Here is the code for youimport java.util.; class HeightOfChild.pdf
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Here is the code for you: import java.util.*; class HeightOfChild { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double childHeight; int feet, inches, fatherHeight, motherHeight; while(true) { System.out.print(\"Enter the gender of child (M)ale or (F)emale: \"); char gender = sc.next().charAt(0); System.out.print(\"Choose your input style: 1. Feet & Inches. 2. Inches: \"); int inputStyle = sc.nextInt(); if(inputStyle == 1) { System.out.println(\"Enter the height of the mother: \"); System.out.print(\"Feet: \"); feet = sc.nextInt(); System.out.print(\"Inches: \"); inches = sc.nextInt(); motherHeight = feet * 12 + inches; System.out.println(\"Enter the height of the father: \"); System.out.print(\"Feet: \"); feet = sc.nextInt(); System.out.print(\"Inches: \"); inches = sc.nextInt(); fatherHeight = feet * 12 + inches; } else { System.out.print(\"Enter the height of mother in inches: \"); motherHeight = sc.nextInt(); System.out.print(\"Enter the height of father in inches: \"); fatherHeight = sc.nextInt(); } if(gender == \'M\') childHeight = ((motherHeight * 13 / 12.0) + fatherHeight) / 2; else childHeight = ((fatherHeight * 12 / 13.0) + motherHeight) / 2; System.out.println(\"The height of the child is: \" + childHeight); System.out.print(\"Do you want to calculate again...(Y/N): \"); char again = sc.next().charAt(0); if(again != \'Y\') return; } } } If you need any refinements, just get back to me. Solution Here is the code for you: import java.util.*; class HeightOfChild { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double childHeight; int feet, inches, fatherHeight, motherHeight; while(true) { System.out.print(\"Enter the gender of child (M)ale or (F)emale: \"); char gender = sc.next().charAt(0); System.out.print(\"Choose your input style: 1. Feet & Inches. 2. Inches: \"); int inputStyle = sc.nextInt(); if(inputStyle == 1) { System.out.println(\"Enter the height of the mother: \"); System.out.print(\"Feet: \"); feet = sc.nextInt(); System.out.print(\"Inches: \"); inches = sc.nextInt(); motherHeight = feet * 12 + inches; System.out.println(\"Enter the height of the father: \"); System.out.print(\"Feet: \"); feet = sc.nextInt(); System.out.print(\"Inches: \"); inches = sc.nextInt(); fatherHeight = feet * 12 + inches; } else { System.out.print(\"Enter the height of mother in inches: \"); motherHeight = sc.nextInt(); System.out.print(\"Enter the height of father in inches: \"); fatherHeight = sc.nextInt(); } if(gender == \'M\') childHeight = ((motherHeight * 13 / 12.0) + fatherHeight) / 2; else childHeight = ((fatherHeight * 12 / 13.0) + motherHeight) / 2; System.out.println(\"The height of the child is: \" + childHeight); System.out.print(\"Do you want to calculate again...(Y/N): \"); char again = sc.next().charAt(0); if(again != \'Y\') return; } } } If you need any refinements, just get back to me..
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![Here is the code for you:
import java.util.*;
class HeightOfChild
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
double childHeight;
int feet, inches, fatherHeight, motherHeight;
while(true)
{
System.out.print("Enter the gender of child (M)ale or (F)emale: ");
char gender = sc.next().charAt(0);
System.out.print("Choose your input style: 1. Feet & Inches. 2. Inches: ");
int inputStyle = sc.nextInt();
if(inputStyle == 1)
{
System.out.println("Enter the height of the mother: ");
System.out.print("Feet: ");
feet = sc.nextInt();
System.out.print("Inches: ");
inches = sc.nextInt();
motherHeight = feet * 12 + inches;
System.out.println("Enter the height of the father: ");
System.out.print("Feet: ");
feet = sc.nextInt();
System.out.print("Inches: ");
inches = sc.nextInt();
fatherHeight = feet * 12 + inches;
}
else
{
System.out.print("Enter the height of mother in inches: ");
motherHeight = sc.nextInt();
System.out.print("Enter the height of father in inches: ");](https://image.slidesharecdn.com/hereisthecodeforyouimportjava-230408191931-a8881cfe/85/Here-is-the-code-for-youimport-java-util-class-HeightOfChild-pdf-1-320.jpg)
![fatherHeight = sc.nextInt();
}
if(gender == 'M')
childHeight = ((motherHeight * 13 / 12.0) + fatherHeight) / 2;
else
childHeight = ((fatherHeight * 12 / 13.0) + motherHeight) / 2;
System.out.println("The height of the child is: " + childHeight);
System.out.print("Do you want to calculate again...(Y/N): ");
char again = sc.next().charAt(0);
if(again != 'Y')
return;
}
}
}
If you need any refinements, just get back to me.
Solution
Here is the code for you:
import java.util.*;
class HeightOfChild
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
double childHeight;
int feet, inches, fatherHeight, motherHeight;
while(true)
{
System.out.print("Enter the gender of child (M)ale or (F)emale: ");
char gender = sc.next().charAt(0);
System.out.print("Choose your input style: 1. Feet & Inches. 2. Inches: ");
int inputStyle = sc.nextInt();
if(inputStyle == 1)
{
System.out.println("Enter the height of the mother: ");](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
StudentData.javaimport java.util.Scanner; public class Student.pdf
StudentData.java
import java.util.Scanner;
public class StudentData {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int totalStudents = 0;
int maleCount = 0, femaleCount = 0, minorCount = 0, adultCount = 0, seniorCount = 0;
while(true){
System.out.println(\"Do you ant to add a student (n to stop):\");
char ch = scan.next().charAt(0);
if(ch == \'n\' || ch == \'N\'){
break;
}
else{
System.out.println(\"Enter the student gender (male or female)\");
String gender = scan.next();
if(gender.equalsIgnoreCase(\"male\")){
maleCount++;
}
else{
femaleCount++;
}
System.out.println(\"Enter student age:\");
int age = scan.nextInt();
if(age <= 18){
minorCount++;
}
else if(age >=19 && age <= 65){
adultCount++;
}
else{
seniorCount++;
}
}
}
totalStudents = maleCount + femaleCount;
System.out.println(\"Total Students: \"+totalStudents);
System.out.println(\"Male: \"+maleCount);
System.out.println(\"Female: \"+femaleCount);
System.out.println(\"Minor: \"+minorCount);
System.out.println(\"Adult: \"+adultCount);
System.out.println(\"Senior: \"+seniorCount);
String s = (maleCount >= femaleCount)? \"Students are mre males\":\"Students are more
females\";
System.out.println(s);
}
}
Output:
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
44
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
77
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
12
Do you ant to add a student (n to stop):
yy
Enter the student gender (male or female)
female
Enter student age:
55
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
female
Enter student age:
33
Do you ant to add a student (n to stop):
n
Total Students: 5
Male: 3
Female: 2
Minor: 1
Adult: 3
Senior: 1
Students are mre males
Solution
StudentData.java
import java.util.Scanner;
public class StudentData {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int totalStudents = 0;
int maleCount = 0, femaleCount = 0, minorCount = 0, adultCount = 0, seniorCount = 0;
while(true){
System.out.println(\"Do you ant to add a student (n to stop):\");
char ch = scan.next().charAt(0);
if(ch == \'n\' || ch == \'N\'){
break;
}
else{
System.out.println(\"Enter the student gender (male or female)\");
String gender = scan.next();
if(gender.equalsIgnoreCase(\"male\")){
maleCount++;
}
else{
femaleCount++;
}
System.out.println(\"Enter student age:\");
int age = scan.nextInt();
if(age <= 18){
minorCount++;
}
else if(age >=19 && age <= 65){
adultCount++;
}
else{
seniorCount++;
}
}
}
totalStudents = maleCount + femaleCount;
System.out.println(\"Total Students: \"+totalStudents);
System.out.println(\"Male: \"+maleCount);
System.out.println(\"Female: \"+femaleCount);
System.out.println(\"Minor: \"+minorCount);
System.out.println(\"Adult: \"+adultCount);
System.out.println(\"Senior: \"+seni.
Average.javaimport java.util.Scanner;public class Average{ .pdf
// Average.java
import java.util.Scanner;
public class Average{
public static void main(String[] args){
Scanner input = new Scanner(System.in);
double averageMale = 0, averageFemale = 0;
int countMale = 0, countFemale = 0;
char mf;
double average;
System.out.println(\"How many Students? \");
int n = input.nextInt();
for (int i = 1; i <= n; i++ ) {
System.out.println(\"Is Student \" + i + \" male or female? \");
mf = input.next().charAt(0);
if(mf == \'m\'){
countMale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageMale = averageMale + average;
}
else{
countFemale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageFemale = averageFemale + average;
}
}
System.out.println(\"The \" + countMale + \" male Students average is \" +
averageMale/countMale);
System.out.println(\"The \" + countFemale + \" male Students average is \" +
averageFemale/countFemale);
}
}
/*
output:
How many Students?
5
Is Student 1 male or female?
m
What is Student\'s 1\'s average?
85
Is Student 2 male or female?
m
What is Student\'s 2\'s average?
91
Is Student 3 male or female?
f
What is Student\'s 3\'s average?
95
Is Student 4 male or female?
f
What is Student\'s 4\'s average?
80
Is Student 5 male or female?
m
What is Student\'s 5\'s average?
88
The 3 male Students average is 88.0
The 2 male Students average is 87.5
*/
Solution
// Average.java
import java.util.Scanner;
public class Average{
public static void main(String[] args){
Scanner input = new Scanner(System.in);
double averageMale = 0, averageFemale = 0;
int countMale = 0, countFemale = 0;
char mf;
double average;
System.out.println(\"How many Students? \");
int n = input.nextInt();
for (int i = 1; i <= n; i++ ) {
System.out.println(\"Is Student \" + i + \" male or female? \");
mf = input.next().charAt(0);
if(mf == \'m\'){
countMale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageMale = averageMale + average;
}
else{
countFemale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageFemale = averageFemale + average;
}
}
System.out.println(\"The \" + countMale + \" male Students average is \" +
averageMale/countMale);
System.out.println(\"The \" + countFemale + \" male Students average is \" +
averageFemale/countFemale);
}
}
/*
output:
How many Students?
