import java.util.Scanner; public class Palin { public static v.pdf
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import java.util.Scanner; public class Palin { public static void main(String args[]) { Scanner s=new Scanner(System.in); System.out.println(\"enter string : \"); String str=s.next(); int i,j; boolean flag=true; for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--) { if(str.charAt(i)!=str.charAt(j)) flag=false; } if(flag==true) System.out.println(\"palindrome\"); else System.out.println(\"not a palindrome\"); } } Solution import java.util.Scanner; public class Palin { public static void main(String args[]) { Scanner s=new Scanner(System.in); System.out.println(\"enter string : \"); String str=s.next(); int i,j; boolean flag=true; for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--) { if(str.charAt(i)!=str.charAt(j)) flag=false; } if(flag==true) System.out.println(\"palindrome\"); else System.out.println(\"not a palindrome\"); } }.
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![import java.util.Scanner;
public class Palin
{
public static void main(String args[])
{
Scanner s=new Scanner(System.in);
System.out.println("enter string : ");
String str=s.next();
int i,j;
boolean flag=true;
for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--)
{
if(str.charAt(i)!=str.charAt(j))
flag=false;
}
if(flag==true)
System.out.println("palindrome");
else
System.out.println("not a palindrome");
}
}
Solution
import java.util.Scanner;
public class Palin
{
public static void main(String args[])
{
Scanner s=new Scanner(System.in);
System.out.println("enter string : ");
String str=s.next();
int i,j;
boolean flag=true;
for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--)](https://image.slidesharecdn.com/importjava-230408123429-d7afeb5e/85/import-java-util-Scanner-public-class-Palin-public-static-v-pdf-1-320.jpg)
Recommended
PrimeRange.java import java.util.Scanner;public class PrimeRan.pdf
PrimeRange.java
import java.util.Scanner;
public class PrimeRange {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter low range:\");
int low = scan.nextInt();
System.out.println(\"Enter high range:\");
int high = scan.nextInt();
for(int i=low; i<=high; i++){
if(isPrime(i))
System.out.print(i+\" \");
}
}
public static boolean isPrime(int n){
for (int f = 2; f < n / 2; f++) {
if (n % f == 0) {
return false;
}
}
return true;
}
}
Output:
Enter low range:
10
Enter high range:
30
11 13 17 19 23 29
Solution
PrimeRange.java
import java.util.Scanner;
public class PrimeRange {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter low range:\");
int low = scan.nextInt();
System.out.println(\"Enter high range:\");
int high = scan.nextInt();
for(int i=low; i<=high; i++){
if(isPrime(i))
System.out.print(i+\" \");
}
}
public static boolean isPrime(int n){
for (int f = 2; f < n / 2; f++) {
if (n % f == 0) {
return false;
}
}
return true;
}
}
Output:
Enter low range:
10
Enter high range:
30
11 13 17 19 23 29.
Throwing.javaimport java.util.InputMismatchException; import jav.pdf
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer.
Solution
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer..
CountStringCharacters.javaimport java.util.Scanner; public cla.pdf
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i
Solution
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i.
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44
Solution
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Recommended
PrimeRange.java import java.util.Scanner;public class PrimeRan.pdf
PrimeRange.java
import java.util.Scanner;
public class PrimeRange {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter low range:\");
int low = scan.nextInt();
System.out.println(\"Enter high range:\");
int high = scan.nextInt();
for(int i=low; i<=high; i++){
if(isPrime(i))
System.out.print(i+\" \");
}
}
public static boolean isPrime(int n){
for (int f = 2; f < n / 2; f++) {
if (n % f == 0) {
return false;
}
}
return true;
}
}
Output:
Enter low range:
10
Enter high range:
30
11 13 17 19 23 29
Solution
PrimeRange.java
import java.util.Scanner;
public class PrimeRange {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter low range:\");
int low = scan.nextInt();
System.out.println(\"Enter high range:\");
int high = scan.nextInt();
for(int i=low; i<=high; i++){
if(isPrime(i))
System.out.print(i+\" \");
}
}
public static boolean isPrime(int n){
for (int f = 2; f < n / 2; f++) {
if (n % f == 0) {
return false;
}
}
return true;
}
}
Output:
Enter low range:
10
Enter high range:
30
11 13 17 19 23 29.
Throwing.javaimport java.util.InputMismatchException; import jav.pdf
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer.
Solution
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer..
CountStringCharacters.javaimport java.util.Scanner; public cla.pdf
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i
Solution
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i.
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44
Solution
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45
Solution
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45.
Codeimport java.util.Random; import java.util.Scanner;public .pdf
Code:
import java.util.Random;
import java.util.Scanner;
public class Test{
public static void main(String args[]){
Scanner input = new Scanner(System.in);
String bin = \"1\";
int n;
System.out.print(\"Enter the number of binary digits : \");
n = input.nextInt();
for(int i = 0; i < n-1; i++){
bin += randomBin();
}
System.out.println(bin);
}
public static String randomBin() {
Random rg = new Random();
int n = rg.nextInt(2);
return Integer.toBinaryString(n);
}
}
Output:
Enter the number of binary digits : 5
10110
Solution
Code:
import java.util.Random;
import java.util.Scanner;
public class Test{
public static void main(String args[]){
Scanner input = new Scanner(System.in);
String bin = \"1\";
int n;
System.out.print(\"Enter the number of binary digits : \");
n = input.nextInt();
for(int i = 0; i < n-1; i++){
bin += randomBin();
}
System.out.println(bin);
}
public static String randomBin() {
Random rg = new Random();
int n = rg.nextInt(2);
return Integer.toBinaryString(n);
}
}
Output:
Enter the number of binary digits : 5
10110.
