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1) The document discusses equations for modeling strain in materials due to applied loads and temperature changes. 2) Hooke's law relates stress to strain, and strain can arise from applied loads or temperature changes. 3) Equations are presented to calculate total strain, stress, and temperature coefficients for composite materials made of two components with different material properties.
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Home work
1) The document discusses equations for modeling strain in materials due to applied loads and temperature changes.
2) Hooke's law relates stress to strain, and strain can arise from applied loads or temperature changes.
3) Equations are presented to calculate total strain, stress, and temperature coefficients for composite materials made of two components with different material properties.
Home work
1) The document discusses equations for calculating strain and stress in composite materials made of two components.
2) It presents Hook's law equations relating stress to strain for individual components and accounting for temperature changes.
3) Equations are developed relating the overall composite material's stress, strain, and temperature coefficient to the properties of its individual components, weighted by their relative volumes.
Home work
1) The document discusses equations for calculating strain and stress in composite materials made of two components.
2) It presents Hook's law equations relating stress to strain for individual components and accounting for temperature changes.
3) Equations are developed relating the overall composite material's stress, strain, and temperature coefficient to the properties of its individual components weighted by their relative volumes.
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PCOS corelations and management through Ayurveda.
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
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Home work
- 1. Home work (3): ΔL= ε L0 + BΔm+αΔT Hook’s law: 1-according to load (σ): σ = E εm 2-according to temp change ΔT: εt = α . ΔT Total strain is ε =εm+εt =σ/E + α . ΔT For direction (1): ε1=εf=εm εf=σf/Ef+αf.ΔT σ1 εm=σm/Em +αm.ΔT σf=Ef(εf-αf T) σm=Em(εm-αm.T) σ1=Vf σf + Vm σm σ1=E1(ε1-α1 ΔT) σ1=Vf Ef (εf-αfΔ T)+Vm Em (εm-αm.ΔT) by sub with σ1 E1( ε1-α1 ΔT)= Vf Ef (εf-αfΔ T)+Vm Em (εm-αm.ΔT) We have: ε1=εf=εm We can get: α1 E1 = Vf Ef αf + Vm Em αm
- 2. for direction 2: σ2 σ2=σm=σf ε2=εf Vf+εm Vm ε= σ/E + α . ΔT σ2/E2+α2 ΔT= (σf/Ef+αf ΔT)Vf+(σm/Em+αm ΔT) Vm by solve the last eguation: α2= αf Vf +αm Vm