5
Is Student 1 male or female?
m
What is Student\'s 1\'s average?
85
Is Student 2 male or female?
m
What is Student\'s 2\'s average?
91
Is Student 3 male or female?
f
What is Student\'s 3\'s average?
95
Is Student 4 male or female?
f
What is Student\'s 4\'s average?
80
Is Student 5 male or female?
m
What is Student\'s 5\'s average?
88
The 3 male Students average is 88.0
The 2 male Students average is 87.5
*/.
Review Questions for Exam 10182016 1. public class .pdf
Q3 GIVEN THE TREND EQUATION NO OF STUDENTS-3000+200 YEAR BASE: 2003-0
1.INTERPRET EQUATION RESULTS 2.FORECAST FOR 2020 3.WHEN WILL THE NO OF
STUDENTS REACH 6000
Solution
x no of years from 2003 y no of students y = 3000+200x 1) The regression
equation has a positive slope of 200 y intercept is 3000 i.e. no of students in the year 2000
Thus for every year 200 students increase 2) For 2020, x = 17, y = 3000+200(17) = 6400
3) When y =6000, 6000 = 3000+200x or x = 15 Hence in year 2018 students reach 6000
B Regression C D. All the above.
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
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{
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
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System.out.print(x);
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Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
StudentData.javaimport java.util.Scanner; public class Student.pdf
StudentData.java
import java.util.Scanner;
public class StudentData {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int totalStudents = 0;
int maleCount = 0, femaleCount = 0, minorCount = 0, adultCount = 0, seniorCount = 0;
while(true){
System.out.println(\"Do you ant to add a student (n to stop):\");
char ch = scan.next().charAt(0);
if(ch == \'n\' || ch == \'N\'){
break;
}
else{
System.out.println(\"Enter the student gender (male or female)\");
String gender = scan.next();
if(gender.equalsIgnoreCase(\"male\")){
maleCount++;
}
else{
femaleCount++;
}
System.out.println(\"Enter student age:\");
int age = scan.nextInt();
if(age <= 18){
minorCount++;
}
else if(age >=19 && age <= 65){
adultCount++;
}
else{
seniorCount++;
}
}
}
totalStudents = maleCount + femaleCount;
System.out.println(\"Total Students: \"+totalStudents);
System.out.println(\"Male: \"+maleCount);
System.out.println(\"Female: \"+femaleCount);
System.out.println(\"Minor: \"+minorCount);
System.out.println(\"Adult: \"+adultCount);
System.out.println(\"Senior: \"+seniorCount);
String s = (maleCount >= femaleCount)? \"Students are mre males\":\"Students are more
females\";
System.out.println(s);
}
}
Output:
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
44
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
77
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
male
Enter student age:
12
Do you ant to add a student (n to stop):
yy
Enter the student gender (male or female)
female
Enter student age:
55
Do you ant to add a student (n to stop):
y
Enter the student gender (male or female)
female
Enter student age:
33
Do you ant to add a student (n to stop):
n
Total Students: 5
Male: 3
Female: 2
Minor: 1
Adult: 3
Senior: 1
Students are mre males
Solution
StudentData.java
import java.util.Scanner;
public class StudentData {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int totalStudents = 0;
int maleCount = 0, femaleCount = 0, minorCount = 0, adultCount = 0, seniorCount = 0;
while(true){
System.out.println(\"Do you ant to add a student (n to stop):\");
char ch = scan.next().charAt(0);
if(ch == \'n\' || ch == \'N\'){
break;
}
else{
System.out.println(\"Enter the student gender (male or female)\");
String gender = scan.next();
if(gender.equalsIgnoreCase(\"male\")){
maleCount++;
}
else{
femaleCount++;
}
System.out.println(\"Enter student age:\");
int age = scan.nextInt();
if(age <= 18){
minorCount++;
}
else if(age >=19 && age <= 65){
adultCount++;
}
else{
seniorCount++;
}
}
}
totalStudents = maleCount + femaleCount;
System.out.println(\"Total Students: \"+totalStudents);
System.out.println(\"Male: \"+maleCount);
System.out.println(\"Female: \"+femaleCount);
System.out.println(\"Minor: \"+minorCount);
System.out.println(\"Adult: \"+adultCount);
System.out.println(\"Senior: \"+seni.
Average.javaimport java.util.Scanner;public class Average{ .pdf
// Average.java
import java.util.Scanner;
public class Average{
public static void main(String[] args){
Scanner input = new Scanner(System.in);
double averageMale = 0, averageFemale = 0;
int countMale = 0, countFemale = 0;
char mf;
double average;
System.out.println(\"How many Students? \");
int n = input.nextInt();
for (int i = 1; i <= n; i++ ) {
System.out.println(\"Is Student \" + i + \" male or female? \");
mf = input.next().charAt(0);
if(mf == \'m\'){
countMale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageMale = averageMale + average;
}
else{
countFemale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageFemale = averageFemale + average;
}
}
System.out.println(\"The \" + countMale + \" male Students average is \" +
averageMale/countMale);
System.out.println(\"The \" + countFemale + \" male Students average is \" +
averageFemale/countFemale);
}
}
/*
output:
How many Students?
5
Is Student 1 male or female?
m
What is Student\'s 1\'s average?
85
Is Student 2 male or female?
m
What is Student\'s 2\'s average?
91
Is Student 3 male or female?
f
What is Student\'s 3\'s average?
95
Is Student 4 male or female?
f
What is Student\'s 4\'s average?
80
Is Student 5 male or female?
m
What is Student\'s 5\'s average?
88
The 3 male Students average is 88.0
The 2 male Students average is 87.5
*/
Solution
// Average.java
import java.util.Scanner;
public class Average{
public static void main(String[] args){
Scanner input = new Scanner(System.in);
double averageMale = 0, averageFemale = 0;
int countMale = 0, countFemale = 0;
char mf;
double average;
System.out.println(\"How many Students? \");
int n = input.nextInt();
for (int i = 1; i <= n; i++ ) {
System.out.println(\"Is Student \" + i + \" male or female? \");
mf = input.next().charAt(0);
if(mf == \'m\'){
countMale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageMale = averageMale + average;
}
else{
countFemale++;
System.out.println(\"What is Student\'s \" + i + \"\'s average? \");
average = input.nextDouble();
averageFemale = averageFemale + average;
}
}
System.out.println(\"The \" + countMale + \" male Students average is \" +
averageMale/countMale);
System.out.println(\"The \" + countFemale + \" male Students average is \" +
averageFemale/countFemale);
}
}
/*
output:
How many Students?
5
Is Student 1 male or female?
m
What is Student\'s 1\'s average?
85
Is Student 2 male or female?
m
What is Student\'s 2\'s average?
91
Is Student 3 male or female?
f
What is Student\'s 3\'s average?
95
Is Student 4 male or female?
f
What is Student\'s 4\'s average?
80
Is Student 5 male or female?
m
What is Student\'s 5\'s average?
88
The 3 male Students average is 88.0
The 2 male Students average is 87.5
*/.
Review Questions for Exam 10182016 1. public class .pdf
Q3 GIVEN THE TREND EQUATION NO OF STUDENTS-3000+200 YEAR BASE: 2003-0
1.INTERPRET EQUATION RESULTS 2.FORECAST FOR 2020 3.WHEN WILL THE NO OF
STUDENTS REACH 6000
Solution
x no of years from 2003 y no of students y = 3000+200x 1) The regression
equation has a positive slope of 200 y intercept is 3000 i.e. no of students in the year 2000
Thus for every year 200 students increase 2) For 2020, x = 17, y = 3000+200(17) = 6400
3) When y =6000, 6000 = 3000+200x or x = 15 Hence in year 2018 students reach 6000
B Regression C D. All the above.
In your Person classAdd a constant field to store the current yea.pdf
In your Person class:
Add a constant field to store the current year (review the Week 4 Lesson if you aren\'t sure how
to create a constant) :
Assign a value to the current year field when it is declared (do not add it to the constructors).
Add fields to store a person\'s age in years and how many years they have been with the college:
Do not add mutator or accessor methods for these fields.
Set the visibility modifier to private for these fields.
Modify both constructors to set default values for both fields.
Add processing actions:
Add a method to calculate a person\'s age in years only.
Add a method to calculate how long a person has been in college in years only.
Make both methods private.
Do not take any input or display any output in these methods.
Modify the toString() method:
Call the method to calculate the person\'s age.
Call the method to calculate how long the person has been in college.
Add the person\'s age to the String.
Add the person\'s time in college to the String.
Add output messages for each field so that the user knows what they are looking at.
Format the string using the new line escape sequence \ so that each field and it\'s message is on a
separate line.
*** This is what I have so far
48 class Persons_Information
49 {
50 private String personName;
51 private String currentAdress;
52 private String permanentAdress;
53 private int idNumber;
54 private String birthDate;
55 private int personAge;
56 private int entryYear;
57 private int totalYears;
58
59 public Persons_Information() {
60 personName = \"\";
61 currentAdress = \"\";
62 permanentAdress = \"\";
63 idNumber = 0;
64 birthDate = \"\";
65 personAge = 0;
66 entryYear = 0;
67 totalYears = 0;
68 }
69
70 public Persons_Information (int atIdNumber) {
71 idNumber = atIdNumber;
72 personName = \"\";
73 currentAdress = \"\";
74 permanentAdress = \"\";
75 birthDate = \"\";
76 personAge = 0;
77 entryYear = 0;
78 totalYears = 0;
79 }
80
81 //intput
82
83 public void setPersonName(String personName) {
84 this.personName = personName;
85 }
86
87 public void setCurrentAdress(String currentAdress) {
88 this.currentAdress = currentAdress;
89 }
90
91
92 public void setpermanentAdress(String permanentAdress) {
93 this.permanentAdress = permanentAdress;
94 }
95
96 public void setIdNumber(int id) {
97 idNumber = id;
98 }
99
100 public void setBirthDate(String birthDate) {
101 this.birthDate = birthDate;
102 }
103
104 public void setPersonAge(int pa) {
105 personAge = pa;
106 }
107
108 public void setEntryYear(int ey) {
109 entryYear = ey;
110 }
111
112 public void setTotalYears(int ty) {
113 totalYears = ty;
114 }
115
116 //output
117
118 public String getPersonName() {
119 return personName;
120 }
121
122 public String getCurrentAdress() {
123 return currentAdress;
124 }
125
126 public String getPermanentAdress() {
127 return permanentAdress;
128 }
129
130 public int getIdNumber() {
131 return idNumber;
132 }
133 public String getBirthDate() {
134 return birthDate;
135 }
136
137 pu.