Problem1 java codeimport java.util.Scanner; Java code to pr.pdf
// Problem1 java code
import java.util.Scanner;
// Java code to print all possible strings of letter L and R
class Problem1 {
static void print(char set[], int length) {
int setLength = set.length;
printRecursion(set, \"\", setLength, length);
}
static void printRecursion(char set[], String prefixset, int setLength, int length) {
// Base case: length is 0
if (length == 0) {
System.out.println(prefixset);
return;
}
for (int i = 0; i < setLength; ++i) {
String newPrefixset = prefixset + set[i];
printRecursion(set, newPrefixset, setLength, length - 1);
}
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter length: \");
int length = scan.nextInt();
char set[] = {\'L\', \'R\'};
print(set, length);
}
}
/*
output:
Enter length:
3
LLL
LLR
LRL
LRR
RLL
RLR
RRL
RRR
*/
// Problem2 java code
import java.util.Scanner;
// Java code to print all possible strings of letter L and R
class Problem2 {
static void print(char set[], int length) {
int setLength = set.length;
printRecursion(set, \"\", setLength, length);
}
static void printRecursion(char set[], String prefixset, int setLength, int length) {
// Base case: length is 0
if (length == 0) {
System.out.print(prefixset + \" \");
return;
}
for (int i = 0; i < setLength; ++i) {
String newPrefixset = prefixset + set[i];
printRecursion(set, newPrefixset, setLength, length - 1);
}
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter length: \");
int length = scan.nextInt();
char set[] = {\'1\', \'3\', \'5\', \'7\', \'9\'};
print(set, length);
System.out.println();
}
}
/*
output:
Enter length:
3
111 113 115 117 119 131 133 135 137 139 151 153 155
157 159 171 173 175 177 179 191 193 195 197 199 311
313 315 317 319 331 333 335 337 339 351 353 355 357
359 371 373 375 377 379 391 393 395 397 399 511 513
515 517 519 531 533 535 537 539 551 553 555 557 559
571 573 575 577 579 591 593 595 597 599 711 713 715
717 719 731 733 735 737 739 751 753 755 757 759 771
773 775 777 779 791 793 795 797 799 911 913 915 917
919 931 933 935 937 939 951 953 955 957 959 971 973
975 977 979 991 993 995 997 999
*/
// Problem3 java code
import java.util.Scanner;
// Java code to multiply 2 numbers
class Problem3 {
public static int multiply(int a, int b)
{
int temp = b;
for (int i = 1; i < a; i++ ) {
b = b + temp;
}
return b;
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter a: \");
int a = scan.nextInt();
System.out.println(\"Enter b: \");
int b = scan.nextInt();
System.out.println(a + \"X\" + b + \" = \" + multiply(a,b));
}
}
/*
output:
Enter a:
7
Enter b:
6
7X6 = 42
*/
// Problem4 java code
import java.util.Scanner;
// Java code to find gcd 2 numbers
class Problem4 {
public static int gcd(int a, int b)
{
if (b!=0)
return gcd(b, a%b);
else
return a;
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter a: \");
int a = scan.ne.
Java AssignmentWrite a program using sortingsorting bubble,sele.pdf
Java Assignment
Write a program using sorting
sorting: bubble,selection,insertion,quick,merge
Solution
Bubble Sort:
import java.util.Scanner;
class SortBubble {
public static void main(String []args) {
int number, c, d, swap;
Scanner in = new Scanner(System.in);
System.out.println(\"Please enter the number of elements to be sorted\");
number = in.nextInt();
int ar[] = new int[number];
System.out.println(\"Enter \" + number + \" integers\");
for (int i = 0; i < number; i++)
ar[i] = in.nextInt();
for (int i = 0; i < ( number - 1 ); i++) {
for (int j = 0; j < number - c - 1; j++) {
if (ar[j] > ar[j+1])
{
swap = ar[j]];
ar[j] = ar[j+1];
ar[j+1] = swap;
}
}
}
System.out.println(\"Sorted list of numbers\");
for (int c = 0; c < number; c++)
System.out.println(ar[c]);
}
}
b) Selection Sort:
public class SortSelection {
public static int[] sort(int[] arr){
for (int i = 0; i < arr.length - 1; i++)
{
int index = i;
for (int j = i + 1; j < arr.length; j++)
if (arr[j] < arr[index])
index = j;
int temp= arr[index];
arr[index] = arr[i];
arr[i] = temp;
}
return arr;
}
public static void main(String a[]){
int[] arr1 = {10,34,2,56,7,67,88,42};
int[] arr2 = sort(arr1);
for(int i:arr2){
System.out.print(i);
System.out.print(\", \");
}
}
}
c) Insertion
public class SortInsertion {
public static void main(String[] args) {
