displayLink() //display this link
{
cout << dData << " ";
}
//-------------------------------------------------------------
}; //end class Link
////////////////////////////////////////////////////////////////
class DoublyLinkedList {
private:
Link * pFirst; //pointer to first item
Link * pLast; //pointer to last item
public:
//-------------------------------------------------------------
DoublyLinkedList(): //constructor
pFirst(NULL), pLast(NULL) {}
//-------------------------------------------------------------
~DoublyLinkedList() //destructor (deletes links)
{
Link * pCurrent = pFirst; //start at beginning of list
while (pCurrent != NULL) //until end of list,
{
Link * pOldCur = pCurrent; //save current link
pCurrent = pCurrent -> pNext; //move to next link
delete pOldCur; //delete old current
}
}
//-------------------------------------------------------------
bool isEmpty() //true if no links
{
return pFirst == NULL;
}
//-------------------------------------------------------------
void insertFirst(double dd) //insert at front of list
{
Link * pNewLink = new Link(dd); //make new link
if (isEmpty()) //if empty list,
pLast = pNewLink; //newLink <-- last
else
pFirst -> pPrevious = pNewLink; //newLi.
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