MagicSquareTest.java import java.util.Scanner;public class Mag.pdf
MagicSquareTest.java
import java.util.Scanner;
public class MagicSquareTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter Number of rows:\");
int rows = scan.nextInt();
System.out.println(\"Enter Nummber of columns:\");
int cols = scan.nextInt();
int a[][] = new int[rows][cols];
System.out.println(\"Enter matrix elements;\");
for(int i=0; i
Solution
MagicSquareTest.java
import java.util.Scanner;
public class MagicSquareTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter Number of rows:\");
int rows = scan.nextInt();
System.out.println(\"Enter Nummber of columns:\");
int cols = scan.nextInt();
int a[][] = new int[rows][cols];
System.out.println(\"Enter matrix elements;\");
for(int i=0; i.
Create a menu-driven program that will accept a collection of non-ne.pdf
Create a menu-driven program that will accept a collection of non-negative integers from the
keyboard, calculate the mean and median values and display those values on the screen. Your
menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the
median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit
Program particulars: Use an array of type int to store the integers entered by the user. There
must be error checking on the input integer. If it is negative, the program will print an error
message and re-prompt. This process will continue until a non-negative integer is entered. You
must use a try-catch structure to trap both types of input errors (like letters where numbers
should go) and range errors (like -1). You must write your own selectionSort utility method to
sort your array. Place the method in an external file named SortSearchUtil.java. There must be
error checking on the menu choice entered. If the user enters a choice not on the menu, the
program will print an error message, re-display the menu and re-prompt. This process will
continue until a valid option value is entered. Your solution must be modular. The design of your
methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed.
Your program should be well-documented. Explain what you’re doing in your code. Be sure to
include the usual name and assignment notes. Note your program will have to sort your array
before you can find the median. Include your SortSearchUtil.java file which will contain your
sort method.
This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be
included.
import java.util.Scanner;
public class ArraySorting
{
public static void main(String[] args)
{
int option;
int integer = 0;
int optionOne;
int optionTwo;
int optionThree;
int optionFour;
int optionFive;
int[] numbers = new int[5];
Scanner kb = new Scanner(System.in);
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
while((integer < 0))
{
System.out.println(\"I am sorry that is not a non-negative integer.\");
System.out.println(\"\");
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
}
option = displayMenu(kb);
while (option != 6)
{
switch (option)
{
case 1:
optionOne(numbers);
System.out.println(\"\");
break;
case 2:
optionTwo(numbers);
System.out.println(\"\");
case 3:
//optionThree();
System.out.println(\"\");
break;
case 4:
//optionFour();
System.out.println(\"\");
break;
case 5:
//optionFive();
System.out.println(\"\");
break;
}
option = displayMenu(kb);
}
if (option == 6)
{
System.out.println();
System.out.println(\"Thank you. Have a nice day.\");
}
}
private static int displayMenu(Scanner kb)
{
int option = 0;
while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option
!=6)
{
System.out.println(\"\\t\\t1. Add a number to the array\ \\t\\t2. Display the mean\ \\t\.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}
Solution
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}.
Write a program (any language) to randomly generate the following se.pdf
Write a program (any language) to randomly generate the following sets of data: 1) 10 numbers
2) 1,000 numbers 3) 100,000 numbers 4) 1,000,000 numbers 5) 10,000,000 numbers Your
program must sort the above sets of numbers using the following algorithms: a) Insertion Sort b)
Merge Sort c) Quick Sort d) Heap Sort Print out the time each algorithm takes to sort the above
numbers
Solution
import java.io.*;
publicclass randomNo{
publicstaticvoid main(String[] args) throws NumberFormatException, IOException {
int n1,n2,ch;
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int count = 0;
do
{
System.out.println(\"\ \");
System.out.println(\"Menu:\");
System.out.println(\"1.Insertion Sort\");
System.out.println(\"2.Heap Sort.\");
System.out.println(\"3.Quick SOrt\");
System.out.println(\"4.Merge SOrt\");
System.out.println(\"5.Exit\");
System.out.println(\"Enter your choice: \");
ch=Integer.parseInt(br.readLine());
switch(ch)
{
case 1:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr=newint[n2];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr[i]=Random;
System.out.println(Random);
count++;
}
insertionSort(arr,count);
break;
case 2:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr1=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr1[i]=Random;
System.out.println(Random);
count++;
}
System.out.println(\"\ Before Sorting\");
for(int i=0; i1; i--) {
HeapSort(arr1, i - 1);
}
System.out.println(\"\ Ascending Order\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr1[i]);
}
break;
case 3:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr3=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr3[i]=Random;
System.out.println(Random);
count++;
}
QuickSort(arr3, 0, count-1);
System.out.println(\"\ \ After Sorting\");
System.out.println(\"\ Ascending Order\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr3[i]);
}
break;
case 4:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr2=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr2[i]=Random;
System.out.println(Random);
count++;
}
System.out.println(\"\ Before Sorting\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr2[i]);
}
break;
case 5:
System.out.println(\"Invalid\");
default:
break;
}
}while(ch!=5);
}
//Insertion Sort
publicstaticvoid insertionSort(int arr[],int n){
System.out.println(\"\ Before Sorting :\");
for(int i=0; i 0) && .
Vasarecta is a series of straight capillaries, that lie parallel to .pdf
Vasarecta is a series of straight capillaries, that lie parallel to the loop of Henley. It causes
counter current forces and facilitates to collect ions and water back into blood.
Solution
Vasarecta is a series of straight capillaries, that lie parallel to the loop of Henley. It causes
counter current forces and facilitates to collect ions and water back into blood..
There is no question posted or image attached to answer hereSolu.pdf
There is no question posted or image attached to answer here
Solution
There is no question posted or image attached to answer here.
The technique which is used to exclusively moniter cell death is TRA.pdf
The technique which is used to exclusively moniter cell death is TRAPAN BLUE STAINING. It
is a diazo dye which selectively stains dead cells only. This dye does not get absorbed by the
mebrane of live cells but gets absorbed by dead cells. So dead cells appear blue when viewed in
microscope against a light background. So this method is also known as dye exclusion method.
Solution
The technique which is used to exclusively moniter cell death is TRAPAN BLUE STAINING. It
is a diazo dye which selectively stains dead cells only. This dye does not get absorbed by the
mebrane of live cells but gets absorbed by dead cells. So dead cells appear blue when viewed in
microscope against a light background. So this method is also known as dye exclusion method..
The DNA polymerase is involved in the complementary DNA strand from .pdf
The DNA polymerase is involved in the complementary DNA strand from a template DNA
strand. Therefore, DNA polymerase is an important enzyme in DNA replication and by its
activity two strands of parent DNA molecule are seperated and produce a new daughter strand
two form two DNA molecules. The DNA polymerase identifies the primer which is
complementarily forms base pairing with template strand and adds the deoxynucleotide
triphosphates to extensd the DNA strand.
RNA polymerase is involved in synthesis of RNA using a DNA template strand. The RNA
polymerase binds to promoter region of DNA through the sigma factor. The sigma factor
recognizes the promoter and RNA polymerase binds to promoter to initiate the RNA synthesis.
The ribosomes are the sites of protein synthesis. When mRNA binds to small subunit of
ribosome, it joins with large subunit and initiates the translation or protein synthesis process. The
translation initiation factors involve in binding of mRNA to ribosomes and binding of small and
large subunits. A methinoyl tRNA (tRNA carrying methionine amino acid) attaches to small
subunit along with mRNA and then binds to the large subunit and initiates the transaltion
process.
Solution
The DNA polymerase is involved in the complementary DNA strand from a template DNA
strand. Therefore, DNA polymerase is an important enzyme in DNA replication and by its
activity two strands of parent DNA molecule are seperated and produce a new daughter strand
two form two DNA molecules. The DNA polymerase identifies the primer which is
complementarily forms base pairing with template strand and adds the deoxynucleotide
triphosphates to extensd the DNA strand.
RNA polymerase is involved in synthesis of RNA using a DNA template strand. The RNA
polymerase binds to promoter region of DNA through the sigma factor. The sigma factor
recognizes the promoter and RNA polymerase binds to promoter to initiate the RNA synthesis.
The ribosomes are the sites of protein synthesis. When mRNA binds to small subunit of
ribosome, it joins with large subunit and initiates the translation or protein synthesis process. The
translation initiation factors involve in binding of mRNA to ribosomes and binding of small and
large subunits. A methinoyl tRNA (tRNA carrying methionine amino acid) attaches to small
subunit along with mRNA and then binds to the large subunit and initiates the transaltion
process..
The common name of Nymphaea nouchali is blue lotus, star lotus, red .pdf
The common name of Nymphaea nouchali is blue lotus, star lotus, red or blue water lily. It
belongs to the family of Nymphaeaceae. It is found in Afghanistan, the Indian subcontinent,
South-east Asia, Thialand, Myanmar, Australia,
Nymphaea nouchali is used as an ornamental plant, medicinal plant in Indian Ayurvedic
medicine, as food items, and for animal forage.
It holds great importance in Egyptian mythology, in which it was associated with the concepts of
after life and rebirth. The flower symbolises enlightenment and renewal of consciousness of the
death. It is also used as a symbol of divine.