int[] array= { 4, 2, 9, 6, 23, 12, 34, 0, 1 };
sort(array);
}
static void printNumbers(int[] input) {
for (int i = 0; i < array.length; i++) {
System.out.print(array[i] + \", \");
}
System.out.println(\"\ \");
}
public static void sort(int array[]) {
int n = array.length;
for (int j = 1; j < n; j++) {
int key = array[j];
int i = j-1;
while ( (i > -1) && ( array [i] > key ) ) {
array [i+1] = array [i];
i--;
}
array[i+1] = key;
printNumbers(array);
}
}
}
d) Quick Sort:
public class SortQuick {
int array[];
int length;
public void sort(int[] inputArr) {
if (inputArr == null || inputArr.length == 0) {
return;
}
this.array = inputArr;
length = inputArr.length;
quickSort(0, length - 1);
}
private void quickSort(int lowerIndex, int higherIndex) {
int i = lowerIndex;
int j = higherIndex;
int pivot = array[lowerIndex+(higherIndex-lowerIndex)/2];
while (i <= j) {
while (array[i] < pivot) {
i++;
}
while (array[j] > pivot) {
j--;
}
if (i <= j) {
exchangeNumbers(i, j);
i++;
j--;
}
}
if (lowerIndex < j)
quickSort(lowerIndex, j);
if (i < higherIndex)
quickSort(i, higherIndex);
}
private void exchangeNumbers(int i, int j) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
public static void main(String a[]){
MyQuickSort sorter = new MyQuickSort();
int[] input = {24,2,45,20,56,75,2,56,99,53,12};
sorter.sort(input);
for(int i:input){
System.out.print(i);
System.out.print(\" \");
}
}
}.
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...Sunil Kumar Gunasekaran
The three components of a nucleotide ... Sugar -.pdf
The three components of a nucleotide ... Sugar - Either ribose or deoxyribose (in
RNA or DNA) Nitrogenous base - Adenine, guanine, cytosine, thymine (only in DNA), uracil
(only in RNA) Phosphates - One to three, two of which are usually hydrolyzed to provide the
energy to attach the nucleotide and form the phosphodiester bond
Solution
The three components of a nucleotide ... Sugar - Either ribose or deoxyribose (in
RNA or DNA) Nitrogenous base - Adenine, guanine, cytosine, thymine (only in DNA), uracil
(only in RNA) Phosphates - One to three, two of which are usually hydrolyzed to provide the
energy to attach the nucleotide and form the phosphodiester bond.
The alcohol is a secondary alcohol,therefore must.pdf
The alcohol is a secondary alcohol,therefore must have been made from reduction
(using metalhydrides) of ketones (It\'s not letting me insert diagrams, but the structure is1-
phenyl-2-propanone)
Solution
The alcohol is a secondary alcohol,therefore must have been made from reduction
(using metalhydrides) of ketones (It\'s not letting me insert diagrams, but the structure is1-
phenyl-2-propanone).
rate = K[R1][R2] Order of the reaction is the sum.pdf
rate = K[R1][R2] Order of the reaction is the sum of the powers of the
concentration terms of the reactants in the rate expression. So order = 1+1 = 2 ---> 2nd order
reaction
Solution
rate = K[R1][R2] Order of the reaction is the sum of the powers of the
concentration terms of the reactants in the rate expression. So order = 1+1 = 2 ---> 2nd order
reaction.
moles of Fe = 1.2656 = 0.0225 moles of O2 = (1.8.pdf
moles of Fe = 1.26/56 = 0.0225 moles of O2 = (1.8-1.26)/16 = 0.03375 so, for
every atom of Fe there is 3/2 moles of O so, empirical formula is Fe2O3
Solution
moles of Fe = 1.26/56 = 0.0225 moles of O2 = (1.8-1.26)/16 = 0.03375 so, for
every atom of Fe there is 3/2 moles of O so, empirical formula is Fe2O3.
In SO2, the charge of O is 2(-2)= -4 so the charg.pdf
In SO2, the charge of O is 2(-2)= -4 so the charge of S is +4. In H2SO4, the charge
of O is 4(-2)= -8, the charge of H is 2(+1)= +2, so the charge of S is +6. Since S +4 becomes S
+6, electrons are lost, and this is oxidation. So, SO2 is the substance oxidized, and it is also the
reducing agent. The other reactant, HNO3, is the substance reduced, and it is the oxidizing agent.
Solution
In SO2, the charge of O is 2(-2)= -4 so the charge of S is +4. In H2SO4, the charge
of O is 4(-2)= -8, the charge of H is 2(+1)= +2, so the charge of S is +6. Since S +4 becomes S
+6, electrons are lost, and this is oxidation. So, SO2 is the substance oxidized, and it is also the
reducing agent. The other reactant, HNO3, is the substance reduced, and it is the oxidizing agent..