Due to its psychoactive composition it was used by the religious people to achieve an state of
meditative ectasy. This could be attributed to the presence of phtyosterol compounds present in
the flower. They could also contain Apomorphine and Nuciferine, which are atropine like
compound having intoxicating effects.
Solution
The common name of Nymphaea nouchali is blue lotus, star lotus, red or blue water lily. It
belongs to the family of Nymphaeaceae. It is found in Afghanistan, the Indian subcontinent,
South-east Asia, Thialand, Myanmar, Australia,
Nymphaea nouchali is used as an ornamental plant, medicinal plant in Indian Ayurvedic
medicine, as food items, and for animal forage.
It holds great importance in Egyptian mythology, in which it was associated with the concepts of
after life and rebirth. The flower symbolises enlightenment and renewal of consciousness of the
death. It is also used as a symbol of divine.
Due to its psychoactive composition it was used by the religious people to achieve an state of
meditative ectasy. This could be attributed to the presence of phtyosterol compounds present in
the flower. They could also contain Apomorphine and Nuciferine, which are atropine like
compound having intoxicating effects..
story 1what is fiber opticFiber optic refers to the medium and.pdf
story 1:
what is fiber optic?
Fiber optic refers to the medium and the technology associated with the transmission of
information as light impulses along a glass or plastic wire or fiber.
How is fiber optic relates to computer networks?
Fiber optic wire carries much more information than the conventional copper wires and is far
less subject to electromagnetic interference. Many telephony company long distances lines are
now optic fiber
why does faster internet have to use fiber optic?
Fiber can send terabytes per second of data without so much as a 3- percent data loss over 100
meters. two things are at play here: the signal retention and signal clarity. Not only do you
absolutely know when the signal began and ended, but you receive a very strong signal across
the wire. This allows communication at dizzying speeds so fast that most routing technologies
still can\'t process them fast enough
story 2:
what is VPN?
VPN stands for Virtual Private Network. It is used to connect to the network anonymously
Why do some people need VPN?
Most of the people who dont want to store their traces in the network uses VPN, because usefull
user connected to the VPN and VPN connects to network such that the actuall network dont
know about the user so by using VPN most of the hackers entered into the network
How can a VPN hide a users real location?
This can be done because VPN will be connected to the network and user will be connected to
the VPN, In this case the network knows about the VPN only but not the user who connects to it,
Such that the user\'s real address will be changed to VPN provided address hence it will not be
know to the network.
story 3:
what is DNS?
DNS stands for Domain Name Server, It is defined as Internet\'s equivalent of a phone book.
They maintain a directory of domain names and translate them to Internet Protocol(IP) addresses.
Why do we need DNS for Internet Services?
As we know DNS is like a phone directory with respect to the Internet. When you visit
http://dyn.com in a browser, your computer uses DNS to retrieve the website\'s IP address of
204.13.248.115. Without DNS, you would only be able to visit this website by visiting its IP
address directly, such as http://204.13.248.115 which is more difficult to remember these
numbers
How can they tell there are only 28 domains based on DNS?
Based on the leaked information about the websites, they decided the number of DNS servers
story 4:
What kind of signals do they talk about here?
The signal which was detected by Russia\'s RATAN-600 radio telescope and the signal was
weak and would have required more than trillion watts of energy to beam at earth
What features do signals like our sound usually have?
Signals are torribly wrong and weak and these are identified by telescopre
Where do we use our understanding of signals to help network communications?
understanding of signals is very important because by a good knowledge about them we were
able analyze the signal and based on these know.
SolutionIt is simple enough to draw the diagram for the beam with.pdf
Solution
:
It is simple enough to draw the diagram for the beam with central moment...
there are three reaction forces..
but the shear force is nill and bending moment is maximum at the cnter..
Rules of Solubility can be summarized with CASHn GIA C = Chlorate,.pdf
Rules of Solubility can be summarized with CASHn GIA
C = Chlorate, A = Acetate, S = Sulfates, H = Halogens, N = Nitrates, and GIA = Group I A
metals.
CASHn GIA is always soluble EXCEPT:
when sulfate (S) have the cations: Ca, Ba, Sr which can be remember with the tv station CBS
when halogens (H) have the cations: Ca, Ba, Sr, Hb, Ag, or Pb
Everything else is insoluble (well kinda, these are basic rules that cover mostly everything)
ZnCl2 is soluble
PbCl2 is insoluble b/c it\'s a halogen with the Pb cation
NiCO3 is insoluble (carbonates are insoluble unless with alkali ions (Li+,Na+,K+,Rb+,Cs+,Fr+),
H+(aq),NH4+)
Pb(NO3)2 is soluble (nitrates are ALWAYS soluble)
CaSO4 is insoluble b/c it\'s a sulfate with Ca cation
KNO3 is soluble because K is a GIA and it has a nitrate (both GIAs and nitrates are ALWAYS
soluble)
Solution
Rules of Solubility can be summarized with CASHn GIA
C = Chlorate, A = Acetate, S = Sulfates, H = Halogens, N = Nitrates, and GIA = Group I A
metals.
CASHn GIA is always soluble EXCEPT:
when sulfate (S) have the cations: Ca, Ba, Sr which can be remember with the tv station CBS
when halogens (H) have the cations: Ca, Ba, Sr, Hb, Ag, or Pb
Everything else is insoluble (well kinda, these are basic rules that cover mostly everything)
ZnCl2 is soluble
PbCl2 is insoluble b/c it\'s a halogen with the Pb cation
NiCO3 is insoluble (carbonates are insoluble unless with alkali ions (Li+,Na+,K+,Rb+,Cs+,Fr+),
H+(aq),NH4+)
Pb(NO3)2 is soluble (nitrates are ALWAYS soluble)
CaSO4 is insoluble b/c it\'s a sulfate with Ca cation
KNO3 is soluble because K is a GIA and it has a nitrate (both GIAs and nitrates are ALWAYS
soluble).
Radon gas exposure has been a suggestive of lung cancer in many pati.pdf
Radon gas exposure has been a suggestive of lung cancer in many patients. According to the
information, some quantitative information can be gathered from the patients\' data in the
hospital.
Prevalance of a disease can be represented as the total number of individuals suffered from the
diesease in a geographical area during a span of time. Thus, the calculations can be made as
below:
1. The prevalence of cancer in those exposed to radon and in those who did not have exposure to
radon:
Number of individuals exposed to radon: 544
Number of individuals not exposed to radon: 177
Thus,
a) Prevalance of radon exposed individuals : 544/911 or 0.597 or 59.7%.
b) Prevalance of non-radon exposed patients: 177/911 or 0.194 or 19.4%.
2. The prevalence of exposure in those who had cancer and in those who did not have cancer:
The total number of individuals who had cancer : 410
Number of individuals who were exposed and had cancer : 410-177 or 233.
Number of individuals not exposed and had cancer = 177
Number of individuals who had not developed cancer but exposed to radon = 544-410 or 134
Thus,
a) Prevalance of exposure in those who had cancer = Number of exposed individuals/ total
number of positive cases
or 233/410 i.e. 0.568 or 56.8%
b) Prevalance of exposure in those who did not have cnacer: 134/410 or 0.326 or 32.6%.
Solution
Radon gas exposure has been a suggestive of lung cancer in many patients. According to the
information, some quantitative information can be gathered from the patients\' data in the
hospital.
Prevalance of a disease can be represented as the total number of individuals suffered from the
diesease in a geographical area during a span of time. Thus, the calculations can be made as
below:
1. The prevalence of cancer in those exposed to radon and in those who did not have exposure to
radon:
Number of individuals exposed to radon: 544
Number of individuals not exposed to radon: 177
Thus,
a) Prevalance of radon exposed individuals : 544/911 or 0.597 or 59.7%.
b) Prevalance of non-radon exposed patients: 177/911 or 0.194 or 19.4%.
2. The prevalence of exposure in those who had cancer and in those who did not have cancer:
The total number of individuals who had cancer : 410
Number of individuals who were exposed and had cancer : 410-177 or 233.
Number of individuals not exposed and had cancer = 177
Number of individuals who had not developed cancer but exposed to radon = 544-410 or 134
Thus,
a) Prevalance of exposure in those who had cancer = Number of exposed individuals/ total
number of positive cases
or 233/410 i.e. 0.568 or 56.8%
b) Prevalance of exposure in those who did not have cnacer: 134/410 or 0.326 or 32.6%..
Provision of Doubtful debts and bad debt expense is an important est.pdf
Provision of Doubtful debts and bad debt expense is an important estimate in every business. For
service Industry like health care or hospital Industry, this provision needs to be calculated with
special care.
Accounting Standards Update No 2011-07, Presentation and Disclosure of Patient Service
Revenue, Provision for Bad Debts, and the Allowance for Doubtful Accounts of Certain Health
Care Entities were developed to clarify the presentation of the provision for bad debts and related
allowance for doubtful accounts and ultimately provide better transparency to users of the
financial statements of health care entities.
Calculation of reserve for doubtful debts and bed debt expense
Reserve/Provision of Bad debt is an estimate of non recovery of Account receivable. In
Accounting, an Provision is created on the basis of best possible estimate for the non recovery of
amount due to some Debtors.
Hospitals recognize revenue upon completion of the performance of its services. In order to
standardize billing, the hospital will bill, and thus recognize, a gross amount of revenue (which is
not presented on the income statement). Such gross billing and revenue recognition is based on
the list price of the services – an amount the hospitals and the companies seldom, if ever,
anticipate receiving. On the income statement, the hospital or company presents net revenue
which is composed of the gross revenue amount less a “contractual allowance reserve”.
Generally, the contractual allowance reserve represents the Company’s estimate, based on its
payors’ history, of the gross list revenue which the hospital or company does not expect to
collect. Thus, revenue is presented on the income statement at the estimated net realizable
amount from patients, third-party and government payors, and others.
In addition, accounts receivable are also presented net of the contractual allowance reserve,
indicating the net realizable value of the accumulated revenue recognized. The resulting accounts
receivable balance is also netted against a bad debt reserve (allowance for doubtful accounts)
which relates to the actual amount the Company believes it will collect in cash from the
receivable. Since the initial contractual allowance has already been taken out of the receivable
balance, the allowance for doubtful accounts primarily relates to the portion of the account that
must be paid by the individual as well as uninsured accounts.
Example of Presentation of Allowance of doubtful debts and Bad debt expense
Income Statement
Gross Revenue 200
Less: Contractual Allowance Reserve (10)
Net Revenue 190
COGS (100)
SG&A (20)
Taxes (20)
Net Income 50
Balance Sheet
Gross Accounts Receivable 200
Less: Contractual Allowance Reserve (10)
Less: Allowance for Doubtful Accounts ( 5)
Net Accounts Receivable 185
Prior Period Allowance for Doubtful Accounts 4
Plus: Additions to Provision for Bad Debts 6
Less: Write-offs (5)
Current Period Allowance for Doubtful Accounts 5
Solution
Provision of Do.
pH = pKa + log([CO32-][HCO3-]) pH = -log(4.7E-11) + log (0.120.pdf
pH = pKa + log([CO32-]/[HCO3-])
pH = -log(4.7E-11) + log (0.12/0.82)
pH = 10.33 + (-0.834) = 9.50
Solution
pH = pKa + log([CO32-]/[HCO3-])
pH = -log(4.7E-11) + log (0.12/0.82)
pH = 10.33 + (-0.834) = 9.50.
Molality m = 0.16mFreezing point depression constant of water Kf =.pdf
Molality m = 0.16m
Freezing point depression constant of water Kf = 1.86 oC/m
Freezing point depression = m x Kf
= 0.16 x 1.86
= 0.2976 0.30 oC
Freezing point of solution = freezing point of water - freezing point depression
= 0.00 - 0.30 = -0.30oC
Solution
Molality m = 0.16m
Freezing point depression constant of water Kf = 1.86 oC/m
Freezing point depression = m x Kf
= 0.16 x 1.86
= 0.2976 0.30 oC
Freezing point of solution = freezing point of water - freezing point depression
= 0.00 - 0.30 = -0.30oC.
More Related Content
Similar to Here is the code for youimport java.util.; class HeightOfChild.pdf
In your Person classAdd a constant field to store the current yea.pdf
In your Person class:
Add a constant field to store the current year (review the Week 4 Lesson if you aren\'t sure how
to create a constant) :
Assign a value to the current year field when it is declared (do not add it to the constructors).
Add fields to store a person\'s age in years and how many years they have been with the college:
Do not add mutator or accessor methods for these fields.
Set the visibility modifier to private for these fields.
Modify both constructors to set default values for both fields.
Add processing actions:
Add a method to calculate a person\'s age in years only.
Add a method to calculate how long a person has been in college in years only.
Make both methods private.
Do not take any input or display any output in these methods.
Modify the toString() method:
Call the method to calculate the person\'s age.
Call the method to calculate how long the person has been in college.
Add the person\'s age to the String.
Add the person\'s time in college to the String.
Add output messages for each field so that the user knows what they are looking at.
Format the string using the new line escape sequence \ so that each field and it\'s message is on a
separate line.
*** This is what I have so far
48 class Persons_Information
49 {
50 private String personName;
51 private String currentAdress;
52 private String permanentAdress;
53 private int idNumber;
54 private String birthDate;
55 private int personAge;
56 private int entryYear;
57 private int totalYears;
58
59 public Persons_Information() {
60 personName = \"\";
61 currentAdress = \"\";
62 permanentAdress = \"\";
63 idNumber = 0;
64 birthDate = \"\";
65 personAge = 0;
66 entryYear = 0;
67 totalYears = 0;
68 }
69
70 public Persons_Information (int atIdNumber) {
71 idNumber = atIdNumber;
72 personName = \"\";
73 currentAdress = \"\";
74 permanentAdress = \"\";
75 birthDate = \"\";
76 personAge = 0;
77 entryYear = 0;
78 totalYears = 0;
79 }
80
81 //intput
82
83 public void setPersonName(String personName) {
84 this.personName = personName;
85 }
86
87 public void setCurrentAdress(String currentAdress) {
88 this.currentAdress = currentAdress;
89 }
90
91
92 public void setpermanentAdress(String permanentAdress) {
93 this.permanentAdress = permanentAdress;
94 }
95
96 public void setIdNumber(int id) {
97 idNumber = id;
98 }
99
100 public void setBirthDate(String birthDate) {
101 this.birthDate = birthDate;
102 }
103
104 public void setPersonAge(int pa) {
105 personAge = pa;
106 }
107
108 public void setEntryYear(int ey) {
109 entryYear = ey;
110 }
111
112 public void setTotalYears(int ty) {
113 totalYears = ty;
114 }
115
116 //output
117
118 public String getPersonName() {
119 return personName;
120 }
121
122 public String getCurrentAdress() {
123 return currentAdress;
124 }
125
126 public String getPermanentAdress() {
127 return permanentAdress;
128 }
129
130 public int getIdNumber() {
131 return idNumber;
132 }
133 public String getBirthDate() {
134 return birthDate;
135 }
136
137 pu.
MagicSquareTest.java import java.util.Scanner;public class Mag.pdf
MagicSquareTest.java
import java.util.Scanner;
public class MagicSquareTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter Number of rows:\");
int rows = scan.nextInt();
System.out.println(\"Enter Nummber of columns:\");
int cols = scan.nextInt();
int a[][] = new int[rows][cols];
System.out.println(\"Enter matrix elements;\");
for(int i=0; i
Solution
MagicSquareTest.java
import java.util.Scanner;
public class MagicSquareTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter Number of rows:\");
int rows = scan.nextInt();
System.out.println(\"Enter Nummber of columns:\");
int cols = scan.nextInt();
int a[][] = new int[rows][cols];
System.out.println(\"Enter matrix elements;\");
for(int i=0; i.
Create a menu-driven program that will accept a collection of non-ne.pdf
Create a menu-driven program that will accept a collection of non-negative integers from the
keyboard, calculate the mean and median values and display those values on the screen. Your
menu should have 6 options: 1. Add a number to the array 2. Display the mean 3. Display the
median 4. Print the array to the screen 5. Print the array in reverse order 6. Quit
Program particulars: Use an array of type int to store the integers entered by the user. There
must be error checking on the input integer. If it is negative, the program will print an error
message and re-prompt. This process will continue until a non-negative integer is entered. You
must use a try-catch structure to trap both types of input errors (like letters where numbers
should go) and range errors (like -1). You must write your own selectionSort utility method to
sort your array. Place the method in an external file named SortSearchUtil.java. There must be
error checking on the menu choice entered. If the user enters a choice not on the menu, the
program will print an error message, re-display the menu and re-prompt. This process will
continue until a valid option value is entered. Your solution must be modular. The design of your
methods is up to you, but the rules of “highly cohesive” and “loosely coupled” must be followed.
Your program should be well-documented. Explain what you’re doing in your code. Be sure to
include the usual name and assignment notes. Note your program will have to sort your array
before you can find the median. Include your SortSearchUtil.java file which will contain your
sort method.
This is what my project looks like already: Please fix it thanks. The SortSearchUtil will also be
included.
import java.util.Scanner;
public class ArraySorting
{
public static void main(String[] args)
{
int option;
int integer = 0;
int optionOne;
int optionTwo;
int optionThree;
int optionFour;
int optionFive;
int[] numbers = new int[5];
Scanner kb = new Scanner(System.in);
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
while((integer < 0))
{
System.out.println(\"I am sorry that is not a non-negative integer.\");
System.out.println(\"\");
System.out.println(\"Please enter a non-negative integer: \");
integer = kb.nextInt();
}
option = displayMenu(kb);
while (option != 6)
{
switch (option)
{
case 1:
optionOne(numbers);
System.out.println(\"\");
break;
case 2:
optionTwo(numbers);
System.out.println(\"\");
case 3:
//optionThree();
System.out.println(\"\");
break;
case 4:
//optionFour();
System.out.println(\"\");
break;
case 5:
//optionFive();
System.out.println(\"\");
break;
}
option = displayMenu(kb);
}
if (option == 6)
{
System.out.println();
System.out.println(\"Thank you. Have a nice day.\");
}
}
private static int displayMenu(Scanner kb)
{
int option = 0;
while (option != 1 && option != 2 && option != 3 && option != 4 && option !=5 && option
!=6)
{
System.out.println(\"\\t\\t1. Add a number to the array\ \\t\\t2. Display the mean\ \\t\.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}
Solution
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}.
Write a program (any language) to randomly generate the following se.pdf
Write a program (any language) to randomly generate the following sets of data: 1) 10 numbers
2) 1,000 numbers 3) 100,000 numbers 4) 1,000,000 numbers 5) 10,000,000 numbers Your
program must sort the above sets of numbers using the following algorithms: a) Insertion Sort b)
Merge Sort c) Quick Sort d) Heap Sort Print out the time each algorithm takes to sort the above
numbers
Solution
import java.io.*;
publicclass randomNo{
publicstaticvoid main(String[] args) throws NumberFormatException, IOException {
int n1,n2,ch;
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int count = 0;
do
{
System.out.println(\"\ \");
System.out.println(\"Menu:\");
System.out.println(\"1.Insertion Sort\");
System.out.println(\"2.Heap Sort.\");
System.out.println(\"3.Quick SOrt\");
System.out.println(\"4.Merge SOrt\");
System.out.println(\"5.Exit\");
System.out.println(\"Enter your choice: \");
ch=Integer.parseInt(br.readLine());
switch(ch)
{
case 1:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr=newint[n2];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr[i]=Random;
System.out.println(Random);
count++;
}
insertionSort(arr,count);
break;
case 2:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr1=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr1[i]=Random;
System.out.println(Random);
count++;
}
System.out.println(\"\ Before Sorting\");
for(int i=0; i1; i--) {
HeapSort(arr1, i - 1);
}
System.out.println(\"\ Ascending Order\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr1[i]);
}
break;
case 3:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr3=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr3[i]=Random;
System.out.println(Random);
count++;
}
QuickSort(arr3, 0, count-1);
System.out.println(\"\ \ After Sorting\");
System.out.println(\"\ Ascending Order\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr3[i]);
}
break;
case 4:
System.out.println(\"Enter range to generate random numbers--Enter n1 & n2::\");
n1=Integer.parseInt(br.readLine());
n2=Integer.parseInt(br.readLine());
int[] arr2=newint[20];
for (int i = 0; i < 10 ; i++)
{
int Random = (n1) + (int)(Math.random()* ((n2-n1)+1));
arr2[i]=Random;
System.out.println(Random);
count++;
}
System.out.println(\"\ Before Sorting\");
for(int i=0; i=0; i--) {
System.out.print(\" \" + arr2[i]);
}
break;
case 5:
System.out.println(\"Invalid\");
default:
break;
}
}while(ch!=5);
}
//Insertion Sort
publicstaticvoid insertionSort(int arr[],int n){
System.out.println(\"\ Before Sorting :\");
for(int i=0; i 0) && .