Elution order is based on the polarities of the c.pdf
Elution order is based on the polarities of the compounds. Remember the saying
\"like dissolves like\" when thinking about theanswer. The mobile phase starts out very non-polar
usinghexanes; so the compound that will elute first is the mostnon-polar compound. The
compound that is more polar than oneof the other compounds but not as polar as the third
compound willelute second, and the most polar compound will elute third. Adding
dichloromethane speeds up the elution of the more polarcompounds. Naphthalene is the most
non-polar compound due tothe fact that it only has carbons and hydrogens. Fluorenol ismostly
carbons and hydrogens, but it contains a hydroxy groupmaking it a little more polar than
naphthalene. o-Toluic acidcontains a carboxylic acid group making it the most polar
compoundof the three. So, the elution order for these three compoundsis: naphthalene, then
fluorenol, and then o-toluic acid.
Solution
Elution order is based on the polarities of the compounds. Remember the saying
\"like dissolves like\" when thinking about theanswer. The mobile phase starts out very non-polar
usinghexanes; so the compound that will elute first is the mostnon-polar compound. The
compound that is more polar than oneof the other compounds but not as polar as the third
compound willelute second, and the most polar compound will elute third. Adding
dichloromethane speeds up the elution of the more polarcompounds. Naphthalene is the most
non-polar compound due tothe fact that it only has carbons and hydrogens. Fluorenol ismostly
carbons and hydrogens, but it contains a hydroxy groupmaking it a little more polar than
naphthalene. o-Toluic acidcontains a carboxylic acid group making it the most polar
compoundof the three. So, the elution order for these three compoundsis: naphthalene, then
fluorenol, and then o-toluic acid..
D. p-electrons in CI(Z = 17) .pdf
D. p-electrons in CI(Z = 17)
Solution
D. p-electrons in CI(Z = 17).
More Related Content
Similar to import java.util.Scanner; public class Palin { public static v.pdf
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45
Solution
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45.
Codeimport java.util.Random; import java.util.Scanner;public .pdf
Code:
import java.util.Random;
import java.util.Scanner;
public class Test{
public static void main(String args[]){
Scanner input = new Scanner(System.in);
String bin = \"1\";
int n;
System.out.print(\"Enter the number of binary digits : \");
n = input.nextInt();
for(int i = 0; i < n-1; i++){
bin += randomBin();
}
System.out.println(bin);
}
public static String randomBin() {
Random rg = new Random();
int n = rg.nextInt(2);
return Integer.toBinaryString(n);
}
}
Output:
Enter the number of binary digits : 5
10110
Solution
Code:
import java.util.Random;
import java.util.Scanner;
public class Test{
public static void main(String args[]){
Scanner input = new Scanner(System.in);
String bin = \"1\";
int n;
System.out.print(\"Enter the number of binary digits : \");
n = input.nextInt();
for(int i = 0; i < n-1; i++){
bin += randomBin();
}
System.out.println(bin);
}
public static String randomBin() {
Random rg = new Random();
int n = rg.nextInt(2);
return Integer.toBinaryString(n);
}
}
Output:
Enter the number of binary digits : 5
10110.
Problem1 java codeimport java.util.Scanner; Java code to pr.pdf
// Problem1 java code
import java.util.Scanner;
// Java code to print all possible strings of letter L and R
class Problem1 {
static void print(char set[], int length) {
int setLength = set.length;
printRecursion(set, \"\", setLength, length);
}
static void printRecursion(char set[], String prefixset, int setLength, int length) {
// Base case: length is 0
if (length == 0) {
System.out.println(prefixset);
return;
}
for (int i = 0; i < setLength; ++i) {
String newPrefixset = prefixset + set[i];
printRecursion(set, newPrefixset, setLength, length - 1);
}
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter length: \");
int length = scan.nextInt();
char set[] = {\'L\', \'R\'};
print(set, length);
}
}
/*
output:
Enter length:
3
LLL
LLR
LRL
LRR
RLL
RLR
RRL
RRR
*/
// Problem2 java code
import java.util.Scanner;
// Java code to print all possible strings of letter L and R
class Problem2 {
static void print(char set[], int length) {
int setLength = set.length;
printRecursion(set, \"\", setLength, length);
}
static void printRecursion(char set[], String prefixset, int setLength, int length) {
// Base case: length is 0
if (length == 0) {
System.out.print(prefixset + \" \");
return;
}
for (int i = 0; i < setLength; ++i) {
String newPrefixset = prefixset + set[i];
printRecursion(set, newPrefixset, setLength, length - 1);
}
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter length: \");
int length = scan.nextInt();
char set[] = {\'1\', \'3\', \'5\', \'7\', \'9\'};
print(set, length);
System.out.println();
}
}
/*
output:
Enter length:
3
111 113 115 117 119 131 133 135 137 139 151 153 155
157 159 171 173 175 177 179 191 193 195 197 199 311
313 315 317 319 331 333 335 337 339 351 353 355 357
359 371 373 375 377 379 391 393 395 397 399 511 513
515 517 519 531 533 535 537 539 551 553 555 557 559
571 573 575 577 579 591 593 595 597 599 711 713 715
717 719 731 733 735 737 739 751 753 755 757 759 771
773 775 777 779 791 793 795 797 799 911 913 915 917
919 931 933 935 937 939 951 953 955 957 959 971 973
975 977 979 991 993 995 997 999
*/
// Problem3 java code
import java.util.Scanner;
// Java code to multiply 2 numbers
class Problem3 {
public static int multiply(int a, int b)
{
int temp = b;
for (int i = 1; i < a; i++ ) {
b = b + temp;
}
return b;
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter a: \");
int a = scan.nextInt();
System.out.println(\"Enter b: \");
int b = scan.nextInt();
System.out.println(a + \"X\" + b + \" = \" + multiply(a,b));
}
}
/*
output:
Enter a:
7
Enter b:
6
7X6 = 42
*/
// Problem4 java code
import java.util.Scanner;
// Java code to find gcd 2 numbers
class Problem4 {
public static int gcd(int a, int b)
{
if (b!=0)
return gcd(b, a%b);
else
return a;
}
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
System.out.println(\"Enter a: \");
int a = scan.ne.