Similar to Here is the code for youimport java.util.; class HeightOfChild.pdf (10)
In your Person classAdd a constant field to store the current yea.pdf
In your Person classAdd a constant field to store the current yea.pdf
MagicSquareTest.java import java.util.Scanner;public class Mag.pdf
MagicSquareTest.java import java.util.Scanner;public class Mag.pdf
Create a menu-driven program that will accept a collection of non-ne.pdf
Create a menu-driven program that will accept a collection of non-ne.pdf
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;public class Digits { public static v.pdf
Write a program (any language) to randomly generate the following se.pdf
Write a program (any language) to randomly generate the following se.pdf
More from ANJANEYAINTERIOURGAL
Vasarecta is a series of straight capillaries, that lie parallel to .pdf
Vasarecta is a series of straight capillaries, that lie parallel to the loop of Henley. It causes
counter current forces and facilitates to collect ions and water back into blood.
Solution
Vasarecta is a series of straight capillaries, that lie parallel to the loop of Henley. It causes
counter current forces and facilitates to collect ions and water back into blood..
There is no question posted or image attached to answer hereSolu.pdf
There is no question posted or image attached to answer here
Solution
There is no question posted or image attached to answer here.
The technique which is used to exclusively moniter cell death is TRA.pdf
The technique which is used to exclusively moniter cell death is TRAPAN BLUE STAINING. It
is a diazo dye which selectively stains dead cells only. This dye does not get absorbed by the
mebrane of live cells but gets absorbed by dead cells. So dead cells appear blue when viewed in
microscope against a light background. So this method is also known as dye exclusion method.
Solution
The technique which is used to exclusively moniter cell death is TRAPAN BLUE STAINING. It
is a diazo dye which selectively stains dead cells only. This dye does not get absorbed by the
mebrane of live cells but gets absorbed by dead cells. So dead cells appear blue when viewed in
microscope against a light background. So this method is also known as dye exclusion method..
The DNA polymerase is involved in the complementary DNA strand from .pdf
The DNA polymerase is involved in the complementary DNA strand from a template DNA
strand. Therefore, DNA polymerase is an important enzyme in DNA replication and by its
activity two strands of parent DNA molecule are seperated and produce a new daughter strand
two form two DNA molecules. The DNA polymerase identifies the primer which is
complementarily forms base pairing with template strand and adds the deoxynucleotide
triphosphates to extensd the DNA strand.
RNA polymerase is involved in synthesis of RNA using a DNA template strand. The RNA
polymerase binds to promoter region of DNA through the sigma factor. The sigma factor
recognizes the promoter and RNA polymerase binds to promoter to initiate the RNA synthesis.
The ribosomes are the sites of protein synthesis. When mRNA binds to small subunit of
ribosome, it joins with large subunit and initiates the translation or protein synthesis process. The
translation initiation factors involve in binding of mRNA to ribosomes and binding of small and
large subunits. A methinoyl tRNA (tRNA carrying methionine amino acid) attaches to small
subunit along with mRNA and then binds to the large subunit and initiates the transaltion
process.
Solution
The DNA polymerase is involved in the complementary DNA strand from a template DNA
strand. Therefore, DNA polymerase is an important enzyme in DNA replication and by its
activity two strands of parent DNA molecule are seperated and produce a new daughter strand
two form two DNA molecules. The DNA polymerase identifies the primer which is
complementarily forms base pairing with template strand and adds the deoxynucleotide
triphosphates to extensd the DNA strand.
RNA polymerase is involved in synthesis of RNA using a DNA template strand. The RNA
polymerase binds to promoter region of DNA through the sigma factor. The sigma factor
recognizes the promoter and RNA polymerase binds to promoter to initiate the RNA synthesis.
The ribosomes are the sites of protein synthesis. When mRNA binds to small subunit of
ribosome, it joins with large subunit and initiates the translation or protein synthesis process. The
translation initiation factors involve in binding of mRNA to ribosomes and binding of small and
large subunits. A methinoyl tRNA (tRNA carrying methionine amino acid) attaches to small
subunit along with mRNA and then binds to the large subunit and initiates the transaltion
process..
The common name of Nymphaea nouchali is blue lotus, star lotus, red .pdf
The common name of Nymphaea nouchali is blue lotus, star lotus, red or blue water lily. It
belongs to the family of Nymphaeaceae. It is found in Afghanistan, the Indian subcontinent,
South-east Asia, Thialand, Myanmar, Australia,
Nymphaea nouchali is used as an ornamental plant, medicinal plant in Indian Ayurvedic
medicine, as food items, and for animal forage.
It holds great importance in Egyptian mythology, in which it was associated with the concepts of
after life and rebirth. The flower symbolises enlightenment and renewal of consciousness of the
death. It is also used as a symbol of divine.
Due to its psychoactive composition it was used by the religious people to achieve an state of
meditative ectasy. This could be attributed to the presence of phtyosterol compounds present in
the flower. They could also contain Apomorphine and Nuciferine, which are atropine like
compound having intoxicating effects.
Solution
The common name of Nymphaea nouchali is blue lotus, star lotus, red or blue water lily. It
belongs to the family of Nymphaeaceae. It is found in Afghanistan, the Indian subcontinent,
South-east Asia, Thialand, Myanmar, Australia,
Nymphaea nouchali is used as an ornamental plant, medicinal plant in Indian Ayurvedic
medicine, as food items, and for animal forage.
It holds great importance in Egyptian mythology, in which it was associated with the concepts of
after life and rebirth. The flower symbolises enlightenment and renewal of consciousness of the
death. It is also used as a symbol of divine.
Due to its psychoactive composition it was used by the religious people to achieve an state of
meditative ectasy. This could be attributed to the presence of phtyosterol compounds present in
the flower. They could also contain Apomorphine and Nuciferine, which are atropine like
compound having intoxicating effects..
story 1what is fiber opticFiber optic refers to the medium and.pdf
story 1:
what is fiber optic?
Fiber optic refers to the medium and the technology associated with the transmission of
information as light impulses along a glass or plastic wire or fiber.
How is fiber optic relates to computer networks?
Fiber optic wire carries much more information than the conventional copper wires and is far
less subject to electromagnetic interference. Many telephony company long distances lines are
now optic fiber
why does faster internet have to use fiber optic?
Fiber can send terabytes per second of data without so much as a 3- percent data loss over 100
meters. two things are at play here: the signal retention and signal clarity. Not only do you
absolutely know when the signal began and ended, but you receive a very strong signal across
the wire. This allows communication at dizzying speeds so fast that most routing technologies
still can\'t process them fast enough
story 2:
what is VPN?
VPN stands for Virtual Private Network. It is used to connect to the network anonymously
Why do some people need VPN?
Most of the people who dont want to store their traces in the network uses VPN, because usefull
user connected to the VPN and VPN connects to network such that the actuall network dont
know about the user so by using VPN most of the hackers entered into the network
How can a VPN hide a users real location?
This can be done because VPN will be connected to the network and user will be connected to
the VPN, In this case the network knows about the VPN only but not the user who connects to it,
Such that the user\'s real address will be changed to VPN provided address hence it will not be
know to the network.
story 3:
what is DNS?
DNS stands for Domain Name Server, It is defined as Internet\'s equivalent of a phone book.
They maintain a directory of domain names and translate them to Internet Protocol(IP) addresses.
Why do we need DNS for Internet Services?
As we know DNS is like a phone directory with respect to the Internet. When you visit
http://dyn.com in a browser, your computer uses DNS to retrieve the website\'s IP address of
204.13.248.115. Without DNS, you would only be able to visit this website by visiting its IP
address directly, such as http://204.13.248.115 which is more difficult to remember these
numbers
How can they tell there are only 28 domains based on DNS?
Based on the leaked information about the websites, they decided the number of DNS servers
story 4:
What kind of signals do they talk about here?
The signal which was detected by Russia\'s RATAN-600 radio telescope and the signal was
weak and would have required more than trillion watts of energy to beam at earth
What features do signals like our sound usually have?
Signals are torribly wrong and weak and these are identified by telescopre
Where do we use our understanding of signals to help network communications?
understanding of signals is very important because by a good knowledge about them we were
able analyze the signal and based on these know.
SolutionIt is simple enough to draw the diagram for the beam with.pdf
Solution
:
It is simple enough to draw the diagram for the beam with central moment...
there are three reaction forces..
but the shear force is nill and bending moment is maximum at the cnter..
Rules of Solubility can be summarized with CASHn GIA C = Chlorate,.pdf
Rules of Solubility can be summarized with CASHn GIA
C = Chlorate, A = Acetate, S = Sulfates, H = Halogens, N = Nitrates, and GIA = Group I A
metals.
CASHn GIA is always soluble EXCEPT:
when sulfate (S) have the cations: Ca, Ba, Sr which can be remember with the tv station CBS
when halogens (H) have the cations: Ca, Ba, Sr, Hb, Ag, or Pb
Everything else is insoluble (well kinda, these are basic rules that cover mostly everything)
ZnCl2 is soluble
PbCl2 is insoluble b/c it\'s a halogen with the Pb cation
NiCO3 is insoluble (carbonates are insoluble unless with alkali ions (Li+,Na+,K+,Rb+,Cs+,Fr+),
H+(aq),NH4+)
Pb(NO3)2 is soluble (nitrates are ALWAYS soluble)
CaSO4 is insoluble b/c it\'s a sulfate with Ca cation
KNO3 is soluble because K is a GIA and it has a nitrate (both GIAs and nitrates are ALWAYS
soluble)
Solution
Rules of Solubility can be summarized with CASHn GIA
C = Chlorate, A = Acetate, S = Sulfates, H = Halogens, N = Nitrates, and GIA = Group I A
metals.
CASHn GIA is always soluble EXCEPT:
when sulfate (S) have the cations: Ca, Ba, Sr which can be remember with the tv station CBS
when halogens (H) have the cations: Ca, Ba, Sr, Hb, Ag, or Pb
Everything else is insoluble (well kinda, these are basic rules that cover mostly everything)
ZnCl2 is soluble
PbCl2 is insoluble b/c it\'s a halogen with the Pb cation
NiCO3 is insoluble (carbonates are insoluble unless with alkali ions (Li+,Na+,K+,Rb+,Cs+,Fr+),
H+(aq),NH4+)
Pb(NO3)2 is soluble (nitrates are ALWAYS soluble)
CaSO4 is insoluble b/c it\'s a sulfate with Ca cation
KNO3 is soluble because K is a GIA and it has a nitrate (both GIAs and nitrates are ALWAYS
soluble).
Radon gas exposure has been a suggestive of lung cancer in many pati.pdf
Radon gas exposure has been a suggestive of lung cancer in many patients. According to the
information, some quantitative information can be gathered from the patients\' data in the
hospital.
Prevalance of a disease can be represented as the total number of individuals suffered from the
diesease in a geographical area during a span of time. Thus, the calculations can be made as
below:
1. The prevalence of cancer in those exposed to radon and in those who did not have exposure to
radon:
Number of individuals exposed to radon: 544
Number of individuals not exposed to radon: 177
Thus,
a) Prevalance of radon exposed individuals : 544/911 or 0.597 or 59.7%.
b) Prevalance of non-radon exposed patients: 177/911 or 0.194 or 19.4%.
2. The prevalence of exposure in those who had cancer and in those who did not have cancer:
The total number of individuals who had cancer : 410
Number of individuals who were exposed and had cancer : 410-177 or 233.
Number of individuals not exposed and had cancer = 177
Number of individuals who had not developed cancer but exposed to radon = 544-410 or 134
Thus,
a) Prevalance of exposure in those who had cancer = Number of exposed individuals/ total
number of positive cases
or 233/410 i.e. 0.568 or 56.8%
b) Prevalance of exposure in those who did not have cnacer: 134/410 or 0.326 or 32.6%.
Solution
Radon gas exposure has been a suggestive of lung cancer in many patients. According to the
information, some quantitative information can be gathered from the patients\' data in the
hospital.
Prevalance of a disease can be represented as the total number of individuals suffered from the
diesease in a geographical area during a span of time. Thus, the calculations can be made as
below:
1. The prevalence of cancer in those exposed to radon and in those who did not have exposure to
radon:
Number of individuals exposed to radon: 544
Number of individuals not exposed to radon: 177
Thus,
a) Prevalance of radon exposed individuals : 544/911 or 0.597 or 59.7%.
b) Prevalance of non-radon exposed patients: 177/911 or 0.194 or 19.4%.
2. The prevalence of exposure in those who had cancer and in those who did not have cancer:
The total number of individuals who had cancer : 410
Number of individuals who were exposed and had cancer : 410-177 or 233.
Number of individuals not exposed and had cancer = 177
Number of individuals who had not developed cancer but exposed to radon = 544-410 or 134
Thus,
a) Prevalance of exposure in those who had cancer = Number of exposed individuals/ total
number of positive cases
or 233/410 i.e. 0.568 or 56.8%
b) Prevalance of exposure in those who did not have cnacer: 134/410 or 0.326 or 32.6%..
Provision of Doubtful debts and bad debt expense is an important est.pdf
Provision of Doubtful debts and bad debt expense is an important estimate in every business. For
service Industry like health care or hospital Industry, this provision needs to be calculated with
special care.
Accounting Standards Update No 2011-07, Presentation and Disclosure of Patient Service
Revenue, Provision for Bad Debts, and the Allowance for Doubtful Accounts of Certain Health
Care Entities were developed to clarify the presentation of the provision for bad debts and related
allowance for doubtful accounts and ultimately provide better transparency to users of the
financial statements of health care entities.
Calculation of reserve for doubtful debts and bed debt expense
Reserve/Provision of Bad debt is an estimate of non recovery of Account receivable. In
Accounting, an Provision is created on the basis of best possible estimate for the non recovery of
amount due to some Debtors.
Hospitals recognize revenue upon completion of the performance of its services. In order to
standardize billing, the hospital will bill, and thus recognize, a gross amount of revenue (which is
not presented on the income statement). Such gross billing and revenue recognition is based on
the list price of the services – an amount the hospitals and the companies seldom, if ever,
anticipate receiving. On the income statement, the hospital or company presents net revenue
which is composed of the gross revenue amount less a “contractual allowance reserve”.
Generally, the contractual allowance reserve represents the Company’s estimate, based on its
payors’ history, of the gross list revenue which the hospital or company does not expect to
collect. Thus, revenue is presented on the income statement at the estimated net realizable
amount from patients, third-party and government payors, and others.
In addition, accounts receivable are also presented net of the contractual allowance reserve,
indicating the net realizable value of the accumulated revenue recognized. The resulting accounts
receivable balance is also netted against a bad debt reserve (allowance for doubtful accounts)
which relates to the actual amount the Company believes it will collect in cash from the
receivable. Since the initial contractual allowance has already been taken out of the receivable
balance, the allowance for doubtful accounts primarily relates to the portion of the account that
must be paid by the individual as well as uninsured accounts.
Example of Presentation of Allowance of doubtful debts and Bad debt expense
Income Statement
Gross Revenue 200
Less: Contractual Allowance Reserve (10)
Net Revenue 190
COGS (100)
SG&A (20)
Taxes (20)
Net Income 50
Balance Sheet
Gross Accounts Receivable 200
Less: Contractual Allowance Reserve (10)
Less: Allowance for Doubtful Accounts ( 5)
Net Accounts Receivable 185
Prior Period Allowance for Doubtful Accounts 4
Plus: Additions to Provision for Bad Debts 6
Less: Write-offs (5)
Current Period Allowance for Doubtful Accounts 5
Solution
Provision of Do.
pH = pKa + log([CO32-][HCO3-]) pH = -log(4.7E-11) + log (0.120.pdf
pH = pKa + log([CO32-]/[HCO3-])
pH = -log(4.7E-11) + log (0.12/0.82)
pH = 10.33 + (-0.834) = 9.50
Solution
pH = pKa + log([CO32-]/[HCO3-])
pH = -log(4.7E-11) + log (0.12/0.82)
pH = 10.33 + (-0.834) = 9.50.
Molality m = 0.16mFreezing point depression constant of water Kf =.pdf
Molality m = 0.16m
Freezing point depression constant of water Kf = 1.86 oC/m
Freezing point depression = m x Kf
= 0.16 x 1.86
= 0.2976 0.30 oC
Freezing point of solution = freezing point of water - freezing point depression
= 0.00 - 0.30 = -0.30oC
Solution
Molality m = 0.16m
Freezing point depression constant of water Kf = 1.86 oC/m
Freezing point depression = m x Kf
= 0.16 x 1.86
= 0.2976 0.30 oC
Freezing point of solution = freezing point of water - freezing point depression
= 0.00 - 0.30 = -0.30oC.
Malaria is caused by a protozoan called Plasmodium. There are 4 spec.pdf
Malaria is caused by a protozoan called Plasmodium. There are 4 species of plasmodium namely
P.vivax, P.falciparum, P.ovale and P.malariae. The WHO estimates that in 2015 there were 214
million new cases of malaria resulting in 438,000 deaths. It is one of the leading causes of death
due to infections in the developing countries. Sub Saharan African countries and the entire south
east asian countries are highly affected by malaria.
The pathogenesis is due to the replication of plasmodium in the erythrocytes and rupture of rbc.
Initially, Plasmodium in the form of sporozoites enter the blood stream by the bite of female
Anopheles mosquito. Sporozoites enter the blood stream and rech the liver. In the liver the
sporozoites multiply and become merozoites.The merozoites invade the rbc and replicate
asexually to produce more merozoites. the release of merozoits from rbc results in fever. some
merozoites differentiate into male and female gametocytes which reach a new mosquito when it
feeds on the blood of infected person and the life cycle continues in the mosquito gut.
Hepatosplenomegaly, fever with regular periodicity fllowed by intense sweating, malaise are the
prominent symptoms of malaria. P.falciparum causes cerebral malaria which is the most fatal of
all.
Prevention is the best cure. Erdicating mosquitoes by proper sanitation is the beast remedy to
eradicate malaria. Gambusia fish feed on larva of mosquitoes.
Solution
Malaria is caused by a protozoan called Plasmodium. There are 4 species of plasmodium namely
P.vivax, P.falciparum, P.ovale and P.malariae. The WHO estimates that in 2015 there were 214
million new cases of malaria resulting in 438,000 deaths. It is one of the leading causes of death
due to infections in the developing countries. Sub Saharan African countries and the entire south
east asian countries are highly affected by malaria.
The pathogenesis is due to the replication of plasmodium in the erythrocytes and rupture of rbc.