Java AssignmentWrite a program using sortingsorting bubble,sele.pdf
Java Assignment
Write a program using sorting
sorting: bubble,selection,insertion,quick,merge
Solution
Bubble Sort:
import java.util.Scanner;
class SortBubble {
public static void main(String []args) {
int number, c, d, swap;
Scanner in = new Scanner(System.in);
System.out.println(\"Please enter the number of elements to be sorted\");
number = in.nextInt();
int ar[] = new int[number];
System.out.println(\"Enter \" + number + \" integers\");
for (int i = 0; i < number; i++)
ar[i] = in.nextInt();
for (int i = 0; i < ( number - 1 ); i++) {
for (int j = 0; j < number - c - 1; j++) {
if (ar[j] > ar[j+1])
{
swap = ar[j]];
ar[j] = ar[j+1];
ar[j+1] = swap;
}
}
}
System.out.println(\"Sorted list of numbers\");
for (int c = 0; c < number; c++)
System.out.println(ar[c]);
}
}
b) Selection Sort:
public class SortSelection {
public static int[] sort(int[] arr){
for (int i = 0; i < arr.length - 1; i++)
{
int index = i;
for (int j = i + 1; j < arr.length; j++)
if (arr[j] < arr[index])
index = j;
int temp= arr[index];
arr[index] = arr[i];
arr[i] = temp;
}
return arr;
}
public static void main(String a[]){
int[] arr1 = {10,34,2,56,7,67,88,42};
int[] arr2 = sort(arr1);
for(int i:arr2){
System.out.print(i);
System.out.print(\", \");
}
}
}
c) Insertion
public class SortInsertion {
public static void main(String[] args) {
int[] array= { 4, 2, 9, 6, 23, 12, 34, 0, 1 };
sort(array);
}
static void printNumbers(int[] input) {
for (int i = 0; i < array.length; i++) {
System.out.print(array[i] + \", \");
}
System.out.println(\"\ \");
}
public static void sort(int array[]) {
int n = array.length;
for (int j = 1; j < n; j++) {
int key = array[j];
int i = j-1;
while ( (i > -1) && ( array [i] > key ) ) {
array [i+1] = array [i];
i--;
}
array[i+1] = key;
printNumbers(array);
}
}
}
d) Quick Sort:
public class SortQuick {
int array[];
int length;
public void sort(int[] inputArr) {
if (inputArr == null || inputArr.length == 0) {
return;
}
this.array = inputArr;
length = inputArr.length;
quickSort(0, length - 1);
}
private void quickSort(int lowerIndex, int higherIndex) {
int i = lowerIndex;
int j = higherIndex;
int pivot = array[lowerIndex+(higherIndex-lowerIndex)/2];
while (i <= j) {
while (array[i] < pivot) {
i++;
}
while (array[j] > pivot) {
j--;
}
if (i <= j) {
exchangeNumbers(i, j);
i++;
j--;
}
}
if (lowerIndex < j)
quickSort(lowerIndex, j);
if (i < higherIndex)
quickSort(i, higherIndex);
}
private void exchangeNumbers(int i, int j) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
public static void main(String a[]){
MyQuickSort sorter = new MyQuickSort();
int[] input = {24,2,45,20,56,75,2,56,99,53,12};
sorter.sort(input);
for(int i:input){
System.out.print(i);
System.out.print(\" \");
}
}
}.
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...Sunil Kumar Gunasekaran
Similar to import java.util.Scanner; public class Palin { public static v.pdf (13)
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
Codeimport java.util.Random; import java.util.Scanner;public .pdf
Codeimport java.util.Random; import java.util.Scanner;public .pdf
Problem1 java codeimport java.util.Scanner; Java code to pr.pdf
Problem1 java codeimport java.util.Scanner; Java code to pr.pdf
Java AssignmentWrite a program using sortingsorting bubble,sele.pdf
Java AssignmentWrite a program using sortingsorting bubble,sele.pdf
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...
Java programs - bubble sort, iterator, linked list, hash set, reverse string,...
More from LAMJM
The three components of a nucleotide ... Sugar -.pdf
The three components of a nucleotide ... Sugar - Either ribose or deoxyribose (in
RNA or DNA) Nitrogenous base - Adenine, guanine, cytosine, thymine (only in DNA), uracil
(only in RNA) Phosphates - One to three, two of which are usually hydrolyzed to provide the
energy to attach the nucleotide and form the phosphodiester bond
Solution
The three components of a nucleotide ... Sugar - Either ribose or deoxyribose (in
RNA or DNA) Nitrogenous base - Adenine, guanine, cytosine, thymine (only in DNA), uracil
(only in RNA) Phosphates - One to three, two of which are usually hydrolyzed to provide the
energy to attach the nucleotide and form the phosphodiester bond.
The alcohol is a secondary alcohol,therefore must.pdf
The alcohol is a secondary alcohol,therefore must have been made from reduction
(using metalhydrides) of ketones (It\'s not letting me insert diagrams, but the structure is1-
phenyl-2-propanone)
Solution
The alcohol is a secondary alcohol,therefore must have been made from reduction
(using metalhydrides) of ketones (It\'s not letting me insert diagrams, but the structure is1-
phenyl-2-propanone).
rate = K[R1][R2] Order of the reaction is the sum.pdf
rate = K[R1][R2] Order of the reaction is the sum of the powers of the
concentration terms of the reactants in the rate expression. So order = 1+1 = 2 ---> 2nd order
reaction
Solution
rate = K[R1][R2] Order of the reaction is the sum of the powers of the
concentration terms of the reactants in the rate expression. So order = 1+1 = 2 ---> 2nd order
reaction.
moles of Fe = 1.2656 = 0.0225 moles of O2 = (1.8.pdf
moles of Fe = 1.26/56 = 0.0225 moles of O2 = (1.8-1.26)/16 = 0.03375 so, for
every atom of Fe there is 3/2 moles of O so, empirical formula is Fe2O3
Solution
moles of Fe = 1.26/56 = 0.0225 moles of O2 = (1.8-1.26)/16 = 0.03375 so, for
every atom of Fe there is 3/2 moles of O so, empirical formula is Fe2O3.
In SO2, the charge of O is 2(-2)= -4 so the charg.pdf
In SO2, the charge of O is 2(-2)= -4 so the charge of S is +4. In H2SO4, the charge
of O is 4(-2)= -8, the charge of H is 2(+1)= +2, so the charge of S is +6. Since S +4 becomes S
+6, electrons are lost, and this is oxidation. So, SO2 is the substance oxidized, and it is also the
reducing agent. The other reactant, HNO3, is the substance reduced, and it is the oxidizing agent.
Solution
In SO2, the charge of O is 2(-2)= -4 so the charge of S is +4. In H2SO4, the charge
of O is 4(-2)= -8, the charge of H is 2(+1)= +2, so the charge of S is +6. Since S +4 becomes S
+6, electrons are lost, and this is oxidation. So, SO2 is the substance oxidized, and it is also the
reducing agent. The other reactant, HNO3, is the substance reduced, and it is the oxidizing agent..
Elution order is based on the polarities of the c.pdf
Elution order is based on the polarities of the compounds. Remember the saying
\"like dissolves like\" when thinking about theanswer. The mobile phase starts out very non-polar
usinghexanes; so the compound that will elute first is the mostnon-polar compound. The
compound that is more polar than oneof the other compounds but not as polar as the third
compound willelute second, and the most polar compound will elute third. Adding
dichloromethane speeds up the elution of the more polarcompounds. Naphthalene is the most
non-polar compound due tothe fact that it only has carbons and hydrogens. Fluorenol ismostly
carbons and hydrogens, but it contains a hydroxy groupmaking it a little more polar than
naphthalene. o-Toluic acidcontains a carboxylic acid group making it the most polar
compoundof the three. So, the elution order for these three compoundsis: naphthalene, then
fluorenol, and then o-toluic acid.
Solution
Elution order is based on the polarities of the compounds. Remember the saying
\"like dissolves like\" when thinking about theanswer. The mobile phase starts out very non-polar
usinghexanes; so the compound that will elute first is the mostnon-polar compound. The
compound that is more polar than oneof the other compounds but not as polar as the third
compound willelute second, and the most polar compound will elute third. Adding
dichloromethane speeds up the elution of the more polarcompounds. Naphthalene is the most
non-polar compound due tothe fact that it only has carbons and hydrogens. Fluorenol ismostly
carbons and hydrogens, but it contains a hydroxy groupmaking it a little more polar than
naphthalene. o-Toluic acidcontains a carboxylic acid group making it the most polar
compoundof the three. So, the elution order for these three compoundsis: naphthalene, then
fluorenol, and then o-toluic acid..
D. p-electrons in CI(Z = 17) .pdf
D. p-electrons in CI(Z = 17)
Solution
D. p-electrons in CI(Z = 17).
CO carbon monooxide nitrogen oxides, sulfur dioxi.pdf
CO carbon monooxide nitrogen oxides, sulfur dioxide, particulates, and polycyclic
aromatic hydrocarbons (PAHs),
Solution
CO carbon monooxide nitrogen oxides, sulfur dioxide, particulates, and polycyclic
aromatic hydrocarbons (PAHs),.
XSCID - Human Severe Combined Immunodeficiency SyndromeIt is an P.pdf
XSCID :- Human Severe Combined Immunodeficiency Syndrome
It is an Primary Immunodeficiency disorder, which caused due to mutation in the gene on the X
Chromosome,that is essential for T cell growth factor(Gamma c) for formation of Gamma Chain,
due to which T cells wont differentiate thus T cells will decrease in count along with NK cells,
but the B cells will be very high,where T cells plays an vital role in the eradication of pathogens
from the body,not completed by the B cells due to absence of its receptors, so it causes
dysfunction,imbalance in the system thus causes immunodeficiency.