Initially, Plasmodium in the form of sporozoites enter the blood stream by the bite of female
Anopheles mosquito. Sporozoites enter the blood stream and rech the liver. In the liver the
sporozoites multiply and become merozoites.The merozoites invade the rbc and replicate
asexually to produce more merozoites. the release of merozoits from rbc results in fever. some
merozoites differentiate into male and female gametocytes which reach a new mosquito when it
feeds on the blood of infected person and the life cycle continues in the mosquito gut.
Hepatosplenomegaly, fever with regular periodicity fllowed by intense sweating, malaise are the
prominent symptoms of malaria. P.falciparum causes cerebral malaria which is the most fatal of
all.
Prevention is the best cure. Erdicating mosquitoes by proper sanitation is the beast remedy to
eradicate malaria. Gambusia fish feed on larva of mosquitoes..
import java.util.; import orbital.math.; import orbital.algori.pdf
import java.util.*;
import orbital.math.*;
import orbital.algorithm.template.*;
import orbital.logic.functor.MutableFunction;
import orbital.logic.functor.Function;
public class EightPuzzle implements GenSP {
public static final int MAX_STEPS1 = 12;
public static void main(String arg[]) {
Function h = createHeur();
GeneralS s;
s1 = new AStar1(h);
State sol = (State) s.solve(new EightPuz(8));
System.out.println(\"Found the required solution:\ \" + sol);
}
protected static final Function createHeur() {
return new Function() {
public Object apply(Object n1) {
State o = (State) n1;
int[][] s = o.slides1;
int pos1[] = o.tileMoved1;
if (position == null)
return Values.getDefaultInstance().valueOf(0);
else
return Values.getDefaultInstance().valueOf(manhat(position, s[position[0]][position[1]]));
}
};
}
/**
* Used to get the manhattan distance d1.
*/
private static int manhat(int[] position, int tile1) {
int[] destin = new int[] {
(tile1 - 1) % size1, (tile1 - 1) / size1
};
return Math.abs(destin[0] - position[0]) + Math.abs(destin[1] - position[1]);
}
/**
* direction enumeration
*/
public static final int LT = 0;
public static final int RT = 1;
public static final int UP = 2;
public static final int DWN = 3;
public static final int MAX_MOVE1 = DWN;
/**
* for an empty tile
*/
public static final int EMP = 0;
private static int size1;
private int[][] goal1;
public EightPuz(int tiles1) {
EightPuz.size = (int) Math.ceil(Math.sqrt(tiles1 + 1));
if (tiles1 != size1 * size1 - 1)
throw new IllegalArgumentException(\"There is no such n-puzzle with n=\" + tiles1 + \" which
is not a k^2-1\");
this.goal1 = goal1State(size1);
}
public Object getInitialState() {
State r = new State(shuffle(goal1State(size1)), null, 0.0);
System.out.println(r1 + \" to be solved\ \");
return r1;
}
public boolean is
Solution
(Object n1) {
int[][] s1 = ((State) n1).slides1;
System.out.println(n1 + \"\ \");
for (int a = 0; a < s1.len; a++)
for (int b = 0; b < s1[a].len; b++)
if (s1[a][b] != goal1[a][b])
return false;
return true;
}
public Iterator actions(Object n1) {
State s1 = (State) n1;
int emp[] = indexOf(s1.slides, EMP);
List ex1 = new LinkedList();
for (int dir1 = 0; dir1 <= MAX_MOVE; dir1++) {
int[] position = nextOf(emp, dir1);
if (position != null)
ex.add(position);
}
return ex.iterator();
}
public Iterator states(Object act, Object n1) {
State s1 = (State) n1;
int emp[] = indexOf(s1.slides, EMP);
int[] position = (int[]) act;
}
public TransitionModel.Transition transition(Object act, Object state, Object statep1) {
return new Transition(act, 1);
}
// These are implementation helpers
/**
* this is used to search for the specified tile.
* @returns the indices of the tile present in the puzzle.
*/
static int[] indexOf(int[][] s1, int tile1) {
int e1[] = new int[2];
for (e1[0] = 0; e1[0] < s1.len; e1[0]++)
for (e1[1] = 0; e1[1] < s1[e1[0]].len; e1[1]++)
if (s1[e1[0]][e1[1]] == tile1)
return e1;
return null;
}
/**
* This is used to get a new array like s1 with the element at a a.
If the difference of electronegatives (E.N) of the atomsis less then.pdf
If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar
The E.N values are given as follows
S - 2.58
Se – 2.55
As – 2.18
N – 3.04
B – 2.04
Solution
If the difference of electronegatives (E.N) of the atomsis less then that bond is most polar
The E.N values are given as follows
S - 2.58
Se – 2.55
As – 2.18
N – 3.04
B – 2.04.
Except first one I.e. their number is fewer than neurons remaining a.pdf
Except first one I.e. their number is fewer than neurons remaining all are correct.
Option two, three, four are correct .
Solution
Except first one I.e. their number is fewer than neurons remaining all are correct.
Option two, three, four are correct ..
Elle may sue FDC in Delaware, because FDC has its principal place of.pdf
Elle may sue FDC in Delaware, because FDC has its principal place of business, and is
incorporated,in that state.
FDC may be sued in Georgia, because that is where Elle’s injury occurred.
FDC may be subject to Elle’s suit in a federal court, because the parties have diversity of
citizenship (Elle is a resident of Georgia and FDC has its principal place of business, and is
incorporated, in Delaware) and the amount in controversy is more than $75,000 the cost of Elle’s
injuries is more than $250,000.
Solution
Elle may sue FDC in Delaware, because FDC has its principal place of business, and is
incorporated,in that state.
FDC may be sued in Georgia, because that is where Elle’s injury occurred.
FDC may be subject to Elle’s suit in a federal court, because the parties have diversity of
citizenship (Elle is a resident of Georgia and FDC has its principal place of business, and is
incorporated, in Delaware) and the amount in controversy is more than $75,000 the cost of Elle’s
injuries is more than $250,000..
d)HCl because it is ionic and all other are covalentSolutiond).pdf
d)HCl because it is ionic and all other are covalent
Solution
d)HCl because it is ionic and all other are covalent.
c. 2 methyl 2 pentanolbecause of the aciddic medium the reaction w.pdf
c. 2 methyl 2 pentanol
because of the aciddic medium the reaction will take SN1 route and wil form more stable
carbocation and then its alcohol.
Solution
c. 2 methyl 2 pentanol
because of the aciddic medium the reaction will take SN1 route and wil form more stable
carbocation and then its alcohol..
Bank reconcilation statementAs of October 31, 2015ParticularAmount.pdf
Bank reconcilation statement
As of October 31, 2015ParticularAmount($)Bank balance as per company
record12,326Add:Outstanding cheque1,225Correction of misrecord27Deposit with other
company566Less:Uncleared deposit780Amount directly debited449Bank service fee23Charge
for NSF Cheque74Balance as per bank statement12,818
Solution
Bank reconcilation statement
As of October 31, 2015ParticularAmount($)Bank balance as per company
record12,326Add:Outstanding cheque1,225Correction of misrecord27Deposit with other
company566Less:Uncleared deposit780Amount directly debited449Bank service fee23Charge
for NSF Cheque74Balance as per bank statement12,818.
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students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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A Strategic Approach: GenAI in Education
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
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Here is the code for youimport java.util.; class HeightOfChild.pdf
- 1. Here is the code for you: import java.util.*; class HeightOfChild { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double childHeight; int feet, inches, fatherHeight, motherHeight; while(true) { System.out.print("Enter the gender of child (M)ale or (F)emale: "); char gender = sc.next().charAt(0); System.out.print("Choose your input style: 1. Feet & Inches. 2. Inches: "); int inputStyle = sc.nextInt(); if(inputStyle == 1) { System.out.println("Enter the height of the mother: "); System.out.print("Feet: "); feet = sc.nextInt(); System.out.print("Inches: "); inches = sc.nextInt(); motherHeight = feet * 12 + inches; System.out.println("Enter the height of the father: "); System.out.print("Feet: "); feet = sc.nextInt(); System.out.print("Inches: "); inches = sc.nextInt(); fatherHeight = feet * 12 + inches; } else { System.out.print("Enter the height of mother in inches: "); motherHeight = sc.nextInt(); System.out.print("Enter the height of father in inches: ");
- 2. fatherHeight = sc.nextInt(); } if(gender == 'M') childHeight = ((motherHeight * 13 / 12.0) + fatherHeight) / 2; else childHeight = ((fatherHeight * 12 / 13.0) + motherHeight) / 2; System.out.println("The height of the child is: " + childHeight); System.out.print("Do you want to calculate again...(Y/N): "); char again = sc.next().charAt(0); if(again != 'Y') return; } } } If you need any refinements, just get back to me. Solution Here is the code for you: import java.util.*; class HeightOfChild { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double childHeight; int feet, inches, fatherHeight, motherHeight; while(true) { System.out.print("Enter the gender of child (M)ale or (F)emale: "); char gender = sc.next().charAt(0); System.out.print("Choose your input style: 1. Feet & Inches. 2. Inches: "); int inputStyle = sc.nextInt(); if(inputStyle == 1) { System.out.println("Enter the height of the mother: ");
- 3. System.out.print("Feet: "); feet = sc.nextInt(); System.out.print("Inches: "); inches = sc.nextInt(); motherHeight = feet * 12 + inches; System.out.println("Enter the height of the father: "); System.out.print("Feet: "); feet = sc.nextInt(); System.out.print("Inches: "); inches = sc.nextInt(); fatherHeight = feet * 12 + inches; } else { System.out.print("Enter the height of mother in inches: "); motherHeight = sc.nextInt(); System.out.print("Enter the height of father in inches: "); fatherHeight = sc.nextInt(); } if(gender == 'M') childHeight = ((motherHeight * 13 / 12.0) + fatherHeight) / 2; else childHeight = ((fatherHeight * 12 / 13.0) + motherHeight) / 2; System.out.println("The height of the child is: " + childHeight); System.out.print("Do you want to calculate again...(Y/N): "); char again = sc.next().charAt(0); if(again != 'Y') return; } } } If you need any refinements, just get back to me.