It is reported in high number due to X linked defective gene, nearly 45% of all cases are reported
as X SCID.
Difference between X SCID and IL2 deficiency :-
Comparision : Both are immuno deficiency, caused due to impaired T cell differentiation, except
few most of the symptoms are quite similar,
Il2 deficiency is due to alpha receptor dysfunction is also called CD25
dysfunction.S.NoFeatureX SCIDIL2 deficiency1EpidemiologyReport more casesRare
cases2SeverityMore severe due to absence of T cells, high B cellsPoor differentiation of T and B
cells3Phenotypic appearancePrimary ImmunodeficiencyResembles like immune syndromes like
Polyendocrinopathy, IPEX4SymptomsSensitive for diseases, no characteristic
locationInflammation of lymphatic tissues like lung,liver,gut bone.
Solution
XSCID :- Human Severe Combined Immunodeficiency Syndrome
It is an Primary Immunodeficiency disorder, which caused due to mutation in the gene on the X
Chromosome,that is essential for T cell growth factor(Gamma c) for formation of Gamma Chain,
due to which T cells wont differentiate thus T cells will decrease in count along with NK cells,
but the B cells will be very high,where T cells plays an vital role in the eradication of pathogens
from the body,not completed by the B cells due to absence of its receptors, so it causes
dysfunction,imbalance in the system thus causes immunodeficiency.
It is reported in high number due to X linked defective gene, nearly 45% of all cases are reported
as X SCID.
Difference between X SCID and IL2 deficiency :-
Comparision : Both are immuno deficiency, caused due to impaired T cell differentiation, except
few most of the symptoms are quite similar,
Il2 deficiency is due to alpha receptor dysfunction is also called CD25
dysfunction.S.NoFeatureX SCIDIL2 deficiency1EpidemiologyReport more casesRare
cases2SeverityMore severe due to absence of T cells, high B cellsPoor differentiation of T and B
cells3Phenotypic appearancePrimary ImmunodeficiencyResembles like immune syndromes like
Polyendocrinopathy, IPEX4SymptomsSensitive for diseases, no characteristic
locationInflammation of lymphatic tissues like lung,liver,gut bone..
p = 0.25n = 1000standard error, SE = sqrt(p(1-p)n)SE = sq.pdf
p = 0.25
n = 1000
standard error, SE = sqrt(p(1-p)/n)
SE = sqrt(0.25(1-0.25) / 1000) = 0.0137
.
proportion of flights within 3%
= P(-0.03/0.0137
= P( (-0.03 / 0.0137)
Solution
p = 0.25
n = 1000
standard error, SE = sqrt(p(1-p)/n)
SE = sqrt(0.25(1-0.25) / 1000) = 0.0137
.
proportion of flights within 3%
= P(-0.03/0.0137
= P( (-0.03 / 0.0137).
CaO is the lewis base (accepts electrons). SO2 is.pdf
CaO is the lewis base (accepts electrons). SO2 is the lewis acid (donates electrons).
Solution
CaO is the lewis base (accepts electrons). SO2 is the lewis acid (donates electrons)..
The thrust to weight ratio must be higer than one in order to get (V.pdf
The thrust to weight ratio must be higer than one in order to get (VTOL) Vertical lift off and
landing. This ratio must be greater than one to lift from the ground with the thrust vector pointed
downward during take off and pointed back ward during normal flight. In earlier days the main
problem with these aircraft was that thier control was too dificult and the maintenence of engine
was difficult too. In this way accident rate or ratio was too high. SO , Harrier was the first air
craft with successfull VTOL. There were four vectorizing Nozzels which could be turned
vectorially from 0 to 98degrees. WIth the reaction control system with the extra set of small
thruster there were no air stream in hover flight accross any control system . Harrier was prior to
preveous such jets because of its high roll rate, a small turn radius , and its ability of climb to
high altitude abruptly. Another plus point of Horrier was that it lands just like an ordinary plane
vectoring the thrust to about 45 degree down .
Solution
The thrust to weight ratio must be higer than one in order to get (VTOL) Vertical lift off and
landing. This ratio must be greater than one to lift from the ground with the thrust vector pointed
downward during take off and pointed back ward during normal flight. In earlier days the main
problem with these aircraft was that thier control was too dificult and the maintenence of engine
was difficult too. In this way accident rate or ratio was too high. SO , Harrier was the first air
craft with successfull VTOL. There were four vectorizing Nozzels which could be turned
vectorially from 0 to 98degrees. WIth the reaction control system with the extra set of small
thruster there were no air stream in hover flight accross any control system . Harrier was prior to
preveous such jets because of its high roll rate, a small turn radius , and its ability of climb to
high altitude abruptly. Another plus point of Horrier was that it lands just like an ordinary plane
vectoring the thrust to about 45 degree down ..
Views are virtual tables which are not real tables but are generated.pdf
Views are virtual tables which are not real tables but are generated from base tables
Solution
Views are virtual tables which are not real tables but are generated from base tables.
This was an observational study as the investigators obsereved the e.pdf
This was an observational study as the investigators obsereved the effect of proximity on the
interference of competition between two ants species.
The data that was used were gathered from the earlier studies as well as the research conducted
by the various researchers of the particular institute. They had mapped and censused the data
since the summer of 1985 for the ant population Pogonomyrmex (each of the colony was
labelled individually, and located using coordinates from a fixed origin, using a fixed infrared
theodolite. ), and since 1997 they had mapped and censused every Aphaenogaster member on the
particular site(aggression test was performed).
They studied the nesting pattern.
The age of the colony was percieved by the mating pattern of the ants.
By the cooperation among the habitants they found whether the ants belonged to same colony or
the other.
They saw that there was a significant effect of distance among the colonies,between teo different
species and also among the same species.
Solution
This was an observational study as the investigators obsereved the effect of proximity on the
interference of competition between two ants species.
The data that was used were gathered from the earlier studies as well as the research conducted
by the various researchers of the particular institute. They had mapped and censused the data
since the summer of 1985 for the ant population Pogonomyrmex (each of the colony was
labelled individually, and located using coordinates from a fixed origin, using a fixed infrared
theodolite. ), and since 1997 they had mapped and censused every Aphaenogaster member on the
particular site(aggression test was performed).
They studied the nesting pattern.
The age of the colony was percieved by the mating pattern of the ants.
By the cooperation among the habitants they found whether the ants belonged to same colony or
the other.
They saw that there was a significant effect of distance among the colonies,between teo different
species and also among the same species..
System integrationits defined as the development of carrying organ.pdf
System integration
its defined as the development of carrying organized the element subsystems single system and
certifying the subsystems role organized as a system. In evidence skill, systems integration is the
process of connecting composed changed computing systems and software submissions
substantially or functionally to performance as a corresponding complete
System integration (SI) is as well about calculation value the system, competences that are
conceivable since of connections among subsystems
A system integration cause wants a wide range of services and is possible to be clear by a extent
of information relatively than a complexity of information. These services are likely to contain
software, systems then initiative manner, software and hardware engineering, border, and overall
problematic resolving skills. It is expected that the hitches to be resolved have not stayed solved
earlier but in the widest sense. They are likely to comprise new and interesting complications
with an effort from a comprehensive variety of causes wherever the system integration cause
Vertical integration
Vertical integration is the course of mixing subsystems conferring to their functionality by
making efficient objects also mentioned to as storage tower. The advantage of this technique is
that the integration is done rapidly and includes only the essential sellers, so, this technique is
inexpensive in the small term.
Star integration
It’s also known as spaghetti integration, is a procedure of schemes mixing anywhere to each
system is interrelated to apiece of the residual subsystems. Once detected since the belvedere of
the subsystem which is lifecycle joint, the systems are suggestive of a star, but after the general
diagram of the scheme is accessible, the influences look like spaghetti, from now the title of this
process.
Horizontal integration
Horizontal integration is an mixing way in which a dedicated subsystem is devoted to
announcement among further subsystems. This agrees critical the amount of influences first
unique per subsystem which drive link directly to the ESB. The ESB is skilled of decoding the
border into extra interface. This lets wounding the costs of addition and affords dangerous
suppleness.
Internal ownership
On the other pointer, cost-of-ownership can be significantly advanced than seen in other devices,
since in situation of original or improved functionality, the only conceivable way to tool would
be by applying added silo. Recycling subsystems to generate one more functionality is not
possible.
External (third parties) ownership
A third party is an separate or thing that is complex in a deal then is not one of the leaders then
has a smaller attention. Ownership is most simply established in the case of perceptible property.
But, in the case of intelligent stuff which is critical for software. Most similes of intelligent
possessions favor it as analogous to, then not the identical as, palpable stuff
Solution
System integration.
Solution Function of neuron is to transmit information to the oth.pdf
Solution
:
Function of neuron is to transmit information to the other neuron after processing it.It generates
nerve implulses.Neurones play their role or transmit information through electrical nerve
impulses.These electrical nerve information are generated by the action of some chemicals or we
can say that nerve impulses use electric power generated by chemicals for transmission of
information..
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moles of Fe = 1.2656 = 0.0225 moles of O2 = (1.8.pdf
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In SO2, the charge of O is 2(-2)= -4 so the charg.pdf
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CaO is the lewis base (accepts electrons). SO2 is.pdf
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The thrust to weight ratio must be higer than one in order to get (V.pdf
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Views are virtual tables which are not real tables but are generated.pdf
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This was an observational study as the investigators obsereved the e.pdf
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System integrationits defined as the development of carrying organ.pdf
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Solution1. I=VR=107= 1.4282.SolutionSolution1. I=VR.pdf
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import java.util.Scanner; public class Palin { public static v.pdf
- 1. import java.util.Scanner; public class Palin { public static void main(String args[]) { Scanner s=new Scanner(System.in); System.out.println("enter string : "); String str=s.next(); int i,j; boolean flag=true; for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--) { if(str.charAt(i)!=str.charAt(j)) flag=false; } if(flag==true) System.out.println("palindrome"); else System.out.println("not a palindrome"); } } Solution import java.util.Scanner; public class Palin { public static void main(String args[]) { Scanner s=new Scanner(System.in); System.out.println("enter string : "); String str=s.next(); int i,j; boolean flag=true; for( i=0,j=str.length()-1;i<=str.length()/2;i++,j--)